In the circuit shown in figure : `R = 10 Omega , L = (sqrt(3))/(10) H, R_(2) = 20 Omega` and `C = (sqrt(3))/(2) mF`. Current in `L - R_(1)` circuit is

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In the circuit shown in figure : `R = 10 Omega , L = (sqrt(3))/(10) H, R_(2) = 20 Omega` and `C = (sqrt(3)) ... ` B. `90^(@)` C. `180^(@)` D. `60^(@)`

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