What is the perimeter of triangle if its longest side is 162cm when two of its angles are 37.25 degrees and 48.4 degrees?

What is the perimeter of triangle if its longest side is 162cm when two of its angles are 37.25 degrees and 48.4 degrees?
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The largest angle then will be 94.35 degrees opposite the longest sides of 162cm and by using the sine rule of 120/sin(94.35) = b/sinB = c/sinC the perimeter of the triangle works out as 381.83cm rounded to two decimal places.
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