What is the remainder of 270 divided by 30?

What is the remainder of 270 divided by 30?
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A portion of Rs.6600 is invested at a 5% per annum, while the remainder is invested at a 3% per annum. If the annual income from the portion earning a 5% per annum is twice that of the other portion, what is the total income from the two investments after one year? a) Rs.270 b) Rs.370 c) Rs.250 d) Rs.280 e) None of these

Description : A portion of Rs.6600 is invested at a 5% per annum, while the remainder is invested at a 3% per annum. If the annual income from the portion earning a 5% per annum is twice that of the other portion, what is the ... investments after one year? a) Rs.270 b) Rs.370 c) Rs.250 d) Rs.280 e) None of these

Last Answer : 5x + 3y = z (Total Income) x + y = 6600 -(1) 5x= 2(3y) 5x – 6y = 0 -(2) By solving (1) and (2) we get, x = 3600 so y = 3000 (3600*5*1)/100 + (3000*3*1)/100 = 180 + 90 = 270 Answer: a)

What is the reminder of 270 divided by 30?

Description : What is the reminder of 270 divided by 30?

Last Answer : 9

what is 535 divided by 30 with a remainder?

Description : what is 535 divided by 30 with a remainder?

Last Answer : 17.8333

What number is less than 30 leaves a remainder of 3 when divided by 5 and a remainder of 2 when divided my 3?

Description : What number is less than 30 leaves a remainder of 3 when divided by 5 and a remainder of 2 when divided my 3?

Last Answer : 18

A flight is to depart from an airport with runway 09 and 27. Surface wind is 270/05; an inversion is reported at 300 feet with turbulence and wind shear. The wind just above the inversion is 090/30. What is the safest departure procedure? a. Take-off is not possible under these conditions b. Depart on runway 09 with a tailwind c. Depart runway 27 with maximum throttle during the passage through the inversion d. Depart runway 27 with as steep an ascent as possible

Description : A flight is to depart from an airport with runway 09 and 27. Surface wind is 270/05; an  inversion is reported at 300 feet with turbulence and wind shear. The wind just above the  ... throttle during the passage through the inversion  d. Depart runway 27 with as steep an ascent as possible

Last Answer : b. Depart on runway 09 with a tailwind

Zach’s Market recorded the following events involving a recent purchase of merchandise: Received goods for $50,000, terms 2/10, n/30. Returned $1,000 of the shipment for credit. Paid $250 freight on the shipment. Paid the invoice within the discount period. As a result of these events, the company’s merchandise inventory a. increased by $48,020. b. increased by $49,250. c. increased by $48,265. d. increased by $48,270.

Description : Zach's Market recorded the following events involving a recent purchase of merchandise: Received goods for $50,000, terms 2/10, n/30. Returned $1,000 of the shipment for credit. Paid $250 freight on the shipment ... 020. b. increased by $49,250. c. increased by $48,265. d. increased by $48,270.

Last Answer : d. increased by $48,270.

A flight is to depart from an airport with runway 09 and 27. Surface wind is 270/05; an inversion is reported at 300 feet with turbulence and wind shear. The wind just above the inversion is 090/30. What is the safest departure procedure? a. Take-off is not possible under these conditions b. Depart on runway 09 with a tailwind c. Depart runway 27 with maximum throttle during the passage through the inversion d. Depart runway 27 with as steep an ascent as possible

Description : A flight is to depart from an airport with runway 09 and 27. Surface wind is 270/05; an inversion is reported at 300 feet with turbulence and wind shear. The wind just above the ... throttle during the passage through the inversion d. Depart runway 27 with as steep an ascent as possible

Last Answer : b. Depart on runway 09 with a tailwind

Two trains A and B are moving in opposite directions at 180 km/hr and 270 km/hr. their lengths are 3.30 km and 2.7 km respectively. The time taken by the slower train to cross the faster train in second is. A) 48sec B) 13 sec C) 38sec D) 24sec

Description : Two trains A and B are moving in opposite directions at 180 km/hr and 270 km/hr. their lengths are 3.30 km and 2.7 km respectively. The time taken by the slower train to cross the faster train in second is. A) 48sec B) 13 sec C) 38sec D) 24sec

Last Answer : ANSWER: A Explanation: Speed of 1st train = 180 km/hr  Speed of 2nd train = 270 km/hr  Relative speed = (180 + 270)km/hr  = 450 km/hr  = (450 * 5 / 180)m/s  = (2250 / 18)m/s  =125 m/s  Distance covered = (3.30 + 2.70)km  = 6km = 6000m  Required time = 6000 / 125  = 48sec

When a number "n" is divided by 5, the remainder is 0 and when three times a number "n" is divided by 5 the remainder is what?

Description : When a number "n" is divided by 5, the remainder is 0 and when three times a number "n" is divided by 5 the remainder is what?

Last Answer : Since it’s not homework, the answer is 0.

Find the remainder when y3 + y2 - 2y + 5 is divided by y - 5. -Maths 9th

Description : Find the remainder when y3 + y2 - 2y + 5 is divided by y - 5. -Maths 9th

Last Answer : Remainder = 145 Again, we should evaluate p(5) Let p(y) = y3 + y2 - 2y + 5 ∴ p(5) = 53 + 52 - 2 x 5 + 5 = 125 + 25 - 10 + 5 = 145 Thus , we find that p(5) is the remainder when p(y) is divided by y - 5 .

Determine the remainder when polynomial p(x) is divided by x - 2 . -Maths 9th

Description : Determine the remainder when polynomial p(x) is divided by x - 2 . -Maths 9th

Last Answer : p(x) = x4 - 3x2 + 2x - 5 According to remainder theorem, the required remainder will be = p(2) p(x) = x4 - 3x2 + 2x - 5 ∴ p(2) = 24 - 3(2)2 + 2(2) - 5 =16 - 12 + 4 - 5 = 3

If x51 + 51 is divided by x + 1, then the remainder is -Maths 9th

Description : If x51 + 51 is divided by x + 1, then the remainder is -Maths 9th

Last Answer : (d) Let p(x) = x51 + 51 . …(i) When we divide p(x) by x+1, we get the remainder p(-1) On putting x= -1 in Eq. (i), we get p(-1) = (-1)51 + 51 = -1 + 51 = 50 Hence, the remainder is 50.

By actual division, find the quotient and the remainder when the first polynomial is divided by the second polynomial x4 + 1 and x-1. -Maths 9th

Description : By actual division, find the quotient and the remainder when the first polynomial is divided by the second polynomial x4 + 1 and x-1. -Maths 9th

Last Answer : Actual division method

By remainder theorem, find the remainder when p(x) is divided by g(x) -Maths 9th

Description : By remainder theorem, find the remainder when p(x) is divided by g(x) -Maths 9th

Last Answer : Find the remainder when p(x) is divided by g(x)

If the polynomials az3 +4z2 + 3z-4 and z3-4z + 0 leave the same remainder when divided by z – 3, -Maths 9th

Description : If the polynomials az3 +4z2 + 3z-4 and z3-4z + 0 leave the same remainder when divided by z – 3, -Maths 9th

Last Answer : Let p1(z) = az3 +4z2 + 3z-4 and p2(z) = z3-4z + o When we divide p1(z) by z - 3, then we get the remainder p,(3). Now, p1(3) = a(3)3 + 4(3)2 + 3(3) - 4 = 27a+ 36+ 9-4= 27a+ 41 When we ... to' the question, both the remainders are same. p1(3)= p2(3) 27a+41 = 15+a 27a-a = 15 - 41 . 26a = 26 a = -1

The polynomial p{x = x4 -2x3 + 3x2 -ax+3a-7 when divided by x+1 leaves the remainder 19. -Maths 9th

Description : The polynomial p{x = x4 -2x3 + 3x2 -ax+3a-7 when divided by x+1 leaves the remainder 19. -Maths 9th

Last Answer : p(x) is divided by x+ 2 =

Find the remainder when y3 + y2 - 2y + 5 is divided by y - 5. -Maths 9th

Description : Find the remainder when y3 + y2 - 2y + 5 is divided by y - 5. -Maths 9th

Last Answer : Remainder = 145 Again, we should evaluate p(5) Let p(y) = y3 + y2 - 2y + 5 ∴ p(5) = 53 + 52 - 2 x 5 + 5 = 125 + 25 - 10 + 5 = 145 Thus , we find that p(5) is the remainder when p(y) is divided by y - 5 .

Determine the remainder when polynomial p(x) is divided by x - 2 . -Maths 9th

Description : Determine the remainder when polynomial p(x) is divided by x - 2 . -Maths 9th

Last Answer : p(x) = x4 - 3x2 + 2x - 5 According to remainder theorem, the required remainder will be = p(2) p(x) = x4 - 3x2 + 2x - 5 ∴ p(2) = 24 - 3(2)2 + 2(2) - 5 =16 - 12 + 4 - 5 = 3

If x51 + 51 is divided by x + 1, then the remainder is -Maths 9th

Description : If x51 + 51 is divided by x + 1, then the remainder is -Maths 9th

Last Answer : (d) Let p(x) = x51 + 51 . …(i) When we divide p(x) by x+1, we get the remainder p(-1) On putting x= -1 in Eq. (i), we get p(-1) = (-1)51 + 51 = -1 + 51 = 50 Hence, the remainder is 50.

By actual division, find the quotient and the remainder when the first polynomial is divided by the second polynomial x4 + 1 and x-1. -Maths 9th

Description : By actual division, find the quotient and the remainder when the first polynomial is divided by the second polynomial x4 + 1 and x-1. -Maths 9th

Last Answer : Actual division method

By remainder theorem, find the remainder when p(x) is divided by g(x) -Maths 9th

Description : By remainder theorem, find the remainder when p(x) is divided by g(x) -Maths 9th

Last Answer : Find the remainder when p(x) is divided by g(x)

If the polynomials az3 +4z2 + 3z-4 and z3-4z + 0 leave the same remainder when divided by z – 3, -Maths 9th

Description : If the polynomials az3 +4z2 + 3z-4 and z3-4z + 0 leave the same remainder when divided by z – 3, -Maths 9th

Last Answer : Let p1(z) = az3 +4z2 + 3z-4 and p2(z) = z3-4z + o When we divide p1(z) by z - 3, then we get the remainder p,(3). Now, p1(3) = a(3)3 + 4(3)2 + 3(3) - 4 = 27a+ 36+ 9-4= 27a+ 41 When we ... to' the question, both the remainders are same. p1(3)= p2(3) 27a+41 = 15+a 27a-a = 15 - 41 . 26a = 26 a = -1

The polynomial p{x = x4 -2x3 + 3x2 -ax+3a-7 when divided by x+1 leaves the remainder 19. -Maths 9th

Description : The polynomial p{x = x4 -2x3 + 3x2 -ax+3a-7 when divided by x+1 leaves the remainder 19. -Maths 9th

Last Answer : p(x) is divided by x+ 2 =

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Description : If x to the power 11 + 101 is divided by x+1,what is the remainder? -Maths 9th

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Description : If the polynomials az3 + 42z2 + 3z – 4 and z3 - 4z + a leave the same remainder when divided by z – 3, find the value of a. -Maths 9th

Last Answer : Solution :-

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Last Answer : Given that the following polynomials leave the same remainder when divided by (x - 4) : We are to find the value of a. Remainder theorem: When (x - b) divides a polynomial p(x), then the remainder is p(b). So, from (i) and (ii), we get Thus, the required value of a is 1.

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Last Answer : answer:

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Description : When a + b + c + 3a^(1/3) b^(2/3) + 3a(2/3) b^(1/3) is divided by a^(1/3) + b^(1/3) + c^(1/3), what is the remainder ? -Maths 9th

Last Answer : answer:

If the polynomials ax^3 + 4x^2 + 3x – 4 and x^3 – 4x + a leave the same remainder when divided by (x – 3), the value of a is : -Maths 9th

Description : If the polynomials ax^3 + 4x^2 + 3x – 4 and x^3 – 4x + a leave the same remainder when divided by (x – 3), the value of a is : -Maths 9th

Last Answer : Given ax^3 + 4x^2 + 3x - 4 and x^3 - 4x + a leave the same remainder when divided by x - 3. Let p(x) = ax^3 + 4x^2 + 3x - 4 and g(x) = x^3 - 4x + a By remainder theorem, if f(x) is divided by (x − a) then ... 4 27a+41 g(3)=27-4(3)+a 15+a f(3)=G(3) 27a+41=15+a 26a=15-41 a=15-41/26 a=-26/26 a=-1

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Description : If the expression ax^2 + bx + c is equal to 4, when x = 0, leaves a remainder 4 when divided by x + 1 and leaves a -Maths 9th

Last Answer : Given exp. f(x) = ax2 + bx + c ∴ When x = 0, a.0 + b.0 + c = 4 ⇒ c = 4. The remainders when f(x) is divided by (x + 1) and (x + 2) respectively are f(–1) and f(–2). ∴ f( ... 2b = 2 ...(ii) Solving (i) and (ii) simultaneously we get, a = 1, b = 1.

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Description : When x^40 + 2 is divided by x^4 + 1, what is the remainder ? -Maths 9th

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Description : If the remainder of the polynomial a0 + a1x + a2x^2 + ....... + anx^n when divided by (x – 1) is 1, then which one of the following is correct ? -Maths 9th

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Description : If the polynomial x^19 + x^17 + x^13 + x^11 + x^7 + x^5 + x^3 is divided by (x^2 + 1), then the remainder is : -Maths 9th

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Description : The remainder, when x^(200) is divided by x^2 – 3^x + 2 is -Maths 9th

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Description : When x^3 + 2x^2 + 4x + b is divided by (x + 1), the quotient is x^2 + ax + 3 and the remainder -Maths 9th

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Last Answer : Let p(x) = ax³ + bx² + x - 6 A/C to question, (x + 2) is the factor of p(x) , and we know this is possible only when p(-2) = 0 So, p(2) = a(-2)³ + b(-2)² - 2 - 6 = 0 ⇒ ... --(2) solve equations (1) and (2), 4a = 0 ⇒a = 0 and b = 2 Then, equation will be 2x² + x - 6

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