15. Which of the following is correct?(1) \( \tan 1>\tan 2 \)(2) \( \tan 2>\tan 1 \)(3) \( \sin 1\cos 2 \)

15. Which of the following is correct?(1) \( \tan 1>\tan 2 \)(2) \( \tan 2>\tan 1 \)(3) \( \sin 1\cos 2 \)
by

1 Answer

Answer :

15. Which of the following is correct? (1) \( \tan 1>\tan 2 \) (2) \( \tan 2>\tan 1 \) (3) \( \sin 1\cos 2 \)
by
selected by

Related questions

What's the key to remembering how to draw each of the different trigonometric function graphs? (i.e. sin, cos, tan)

Description : What's the key to remembering how to draw each of the different trigonometric function graphs? (i.e. sin, cos, tan)

Last Answer : SOH – sin CAH – cos TOA – tan sin = opposite over hypotenuse cos = adjacent over hypotenuse tan = opposite over adjacent

How to use sin, cos, and tan on a TI-84+Silver Edition?

Description : How to use sin, cos, and tan on a TI-84+Silver Edition?

Last Answer : answer:This may work, haven't tried a real problem yet . here are the steps in changing it from radian to degrees 1. turn on your TI-83 plus 2. press the MODE button near the top of your ... down to options and move the highlight from radian to degree, press enter and clear you're good to go

What is SIN, TAN, COS?

Description : What is SIN, TAN, COS?

Last Answer : Wikipedia knows.

If A lies in the third quadrant and 3 tan A – 4 = 0, then what is the value of 5 sin 2 A + 3 sin A + 4 cos A? -Maths 9th

Description : If A lies in the third quadrant and 3 tan A – 4 = 0, then what is the value of 5 sin 2 A + 3 sin A + 4 cos A? -Maths 9th

Last Answer : answer:

If tan x = b/a , then what is the value of a cos 2x + b sin 2x? -Maths 9th

Description : If tan x = b/a , then what is the value of a cos 2x + b sin 2x? -Maths 9th

Last Answer : answer:

Prove that (sin A + sin 3A + sin 5A + sin7 A)/(Cos A + Cos3 A + cos5 A + cos7 A) = tan 4A. -Maths 9th

Description : Prove that (sin A + sin 3A + sin 5A + sin7 A)/(Cos A + Cos3 A + cos5 A + cos7 A) = tan 4A. -Maths 9th

Last Answer : answer:

If cosec A = 2, then the value of 1/(tan A) + (sin A)/(1+cos A) is -Maths 9th

Description : If cosec A = 2, then the value of 1/(tan A) + (sin A)/(1+cos A) is -Maths 9th

Last Answer : answer:

What is the value of sin A cos A tan A + cos A sin A cot A ? -Maths 9th

Description : What is the value of sin A cos A tan A + cos A sin A cot A ? -Maths 9th

Last Answer : answer:

`(i) int e^(x). "[log (sec x+tan x) + sec x dx "` `(ii) int (e^(-x)(cos x-sin x))/(cos^(2) x) dx`

Description : `(i) int e^(x). "[log (sec x+tan x) + sec x dx "` `(ii) int (e^(-x)(cos x-sin x))/(cos^(2) x) dx`

Last Answer : `(i) int e^(x). "[log (sec x+tan x) + sec x dx "` `(ii) int (e^(-x)(cos x-sin x))/(cos^(2) x) dx`

`(i) int(1)/(sqrt(1-x^(2)).cos^(-1) x)dx` `(ii) int (sin(tan^(-1)x))/(1+x^(2))dx`

Description : `(i) int(1)/(sqrt(1-x^(2)).cos^(-1) x)dx` `(ii) int (sin(tan^(-1)x))/(1+x^(2))dx`

Last Answer : `(i) int(1)/(sqrt(1-x^(2)).cos^(-1) x)dx` `(ii) int (sin(tan^(-1)x))/(1+x^(2))dx`

` (i) int sqrt(1+ sin .(x)/(2)dx)` `(ii) int (1+cos 4x)/(cot x- tan x)dx`

Description : ` (i) int sqrt(1+ sin .(x)/(2)dx)` `(ii) int (1+cos 4x)/(cot x- tan x)dx`

Last Answer : ` (i) int sqrt(1+ sin .(x)/(2)dx)` `(ii) int (1+cos 4x)/(cot x- tan x)dx`

Consider the matrix function `A(x)=[{:(cos^(-1)x,sin^(-1)x,cosec^(-1)x),(sin^(-1)x,sec^(-1)x,tan^(-1)x),(cosec^(-1)x,tan^(-1)x,cot^(-1)x):}]` and `B =

Description : Consider the matrix function `A(x)=[{:(cos^(-1)x,sin^(-1)x,cosec^(-1)x),(sin^(-1)x,sec^(-1)x,tan^(-1)x),(cosec^(-1)x,tan^(-1)x,cot^(-1)x):}]` and `B =

Last Answer : Consider the matrix function `A(x)=[{:(cos^(-1)x,sin^(-1)x,cosec^(-1)x),(sin^(-1)x,sec^(-1)x,tan^(-1)x),( ... )=-A(x)` D. `A(x) + A(-x) = - piI_(3)`

Let `theta ,phi in [0,2pi]` be such that `2 cos theta (1-sin phi)=sin^2 theta ((tan)theta/2+(cot)theta/2) cos phi -1, tan(2pi-theta) > 0 and -1 &lt

Description : Let `theta ,phi in [0,2pi]` be such that `2 cos theta (1-sin phi)=sin^2 theta ((tan)theta/2+(cot)theta/2) cos phi -1, tan(2pi-theta) > 0 and -1 <

Last Answer : Let `theta ,phi in [0,2pi]` be such that `2 cos theta (1-sin phi)=sin^2 theta ((tan)theta/2+(cot)theta/2) ... (3pi)/(2)` D. `(3pi)/(2) lt phi lt 2pi`

Half the angle of nip, (α), for a roll crusher is given by (where, dr, dp and df are diameters of crushing rolls, feed particles and rolls gap respectively). (A) cos α = (dr + dp)/(dr + df) (B) cos α = (dr + df)/(dr + dp) (C) tan α = (dr + dp)/(dr + df) (D) sin α = (dr + dp)/(dr + df)

Description : Half the angle of nip, (α), for a roll crusher is given by (where, dr, dp and df are diameters of crushing rolls, feed particles and rolls gap respectively). (A) cos α = (dr + dp)/(dr + df) (B) cos α = (dr + df)/(dr + dp) (C) tan α = (dr + dp)/(dr + df) (D) sin α = (dr + dp)/(dr + df)

Last Answer : (A) cos α = (dr + dp)/(dr + df)

If tan A = 4/3 and sin A = 4/5 then cos A = —————– a. 4/5 b. 3/5 c. 3⁄4 d.9/11

Description : If tan A = 4/3 and sin A = 4/5 then cos A = —————– a. 4/5 b. 3/5 c. 3⁄4 d.9/11

Last Answer : b. 3/5

The value of 2 tan 2 45°+ cos 2 30° − sin 2 60° is (a) 0 (b) 1 (c) -2 (d) 2

Description : The value of 2 tan 2 45°+ cos 2 30° − sin 2 60° is (a) 0 (b) 1 (c) -2 (d) 2

Last Answer : (d) 2

In right triangle ABC, right angled at C, if tan A = 1, then the value of 2 sin A cos A is (a) 0 (b) 1 (c) – 1 (d) 2

Description : In right triangle ABC, right angled at C, if tan A = 1, then the value of 2 sin A cos A is (a) 0 (b) 1 (c) – 1 (d) 2

Last Answer : (b) 1

1 – cos 2 A is equal to: a sin 2 A b tan 2 A c 1 – sin 2 A d sec 2 A

Description : 1 – cos 2 A is equal to: a sin 2 A b tan 2 A c 1 – sin 2 A d sec 2 A

Last Answer : a sin 2 A

Numerical aperture is expressed as the a) NA = sin θa b) NA = cos θa c) NA = tan θa d) NA = sec θa

Description : Numerical aperture is expressed as the a) NA = sin θa b) NA = cos θa c) NA = tan θa d) NA = sec θa

Last Answer : a) NA = sin θa

If cos2B = (cos(A+C))/(cos(A-C)) , then show that tan A, tan B and tan C are in G.P. -Maths 9th

Description : If cos2B = (cos(A+C))/(cos(A-C)) , then show that tan A, tan B and tan C are in G.P. -Maths 9th

Last Answer : answer:

If (1+cos A)/(1-cos A) = m^2/n^2 , then tan A is equal to -Maths 9th

Description : If (1+cos A)/(1-cos A) = m^2/n^2 , then tan A is equal to -Maths 9th

Last Answer : answer:

`int(tan x + cos x)^(2) dx `

Description : `int(tan x + cos x)^(2) dx `

Last Answer : `int(tan x + cos x)^(2) dx `

If `5(tan^2x - cos^2x)=2cos 2x + 9`, then the value of cos4x is

Description : If `5(tan^2x - cos^2x)=2cos 2x + 9`, then the value of cos4x is

Last Answer : If `5(tan^2x - cos^2x)=2cos 2x + 9`, then the value of cos4x is A. `(-3)/(5)` B. `(1)/(3)` C. `(2)/(9)` D. `-(7)/(9)`

Graph of alternating current is a A. cos wave B. tan wave C. curve D. sine wave

Description : Graph of alternating current is a A. cos wave B. tan wave C. curve D. sine wave

Last Answer : sine wave

`(i) int(tan^(-1))/((1+x^(2)))dx" "(ii) int(1)/(sqrt(1-x^(2)) sin^(-1)x)dx`

Description : `(i) int(tan^(-1))/((1+x^(2)))dx" "(ii) int(1)/(sqrt(1-x^(2)) sin^(-1)x)dx`

Last Answer : `(i) int(tan^(-1))/((1+x^(2)))dx" "(ii) int(1)/(sqrt(1-x^(2)) sin^(-1)x)dx`

Find the maximum and minimum values of the function `f(x) = (sin x)/(1+ tan x) ,(0 lt x lt 2pi)`.

Description : Find the maximum and minimum values of the function `f(x) = (sin x)/(1+ tan x) ,(0 lt x lt 2pi)`.

Last Answer : Find the maximum and minimum values of the function `f(x) = (sin x)/(1+ tan x) ,(0 lt x lt 2pi)`.

If sin theta equals 3/4 and theta is in quadrant II what is the value of tan theta?

Description : If sin theta equals 3/4 and theta is in quadrant II what is the value of tan theta?

Last Answer : 0.75

Reciprocal of sin A is ————- a. cosec A b. sec A c. cot A d.Tan a

Description : Reciprocal of sin A is ————- a. cosec A b. sec A c. cot A d.Tan a

Last Answer : a. cosec A

According to Rankine's formula, the minimum depth of foundation (A) h = (P/W) [(1 - sin )/(1 + sin )]² (B) h = (w/P) [(1 - sin )/(1 + sin )]² (C) h = (P/w) [(1 - sin )/(1 + tan )]² (D) h = (P/w) [(1 - tan )/(1 + tan )]²

Description : According to Rankine's formula, the minimum depth of foundation (A) h = (P/W) [(1 - sin )/(1 + sin )]² (B) h = (w/P) [(1 - sin )/(1 + sin )]² (C) h = (P/w) [(1 - sin )/(1 + tan )]² (D) h = (P/w) [(1 - tan )/(1 + tan )]²

Last Answer : Answer: Option A

The tangent length of a simple circular curve of radius R (A) R tan (B) R tan (C) R sin (D) R sin

Description : The tangent length of a simple circular curve of radius R (A) R tan (B) R tan (C) R sin (D) R sin

Last Answer : Answer: Option B

Explaining the derivatives of sin, cos and toa?

Description : Explaining the derivatives of sin, cos and toa?

Last Answer : answer:I am assuming this isn't homework, as it is summer and from what you wrote it appears you are merely curious, so I think it's legal for me to do the proof here for you (don't strike me down, ... proof for that as well. By toa do you mean tangent? I can prove that one too if you'd like.

Which of the following represents shearing? a.(x, y) → (x+shx, y+shy) b.(x, y) → (ax, by) c.(x, y) → (x cos(θ)+y sin(θ), -x sin(θ)+y cos(θ)) d.(x, y) → (x+shy, y+shx)

Description : Which of the following represents shearing? a.(x, y) → (x+shx, y+shy) b.(x, y) → (ax, by) c.(x, y) → (x cos(θ)+y sin(θ), -x sin(θ)+y cos(θ)) d.(x, y) → (x+shy, y+shx)

Last Answer : d.(x, y) → (x+shy, y+shx)

The original coordinates of the point in polar coordinates are a.X’=r cos (Ф +ϴ) and Y’=r cos (Ф +ϴ) b.X’=r cos (Ф +ϴ) and Y’=r sin (Ф +ϴ) c.X’=r cos (Ф -ϴ) and Y’=r cos (Ф -ϴ) d.X’=r cos (Ф +ϴ) and Y’=r sin (Ф -ϴ)

Description : The original coordinates of the point in polar coordinates are a.X’=r cos (Ф +ϴ) and Y’=r cos (Ф +ϴ) b.X’=r cos (Ф +ϴ) and Y’=r sin (Ф +ϴ) c.X’=r cos (Ф -ϴ) and Y’=r cos (Ф -ϴ) d.X’=r cos (Ф +ϴ) and Y’=r sin (Ф -ϴ)

Last Answer : b.X’=r cos (Ф +ϴ) and Y’=r sin (Ф +ϴ)

For any two real number a b and , we defined aRb if and only if sin^2a + cos^2b = 1. The relation R is -Maths 9th

Description : For any two real number a b and , we defined aRb if and only if sin^2a + cos^2b = 1. The relation R is -Maths 9th

Last Answer : (d) an equivalence relationGiven, a R b ⇒ sin2a + cos2b = 1 Reflexive: a R a ⇒ sin2 a + cos2 a = 1 ∀ a ∈ R (True) Symmetric: a R b ⇒ sin2 a + cos2 b = 1 ⇒ 1 - cos2 a + 1 - sin2 b = 1 ⇒ sin2 b + ... + cos2 b + sin2 b + cos2 c = 2 ⇒ sin2 a + cos2 c = 1 ⇒ a R c (True)∴ R is an equivalence relation.

The angle A lies in the third quadrant and it satisfies the equation 4 (sin^2x + cos x) = 1. What is the measure of angle A? -Maths 9th

Description : The angle A lies in the third quadrant and it satisfies the equation 4 (sin^2x + cos x) = 1. What is the measure of angle A? -Maths 9th

Last Answer : answer:

If cosec |-sin |=l and sec |- cos |=m, prove that l2m2(l2+m2+3)=1 -Maths 9th

Description : If cosec |-sin |=l and sec |- cos |=m, prove that l2m2(l2+m2+3)=1 -Maths 9th

Last Answer : cosec(A) - sin(A) = l ⇒ 1/sin(A) - sin(A) = l ⇒ l² = 1/sin²(A) + sin²(A) - 2 --------- sec(A) - cos(A) = m ⇒ 1/cos(A) - cos(A) = m ⇒ m² = 1/cos²(A) + cos²(A) - 2 ---------- l²m² = [1/sin²(A) + ... A)) = = 1/(sin²(A)cos²(A)) ------------- ⇒ l²m² (l² + m² + 3) = sin²(A)cos²(A) / [sin²(A)cos²(A)] = 1

If x sin3|+ y cos3|=sin|cos| and xsin|=ycos|, prove x2+y2=1. -Maths 9th

Description : If x sin3|+ y cos3|=sin|cos| and xsin|=ycos|, prove x2+y2=1. -Maths 9th

Last Answer : xsin3θ+ycos3θ=sinθcosθ (xsinθ)sin2θ+(ycosθ)cos2θ=sinθcosθ (xsinθ)sin2θ+(xsinθ)cos2θ=sinθcosθ xsinθ=sinθcosθ x=cosθ Again, ycosθ=xsinθ ycosθ=cosθsinθ y=sinθ Therefore, x2+y2=sin2θ+cos2θ=1.

sin ^ 2 θ = cos ^ 2 θ = 1 How is it ?

Last Answer : We hold theta = A. sin2A + cos2 (PM / OP) 2+ (OM / OP) 2 PM2 / OP2 + OM2OP2 (PM2 + OM2) / OP2 OP2 / OP2 => 1 So sin2A + cos2A = 1

`int_(0)^(pi//2) (sin x -cos x)/(1+sin x cos x) dx=?`

Description : `int_(0)^(pi//2) (sin x -cos x)/(1+sin x cos x) dx=?`

Last Answer : `int_(0)^(pi//2) (sin x -cos x)/(1+sin x cos x) dx=?` A. `0` B. `1` C. None of the above D.

`int (1)/(sqrt(sin^(3) x cos x))dx =?`

Description : `int (1)/(sqrt(sin^(3) x cos x))dx =?`

Last Answer : `int (1)/(sqrt(sin^(3) x cos x))dx =?` A. `-2sqrt(tan x) +c` B. `(2)/(sqrt(tan x)) +c` C. `(-2)/(sqrt(tan x)) +c` D.

`" if " int (sin 2x- cos 2x) dx=(1)/(sqrt(2)) sin (2x-k)+c " then " k=?`

Description : `" if " int (sin 2x- cos 2x) dx=(1)/(sqrt(2)) sin (2x-k)+c " then " k=?`

Last Answer : `" if " int (sin 2x- cos 2x) dx=(1)/(sqrt(2)) sin (2x-k)+c " then " k=?` A. `-(5pi)/(4)` B. `(pi)/(4)` C. `-(pi)/(4)` D.

`int_(0)^(pi//2) x sin cos x dx=?`

Description : `int_(0)^(pi//2) x sin cos x dx=?`

Last Answer : `int_(0)^(pi//2) x sin cos x dx=?` A. `(pi)/(4)` B. `(pi)/(8)` C. `(pi)/(12)` D.

`int sin^(3) x cos^(3) x dx =?`

Description : `int sin^(3) x cos^(3) x dx =?`

Last Answer : `int sin^(3) x cos^(3) x dx =?` A. `(1)/(4) sin^(4) x + (1)/(6) sin^(6) x+c` B. `(1)/(4) cos^(4)x-(1)/(6) cos^(6) x+c` C. none of the above D.

`int(sin x)/( sqrt(1+cos x))dx=?`

Description : `int(sin x)/( sqrt(1+cos x))dx=?`

Last Answer : `int(sin x)/( sqrt(1+cos x))dx=?` A. `sqrt(1+cos x) +c` B. `-2sqrt(1+ cos x)+c` C. `2sqrt(1+ cos x) +c` D.

`int (1)/(sin^(2) x cos^(2)x) dx=?`

Description : `int (1)/(sin^(2) x cos^(2)x) dx=?`

Last Answer : `int (1)/(sin^(2) x cos^(2)x) dx=?` A. `tan x-cot x+c` B. `sec x+ cosec x+c` C. `sec x- cosec x+c` D.

`int_(0)^(pi) x sin x. cos^(2) x dx`

Description : `int_(0)^(pi) x sin x. cos^(2) x dx`

Last Answer : `int_(0)^(pi) x sin x. cos^(2) x dx`

`int_(0)^(pi//2) x sin x cos x dx`

Description : `int_(0)^(pi//2) x sin x cos x dx`

Last Answer : `int_(0)^(pi//2) x sin x cos x dx`

` int (3-4 sin x)/(cos^(2) x) dx=?`

Description : ` int (3-4 sin x)/(cos^(2) x) dx=?`

Last Answer : ` int (3-4 sin x)/(cos^(2) x) dx=?` A. `4 tan x +4 sec x+c` B. ` 3 tan x + 4 sec x+ c` C. ` 4 tan x +3 sec x+c` D.

`int_(0)^(pi//2) e^(x) (sin x + cos x) dx`

Description : `int_(0)^(pi//2) e^(x) (sin x + cos x) dx`

Last Answer : `int_(0)^(pi//2) e^(x) (sin x + cos x) dx`

`(i) int_(0)^(pi//4) e^(tanx) . sec^(2) x dx` `(ii) int_(0)^(pi//4) (sin (cos 2x))/(" cosec " 2x)dx`

Description : `(i) int_(0)^(pi//4) e^(tanx) . sec^(2) x dx` `(ii) int_(0)^(pi//4) (sin (cos 2x))/(" cosec " 2x)dx`

Last Answer : `(i) int_(0)^(pi//4) e^(tanx) . sec^(2) x dx` `(ii) int_(0)^(pi//4) (sin (cos 2x))/(" cosec " 2x)dx`