Description : What is .o5 ml times 80?
Last Answer : Need answer
Description : The serum estradiol level in women during 1–10 days of menstrual cycle is (A) 0–10 pg/ml (B) 12–20 pg/ml (C) 24–68 pg/ml (D) 80–100 pg/ml
Last Answer : Answer : C
Description : The total serum testosterone in adult women is (A) 0–5 ng/100 ml (B) 10–15 ng/100 ml (C) 20–80 ng/100 ml (D) 100–200 ng/100 ml
Description : The normal serum concentration of 1,25- dihydroxycholecalciferol in pg/ml is (A) 26–65 (B) 1–5 (C) 5–20 (D) 80–100
Last Answer : Answer : A
Description : Normal insulin clearance is (A) 40 ml/1.73 sqm (B) 60 ml/1.73 sqm (C) 80 ml/1.73 sqm (D) 120 ml/1.73 sqm
Last Answer : Answer : D
Description : Normal fasting blood sugar level per 100 ml. of blood in man is - (1) 30 - 50 mg (2) 50 - 70 mg (3) 80 -100 mg (4) 120 -140 mg
Last Answer : (3) 80 -100 mg Explanation: The blood sugar concentration or blood glucose level is the amount of glucose (sugar) present in the blood of a human or animal. Glucose levels are usually lowest in the ... (termed the fasting level"), and rise after meals for an hour or two by a few millimolar.
Description : What is the normal blood sugar level of a human being? (1) Close to 10 mg/ml (2) 120 - 150 mg/dl (3) 80 - 90 mg/dl (4) 150 — 200 mg/dl
Last Answer : (2) 120 - 150 mg/dl Explanation: The blood sugar concentration or blood glucose level is the amount of glucose (sugar) present in the blood of a human or animal. The body naturally tightly regulates blood ... (termed "the fasting level"), and rise after meals for an hour or two by a few millimolar.
Description : If the total amount of a drug present in the body at a given moment is 2.0 g and its plasma concentration is 25 μg/ml, its volume of distribution is: A. 100 L B. 80 L C. 60 L D. 50 L
Last Answer : B. 80 L
Description : 2 If the total amount of a drug present in the body at a given moment is 2.0 g and its plasma concentration is 25 μg/ml, its volume of distribution is: A. 100 L B. 80 L C. 60 L D. 50 L
Description : If the total amount of a drug present in the body at a given moment is 2.0 g and its plasma concentration is 25 μ g/ml, its volume of distribution is: A. 100 L B. 80 L C. 60 L D. 50 L
Description : Normal fasting blood sugar level per 100 ml. of blood in man is (1) 30 - 50 mg (2) 50 - 70 mg (3) 80 -100 mg (4) 120 -140 mg
Last Answer : 80 -100 mg
Description : The blood cholesterol level in 100 ml of blood in a normal person varies between— (1) 150 and 200 mg (2) 120 and 200 mg (3) 100 and 180 mg (4) 80 and 160 mg
Last Answer : 150 and 200 mg
Description : What is the normal blood sugar level of a human being? (1) Close to 10 mg/ml (2) 120 – 150 mg/dl (3) 80 – 90 mg/dl (4) 150 – 200 mg/dl
Last Answer : 120 – 150 mg/dl
Description : If there is 50 ml of water in a beaker then what is the mass?
Last Answer : 50 gm
Description : What is the mass of 25.0 ml of gold?
Last Answer : 10001/999900
Description : The solubility of `Ba_(3)(AsO_(4))_(2)`(formula mass=690) is `6.9xx10^(-2)` g//100 mL. What is the `K_(sp)`?
Last Answer : The solubility of `Ba_(3)(AsO_(4))_(2)`(formula mass=690) is `6.9xx10^(-2)` g//100 mL. What is the `K_(sp ... )` C. `1.0xx10^(-15)` D. `6.0xx10^(-13)`
Description : If mass of `KHC_(2)O_(4)` (potassium acid oxalate) required to reduce 100 mL of 0.02 M `KMnO_(4)` in acidic medium is x g and to neutralise 100 mL of
Last Answer : If mass of `KHC_(2)O_(4)` (potassium acid oxalate) required to reduce 100 mL of 0.02 M `KMnO_(4)` in acidic ... y is 1g D. If x is 11g then y is 5.5g
Description : 0.037g of an alcohol, R-OH was added to `CH_(3)MgBr` and the gas evolved measured 11.2 mL at STP. The Molecular mass of R-OH will be .
Last Answer : 0.037g of an alcohol, R-OH was added to `CH_(3)MgBr` and the gas evolved measured 11.2 mL at STP. The Molecular ... will be . A. 47 B. 79 C. 74 D. 77
Description : What element has a mass of 170.1 and a volume of 16.2 ml what material is it?
Description : If 5mL of ethenal has mass of 3.9g and 5.0 mL of benzine has mass 44g. Which is denser?
Last Answer : What is the answer ?
Description : If the Earth has over 80 times the mass of the moon, why does it only have about 6 times as much gravity?
Last Answer : The equation for gravitational attractive force is F = G * m1 * m2 / r^2. m2 is your mass. You got the mass ratio right: m1 for Earth is 80x m1 for the Moon. But when you stand on the surface, r ... Earth is 6370 km. if you take the square of the distance ratio you get 0.075. Multiply by 80 => 6
Description : On analysis, a certain compound was found to contain 254 g of iodine (at. Mass 127) and 80 g oxygen (at. Mass 16). What is the formula of the compound
Last Answer : On analysis, a certain compound was found to contain 254 g of iodine (at. Mass 127) and 80 g oxygen (at. Mass 16). ... C. `I_(5)O_(3)` D. `I_(2)O_(5)`
Description : How many electrons are present in an atom of mercury who is atomic number is 80 and whose mass number is 201?
Last Answer : 121 neutrons.
Description : The ratio of neutrons to protons of an element having a mass number and atomic number of 80 and 40 respectively is (A) 1 (B) 0.5 (C) 2 (D) 4
Last Answer : (A) 1
Description : In a triad A, B and C, the atomic masses of A and B are 80 and 120 respectively. What is the atomic mass of element C?
Last Answer : Atomic mass of A=80 Atomic mass of B=120 A C 2 Atomic mass of B = 80 C 2 120x2 80 C 120 240 C 80 C 240 80 C 160
Description : Calculate the value of critical damping coefficient if a vibrating system has mass of 4kg and stiffness of 100N/m A 20 N-sec/m B 40 N-sec/m C 60 N-sec/m D 80 N-sec/m
Last Answer : B 40 N-sec/m
Description : Calculate coefficient of viscous damper, if the system is critically damped. Consider the following data: 1. Mass of spring mass damper system = 350 kg 2. Static deflection = 2 x 10 -3 m 3. Natural frequency of the system = 60 rad/sec ... /m B. 80 x 10 3 N-s/m C. 42 x 10 3 N-s/m D. None of the above
Last Answer : C. 42 x 10 3 N-s/m
Description : Calculate coefficient of viscous damper, if the system is critically damped. Consider the following data: 1. Mass of spring mass damper system = 350 kg 2. Static deflection = 2 x 10 -3 m 3. Natural frequency of the system = 60 rad/sec ... /m b. 80 x 10 3 N-s/m c. 42 x 10 3 N-s/m d. None of the above
Last Answer : c. 42 x 10 3 N-s/m
Description : The weight of an object is 50lb. What is its mass at standard condition? a. 50 lbm b. 60 lbm c. 70 lbm d. 80 lbm formula: m = Fgk /g
Last Answer : 50 lbm