If cos2B = (cos(A+C))/(cos(A-C)) , then show that tan A, tan B and tan C are in G.P. -Maths 9th

1 Answer

Answer :

answer:

Related questions

Description : If A lies in the third quadrant and 3 tan A – 4 = 0, then what is the value of 5 sin 2 A + 3 sin A + 4 cos A? -Maths 9th

Last Answer : answer:

Description : If tan x = b/a , then what is the value of a cos 2x + b sin 2x? -Maths 9th

Last Answer : answer:

Description : If cosec A = 2, then the value of 1/(tan A) + (sin A)/(1+cos A) is -Maths 9th

Last Answer : answer:

Description : If (1+cos A)/(1-cos A) = m^2/n^2 , then tan A is equal to -Maths 9th

Last Answer : answer:

Description : Prove that (sin A + sin 3A + sin 5A + sin7 A)/(Cos A + Cos3 A + cos5 A + cos7 A) = tan 4A. -Maths 9th

Last Answer : answer:

Description : What is the value of sin A cos A tan A + cos A sin A cot A ? -Maths 9th

Last Answer : answer:

Description : If 3sin x + 4cos x = 5, then 6 tan x/2 - 9 tan^2 x/2 is equal to -Maths 9th

Last Answer : answer:

Description : If tan A – tan B = x and cot B – cot A = y, then what is cot (A – B) equal to? -Maths 9th

Last Answer : answer:

Description : If tan^2 y cosec^2 x – 1 = tan^2 y, then which one of the following is correct? -Maths 9th

Last Answer : answer:

Description : Let A, B, C be the angles of a plain triangle (A/2) = (1/3 ), tan (B/2) = (2/3). Then tan (C/2) is equal to -Maths 9th

Last Answer : answer:

Description : If A, B, C, D are the successive angles of a cyclic quadrilateral, then what is cos A + cos B + cos C + cos D equal to: -Maths 9th

Last Answer : answer:

Description : If sinA + sinB = a, cosA – cosB = b, then the value of cos (A – B) is -Maths 9th

Last Answer : answer:

Description : If p(x) is a common multiple of degree 6 of the polynomials f(x) = x^3 + x^2 – x – 1 and g(x) = x^3 – x^2 + x – 1, then which -Maths 9th

Last Answer : answer:

Description : If `5(tan^2x - cos^2x)=2cos 2x + 9`, then the value of cos4x is

Last Answer : If `5(tan^2x - cos^2x)=2cos 2x + 9`, then the value of cos4x is A. `(-3)/(5)` B. `(1)/(3)` C. `(2)/(9)` D. `-(7)/(9)`

Description : If tan A = 4/3 and sin A = 4/5 then cos A = —————– a. 4/5 b. 3/5 c. 3⁄4 d.9/11

Last Answer : b. 3/5

Description : In right triangle ABC, right angled at C, if tan A = 1, then the value of 2 sin A cos A is (a) 0 (b) 1 (c) – 1 (d) 2

Last Answer : (b) 1

Description : If both x – 2 and x -(1/2) are factors of px2+ 5x+r, then show that p = r. -Maths 9th

Last Answer : Show that p = r.

Description : If both x – 2 and x -(1/2) are factors of px2+ 5x+r, then show that p = r. -Maths 9th

Last Answer : Show that p = r.

Description : Let P(–3, 2), Q(–5, –5), R(2, –3) and S(4, 4) be four points in a plane. Then show that PQRS is a rhombus. Is it a square ? -Maths 9th

Last Answer : Let P(1, -1), Q \(\big(rac{-1}{2},rac{1}{2}\big)\) and R(1,2) be the vertices of the ΔPQR.Then, PQ = \(\sqrt{\big(rac{-1}{2}-1\big)^2+\big(rac{1}{2}+1\big)^2}\) = \(\sqrt{rac{9}{4}+rac{9}{4}} ... {3\sqrt2}{2}\)PR = \(\sqrt{(1-1)^2+(2+1)^2}\) = \(\sqrt9\) = 3∵ PQ = QR, the triangle PQR is isosceles.

Description : The expression (tan A)(1-cot A)+(cot A)(1-tan A) can be written as -Maths 9th

Last Answer : answer:

Description : For any two real number a b and , we defined aRb if and only if sin^2a + cos^2b = 1. The relation R is -Maths 9th

Last Answer : (d) an equivalence relationGiven, a R b ⇒ sin2a + cos2b = 1 Reflexive: a R a ⇒ sin2 a + cos2 a = 1 ∀ a ∈ R (True) Symmetric: a R b ⇒ sin2 a + cos2 b = 1 ⇒ 1 - cos2 a + 1 - sin2 b = 1 ⇒ sin2 b + ... + cos2 b + sin2 b + cos2 c = 2 ⇒ sin2 a + cos2 c = 1 ⇒ a R c (True)∴ R is an equivalence relation.

Description : The angle A lies in the third quadrant and it satisfies the equation 4 (sin^2x + cos x) = 1. What is the measure of angle A? -Maths 9th

Last Answer : answer:

Description : If (cos x)/(1 + cosec x) + (cos x)/(cosec x - 1)= 2which one of the following is one of the values of x ? -Maths 9th

Last Answer : answer:

Description : If cosec |-sin |=l and sec |- cos |=m, prove that l2m2(l2+m2+3)=1 -Maths 9th

Last Answer : cosec(A) - sin(A) = l ⇒ 1/sin(A) - sin(A) = l ⇒ l² = 1/sin²(A) + sin²(A) - 2 --------- sec(A) - cos(A) = m ⇒ 1/cos(A) - cos(A) = m ⇒ m² = 1/cos²(A) + cos²(A) - 2 ---------- l²m² = [1/sin²(A) + ... A)) = = 1/(sin²(A)cos²(A)) ------------- ⇒ l²m² (l² + m² + 3) = sin²(A)cos²(A) / [sin²(A)cos²(A)] = 1

Description : If x sin3|+ y cos3|=sin|cos| and xsin|=ycos|, prove x2+y2=1. -Maths 9th

Last Answer : xsin3θ+ycos3θ=sinθcosθ (xsinθ)sin2θ+(ycosθ)cos2θ=sinθcosθ (xsinθ)sin2θ+(xsinθ)cos2θ=sinθcosθ xsinθ=sinθcosθ x=cosθ Again, ycosθ=xsinθ ycosθ=cosθsinθ y=sinθ Therefore, x2+y2=sin2θ+cos2θ=1.

Description : p(x)=x3+3x2+3x+1, g(x) = x+2 -Maths 9th

Last Answer : p(x) = x3+3x2+3x+1, g(x) = x+2 g(x) = 0 ⇒ x+2 = 0 ⇒ x = −2 ∴ Zero of g(x) is -2. Now, p(−2) = (−2)3+3(−2)2+3(−2)+1 = −8+12−6+1 = −1 ≠ 0 ∴By factor theorem, g(x) is not a factor of p(x

Description : Use the Factor Theorem to determine whether g(x) is a factor of p(x) in each of the following cases: (i) p(x) = 2x3+x2–2x–1, g(x) = x+1 -Maths 9th

Last Answer : Solution: p(x) = 2x3+x2–2x–1, g(x) = x+1 g(x) = 0 ⇒ x+1 = 0 ⇒ x = −1 ∴Zero of g(x) is -1. Now, p(−1) = 2(−1)3+(−1)2–2(−1)–1 = −2+1+2−1 = 0 ∴By factor theorem, g(x) is a factor of p(x

Description : Check whether p(x) is a multiple of g(x) or not -Maths 9th

Last Answer : p(x) is a multiple of g(x) or not

Description : By remainder theorem, find the remainder when p(x) is divided by g(x) -Maths 9th

Last Answer : Find the remainder when p(x) is divided by g(x)

Description : By remainder theorem, find the remainder when p(x) is divided by g(x) -Maths 9th

Last Answer : Find the remainder when p(x) is divided by g(x)

Description : Check whether p(x) is a multiple of g(x) or not -Maths 9th

Last Answer : p(x) is a multiple of g(x) or not

Description : BY REAMINDER THEOREM FIND THE REAMINDER, WHEN P(x) IS DIVIDED BY G(X), WHERE -Maths 9th

Last Answer : NEED ANSWER

Description : p(x)=x3-2x2-4x-1, g(x)=x- -Maths 9th

Last Answer : NEED ANSWER

Description : BY REAMINDER THEOREM FIND THE REAMINDER, WHEN P(x) IS DIVIDED BY G(X), WHERE -Maths 9th

Last Answer : This answer was deleted by our moderators...

Description : p(x)=x3-2x2-4x-1, g(x)=x- -Maths 9th

Last Answer : This answer was deleted by our moderators...

Description : If x, y, z are in G.P. and (log x – log 2y), (log 2y – log 3z) and (log 3z – log x) are in A.P., -Maths 9th

Last Answer : (d) obtuse angledx, y, z are in G.P. ⇒ y2 = xz ...(i) (log x - log 2y), (log 2y - log 3z) and (log 3z - log x) are in A.P. ⇒ 2(log 2y - log 3z) = (log x ... x is the length of the side opposite ∠A.∵ cos A is less than 0, i.e, negative, ∠A is obtused and the triangle is obtuse angled.

Description : What's the key to remembering how to draw each of the different trigonometric function graphs? (i.e. sin, cos, tan)

Last Answer : SOH – sin CAH – cos TOA – tan sin = opposite over hypotenuse cos = adjacent over hypotenuse tan = opposite over adjacent

Description : How to use sin, cos, and tan on a TI-84+Silver Edition?

Last Answer : answer:This may work, haven't tried a real problem yet . here are the steps in changing it from radian to degrees 1. turn on your TI-83 plus 2. press the MODE button near the top of your ... down to options and move the highlight from radian to degree, press enter and clear you're good to go

Description : What is SIN, TAN, COS?

Last Answer : Wikipedia knows.

Description : `(i) int e^(x). "[log (sec x+tan x) + sec x dx "` `(ii) int (e^(-x)(cos x-sin x))/(cos^(2) x) dx`

Last Answer : `(i) int e^(x). "[log (sec x+tan x) + sec x dx "` `(ii) int (e^(-x)(cos x-sin x))/(cos^(2) x) dx`

Description : `(i) int(1)/(sqrt(1-x^(2)).cos^(-1) x)dx` `(ii) int (sin(tan^(-1)x))/(1+x^(2))dx`

Last Answer : `(i) int(1)/(sqrt(1-x^(2)).cos^(-1) x)dx` `(ii) int (sin(tan^(-1)x))/(1+x^(2))dx`

Description : ` (i) int sqrt(1+ sin .(x)/(2)dx)` `(ii) int (1+cos 4x)/(cot x- tan x)dx`

Last Answer : ` (i) int sqrt(1+ sin .(x)/(2)dx)` `(ii) int (1+cos 4x)/(cot x- tan x)dx`

Description : `int(tan x + cos x)^(2) dx `

Last Answer : `int(tan x + cos x)^(2) dx `

Description : Consider the matrix function `A(x)=[{:(cos^(-1)x,sin^(-1)x,cosec^(-1)x),(sin^(-1)x,sec^(-1)x,tan^(-1)x),(cosec^(-1)x,tan^(-1)x,cot^(-1)x):}]` and `B =

Last Answer : Consider the matrix function `A(x)=[{:(cos^(-1)x,sin^(-1)x,cosec^(-1)x),(sin^(-1)x,sec^(-1)x,tan^(-1)x),( ... )=-A(x)` D. `A(x) + A(-x) = - piI_(3)`

Description : Let `theta ,phi in [0,2pi]` be such that `2 cos theta (1-sin phi)=sin^2 theta ((tan)theta/2+(cot)theta/2) cos phi -1, tan(2pi-theta) > 0 and -1 <

Last Answer : Let `theta ,phi in [0,2pi]` be such that `2 cos theta (1-sin phi)=sin^2 theta ((tan)theta/2+(cot)theta/2) ... (3pi)/(2)` D. `(3pi)/(2) lt phi lt 2pi`

Description : 15. Which of the following is correct?(1) \( \tan 1>\tan 2 \)(2) \( \tan 2>\tan 1 \)(3) \( \sin 1\cos 2 \)

Last Answer : 15. Which of the following is correct? (1) \( \tan 1>\tan 2 \) (2) \( \tan 2>\tan 1 \) (3) \( \sin 1\cos 2 \)

Description : Half the angle of nip, (α), for a roll crusher is given by (where, dr, dp and df are diameters of crushing rolls, feed particles and rolls gap respectively). (A) cos α = (dr + dp)/(dr + df) (B) cos α = (dr + df)/(dr + dp) (C) tan α = (dr + dp)/(dr + df) (D) sin α = (dr + dp)/(dr + df)

Last Answer : (A) cos α = (dr + dp)/(dr + df)

Description : Graph of alternating current is a A. cos wave B. tan wave C. curve D. sine wave

Last Answer : sine wave

Description : The value of 2 tan 2 45°+ cos 2 30° − sin 2 60° is (a) 0 (b) 1 (c) -2 (d) 2

Last Answer : (d) 2

Description : 1 – cos 2 A is equal to: a sin 2 A b tan 2 A c 1 – sin 2 A d sec 2 A

Last Answer : a sin 2 A