How big is 200 meters in km?

How big is 200 meters in km?
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1 Answer

Answer :

It is: 200/1000 or 1/5 of a km
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For a space wave transmission, the radio horizon distance of a receiving antenna with a height of 64 meters is approximately A. 8 km B. 32 km C. 64 km D. 256 km

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If a transmitting antenna is 100 meters high and a separate receiving antenna is 64 meters high, what is the maximum space wave communication distance possible between them? A. 18 km B. 72 km C. 164 km D. 656 km

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For a space wave transmission, the radio horizon distance of a transmitting antenna with a height of 100 meters is approximately:A. 10 km B. 40 km C. 100 km D. 400 km

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A train running at the speed of 60 km/hr crosses a pole in 9 seconds. What is the length of the train? a) 120 meters b) 180 meters c) 324 meters d) 150 meters

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Two metro train 360 meters and 360 meters in length respectively and running in same directions, one at the rate of 116 km and other at the rate of 100 km an hours. What time will they be cross of each other? A) 100 sec B) 162sec C) 132sec D) 126sec

Description : Two metro train 360 meters and 360 meters in length respectively and running in same directions, one at the rate of 116 km and other at the rate of 100 km an hours. What time will they be cross of each other? A) 100 sec B) 162sec C) 132sec D) 126sec

Last Answer : ANSWER: B Explanation:  Length of the 1st metro train = 360m  Length of the 2nd  metro train = 360m  Total length of the both metro train = 360 + 360 = 720 m  speed of the 1st metro train = 116 km/hr ...  Required time = distance / speed  = (720/(40/9))sec  = 720 * 9 /40  = 162sec.

A shatabadi express takes 240 seconds to cover a distance of length 700 meters at a speed of 270 km/hr. What will be the time taken by the train to cross a standing pole? A) 160sec B) 465sec C) 310sec D) 231sec

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Last Answer : ANSWER:D Explanation:  Speed of the train = 270 km/hr. Converting the speed into m/sec  Speed = 270 km/hr = 270 x 5/18 m/sec = 75 m/sec  First, we have to find the length of the train  Let ... a standing Pole at 75 m/s =( 17300/75)seconds = 231 seconds. Hence the answer is 231 sec(approx.)

A train, 1800 meters long running at the rate of 204 km/hr will cross a platform in: A) 16 B) 32 C) 45 D) 64

Description : A train, 1800 meters long running at the rate of 204 km/hr will cross a platform in: A) 16 B) 32 C) 45 D) 64 

Last Answer : ANSWER: B  Explanation: Speed of the train = 204 km/hr. We have to find the time in seconds, so convert the speed in the unit of m/sec. Therefore 204 km/hr = 204 x 5/18 m/s  = 1020/18 m/s  Length ... m/sec  Time = distance/speed  = 1800/(1020/18)sec  = (1800*18/1020)sec  = 32 sec (approx.)

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Last Answer : ANSWER: C Explanation: Given speed of the train = 63 km/hr = 63*5/18 m/s =17.5m/s Let the length of the pole = x mts Given time taken to cover the distance of (510+ x)mts is 90 sec. We know speed = ... m/s 17. 5 = 510+x/90 1575 = 510+x x = 1065 Therefore the length of the pole is 1065 mts

What should I do now ? There was an annual sports competition at the school where I had to stand for a long time waiting for the race to start. I ran 100 meters and 200 meters with leg pain. Now the leg pain has increased. What should I do now so that the leg pain decreases quickly ?

Description : What should I do now ? There was an annual sports competition at the school where I had to stand for a long time waiting for the race to start. I ran 100 meters and 200 meters with leg pain. Now the leg pain has increased. What should I do now so that the leg pain decreases quickly ?

Last Answer : You take calcium tablets (if you are 14 years old). Apply ointment on the feet. Do not keep feet cold. Heat your feet with hot water and you will get a lot of comfort. And the envoy should consult a physician directly.

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Carlos is pulling a 40 kilogram cart with a horizontal force of 100 newtons. The force of friction on the cart is 20 newtons. The acceleration of the cart is: w) 2 meters per second squared x) 2.5 meters per second squared y) 20 meters per second squared z) 200 meters per second squared

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A worker lifts a 10 kilogram block a vertical height of 2 meters. The work he does on the block is: w) 5 Joules x) 20 Joules y) 49 Joules z) 200 Joules

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A certain machine exerts a force of 200 newtons on a box whose mass is 30 kilograms. The machine moves the box a distance of 20 meters along a horizontal floor. What amount of work does the machine do on the box?

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A satellite orbits the earth 200 km above the surface. What speed, in m/s, is necessary for a circular orbit? The radius of the earth is 6400 km and g = 9.2 m/s2 a.7200 b.6600 c.7800 d.6000 e.107 dynes

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Name any two densely populated regions of Asia having more than 200 persons per sq. km. -Geography

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Earth's atmosphere is an envelope of gases extending to a height of – (1) 100 km (2) 150 km (3) 200 km (4) 300 km

Description : Earth's atmosphere is an envelope of gases extending to a height of – (1) 100 km (2) 150 km (3) 200 km (4) 300 km

Last Answer : (3) 200 km Explanation: The atmosphere of the. Earth is an envelope of gases extending to a height of 200km.

The ozone layer in the atmosphere is at a height of about ______. (1) 25 km (2) 50 km (3) 100 km (4) 200 km

Description : The ozone layer in the atmosphere is at a height of about ______. (1) 25 km (2) 50 km (3) 100 km (4) 200 km

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The angle of elevation of the antenna beam is 20°. Calculate the transmission-path distance for an ionospheric transmission that utilizes a layer of virtual height 200 km. Use flat-earth approximation. A. 966 km B. 2100 km C. 1100 km D. 405 km

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Last Answer : C. 1100 km

India’s territorial water extends up U9to a distance of ? (a) 19.2 miles (b) 12 nautical miles (c) 200 nautical miles (d) 12 km

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Last Answer : (b) 12 nautical miles

The curvature of the earth's surface, is taken into account only if the extent of survey is more than (A) 100 sq km (B) 160 sq km (C) 200 sq km (D) 260 sq km

Description : The curvature of the earth's surface, is taken into account only if the extent of survey is more than (A) 100 sq km (B) 160 sq km (C) 200 sq km (D) 260 sq km

Last Answer : (D) 260 sq km

The sum of the interior angles of a geometrical figure laid on the surface of the earth differs from that of the corresponding plane figure only to the extent of one second for every (A) 100 sq. km of area (B) 150 sq. km of area (C) 200 sq. km of area (D) None of these

Description : The sum of the interior angles of a geometrical figure laid on the surface of the earth differs from that of the corresponding plane figure only to the extent of one second for every (A) 100 sq. km of area (B) 150 sq. km of area (C) 200 sq. km of area (D) None of these

Last Answer : (C) 200 sq. km of area

Orbital radius of GPS satellites is approximately: (A) 15,200 km (B) 26,600 km (C) 18,400 km (D) 36,000 km

Description : Orbital radius of GPS satellites is approximately: (A) 15,200 km (B) 26,600 km (C) 18,400 km (D) 36,000 km

Last Answer : Answer: Option B

The normal altitude of GPS satellite is about (A) 16,200 km (B) 20,200 km (C) 24,400 km (D) 36,100 km

Description : The normal altitude of GPS satellite is about (A) 16,200 km (B) 20,200 km (C) 24,400 km (D) 36,100 km

Last Answer : Answer: Option B

Which one of the following statements is correct regarding the GPS satellites? (A) The nominal altitude is about 20,200 km (B) The inclination of axis satellite is 55° (C) The satellite transmits two L band signals (L1 with 1575.42 MHz and L2 with 1276.6 MHz) (D) All of these

Description : Which one of the following statements is correct regarding the GPS satellites? (A) The nominal altitude is about 20,200 km (B) The inclination of axis satellite is 55° (C) The satellite transmits two L band signals (L1 with 1575.42 MHz and L2 with 1276.6 MHz) (D) All of these

Last Answer : Answer: Option D

While designing hair pin bends on highways, the minimum (A) Designed speed is 20 km/hour(B) Gradient is 1 in 40 (C) Gradient is 1 in 200 (D) All the above

Description : While designing hair pin bends on highways, the minimum (A) Designed speed is 20 km/hour (B) Gradient is 1 in 40 (C) Gradient is 1 in 200 (D) All the above

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The combined mass of car and passengers travelling at 72 km/hr is 1500 kg. Find the kinetic energy of this combined mass. (Formula: K =mv2 / 2k )  a. 300 kJ  b. 200 kJ  c. 500 kJ  d. None of the above

Description : The combined mass of car and passengers travelling at 72 km/hr is 1500 kg. Find the kinetic energy of this combined mass. (Formula: K =mv2 / 2k )  a. 300 kJ  b. 200 kJ  c. 500 kJ  d. None of the above

Last Answer : 300 kJ

It takes eight hours for a 600 km journey, if 120 km is done by train and the rest by car. It takes 20 minutes more, if 200 km is done by train and the rest by car. The ratio of the speed of the train to that of the cars is? a) 2 : 3 b) 3: 2 c) 3 : 4 d) 4 : 3 e) None of these

Description : It takes eight hours for a 600 km journey, if 120 km is done by train and the rest by car. It takes 20 minutes more, if 200 km is done by train and the rest by car. The ratio of the speed of the train to that of the cars is? a) 2 : 3 b) 3: 2 c) 3 : 4 d) 4 : 3 e) None of these

Last Answer : Let the speed of the train be x km/hr and that of the car be y km/hr. Then, 120/x+480/y= 8 1/x+4/y=1/15 ....(i) And, 200/x+400/y=25/3 1/x+2/y=1/24 ....(ii) Solving (i) and (ii), we get: x = 60 and y = 80. Ratio of speeds = 60 : 80 = 3 : 4. Answer: c)

A thief is noticed by a policeman from a distance of 200 m. The thief starts running and the policeman chases him. The thief and the policeman run at the rate of 10 km and 11 km per hour respectively. What is the distance between them after 6 minutes? A.100 m B.150 m C.190 m D.200 m E.None of these

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Last Answer : Answer- A(100m) Explanation: Relative speed of the thief and policeman = (11 – 10) km/hr = 1 km/hr Distance covered in 6 minutes =[(1/60)*6] km = (1/10)km = 100 m. Distance between the thief and policeman = (200 – 100) m = 100 m.

Two trains starting at the same time from two stations 200 km apart and going in opposite directions cross each other at a distance of 110 km from one of the stations. What is the ratio of their speeds? A.9 : 28 B.11 : 9 C.11 : 8 D.9 : 22 E.None of these

Description : Two trains starting at the same time from two stations 200 km apart and going in opposite directions cross each other at a distance of 110 km from one of the stations. What is the ratio of their speeds? A.9 : 28 B.11 : 9 C.11 : 8 D.9 : 22 E.None of these

Last Answer : Answer – B (11 : 9) Explanation – In the same time, they cover 110 km and 90 km respectively.Ratio of their speeds = 110 : 90 = 11 : 9 

. The product of the bit rate and distance of a fiber-optic system is 2 Gbits-km/s. What is the maximum rate at 5 km? ∙ A. 100 Mbits/s ∙ B. 200 Mbits/s ∙ C. 400 Mbits/s ∙ D. 1000 Gbits/s

Description : . The product of the bit rate and distance of a fiber-optic system is 2 Gbits-km/s. What is the maximum rate at 5 km? ∙ A. 100 Mbits/s ∙ B. 200 Mbits/s ∙ C. 400 Mbits/s ∙ D. 1000 Gbits/s

Last Answer : C. 400 Mbits/s

The product of the bit rate and distance of a fiber-optic system is 2 Gbits km/s. What is the maximum rate at 5 km? ∙ a. 100 Mbits/s ∙ b. 200 Mbits/s ∙ c. 400 Mbits/s ∙ d. 1000 Gbits/s

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For transmission of power over a distance of 200 km, the transmission voltage should be (a) 132 kV (b) 66 kV (c) 33 kV (d) 11 kV

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Earth’s atmosphere is an envelope of gases extending to a height of (1) 100 km (2) 150 km (3) 200 km (4) 300 km

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