Calculate the energy released by fission of 1 g of `._(92)^(235)U`, assuming that an energy of 200 MeV is released by fission of each atom of `.^(235)

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Answer :

Calculate the energy released by fission of 1 g of `._(92)^(235)U`, assuming that an energy of 200 MeV is ... `= 6.023 xx 10^(26) kg mol^(-1)`)

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