What is the mean median mode and range of 78 25 57 98 20 48 45 37 88 24 19?

What is the mean median mode and range of 78 25 57 98 20 48 45 37 88 24 19?
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19, 20, 24, 25, 37, 45, 48, 57, 78, 88, 98Mean: 49Median: 45Range: 79There is no mode.
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1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49, 50'. What number is missing? -Riddles

Description : 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49, 50'. What number is missing? -Riddles

Last Answer : 22

(37) 0.75 x [(7056) 0.25] ÷ (64) – 2 = (8) ? (Take 3 digits after the decimal point) a) 95.357 b) 69.567 c) 96.257 d) 78.584 e) 88.598

Description : (37) 0.75 x [(7056) 0.25] ÷ (64) – 2 = (8) ? (Take 3 digits after the decimal point) a) 95.357 b) 69.567 c) 96.257 d) 78.584 e) 88.598

Last Answer : (37) 0.75 x [(7056) 0.25] ÷ (64) – 2 = (8) ? Sol: 27.75 x 1764 ÷ 64 – 2 = 8 x ? 27.75 x 27.5625 – 2 = 8 x ? 762.859/8=? ? = 95.357 Answer: a)

Find the median of the values 37, 31, 42, 43, 46, 25, 39, 45, 32. -Maths 9th

Description : Find the median of the values 37, 31, 42, 43, 46, 25, 39, 45, 32. -Maths 9th

Last Answer : Arranging the data in ascending order, we have 25, 31, 32, 37, 39, 42, 43, 45, 46 Here, number of observations = 9 (odd) Median = value of (9+1 / 2)th Observation = Value of 5th Observation = 39

Find the median of the values 37, 31, 42, 43, 46, 25, 39, 45, 32. -Maths 9th

Description : Find the median of the values 37, 31, 42, 43, 46, 25, 39, 45, 32. -Maths 9th

Last Answer : Arranging the data in ascending order, we have 25, 31, 32, 37, 39, 42, 43, 45, 46 Here, number of observations = 9 (odd) Median = value of (9+1 / 2)th Observation = Value of 5th Observation = 39

The marks obtained by 15 students in an examination are given below : 40, 20, 24, 19,20, 35, 12, 48, 29, 40, 45, 48, 42, 23, 35. Find the average mark

Description : The marks obtained by 15 students in an examination are given below : 40, 20, 24, 19,20, 35, 12, 48, 29, 40, 45, 48, 42, 23, 35. Find the average mark

Last Answer : The marks obtained by 15 students in an examination are given below : 40, 20, 24, 19,20, 35, 12, ... , 23, 35. Find the average mark of the students.

What is the mean median and mode of 52 53 54 55 55 56 57 57 57 59 60?

Description : What is the mean median and mode of 52 53 54 55 55 56 57 57 57 59 60?

Last Answer : Find the mode of the following data: 55,55, 56, 52, 57, 55, 58, 59, 60, 60

The price of dhal is increased from $ 30 to $ 37.5 per kg. Find the percentage increase in price. a) 25 b) 60 c) 45 d) None e) 98

Description : The price of dhal is increased from $ 30 to $ 37.5 per kg. Find the percentage increase in price. a) 25 b) 60 c) 45 d) None e) 98 

Last Answer : Answer: A Price of dhal before = $30 Price of dhal now = $ 37.5 Increase in dhal = current price - original price  = $37.5 - $ 30  = $ 7.5 Therefore, percentage increase in price = Increase in price/ ...  = 7.5 / 30 100 = 750/100 = 25 % Thus, increase in price= 25 %

12 17 32 57 ? 137 a) 98 b) 95 c) 37 d) 92 e) none of these

Description : 12 17 32 57 ? 137 a) 98 b) 95 c) 37 d) 92 e) none of these

Last Answer : The pattern of the number series is 12+5×1=17, 17+5×3=32, 32+5×5=57 57+5×7=92, 92+5×9=137 Answer: d)

Given the following data pairs (x, y), find the regression equation. (1, 1.24), (2, 5.23), (3, 7.24), (4, 7.60), (5, 9.97), (6, 14.31), (7, 13.99), (8, 14.88), (9, 18.04), (10, 20.70) a. y = 0.490 x - 0.053 b. y = 2.04 x c. y = 1.98 x + 0.436 d. y = 0.49 x

Description : Given the following data pairs (x, y), find the regression equation. (1, 1.24), (2, 5.23), (3, 7.24), (4, 7.60), (5, 9.97), (6, 14.31), (7, 13.99), (8, 14.88), (9, 18.04), (10, 20.70) a. y = 0.490 x - 0.053 b. y = 2.04 x c. y = 1.98 x + 0.436 d. y = 0.49 x

Last Answer : c. y = 1.98 x + 0.436

The median of the data 78, 56, 22, 34, 45, 54, 39, 68, 54 and 84 is -Maths 9th

Description : The median of the data 78, 56, 22, 34, 45, 54, 39, 68, 54 and 84 is -Maths 9th

Last Answer : NEED ANSWER

The median of the data 78, 56, 22, 34, 45, 54, 39, 68, 54 and 84 is -Maths 9th

Description : The median of the data 78, 56, 22, 34, 45, 54, 39, 68, 54 and 84 is -Maths 9th

Last Answer : According to question find the median of the data

In a class there are 15 boys and 10 girls. Three students are selected at random. The difference between the probability that 2 boys and 1 girl are selected compared to 1 boy and 2 girls are selected is: a) 23/78 b) 19/88 c) 15/92 d) 4/23 e) 7/46

Description : In a class there are 15 boys and 10 girls. Three students are selected at random. The difference between the probability that 2 boys and 1 girl are selected compared to 1 boy and 2 girls are selected is: a) 23/78 b) 19/88 c) 15/92 d) 4/23 e) 7/46

Last Answer : 2 boys, 1 gi(Prl = (15c2×10c1) / 25c3 = 1050/2300 1 boy, 2 girls = (15c1×10c2) / 25c3 = 675/2300 Difference = (1050 - 675)/2300 = 375/2300 = 15/92 Answer: c)

19/14 x 12/72 x 18/29 x 767 = ? (Take 2 digits after the decimal point) a) 110.69 b) 118.78 c) 111.56 d) None e) 108.98

Description : 19/14 x 12/72 x 18/29 x 767 = ? (Take 2 digits after the decimal point) a) 110.69 b) 118.78 c) 111.56 d) None e) 108.98

Last Answer : 19/14 x 12/72 x 18/29 x 767 =? Sol: 1.35 x 0.16 x 0.62 x 767 = ? 102.71 = ? Answer: d)

Find the magnetic field intensity of a material with flux density of 24 units in air(in 10 6 order) a) 19.09 b) 21 c) 25 d) 26.78

Description : Find the magnetic field intensity of a material with flux density of 24 units in air(in 10 6 order) a) 19.09 b) 21 c) 25 d) 26.78

Last Answer : a) 19.09

A grouped frequency distribution table with classes of equal sizes using 63-72 (72 included) as one of the class is constructed for the following data 30, 32, 45, 54, 74, 78, 108, 112, 66, 76, 88, -Maths 9th

Description : A grouped frequency distribution table with classes of equal sizes using 63-72 (72 included) as one of the class is constructed for the following data 30, 32, 45, 54, 74, 78, 108, 112, 66, 76, 88, -Maths 9th

Last Answer : NEED ANSWER

A grouped frequency distribution table with classes of equal sizes using 63-72 (72 included) as one of the class is constructed for the following data 30, 32, 45, 54, 74, 78, 108, 112, 66, 76, 88, -Maths 9th

Description : A grouped frequency distribution table with classes of equal sizes using 63-72 (72 included) as one of the class is constructed for the following data 30, 32, 45, 54, 74, 78, 108, 112, 66, 76, 88, -Maths 9th

Last Answer : (b) We arrange the given data into groups like 13-22,23-32 103-112. (since, our data is from 14 to 112). The class width in this case is 9. Now, the given data can be arranged in tabular form as follows. Hence, the number of classes in distribution will be 10.

What number comes in the sequence 98 63 37 19?

Description : What number comes in the sequence 98 63 37 19?

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2 male, 6 female, and 8 girls can do a work in 192 hrs, 4 male and 16 girls can do it in 160 hrs, 4 male and 6 female can do it in 240 hrs.10 male and 24 girls can do it in. a) A.87 3/ 11 hrs b) B.78 4 /11 hrs c) C.88 6 /12 hrs d) 80 4 /5 hrs

Description : 2 male, 6 female, and 8 girls can do a work in 192 hrs, 4 male and 16 girls can do it in 160 hrs, 4 male and 6 female can do it in 240 hrs.10 male and 24 girls can do it in. a) A.87 3/ 11 hrs b) B.78 4 /11 hrs c) C.88 6 /12 hrs d) 80 4 /5 hrs

Last Answer : A Let 1 males 1 hr work = x 1 female 1 hour work = y 1 girl 1 hour work = z Then 2x + 6y + 8z = 1/192 ------>1 4x + 16z = 1/160 --------->2 4x + 6y = 1/240 ------------->3 Adding 2 and ... 1/192 + 1/160 =(5+6) / 960 = 11/960 10 male and 24 girls can do work in 960/11 hrs i.e., 87 3 /11 hrs

Find the mean,median,mode and range of the following values:17,7,11,13,2,12,7.?

Description : Find the mean,median,mode and range of the following values:17,7,11,13,2,12,7.?

Last Answer : find the mean,median,mode and range of the following values:17,7,11,13,2,12,7.

The simplest measure of variability in a data set is (A) Mean (B) Range (C) Median (D) Mode

Description : The simplest measure of variability in a data set is (A) Mean (B) Range (C) Median (D) Mode

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The minimum and maximum clearances of check rails at all BG level crossings shall be a) 51 to 57 mm* b) 44 to 48 mm c) 41 to 45 mm d) 55 to 70 mm

Description : The minimum and maximum clearances of check rails at all BG level crossings shall be a) 51 to 57 mm* b) 44 to 48 mm c) 41 to 45 mm d) 55 to 70 mm

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Make a stem-and-leaf plot for this set of data. Find the range,median,and mode of the data. : 47 54 70 62 59 62 82 66 62 73 55 82 59?

Description : Make a stem-and-leaf plot for this set of data. Find the range,median,and mode of the data. : 47 54 70 62 59 62 82 66 62 73 55 82 59?

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Insert the missing number in the following: 3, 8, 18, 23, 33, ?, 48 (A) 37 (B) 40 (C) 38 (D) 45

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The terminal value in year 6 is closest to __________. a) Rs.22.57 b) Rs.20.42 c) Rs.24.30 d) Rs.25.70

Description : The terminal value in year 6 is closest to __________. a) Rs.22.57 b) Rs.20.42 c) Rs.24.30 d) Rs.25.70

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The scores of an English test out of 100 of 20 students are given below : 75, 69, 88, 55, 95, 88, 73, 64, 75, 98, 88, 95, 90, 95, 88, 44, 59, 67, 88, 99. -Maths 9th

Description : The scores of an English test out of 100 of 20 students are given below : 75, 69, 88, 55, 95, 88, 73, 64, 75, 98, 88, 95, 90, 95, 88, 44, 59, 67, 88, 99. -Maths 9th

Last Answer : Median=n=even =n/2=20/2=10th observation =98 Mode =88

The scores of an English test out of 100 of 20 students are given below : 75, 69, 88, 55, 95, 88, 73, 64, 75, 98, 88, 95, 90, 95, 88, 44, 59, 67, 88, 99. -Maths 9th

Description : The scores of an English test out of 100 of 20 students are given below : 75, 69, 88, 55, 95, 88, 73, 64, 75, 98, 88, 95, 90, 95, 88, 44, 59, 67, 88, 99. -Maths 9th

Last Answer : Median=n=even =n/2=20/2=10th observation =98 Mode =88

A batsman average for 20 innings is 25 runs. His highest score exceeds his lowest score by 64 runs. If these 2 innings are excluded, the average of the remaining 18 innings is 24 runs. The highest score of the player is. A) 66 B) 72 C) 77 D) 88

Description : A batsman average for 20 innings is 25 runs. His highest score exceeds his lowest score by 64 runs. If these 2 innings are excluded, the average of the remaining 18 innings is 24 runs. The highest score of the player is. A) 66 B) 72 C) 77 D) 88

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78 India‘s total primary energy consumption is a) 24.3 BTU b) 19.01 BTU c) 120 BTU d) 30.1 BTU

Description : 78 India‘s total primary energy consumption is a) 24.3 BTU b) 19.01 BTU c) 120 BTU d) 30.1 BTU

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Approximately what is the length of the rail-route open to traffic in India? (1) 25,000 kms (2) 48,000 kms (3) 63,000 kms (4) 78,000 kms

Description : Approximately what is the length of the rail-route open to traffic in India? (1) 25,000 kms (2) 48,000 kms (3) 63,000 kms (4) 78,000 kms

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One of the fields on a form contains a text box which accepts numeric values in the range of 18 to 25. Identify the invalid Equivalance class A. 17 B. 19 C. 24 D. 21

Description : One of the fields on a form contains a text box which accepts numeric values in the range of 18 to 25. Identify the invalid Equivalance class A. 17 B. 19 C. 24 D. 21

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Binance Customer Service {+1+}85O7:57..45:58 Care Customer Number Binance Support Number 24/7?

Description : Binance Customer Service {+1+}85O7:57..45:58 Care Customer Number Binance Support Number 24/7?

Last Answer : Binance Customer Service {+1+}85O7:57..45:58 Care Customer Number Binance Support Number 24/7;Binance Customer Service {+1+}85O7:57..45:58 Care Customer Number Binance Support Number 24/7;Binance ... 45:58 Care Customer Number Binance Support Number 24/7;Binance Customer Service {+1+}85O7:57..4

By selling 45 lemons for Rs 40, a man loses 20%.How many should he sell for Rs 24 to gain 20% in the transaction? a) 19 b) 22 c) 20 d) 18 e) 14

Description : By selling 45 lemons for Rs 40, a man loses 20%.How many should he sell for Rs 24 to gain 20% in the transaction? a) 19 b) 22 c) 20 d) 18 e) 14

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When a voltage of 115 VDC is applied to the illustrated circuit with a resistance of 10,230 ohms the current will be _______ EL-0018 A. 88.95 milliamps B. 103.45 milliamps C. 11.24 milliamps D. 0.91 amps

Description : When a voltage of 115 VDC is applied to the illustrated circuit with a resistance of 10,230 ohms the current will be _______ EL-0018 A. 88.95 milliamps B. 103.45 milliamps C. 11.24 milliamps D. 0.91 amps

Last Answer : Answer: C

What is the perimeter of triangle if its longest side is 162cm when two of its angles are 37.25 degrees and 48.4 degrees?

Description : What is the perimeter of triangle if its longest side is 162cm when two of its angles are 37.25 degrees and 48.4 degrees?

Last Answer : The largest angle then will be 94.35 degrees opposite the longest sides of 162cm and by using the sine rule of 120/sin(94.35) = b/sinB = c/sinC the perimeter of the triangle works out as 381.83cm rounded to two decimal places.

What is the perimeter and area of a triangle whose longest side is 162cm when two of its angles are 37.25 degrees and 48.4 degrees?

Description : What is the perimeter and area of a triangle whose longest side is 162cm when two of its angles are 37.25 degrees and 48.4 degrees?

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Last Answer : Answer: D

The mode of the data 48, 45, 49, 51, 46, 48, 47, 49, 48, and 51 is ______.

Description : The mode of the data 48, 45, 49, 51, 46, 48, 47, 49, 48, and 51 is ______.

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The mean monthly temperature and rainfall of a station are given below: Month Temperature ºC Rainfall mm January 24 2 February 25 1 March 27 0 April 29 3 May 30 16 June 29 520 July 28 709 August 27 419 September 27 297 October 28 88 November 28 21 December 26 2 Yearly 27 2078 The above said data relate to which of following cities? [CDS 2004] (a) Ahmedabad (b) Bangalore (c) Mumbai (d) Vadodara

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Last Answer : Ans: (c)

In India, area under rice is about (A) 25 Mha (B) 28 Mha (C) 45 Mha (D) 57 Mha

Description : In India, area under rice is about (A) 25 Mha (B) 28 Mha (C) 45 Mha (D) 57 Mha

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If the yield from weed free is 3500 kg and that from weedy 1500 kg/ha, weed index would be a). 57.1% b). 133.3% c). 45.0% d). 25.6%

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Taper on Cotter is varies from A. 1 in 15 to 1 in 12 B. 1 in 20 to 1 in 15 C. 1 in 25 to 1 in 20 D. 1 in 48 to 1 in 24

Description : Taper on Cotter is varies from A. 1 in 15 to 1 in 12 B. 1 in 20 to 1 in 15 C. 1 in 25 to 1 in 20 D. 1 in 48 to 1 in 24

Last Answer : D. 1 in 48 to 1 in 24

ECE Board Exam March 1996 One hundred twenty µbars of pressure variation is equal to A. 120 dBSPL B. 115.56 dBSPL C. 41.58 dBSPL D. 57.78 dBSPL

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For heavier fuels the cooling system of an internal combustion engine, the temperature is maintained at a) 78 to 80°C b) 80 to 84 °C c) 85 to 88°C d) 88 to 90°C

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67,74,78,?,92,94 a) 86 b) 85 c) 83 d) 84 e) 88

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Last Answer : The next term is obtained by adding the unit’s digit to the number. Hence the missing number =78+8=86 Answer: a)

180 sweets are divided among friends A, B, C and D in which B and C are brothers also such that sweets divided between A and B are in the ratio 2 : 3, between B and C in the ratio 2 : 5 and between C and D in ratio 3 : 4. What is the number of sweets received by the brothers together? A) 78 B) 84 C) 92 D) 102 E) 88

Description : 180 sweets are divided among friends A, B, C and D in which B and C are brothers also such that sweets divided between A and B are in the ratio 2 : 3, between B and C in the ratio 2 : 5 and between C ... . What is the number of sweets received by the brothers together? A) 78 B) 84 C) 92 D) 102 E) 88

Last Answer : Answer: B A : B : C : D 2*2*3 : 3*2*3 : 3*5*3 : 3*5*4 4 : 6 : 15 : 20 B and C together = [(6+15)/(4+6+15+20)] * 180 = 84

A number is increased by 70 % and then decreased by 70 %. Find the net increase or decrease per cent. a) 25 b) 56 c) 45 c) 49 e) 98

Description : A number is increased by 70 % and then decreased by 70 %. Find the net increase or decrease per cent. a) 25 b) 56 c) 45 c) 49 e) 98 

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The cost of a stencil is decreased by 30%. If the original cost is $140, find the decrease cost. a) 25 b) 68 c) 45 d) None e) 98

Description : The cost of a stencil is decreased by 30%. If the original cost is $140, find the decrease cost. a) 25 b) 68 c) 45 d) None e) 98

Last Answer : Answer: E  Original cost = $140  Decrease in it = 30% of $140  = 30/100 × 140  = 4200/100  = $42  Therefore, decrease cost = $140 - $42 = $98

A mixture of 60 kg of rice and dhal contains 60% of dhal. The new mixture is formed by adding 15 kg of dhal. What is the percentage of rice in the new mixture? a) 25 b) 64 c) 45 d) 32 e) 98

Description : A mixture of 60 kg of rice and dhal contains 60% of dhal. The new mixture is formed by adding 15 kg of dhal. What is the percentage of rice in the new mixture? a) 25 b) 64 c) 45 d) 32 e) 98 

Last Answer : Answer: D 60 kg = 36 kg dhal 24 kg rice -------- 15 kg dhal Total = 15 kg dhal 24 kg rice (new) 24/75×100=32%

Gugan obtained a total of 1313 marks out of 1400 in an examination. What is his approximate percentage in the examination? a) 25 b) 60 c) 45 d) None e) 98

Description : Gugan obtained a total of 1313 marks out of 1400 in an examination. What is his approximate percentage in the examination? a) 25 b) 60 c) 45 d) None e) 98

Last Answer : Answer: D Required percentage = 1313/ 1400 × 100 =131300/1400 =93.7

In a plot of 18000 sq. m., only 13500 sq. m. is allowed for construction. What percent of the plot is to be left without construction? a) 25 b) 60 c) 45 d) 40 e) 98

Description : In a plot of 18000 sq. m., only 13500 sq. m. is allowed for construction. What percent of the plot is to be left without construction? a) 25 b) 60 c) 45 d) 40 e) 98

Last Answer : Answer: A Percentage of plot allowed for construction = (13500/18000 × 100) = 75 %. Thus, the percentage of plot to be left without construction = 100 % - 75 % = 25 %.