The total number of `alphaandbeta` particles emitted in the nuclear reaction `""_(92)^(238)Uto""_(82)^(214)Pb` is

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The total number of `alphaandbeta` particles emitted in the nuclear reaction `""_(92)^(238)Uto""_(82)^(214)Pb` is

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Description : Uranium `._(92)U^(238)` decayed to `._(82)Pb^(206)`. They decay process is `._(92)U^(238) underset((x alpha, y beta))(rarr ._(82)Pb^(206))` `t_(1//2)`

Last Answer : Uranium `._(92)U^(238)` decayed to `._(82)Pb^(206)`. They decay process is `._(92)U^(238) underset((x alpha ... 2.303)/(4.5 xx 10^(9)) xx 0.693 log 4`

Description : Uranium `._(92)U^(238)` decayed to `._(82)Pb^(206)`. They decay process is `._(92)U^(238) underset((x alpha, y beta))(rarr ._(82)Pb^(206))` `t_(1//2)`

Last Answer : Uranium `._(92)U^(238)` decayed to `._(82)Pb^(206)`. They decay process is `._(92)U^(238) underset((x alpha, ... be A. 5.25 B. 0.125 C. 12.5 D. 1.25

Description : Uranium (`""_(92)U""^(238)`) decayed to `""_(82)Pb""^(206)`. The process is `""_(92)U""^(238)underset(xalpha,ybeta)to.""_(82)Pb""^(206)` `t""_(1//2)of

Last Answer : Uranium (`""_(92)U""^(238)`) decayed to `""_(82)Pb""^(206)`. The process is `""_(92)U""^(238)underset( ... series are A. 6,8 B. 8,6 C. 8,8 D. 6,6

Description : Which of the following nuclei are doubly magic? a)`._(92)U^(238)` b)`._(2)He^(4)` c)`._(8)O^(16)` d)`._(82)Pb^(208)`

Last Answer : Which of the following nuclei are doubly magic? a)`._(92)U^(238)` b)`._(2)He^(4)` c)`._(8)O^(16)` d)`._( ... O` C. `._(82)^(208)Pb` D. `._(92)^(238)U`

Description : `._(92)^(238)U` atom distintgrates to `._(84)^(214) Po` with a half life of `4.5xx10^(9)` years by emitting six alpha particles and n electrons. Here

Last Answer : `._(92)^(238)U` atom distintgrates to `._(84)^(214) Po` with a half life of `4.5xx10^(9)` years by emitting ... . Here n is - A. 6 B. 4 C. 10 D. 7

Description : The isotope `._(92)^(235)U` decays in a number of steps to an isotope of `._(82)^(207)Pb`. The groups of particle emitted in this process will be:

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Description : The nucleus `._(92)^(235)U` decays according to `._(92)^(238)U rarr ._(92)^(234)Th + ._(2)^(4)He`. Calculate the kinetic energy of the emitted `alpha`

Last Answer : The nucleus `._(92)^(235)U` decays according to `._(92)^(238)U rarr ._(92)^(234)Th + ._(2)^(4)He`. ... kg " " ._(2)^(4)He = 6.64807 xx 10^(-27)`

Description : `._(92)U^(238)` emits `8 alpha-` particles and `6 beta-` particles. The `n//p` ratio in the product nucleus is a)`(62)/(41)` b)`(60)/(41)` c)`(61)/(42

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Description : Consider the following nuclear reactions: `""_(92)""^(238)Mto.""_(y)""^(x)N+2.""_(2)""^(4)He, ""_(x)""^(y)Nto ""_(B)""^(A)L+2beta""^(+)` The number of

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Description : Consider the following nuclear reactions: `""_(92)""^(238)Mto.""_(y)""^(x)N+2.""_(2)""^(4)He, ""_(x)""^(y)Nto ""_(B)""^(A)L+2beta""^(+)` The number of

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Last Answer : The number of `alpha` and `beta`-particles emitted in the nuclear reaction `._(90)^(210) Th to ._(83)^(212 ... `3 alpha, 7 beta` D. `4 alpha, 1 beta`

Description : Assertion `(A):` `._(92)U^(238) (IIIB)overset(-alpha)rarrAoverset(-alpha)rarrB overset(-beta)rarrC` Reason `(R):` Element `B` will be of `II A ` group

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Last Answer : In the transformation of `""_(92)""^(238)U` to `""_(92)""^(234)U`, if one emission is an `alpha` ... `gamma` D. one `beta^(+)` and one `beta^(-)`

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