Thermal efficiencies up to........have been observed in hybrid cooling towers
a. 92
b. 82
c. 72
d. 62

1 Answer

Answer :

92

Related questions

Description : The average heart beat rate per minute in a normal person is - (1) 82 (2) 92 (3) 72 (4) 98

Last Answer : (3) 72 Explanation: The average heart rate for adult humans is about 70 to 75 beats per minute in a normal relaxed mode. While we tend to think of the "normal" heart beat rate as being "72 ... health risk. The "72 beats per minute" that we are familiar with is the normal average heart beat rate.

Description : The average heartbeat rate per minute in a normal person is (1) 82 (2) 92 (3) 72 (4) 98

Last Answer : 72

Description : The average heart beat rate per minute in a normal person is (1) 82 (2) 92 (3) 72 (4) 98

Last Answer : 72

Description : Common applications of Cooling towers include a. Cooling the circulating water used in oil refineries b. petrochemical and other chemical plants c. thermal power stations d. All of the above.

Last Answer : All of the above.

Description : The hyperbolic cooling towers are associated with ……. and …….. power plants. a) electrical, thermal c) thermal, nuclear b) nuclear, electrical d) none of above

Last Answer : thermal, nuclear

Description :  Find the speed and average speed of a bus which leaves salem at 4 p.m. and reaches madurai in the same day at 8 p.m. The distance between the two stations is 216 km and the total time for stoppage is 1 hour between these stations. a) 54,72 b) 62,84 c) 72,54 d) 82,64

Last Answer : C Total time taken = 4 hours; Time of stoppage = 1 hour, that is, actual time taken = 4 hours - 1 hours = 3 hours Speed = Distance/Time = 216/3 = 72 km/hr Average speed = Total Distance/ Total Time = 216/4 = 54 km/hr

Description : What states that thermal efficiencies of all reversible heat engines operating between the same two reservoirs are the same and that no heat engine is more efficient than a reversible one operating between the ... A. Ericson principle  B. Carnot principle  C. Otto principle  D. Stirling principle

Last Answer : Carnot principle

Description : Hyperbolic cooling towers used in a) Coal-fired power plant b) Nuclear plants c) Thermal power plant d) All of these

Last Answer : d) All of these

Description : Hyperbolic cooling towers are made up of high height reinforced ………structure. a) plastic c)metal b) alloy d) concrete

Last Answer : concrete

Description : Cooling towers vary in size from small roof-top units to very large hyperboloid structures that can be up to ____meters tall and _____ meters in diameter, or rectangular structures that can be over 40 meters tall and 80 meters long. a. 200&100 b. 100&50 c. 200&50 d. 200 &150

Last Answer : 200&100

Description : Cooling towers vary in size from small roof-top units to very large hyperboloid structures that can be up to ____ meters tall and _____ meters in diameter, or rectangular structures that can be over 40 meters tall and 80 meters long. a. 200&100 b. 100&50 c. 200&50 d. 200 &150

Last Answer : a. 200&100

Description : In hyperboloid cooling towers the material is filled at 1. Tower’s bottom 2. Tower’s top 3. Near tower 4. None of above

Last Answer : Tower’s top

Description : Cooling towers operate through a ____process that efficiently cools the already cycled water to be reused. 1. Heat exchange 2. Heat expand 3. Heat transfer 4. None of above

Last Answer : Heat transfer

Description : How many times chlorination must be carried out for cooling towers 1. Twice a year 2. Once a year 3. Thrice a year 4. None of above

Last Answer : Twice a year

Description : How does the flow of air occur in natural draught cooling towers? a) Natural pressure head density between cold outside air and humid inside air b) Variation in pressure of both cold outside air and ... given air vents and vacuum ports d) Because of difference in the volume of both the of airs

Last Answer : Natural pressure head density between cold outside air and humid inside air

Description : . Improved cooling efficiency and minimum usage of material are the key features of ______ a. Natural draft cooling towers b. Cross flow towers c. Hyperbolic cooling d. All of above

Last Answer : Hyperbolic cooling

Description : . _____ type of cooling towers are used with nuclear power plants. a. Cross flow b. Natural draft c. Hyperbolic d. None of above

Last Answer : Hyperbolic

Description : Hyperbolic cooling towers are also referred as a. Natural draft towers b. Cross flow towers c. Hyperboloid towers d. None of the above

Last Answer : Hyperboloid towers

Description : Which type of cooling towers operate through a chimney or stack ___ a. Cross flow b. Counter flow c. Hyperbolic d. All of above

Last Answer : Hyperbolic

Description : . ______ type of cooling towers are structurally strong. a. Counter flow towers b. Hyperbolic towers c. Cross flow towers d. None of the above

Last Answer : Hyperbolic towers

Description : The hyperboloid cooling towers are often associated __ a. with nuclear power plants b. Used in some coal-fired plants c. In some large chemical and other industrial plants. d. All of the above.

Last Answer : All of the above

Description : Hyperbolic cooling towers have become design standard for all natural draft structural towers because usage of . a. Their structural strength b. Minimum usage of material. c. Improving cooling efficiency d. All of the above.

Last Answer : All of the above.

Description : Which one of the following fill material is more energy efficient for cooling towers in case of sea water cooling? • Splash fill • Film fill • Low clog film fill • None of the above

Last Answer : Film fill

Description : Natural draft cooling towers are mainly used in the _____. • Steel industry • Fertilizer industry • Alumina industry • Power stations

Last Answer : Power stations

Description : How does the flow of air occur in natural draught cooling towers? a) Natural pressure head density between cold outside air and humid inside air b) Variation in pressure of both cold outside air and ... given air vents and vacuum ports d) Because of difference in the volume of both the of airs

Last Answer : Natural pressure head density between cold outside air and humid inside air

Description : . Most cooling towers are capacity rated at a "standard" wet bulb temperature of ___of • 72°F • 52°F • 78°F • 75°F

Last Answer : 78°F

Description : __________ Cooling towers have become the design standard for all natural-draft cooling towers because oftheir structural strength and minimum usage of material. • HCT • CCT • Hyperboloid • None

Last Answer : Hyperboloid

Description : There are two huge cooling towers close to building site of reactor __ and __ of the Chernobyl Power Plant. a. 1&3 b. 4&5 c. 2&5 d. 1&4

Last Answer : 4&5

Description : There are _______main types of cooling towers that are defined by how water or air passes through them. a. One b. Two c. Three d. Four

Last Answer : three

Description : . There are two huge cooling towers close to building site of reactor __ and __ of the Chernobyl Power Plant. a. 1&3 b. 4&5 c. 2&5 d. 1&4

Last Answer : b. 4&5

Description : Uranium `._(92)U^(238)` decayed to `._(82)Pb^(206)`. They decay process is `._(92)U^(238) underset((x alpha, y beta))(rarr ._(82)Pb^(206))` `t_(1//2)`

Last Answer : Uranium `._(92)U^(238)` decayed to `._(82)Pb^(206)`. They decay process is `._(92)U^(238) underset((x alpha ... 2.303)/(4.5 xx 10^(9)) xx 0.693 log 4`

Description : Uranium `._(92)U^(238)` decayed to `._(82)Pb^(206)`. They decay process is `._(92)U^(238) underset((x alpha, y beta))(rarr ._(82)Pb^(206))` `t_(1//2)`

Last Answer : Uranium `._(92)U^(238)` decayed to `._(82)Pb^(206)`. They decay process is `._(92)U^(238) underset((x alpha, ... be A. 5.25 B. 0.125 C. 12.5 D. 1.25

Description : Uranium (`""_(92)U""^(238)`) decayed to `""_(82)Pb""^(206)`. The process is `""_(92)U""^(238)underset(xalpha,ybeta)to.""_(82)Pb""^(206)` `t""_(1//2)of

Last Answer : Uranium (`""_(92)U""^(238)`) decayed to `""_(82)Pb""^(206)`. The process is `""_(92)U""^(238)underset( ... series are A. 6,8 B. 8,6 C. 8,8 D. 6,6

Description : The total number of `alphaandbeta` particles emitted in the nuclear reaction `""_(92)^(238)Uto""_(82)^(214)Pb` is

Last Answer : The total number of `alphaandbeta` particles emitted in the nuclear reaction `""_(92)^(238)Uto""_(82)^(214)Pb` is

Description : Which of the following nuclei are doubly magic? a)`._(92)U^(238)` b)`._(2)He^(4)` c)`._(8)O^(16)` d)`._(82)Pb^(208)`

Last Answer : Which of the following nuclei are doubly magic? a)`._(92)U^(238)` b)`._(2)He^(4)` c)`._(8)O^(16)` d)`._( ... O` C. `._(82)^(208)Pb` D. `._(92)^(238)U`

Description : The isotope `._(92)^(235)U` decays in a number of steps to an isotope of `._(82)^(207)Pb`. The groups of particle emitted in this process will be:

Last Answer : The isotope `._(92)^(235)U` decays in a number of steps to an isotope of `._(82)^(207)Pb`. The groups ... C. `7 alpha, 4 beta` D. `10 alpha, 8 beta`

Description : The percentage of water content in the human blood plasma normally varies from (1) 60-64 (2) 70-75 (3) 80-82 (4) 91-92

Last Answer : (4) 91-92 Explanation: Blood plasma is the strawcolored/pale-yellow liquid component of blood that normally holds the blood cells in whole blood in suspension. It makes up about 55% ... , electrolytes, hormones and carbon dioxide (plasma being the main medium for excretory product transportation).

Description : The percentage of water content in the human blood plasma normally varies from (1) 60-64 (2) 70-75 (3) 80-82 (4) 91-92

Last Answer : 91-92

Description : Make a stem-and-leaf plot for this set of data. Find the range,median,and mode of the data. : 47 54 70 62 59 62 82 66 62 73 55 82 59?

Last Answer : nevermind- i figured it out

Description : The power in a wave given that H component is 0.82 units in air. a) 126.74 b) 621.47 c) 216.47 d) 745.62

Last Answer : a) 126.74

Description : Co-efficient of discharge (Cd ) is defined as actual discharge/theoretical discharge and is equal to Cc . Cv ; where Cc = Co-efficient of contraction and Cv = co-efficient of velocity. Cd of an orifice is usually about (A) 0.42 (B) 0.62 (C) 0.82 (D) 0.98

Last Answer : (B) 0.62

Description : Co-efficient of discharge (Cd ) is defined as actual discharge/theoretical discharge and is equal to Cc . Cv ; where Cc = Co-efficient of contraction and Cv = co-efficient of velocity. Cd of an orifice is usually about (A) 0.42 (B) 0.62 (C) 0.82 (D) 0.98

Last Answer : (B) 0.62

Description : `._(92)U^(238)` emits `8 alpha-` particles and `6 beta-` particles. The `n//p` ratio in the product nucleus is a)`(62)/(41)` b)`(60)/(41)` c)`(61)/(42

Last Answer : `._(92)U^(238)` emits `8 alpha-` particles and `6 beta-` particles. The `n//p` ratio in the product nucleus ... A. 60/41 B. 61/40 C. 62/41 D. 61/42

Description : Which of the following statements is correct concerning the motor performance curves and data table shown in the illustration? EL-0006 A. The motor RPM at full load is 1737 RPM. B. The motor draws 12.62 kw ... If the motor was developing 10 HP its power factor would be 0.92. D. All of the above.

Last Answer : Answer: D

Description : At normal boiling point, molar entropy of vaporisation is __________ Joule/K°.mole. (A) 72 (B) 92 (C) 142 (D) 192

Last Answer : (B) 92

Description : The least number, which when divided by 48, 60, 72, 108 and 140 leaves 38, 50, 62, 98 and 130 as remainders respectively, is: A.11115 B.15110 C.15130 D.15310 E.None of these

Last Answer : Answer – B (15110) Explanation – Here (48 – 38) = 10, (60 – 50) = 10, (72 – 62) = 10, (108 – 98) = 10 & (140 – 130) = 10. Required number = (L.C.M. of 48, 60, 72, 108, 140) – 10 = 15120 – 10 = 15110

Description : .What is the sum between money spent on bonus by these two companies? a) Rs.72 lakhs b) Rs.62 lakhs c) Rs.60 lakhs d) Rs.65 lakhs e) None of these

Last Answer : e) None of these

Description : The next term in the series  2, 5, 10, 17, 26, 37, ? is: (A) 50 (B) 57 (C) 62 (D) 72

Last Answer : Answer: A

Description : The number of function points of a proposed system is calculated as 500. Suppose that the system is planned to be developed in Java and the LOC/FP ratio of Java is 50. Estimate the effort (E) required to ... ) 25 person months (B) 75 person months (C) 62.5 person months (D) 72.5 person months

Last Answer : (C) 62.5 person months 

Description : The ratio of the monthly salaries of A and B is in the ratio 15 : 16 and that of B and C is in the ratio 17 : 18. Find the monthly income of C if the total of their monthly salary is Rs 1,87,450. A) Rs 66,240 B) Rs 72,100 C) Rs 62,200 D) Rs 65,800 E) Rs 60,300

Last Answer : Answer: A A/B = 15/16 and B/C = 17*18 So A : B : C = 15*17 : 16*17 : 16*18 = 255 : 272 : 288 So C’s salary = [288/(255+272+288)] * 1,87,450= Rs 66,240