Description : In the circuit diagram shown in Fig. 4.53, a voltmeter reads 30 V when connected across `400 Omega` resistance. Calculate what the same voltmeter read
Last Answer : In the circuit diagram shown in Fig. 4.53, a voltmeter reads 30 V when connected across `400 ... when it is connected across `300 Omega` resistance.
Description : Find the minimum number of cells required to produce an electric current of 1.5 A through a resistance of `30 Omega`. Given that the emf of each cell
Last Answer : Find the minimum number of cells required to produce an electric current of 1.5 A through a resistance ... .5 V and internal resistance `1.0 Omega`.
Description : In the circuit shown in figure, the resistance R has a value that depends on the current. Specifically R is 20 `Omega` when `i` is zero and the amount
Last Answer : In the circuit shown in figure, the resistance R has a value that depends on the current. Specifically R is 20 `Omega` ... A B. `10A` C. 20 A D. `5A`
Description : 10 cells, each of internal resistance `0.5 Omega` and 1.2 V emf are connected (a) all in series and (b) all in paralle. Calculate the current sent in
Last Answer : 10 cells, each of internal resistance `0.5 Omega` and 1.2 V emf are connected (a) all in ... each case through a wire of resistance `0.8 Omega`.
Description : Each resistor shown in the figure has a resistance of `10 Omega` and the battery has the emf 6 V. What will be the current supplied by the battery ?
Last Answer : Each resistor shown in the figure has a resistance of `10 Omega` and the battery has the emf 6 V. What will be the ... 2 A` C. `1.8 A` D. `0.3 A`
Description : Determine the voltage drop across the resistance `R_(1)` in the circuit given in Fig. 4.55 with `epsilon=90 V, R_(1)=5 k Omega, R_(2)=5k Omega, R_(3)=
Last Answer : Determine the voltage drop across the resistance `R_(1)` in the circuit given in Fig. 4.55 with `epsilon=90 V, ... k Omega " and " R_(4)=10 k Omega`.
Description : In the given circuit, the voltmeter records 5 V. The resistance of the voltmeter in `Omega` is
Last Answer : In the given circuit, the voltmeter records 5 V. The resistance of the voltmeter in `Omega` is A. 200 B. 100 C. 10 D. 50
Description : Given three resistances of `30 Omega` each. How can they be connected to given a total resistance of (i) `90 Omega (ii) 10 Omega (iii) 45 Omega` ?
Last Answer : Given three resistances of `30 Omega` each. How can they be connected to given a total resistance of (i) `90 Omega (ii) 10 Omega (iii) 45 Omega` ?
Description : Consider the diagram shown below. A Voltmeter of resistance `150 Omega` is connected across A and B. The potential drop across B and C measured by vol
Last Answer : Consider the diagram shown below. A Voltmeter of resistance `150 Omega` is connected across A and B. The potential ... 29 B. 27 V C. 31 V D. 30 V
Description : How would you arrange 64 similar cells each having an emf of 2.0 V and internal resistance `2 Omega` so as to send maximum current through an external
Last Answer : How would you arrange 64 similar cells each having an emf of 2.0 V and internal resistance ` ... current through an external resistance of `8 Omega`.
Description : A galvanometer having resistance of `50 Omega` requires a current of `100 Omega A` to given full scale deflection. How much resistance is required to
Last Answer : A galvanometer having resistance of `50 Omega` requires a current of `100 Omega A` to given full scale ... in series D. `10^(5)Omega` in parallel
Description : A DC ammeter has resistance `0.1 Omega` and its current ranges `0-100 A`. If the range is to be extended to `0-500`, then the following shunt resistan
Last Answer : A DC ammeter has resistance `0.1 Omega` and its current ranges `0-100 A`. If the range is to be extended ... Omega` C. `0.025 Omega` D. `0.25 Omega`
Description : When 10 cells in series are connected to the ends of a resistance of `59 Omega`, the current is found to be 0.25 A, but when the same cells after bein
Last Answer : When 10 cells in series are connected to the ends of a resistance of `59 Omega`, the ... Calculate the internal resistance and emf of each cell.
Description : The internal resistance of a `2.1 V` cell which gives a current `0.2 A` through a resistance of `10 Omega`
Last Answer : The internal resistance of a `2.1 V` cell which gives a current `0.2 A` through a resistance of `10 Omega` A ... Omega` C. `0.8 Omega` D. `1.0 Omega`
Description : In the circuit shown in figure : `R = 10 Omega , L = (sqrt(3))/(10) H, R_(2) = 20 Omega` and `C = (sqrt(3))/(2) mF`. Current in `L - R_(1)` circuit is
Last Answer : In the circuit shown in figure : `R = 10 Omega , L = (sqrt(3))/(10) H, R_(2) = 20 Omega` and `C = (sqrt(3)) ... ` B. `90^(@)` C. `180^(@)` D. `60^(@)`
Last Answer : In the circuit shown in figure : `R = 10 Omega , L = (sqrt(3))/(10) H, R_(2) = 20 Omega` and `C = (sqrt( ... 10 sqrt(2) A` C. `20 sqrt(2) A` D. `25 A`
Last Answer : In the circuit shown in figure : `R = 10 Omega , L = (sqrt(3))/(10) H, R_(2) = 20 Omega` and `C = (sqrt(3) ... 2) A` C. `5 sqrt(6) A` D. `5 sqrt(3) A`
Description : In the circuit shown the cells `A` and `B` have negligible resistance. For `V_(A) = 12 V, R_(1) = 500 Omega` and `R = 100 Omega`, the galvanometer `(G
Last Answer : In the circuit shown the cells `A` and `B` have negligible resistance. For `V_(A) = 12 V, R_(1) = 500 Omega` and ` ... A. 4 V B. 2 V C. 12 V D. 6 V
Description : An AC circuit consists of a resistance and a choke coil in series . The resistance is of 220 `Omega` and choke coils is of 0.7 H . The power abosorbed
Last Answer : An AC circuit consists of a resistance and a choke coil in series . The resistance is of 220 ` ... 50 Hz , source connected with the circuit , is
Description : Given that resistivity of copper is `1.68xx10^(-8) Omega`m. Calculate the amount of copper required to draw a wire 10 km long having resistance of `10
Last Answer : Given that resistivity of copper is `1.68xx10^(-8) Omega`m. Calculate the amount of copper required to draw a ... copper is `8.9xx10^(3) kg m^(-3)`.
Description : In given figure, the potentiometer wire AB has a resistance of `5 Omega` and length 10 m . The balancing length AM for the emf of 0.4 V is
Last Answer : In given figure, the potentiometer wire AB has a resistance of `5 Omega` and length 10 m . The balancing length AM for ... B. 4 m C. `0.8` m D. 8 m
Description : The value of current in the \( 6 \Omega \) resistance is:
Last Answer : The value of current in the \( 6 \Omega \) resistance is:
Description : When a resistance of `2 Omega` is placed across the terminals of a battery, the current is 0.5 A. When the resistance across the terminals of the batt
Last Answer : When a resistance of `2 Omega` is placed across the terminals of a battery, the current is 0 ... emf of the battery and also its internal resistance.
Description : A galvanometer has a coil of resistance `100 Omega` and gives a full-scale deflection for `30 mA` current. If it is to work as a voltmeter of `30 V` r
Last Answer : A galvanometer has a coil of resistance `100 Omega` and gives a full-scale deflection for `30 mA` current. ... Omega` C. `1000 Omega` D. `1800 Omega`
Description : In the circuit shown in Fig. 4.63, the terminal voltage of the battery is 6.0 V. Find the current I through the `18 Omega` resistor.
Last Answer : In the circuit shown in Fig. 4.63, the terminal voltage of the battery is 6.0 V. Find the current I through the `18 Omega` resistor.
Description : In the Wheatstone network given, `P=10 Omega, Q=20Omega, R=15Omega, S=30Omega`, the current passing through the battery (of negligible internal resist
Last Answer : In the Wheatstone network given, `P=10 Omega, Q=20Omega, R=15Omega, S=30Omega`, the current passing through the ... zero C. `0.18 A` D. `0.72 A`
Description : Three identical cells each of emf 2 V and unknown internal resistance are connected in parallel. This combination is connected to a `5 Omega` resistor
Last Answer : Three identical cells each of emf 2 V and unknown internal resistance are connected in parallel. ... what is the internal resistance of each cell ?
Description : Three identical, each of emf 2 V and internal resistance `0.2 Omega` are connected in series to an external resistor of `7.4 Omega`. Calculate the cur
Last Answer : Three identical, each of emf 2 V and internal resistance `0.2 Omega` are connected in series to ... 7.4 Omega`. Calculate the current in the circuit.
Description : A `5 Omega` resistor is connected in series with a parallel combination of n resistors of `6 Omega` each. The equivalent resistance is `7 Omega`. Find
Last Answer : A `5 Omega` resistor is connected in series with a parallel combination of n resistors of `6 Omega ... The equivalent resistance is `7 Omega`. Find n.
Description : A uniform wire is cut into four segments. Each segment is twice as long as the earlier segment. If the shortest segment has a resistance of `4 Omega`,
Last Answer : A uniform wire is cut into four segments. Each segment is twice as long as the earlier segment. ... Omega`, find the resistance of the original wire.
Description : Six resistance each of value `r=5 Omega` are connected between points A, B and C as shown in figure. If `R_(1), R_(2)` and `R_(3)` are the net resista
Last Answer : Six resistance each of value `r=5 Omega` are connected between points A, B and C as shown in figure. If `R_(1), R_(2) ... 1:2:3` C. `5:4:3` D. `4:3:2`
Description : Two copper wires A and B of equal masses are taken. The length of A is double the length of B. If the resistance of wire A is `160 Omega `, then calcu
Last Answer : Two copper wires A and B of equal masses are taken. The length of A is double the length of ... Omega `, then calculate the resistance of the wire B.
Description : A uniform wire of resistance `9 Omega` is joined end-to-end to from a circule. Then, the resistance of the circular wire between any two diametrically
Last Answer : A uniform wire of resistance `9 Omega` is joined end-to-end to from a circule. Then, the resistance of the ... (9)/(4)Omega` D. `(3)/(2)Omega`
Description : A `1 Omega` resistance in series with an ammeter is balanced by 25 cm of potentiometer by 50 cm. The ammeter shows a reding of `1.5 A`. Then, the erro
Last Answer : A `1 Omega` resistance in series with an ammeter is balanced by 25 cm of potentiometer by 50 cm. The ammeter shows a ... B. 3A C. `1.3 A` D. `0.3A`
Description : When a resistance of 100`Omega` is connected in series with a galvanometer of resistance R, then its range is V. To double its range, a resistance of
Last Answer : When a resistance of 100`Omega` is connected in series with a galvanometer of resistance R, then its range ... 800`Omega` C. 900`Omega` D. 100`Omega`
Description : Two unpedauces given by Z1 = 10 + j5 and Z2 = 8 + j9 are joined in parallel and connected across a voltage of V = 200 + j0. Calculate the circuit current and branch currents. Draw the vector diagram.
Last Answer : Solution: Given, Z1=10+j5, Z2=8+j9, V=200+j0
Description : In the circuit diagram shown in figure, potential difference across `3Omega` resistance is 20 V. Then, match the following two columns.
Last Answer : In the circuit diagram shown in figure, potential difference across `3Omega` resistance is 20 V. Then, match the following two columns.
Description : A plantinum wire has resistance of `10 Omega` at `0^(@)C` and `20 Omega` at `273^(@)C`. Find the value of coefficient of resistance.
Last Answer : A plantinum wire has resistance of `10 Omega` at `0^(@)C` and `20 Omega` at `273^(@)C`. Find the value of coefficient of resistance.
Description : A potential difference of 10 V is applied across a conductor of resistance `1 k Omega`. Find the number of electrons flowing through the conductor in
Last Answer : A potential difference of 10 V is applied across a conductor of resistance `1 k Omega`. ... of electrons flowing through the conductor in 5 minutes.
Description : What length of a wire of diameter 0.46 mm and specific resistance `50xx10^(-6) Omega`m would be required to make a coil of resistance `10 Omega` ?
Last Answer : What length of a wire of diameter 0.46 mm and specific resistance `50xx10^(-6) Omega`m would be required to make a coil of resistance `10 Omega` ?
Description : Calculate the conductivity of a wire of length 2 m, area of cross-sectionl `2 cm^(2)` and resistance `10^(-4) Omega`.
Last Answer : Calculate the conductivity of a wire of length 2 m, area of cross-sectionl `2 cm^(2)` and resistance `10^(-4) Omega`.
Description : A wire of resistance `10 Omega` is drawn out so that its length is thrice its original length. Calculate its new resistance (resistivity and density o
Last Answer : A wire of resistance `10 Omega` is drawn out so that its length is thrice its original ... (resistivity and density of the material remain uncharged).
Description : A galvanometer having internal resistance `10 Omega` required `0.01` A for a full scale deflection. To convert this galvanometer to a voltmeter of ful
Last Answer : A galvanometer having internal resistance `10 Omega` required `0.01` A for a full scale deflection. ... Omega` in series D. `12010 Omega` in parallel
Description : A potentiometer wire of length 10 m and resistance `10 Omega` per meter is connected in serice with a resistance box and a 2 volt battery. If a potent
Last Answer : A potentiometer wire of length 10 m and resistance `10 Omega` per meter is connected in serice with a ... Omega` C. `190 Omega` D. `90 Omega`
Description : A potentiometer wire of length `100 cm` having a resistance of `10 Omega` is connected in series with a resistance `R` and a cell of emf `2V` of negli
Last Answer : A potentiometer wire of length `100 cm` having a resistance of `10 Omega` is connected in series with a ... Omega` C. `790 Omega` D. `840 Omega`
Description : The range of voltmeter is 10 V and its internal resistance is `50 Omega`. To convert it to voltmeter of range 15 V, how much resistance is to be added
Last Answer : The range of voltmeter is 10 V and its internal resistance is `50 Omega`. To convert it to ... in parallel D. Add `125 Omega` resistor in series
Description : Two electric bulbs rated 50 W and 100 W are glowing at full powr, when used in parallel with a battery of emf 120 V and internal resistance 10 `Omega`
Last Answer : Two electric bulbs rated 50 W and 100 W are glowing at full powr, when used in parallel with a battery of emf 120 V ... power, is A. 6 B. 4 C. 2 D. 8
Description : The resistance of a wire is `10 Omega`. Its length is increased by `10%` by stretching. The new resistance will now be
Last Answer : The resistance of a wire is `10 Omega`. Its length is increased by `10%` by stretching. The new resistance ... B. `1.2Omega` C. `13Omega` D. `11Omega`
Description : A resistance of `4 Omega` and a wire of length 5 meters and resistance `5 Omega` are joined in series and connected to a cell of e.m.f. `10 V` and int
Last Answer : A resistance of `4 Omega` and a wire of length 5 meters and resistance `5 Omega` are joined in series and connected ... `3.0V` C. `0.67V` D. `1.33V`
Description : In the given circuit, it is observed that the current I is independent of the value of the resistance `R_6`. Then the resistance values must satisfy .
Last Answer : In the given circuit, it is observed that the current I is independent of the value of the resistance `R_6`. Then the ... R_(3)=R_(2)R_(4)=R_(5)R_(6)`