The compound ratio of ` p : r and r: q` is __________ .

The compound ratio of ` p : r and r: q` is __________ .
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The compound ratio of ` p : r and r: q` is __________ .
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Compound P on treatement with `CH_(2)N_(2)` (diazomethane) produces compound Q. compound Q on reaction with Hl produces two alkyl iodides R and S . Al

Description : Compound P on treatement with `CH_(2)N_(2)` (diazomethane) produces compound Q. compound Q on reaction with Hl produces two alkyl iodides R and S . Al

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Two aliphatic aldehydes P and Q react in th presence of aqueous `k_(2)CO_(3)` to give compound R, which upon treatment with HCN provides compound S. O

Description : Two aliphatic aldehydes P and Q react in th presence of aqueous `k_(2)CO_(3)` to give compound R, which upon treatment with HCN provides compound S. O

Last Answer : Two aliphatic aldehydes P and Q react in th presence of aqueous `k_(2)CO_(3)` to give compound R, which ... shown below: The compound S is B. C. D.

Two aliphatic aldehydes (P) and (Q) react in the presence of aqueous `K_(2)CO_(3)` to give compound (R ) which upon treatment with HCN gives compound(

Description : Two aliphatic aldehydes (P) and (Q) react in the presence of aqueous `K_(2)CO_(3)` to give compound (R ) which upon treatment with HCN gives compound(

Last Answer : Two aliphatic aldehydes (P) and (Q) react in the presence of aqueous `K_(2)CO_(3)` to give compound (R ) ... (P) and (Q), respectively, are: B. C. D.

Which of the following shall be a compound proposition involving the propositions p, q and r, that is true when exactly two of the p, q and r are true and is false otherwise? (A) (p∨q∧˥r) ∨ (p∨q∧r) ∧ (˥p∧q∨r) (B) (p∧q∨r) ∧ (p∧q∧r) ∨ (˥q∨˥p∧˥r) (C) (p∧q∧˥r) ∨ (p∨˥q∧r) ∨ (˥p∧q∧r) (D) (p∨r∧q) ∨ (p∧q∧r) ∨ (˥p∧q∧r)

Description : Which of the following shall be a compound proposition involving the propositions p, q and r, that is true when exactly two of the p, q and r are true and is false otherwise? (A) (p∨q∧˥r) ∨ (p∨q∧r) ∧ (˥p∧q∨r) (B) ... ) ∨ (˥q∨˥p∧˥r) (C) (p∧q∧˥r) ∨ (p∨˥q∧r) ∨ (˥p∧q∧r) (D) (p∨r∧q) ∨ (p∧q∧r) ∨ (˥p∧q∧r) 

Last Answer : (C) (p∧q∧˥r) ∨ (p∨˥q∧r) ∨ (˥p∧q∧r)

Rs 117 was supposed to be divided among P, Q and R in the ratio 3:4:6. But, by mistake, it was divided in the ratio `(1)/(3):(1)/(4):(1)/(6)` How many

Description : Rs 117 was supposed to be divided among P, Q and R in the ratio 3:4:6. But, by mistake, it was divided in the ratio `(1)/(3):(1)/(4):(1)/(6)` How many

Last Answer : Rs 117 was supposed to be divided among P, Q and R in the ratio 3:4:6. But, by mistake, it was ... How many of P,Q and R gained due to this mistake?

P and Q started a partnership business investing some amount in the ratio of 3:5. R joined them after six months with an amount equal to that of Q. In what proportion should the profit at the end of one year be distributed among P, Qand R? A.5 : 8 : 10 B.6 : 10 : 5 C.6 : 4 : 10 D.10 : 6 : 3

Description : P and Q started a partnership business investing some amount in the ratio of 3:5. R joined them after six months with an amount equal to that of Q. In what proportion should the profit at the end of one year be distributed among P, Qand R? A.5 : 8 : 10 B.6 : 10 : 5 C.6 : 4 : 10 D.10 : 6 : 3

Last Answer : Answer – B (6 : 10 : 5) Explanation – Let the initial investments of P and Q be 3a amd 5a. P : Q : R = (3a x 12) : (5a x 12) : (5a x 6) = 36 : 60 : 30 = 6 : 10 : 5.

In a business P and R invested amounts in the ratio 2 : 1, whereas the ratio between amounts invested by P and Q was 3 : 2 . If Rs. 2,236 was their profit, how much amount did Q receive ? A.Rs.650 B.Rs.688 c.Rs.588 D.Rs.490

Description : In a business P and R invested amounts in the ratio 2 : 1, whereas the ratio between amounts invested by P and Q was 3 : 2 . If Rs. 2,236 was their profit, how much amount did Q  receive ? A.Rs.650 B.Rs.688 c.Rs.588 D.Rs.490

Last Answer : Answer- B(Rs.688 ) Solution : P : Q = 3 : 2 , P : R = 2 : 1 [given] Q : P = 2 : 3 [reverse], Q : P = 4 : 6 [multiply by 2] Now, P : R = 2 : 1 P : R = 6 : 3 [multiply by 3] P : Q =6 : 4 [after x3] , So Q : P : R = 4 : 6 : 3 or, P : Q : R = 6 : 4 : 3 Q’s share= 4/13 x 2236=Rs.688

P and Q together can complete a job in 30 days. Q and R together can complete the same job in 40 days. P and R together can complete the same job in 40 days. What is the respective ratio of the number of days taken by P when completing the same job alone to the number of days taken by R when completing the same job alone? a) A.2:5 b) B.1:2 c) C.3:4 d) D.2:3

Description : P and Q together can complete a job in 30 days. Q and R together can complete the same job in 40 days. P and R together can complete the same job in 40 days. What is the respective ratio of the number of days taken by P ... R when completing the same job alone? a) A.2:5 b) B.1:2 c) C.3:4 d) D.2:3

Last Answer : B Efficiency of P and Q= 1/30 per day ___________1 ⇒ Efficiency of Q and R = 1/40 per day_________2 ⇒ Efficiency of R and P = 1/40 per day _________3 Taking equation 2 and 3 together ⇒ Q + R = ... 120 days he they work alone. ⇒ Ratio of number of days in which P and R can complete the job 1:2.

Total of the ages of P, Q and R at present is 99 years. Eight years ago, the ratio of their ages was 4: 5: 6. What is the age of Q at present a) 44 b) 30 c) 45 d) 33

Description : Total of the ages of P, Q and R at present is 99 years. Eight years ago, the ratio of their ages was 4: 5: 6. What is the age of Q at present a) 44 b) 30 c) 45 d) 33

Last Answer : D Let their ages 8 years ago is4x, 5x and 6x years.  4x+8+5x + 8 + 6x + 8= 99 hence x= 5 Q’s present age = (5x + 8)  =33 years

An amount of money is to be distributed among P, Q and R in the ratio of 5:4:7 respectively. If the total share of P and R is 3 times the share of Q, what is definitely Q’s share? a) 2000 b) 4000 c) 6000 d) Data inadequate e) None of these

Description : An amount of money is to be distributed among P, Q and R in the ratio of 5:4:7 respectively. If the total share of P and R is 3 times the share of Q, what is definitely Q’s share? a) 2000 b) 4000 c) 6000 d) Data inadequate e) None of these

Last Answer : Answer: D 

The amounts of P, Q and R in the ratio 3:4:5 and their spending are in the ratio 4:5:6. If P saves 1/6th of his income then then savings of P, Q, R are in the ratio A) 18:11:3. B) 12:13:4. C) 4:11:18. D) None

Description : The amounts of P, Q and R in the ratio 3:4:5 and their spending are in the ratio 4:5:6. If P saves 1/6th of his income then then savings of P, Q, R are in the ratio A) 18:11:3. B) 12:13:4. C) 4:11:18. D) None

Last Answer : Answer: C)  Income of P,Q,R = 3x:4x:5x Expense of 4:5:6=4y:5y:6y.  Savings [income –expenditure]  =3x-4y :4x-5y :5x-6y------->1  Given 3x-4y=x/6  y=17x/24  Sub if (1) is,  =3x-4(17x/24) :4x-5(17x/24) :5x-6(17x/24)  =8x:22x:36x  = 4:11:18

Three persons enter into a partnership by investing in the ratio of 9:8:1. After one year P double its investment and R puts another Rs.6000 to the initial investment. Now the ratio of investment changes to 9:8:2. What is total investment P,Q, R after 2years? A) 108000. B) 114000. C) 126000. D) None

Description : Three persons enter into a partnership by investing in the ratio of 9:8:1. After one year P double its investment and R puts another Rs.6000 to the initial investment. Now the ratio of investment changes to 9:8:2. What is total investment P,Q, R after 2years? A) 108000. B) 114000. C) 126000. D) None

Last Answer : Answer: B)  Let investment of P, Q & R are 9x,8x & x for 1year.  After 1 year ratio of their investments.  9:8:2 =9 x +18x : 8x: x+6000=27x :8x: x+6000 X =Rs.6000 Total investments of P, Q & R After 2 years =[9+8+2]*6000=Rs.114000.

P, Q, R invested in the ratio of 15:16:17. After the end of the business teram they receives the profit in the ratio 9:10:11. Find the ratio of time in which they invested in the business. A) 934:1699:1578 B)1224:1275:1320 C)1578:1668:8096. D) None

Description : P, Q, R invested in the ratio of 15:16:17. After the end of the business teram they receives the profit in the ratio 9:10:11. Find the ratio of time in which they invested in the business. A) 934:1699:1578 B)1224:1275:1320 C)1578:1668:8096. D) None

Last Answer : Answer: B)  P, Q, R invest the amount in the ratio 15:16:17  T1, T2, T3 are time for investment profit gained =investment × time  Profit ratio= 9: 10: 11=15 × T1 :16 × T2 : 17 × T3  T1:T2:T3 =1224:1275:1320

The reaction of compounf P with `CH_(3)MgBr` (excess) in `(C_(2)H_(5)_(2)O` followed by addition of `H_(2)O` give Q the compound Q on treatment with `

Description : The reaction of compounf P with `CH_(3)MgBr` (excess) in `(C_(2)H_(5)_(2)O` followed by addition of `H_(2)O` give Q the compound Q on treatment with `

Last Answer : The reaction of compounf P with `CH_(3)MgBr` (excess) in `(C_(2)H_(5)_(2) ... and Friedel-Crafts acylation D. Dehydration and Friedel-Crafts acylation

The reaction of compounf P with `CH_(3)MgBr` (excess) in `(C_(2)H_(5)_(2)O` followed by addition of `H_(2)O` give Q the compound Q on treatment with `

Description : The reaction of compounf P with `CH_(3)MgBr` (excess) in `(C_(2)H_(5)_(2)O` followed by addition of `H_(2)O` give Q the compound Q on treatment with `

Last Answer : The reaction of compounf P with `CH_(3)MgBr` (excess) in `(C_(2)H_(5)_(2)O` followed by addition of `H_ ... product S is The product S is A. B. C. D.

A carbonyl compound (P) which gives positive iodoform test, undergoes reaction with MeMgBr followed by dehydration to give an olefin (Q). Ozonolysis o

Description : A carbonyl compound (P) which gives positive iodoform test, undergoes reaction with MeMgBr followed by dehydration to give an olefin (Q). Ozonolysis o

Last Answer : A carbonyl compound (P) which gives positive iodoform test, undergoes reaction with MeMgBr followed by dehydration to give ... (S) is: A. B. C. D.

A carbonyl compound (P) which gives positive iodoform test, undergoes reaction with MeMgBr followed by dehydration to give an olefin (Q). Ozonolysis o

Description : A carbonyl compound (P) which gives positive iodoform test, undergoes reaction with MeMgBr followed by dehydration to give an olefin (Q). Ozonolysis o

Last Answer : A carbonyl compound (P) which gives positive iodoform test, undergoes reaction with MeMgBr followed by dehydration ... respectively, are: A. B. C. D.

A carbonyl compound (P) which gives positive iodoform test, undergoes reaction with MeMgBr followed by dehydration to give an olefin (Q). Ozonolysis o

Description : A carbonyl compound (P) which gives positive iodoform test, undergoes reaction with MeMgBr followed by dehydration to give an olefin (Q). Ozonolysis o

Last Answer : A carbonyl compound (P) which gives positive iodoform test, undergoes reaction with MeMgBr followed by dehydration to give ... (P) is: A. B. C. D.

Let us assume that you construct ordered tree to represent the compound proposition (~(p˄q))↔(~p˅~q). Then, the prefix expression and post-fix expression determined using this ordered tree are given as ........... and ............. respectively. (A) ↔~˄pq˅ ~~pq, pq˄~p~q~˅↔ (B) ↔~˄pq˅ ~p~q, pq˄~p~q~˅↔ (C) ↔~˄pq˅ ~~pq, pq˄~p~ ~q˅↔ (D) ↔~˄pq˅ ~p~q, pq˄~p~~q˅↔

Description : Let us assume that you construct ordered tree to represent the compound proposition (~(p˄q))↔(~p˅~q). Then, the prefix expression and post-fix expression determined using this ordered tree are given as ........... and .......... ... ~p~q~˅↔ (C) ↔~˄pq˅ ~~pq, pq˄~p~ ~q˅↔ (D) ↔~˄pq˅ ~p~q, pq˄~p~~q˅↔

Last Answer : (B) ↔~˄pq˅ ~p~q, pq˄~p~q~˅↔

I want to put "S.P.Q.R." on something. Any suggestions?

Description : I want to put "S.P.Q.R." on something. Any suggestions?

Last Answer : Put it in your profile.

Match the following: NC code DefinitionP. M05 1. Absolute coordinate system Q. G01 2. Dwell R. G04 3. Spindle stop S. G09 4. Linear interpolation a.P-2, Q-3, R-4, S-1 b.P-3, Q-4, R-1, S-2 c.P-3, Q-4, R-2, S-1 d.P-4, Q-3, R-2, S-1

Description : Match the following: NC code DefinitionP. M05 1. Absolute coordinate system Q. G01 2. Dwell R. G04 3. Spindle stop S. G09 4. Linear interpolation a.P-2, Q-3, R-4, S-1 b.P-3, Q-4, R-1, S-2 c.P-3, Q-4, R-2, S-1 d.P-4, Q-3, R-2, S-1

Last Answer : c.P-3, Q-4, R-2, S-1

Write the given sets in roster form: (a). P = {y: y is an integer and -4 < y < 6}. (b). Q = {y: y is a natural number which is <8} (c). R = {y: y is a 2 digit natural number in which the sum of its digits is 9} -Other

Description : Write the given sets in roster form: (a). P = {y: y is an integer and -4 < y < 6}. (b). Q = {y: y is a natural number which is

Last Answer : (i) A = {x: x is an integer and †3 < x < 7} The elements of this set are †2, †1, 0, 1, 2, 3, 4, 5, and 6 only. Therefore, the given set can be written in roster form as A = {†2, †... and 80 only. Therefore, this set can be written in roster form as C = {17, 26, 35, 44, 53, 62, 71, 80}}.

3. ABCD is a rectangle and P, Q, R and S are mid-points of the sides AB, BC, CD and DA respectively. Show that the quadrilateral PQRS is a rhombus. -Maths 9th

Description : 3. ABCD is a rectangle and P, Q, R and S are mid-points of the sides AB, BC, CD and DA respectively. Show that the quadrilateral PQRS is a rhombus. -Maths 9th

Last Answer : Solution: Given in the question, ABCD is a rectangle and P, Q, R and S are mid-points of the sides AB, BC, CD and DA respectively. Construction, Join AC and BD. To Prove, PQRS is a rhombus. Proof: In ΔABC P and Q ... (ii), (iii), (iv) and (v), PQ = QR = SR = PS So, PQRS is a rhombus. Hence Proved

2. ABCD is a rhombus and P, Q, R and S are the mid-points of the sides AB, BC, CD and DA respectively. Show that the quadrilateral PQRS is a rectangle. -Maths 9th

Description : 2. ABCD is a rhombus and P, Q, R and S are the mid-points of the sides AB, BC, CD and DA respectively. Show that the quadrilateral PQRS is a rectangle. -Maths 9th

Last Answer : Solution: Given in the question, ABCD is a rhombus and P, Q, R and S are the mid-points of the sides AB, BC, CD and DA respectively. To Prove, PQRS is a rectangle. Construction, Join AC and BD. Proof: In ΔDRS and ... , In PQRS, RS = PQ and RQ = SP from (i) and (ii) ∠Q = 90° , PQRS is a rectangle.

ABCD is a quadrilateral in which P, Q, R and S are mid-points of the sides AB, BC, CD and DA (see Fig 8.29). AC is a diagonal. Show that: (i) SR || AC and SR = 1/2 AC (ii) PQ = SR (iii) PQRS is a parallelogram. -Maths 9th

Description : ABCD is a quadrilateral in which P, Q, R and S are mid-points of the sides AB, BC, CD and DA (see Fig 8.29). AC is a diagonal. Show that: (i) SR || AC and SR = 1/2 AC (ii) PQ = SR (iii) PQRS is a parallelogram. -Maths 9th

Last Answer : . Solution: (i) In ΔDAC, R is the mid point of DC and S is the mid point of DA. Thus by mid point theorem, SR || AC and SR = ½ AC (ii) In ΔBAC, P is the mid point of AB and Q is the mid point of BC. ... ----- from question (ii) ⇒ SR || PQ - from (i) and (ii) also, PQ = SR , PQRS is a parallelogram.

P is the mid - point of side AB of a parallelogram ABCD. A line through B parallel to PD meets DC at Q and AD produced at R (see figure). -Maths 9th

Description : P is the mid - point of side AB of a parallelogram ABCD. A line through B parallel to PD meets DC at Q and AD produced at R (see figure). -Maths 9th

Last Answer : (i) In △ARB,P is the mid point of AB and PD || BR. ∴ D is a mid - point of AR [converse of mid - point theorem] ∴ AR = 2AD But BC = AD [opp sides of ||gm ABCD] Thus, AR = 2BC (ii) ∴ ABCD is a ... a mid - point of AR and DQ || AB ∴ Q is a mid point of BR [converse of mid - point theorem] ⇒ BR = 2BQ

If P,Q,R,S are respectively the mid - points of the sides of a parallelogram ABCD, if ar(||gm PQRS) = 32.5cm2 , then find ar(||gm ABCD). -Maths 9th

Description : If P,Q,R,S are respectively the mid - points of the sides of a parallelogram ABCD, if ar(||gm PQRS) = 32.5cm2 , then find ar(||gm ABCD). -Maths 9th

Last Answer : Join PR. ∵ △PSR and ||gm APRD are on the same base and between same parallel lines. ar(△PSR) = 1/2 ar(||gm APRD) Similarly, ar(△PQR) = 1/2 ar(||gm PBCR) ar(△PQRS) = ar(△PSR) + △(PQR) = 1/2 ar(||gm APRD) + 1 ... |gm PBCR) = 1/2 ar(||gm ABCD) ⇒ ar(||gm ABCD) = 2 ar(||gm PQRS) = 2 32.5 = 65cm2

If P(-l, 1), Q(3, -4), R(1, -1), S(-2, -3) and T(-4, 4) are plotted on the graph paper, then the point(s) in the fourth quadrant is/are -Maths 9th

Description : If P(-l, 1), Q(3, -4), R(1, -1), S(-2, -3) and T(-4, 4) are plotted on the graph paper, then the point(s) in the fourth quadrant is/are -Maths 9th

Last Answer : (b) In point P (-1, 1), x-coordinate is -1 unit and y-coordinate is 1 unit, so it lies in llnd quadrant. Similarly, we can plot all the points Q (3, -4), R (1, -1), S (-2, -3) and T (-4, 4), It is clear from the graph that points R and Q lie in fourth quadrant.

If P (5,1), Q (8, 0), R(0, 4), S(0, 5) and O(0, 0) are plotted on the graph paper, then the points on the X-axis is/are -Maths 9th

Description : If P (5,1), Q (8, 0), R(0, 4), S(0, 5) and O(0, 0) are plotted on the graph paper, then the points on the X-axis is/are -Maths 9th

Last Answer : (d) We know that, a point lies on X-axis, if its y-coordinate is zero. So, on plotting the given points on graph paper, we get Q and O lie on the X-axis.

Which of the points P(0, 3), Q(l, 0), R(0, – 1), S(-5, 0) and T(1, 2) do not lie on the X-axis ? -Maths 9th

Description : Which of the points P(0, 3), Q(l, 0), R(0, – 1), S(-5, 0) and T(1, 2) do not lie on the X-axis ? -Maths 9th

Last Answer : (c) We know that, if a point is of the form (x, 0)i.e., its y-coordinate is zero, then it will lie on X-axis otherwise not. Here, y-coordinates of points P(0, 3), R (0, -1) and T (1,2) are not zero, so these points do not lie on the X-axis.

Write the coordinates of each of the points P, Q, R, S, T and 0 from the figure . -Maths 9th

Description : Write the coordinates of each of the points P, Q, R, S, T and 0 from the figure . -Maths 9th

Last Answer : Here, points P and S lie in I quadrant so their both coordinates will be positive. Now, perpendicular distance of P from both axes is 1, so coordinates of P are (1, 1). Also, perpendicular distance of S ... 0 is the intersection of both axes, so it is the origin and its coordinates are O (0,0).

Plot the points P(1, 0), Q(4, 0) and 5(1, 3). Find the coordinates of the point R such that PQRS is a square. -Maths 9th

Description : Plot the points P(1, 0), Q(4, 0) and 5(1, 3). Find the coordinates of the point R such that PQRS is a square. -Maths 9th

Last Answer : see the below answer

P, Q, R and S are respectively the mid-points of the sides AB, BC, CD and DA of a quadrilateral ABCD in which AC = BD. -Maths 9th

Description : P, Q, R and S are respectively the mid-points of the sides AB, BC, CD and DA of a quadrilateral ABCD in which AC = BD. -Maths 9th

Last Answer : Given In a quadrilateral ABCD, P, Q, R and S are the mid-points of sides AB, BC, CD and DA, respectively. Also, AC = BD To prove PQRS is a rhombus.

P, Q, R and S are respectively the mid-points of sides AB, BC, CD and DA of quadrilateral ABCD in which AC = BD and AC ⊥ BD. Prove that PQRS is a square. -Maths 9th

Description : P, Q, R and S are respectively the mid-points of sides AB, BC, CD and DA of quadrilateral ABCD in which AC = BD and AC ⊥ BD. Prove that PQRS is a square. -Maths 9th

Last Answer : Given In quadrilateral ABCD, P, Q, R and S are the mid-points of the sides AB, BC, CD and DA, respectively. Also, AC = BD and AC ⊥ BD. To prove PQRS is a square. Proof Now, in ΔADC, S and R are the mid-points of the sides AD and DC respectively, then by mid-point theorem,

If P, Q and R are the mid-points of the sides, BC, CA and AB of a triangle and AD is the perpendicular from A on BC, then prove that P, Q, R and D are concyclic. -Maths 9th

Description : If P, Q and R are the mid-points of the sides, BC, CA and AB of a triangle and AD is the perpendicular from A on BC, then prove that P, Q, R and D are concyclic. -Maths 9th

Last Answer : According to question prove that P, Q, R and D are concyclic.

P is the mid - point of side AB of a parallelogram ABCD. A line through B parallel to PD meets DC at Q and AD produced at R (see figure). -Maths 9th

Description : P is the mid - point of side AB of a parallelogram ABCD. A line through B parallel to PD meets DC at Q and AD produced at R (see figure). -Maths 9th

Last Answer : (i) In △ARB,P is the mid point of AB and PD || BR. ∴ D is a mid - point of AR [converse of mid - point theorem] ∴ AR = 2AD But BC = AD [opp sides of ||gm ABCD] Thus, AR = 2BC (ii) ∴ ABCD is a ... a mid - point of AR and DQ || AB ∴ Q is a mid point of BR [converse of mid - point theorem] ⇒ BR = 2BQ

If P,Q,R,S are respectively the mid - points of the sides of a parallelogram ABCD, if ar(||gm PQRS) = 32.5cm2 , then find ar(||gm ABCD). -Maths 9th

Description : If P,Q,R,S are respectively the mid - points of the sides of a parallelogram ABCD, if ar(||gm PQRS) = 32.5cm2 , then find ar(||gm ABCD). -Maths 9th

Last Answer : Join PR. ∵ △PSR and ||gm APRD are on the same base and between same parallel lines. ar(△PSR) = 1/2 ar(||gm APRD) Similarly, ar(△PQR) = 1/2 ar(||gm PBCR) ar(△PQRS) = ar(△PSR) + △(PQR) = 1/2 ar(||gm APRD) + 1 ... |gm PBCR) = 1/2 ar(||gm ABCD) ⇒ ar(||gm ABCD) = 2 ar(||gm PQRS) = 2 32.5 = 65cm2

If P(-l, 1), Q(3, -4), R(1, -1), S(-2, -3) and T(-4, 4) are plotted on the graph paper, then the point(s) in the fourth quadrant is/are -Maths 9th

Description : If P(-l, 1), Q(3, -4), R(1, -1), S(-2, -3) and T(-4, 4) are plotted on the graph paper, then the point(s) in the fourth quadrant is/are -Maths 9th

Last Answer : (b) In point P (-1, 1), x-coordinate is -1 unit and y-coordinate is 1 unit, so it lies in llnd quadrant. Similarly, we can plot all the points Q (3, -4), R (1, -1), S (-2, -3) and T (-4, 4), It is clear from the graph that points R and Q lie in fourth quadrant.

If P (5,1), Q (8, 0), R(0, 4), S(0, 5) and O(0, 0) are plotted on the graph paper, then the points on the X-axis is/are -Maths 9th

Description : If P (5,1), Q (8, 0), R(0, 4), S(0, 5) and O(0, 0) are plotted on the graph paper, then the points on the X-axis is/are -Maths 9th

Last Answer : (d) We know that, a point lies on X-axis, if its y-coordinate is zero. So, on plotting the given points on graph paper, we get Q and O lie on the X-axis.

Which of the points P(0, 3), Q(l, 0), R(0, – 1), S(-5, 0) and T(1, 2) do not lie on the X-axis ? -Maths 9th

Description : Which of the points P(0, 3), Q(l, 0), R(0, – 1), S(-5, 0) and T(1, 2) do not lie on the X-axis ? -Maths 9th

Last Answer : (c) We know that, if a point is of the form (x, 0)i.e., its y-coordinate is zero, then it will lie on X-axis otherwise not. Here, y-coordinates of points P(0, 3), R (0, -1) and T (1,2) are not zero, so these points do not lie on the X-axis.

Write the coordinates of each of the points P, Q, R, S, T and 0 from the figure . -Maths 9th

Description : Write the coordinates of each of the points P, Q, R, S, T and 0 from the figure . -Maths 9th

Last Answer : Here, points P and S lie in I quadrant so their both coordinates will be positive. Now, perpendicular distance of P from both axes is 1, so coordinates of P are (1, 1). Also, perpendicular distance of S ... 0 is the intersection of both axes, so it is the origin and its coordinates are O (0,0).

Plot the points P(1, 0), Q(4, 0) and 5(1, 3). Find the coordinates of the point R such that PQRS is a square. -Maths 9th

Description : Plot the points P(1, 0), Q(4, 0) and 5(1, 3). Find the coordinates of the point R such that PQRS is a square. -Maths 9th

Last Answer : see the below answer

P, Q, R and S are respectively the mid-points of the sides AB, BC, CD and DA of a quadrilateral ABCD in which AC = BD. -Maths 9th

Description : P, Q, R and S are respectively the mid-points of the sides AB, BC, CD and DA of a quadrilateral ABCD in which AC = BD. -Maths 9th

Last Answer : Given In a quadrilateral ABCD, P, Q, R and S are the mid-points of sides AB, BC, CD and DA, respectively. Also, AC = BD To prove PQRS is a rhombus.

P, Q, R and S are respectively the mid-points of sides AB, BC, CD and DA of quadrilateral ABCD in which AC = BD and AC ⊥ BD. Prove that PQRS is a square. -Maths 9th

Description : P, Q, R and S are respectively the mid-points of sides AB, BC, CD and DA of quadrilateral ABCD in which AC = BD and AC ⊥ BD. Prove that PQRS is a square. -Maths 9th

Last Answer : Given In quadrilateral ABCD, P, Q, R and S are the mid-points of the sides AB, BC, CD and DA, respectively. Also, AC = BD and AC ⊥ BD. To prove PQRS is a square. Proof Now, in ΔADC, S and R are the mid-points of the sides AD and DC respectively, then by mid-point theorem,

If P, Q and R are the mid-points of the sides, BC, CA and AB of a triangle and AD is the perpendicular from A on BC, then prove that P, Q, R and D are concyclic. -Maths 9th

Description : If P, Q and R are the mid-points of the sides, BC, CA and AB of a triangle and AD is the perpendicular from A on BC, then prove that P, Q, R and D are concyclic. -Maths 9th

Last Answer : According to question prove that P, Q, R and D are concyclic.

If P, Q and R are three points on a line and Q is between P and R,then prove that PR - QR= PQ. -Maths 9th

Description : If P, Q and R are three points on a line and Q is between P and R,then prove that PR - QR= PQ. -Maths 9th

Last Answer : Solution :-

ABCD is a parallelogram in which P and Q are the mid-points of opposite sides AB and CD (Fig. 8.48). If AQ intersects DP at S and BQ intersects CP at R, show that -Maths 9th

Description : ABCD is a parallelogram in which P and Q are the mid-points of opposite sides AB and CD (Fig. 8.48). If AQ intersects DP at S and BQ intersects CP at R, show that -Maths 9th

Last Answer : Solution :-

AB and AC are two chords of a circle of radius r such that AB = 2AC. If p and q are the distances of AB and AC from the centre. Prove that -Maths 9th

Description : AB and AC are two chords of a circle of radius r such that AB = 2AC. If p and q are the distances of AB and AC from the centre. Prove that -Maths 9th

Last Answer : Draw OM perpendicular AB and ON perpendicular AC Join OA. In right △OAM, OA2 = OM2 + AM2 ⇒ r2 = p2 + (1/2AB)2 (Since,OM perpendicular AB, ∴ OM bisects AB ) ⇒ 1/4AB2 = r2 - p2 or AB2 = 4r2 - 4p2 ... ) and (ii), we have 4r2 - 4p2 = 16r2 - 16q2 or r2 - p2 = 4r2 - 4q2 or 4q2 = 3r2 + p2

ABCD is a rectangle and p q r s are the mid points of the side AB BC CD AND DA respectively. Show that the quadrilateral PQRS is a rhombus -Maths 9th

Description : ABCD is a rectangle and p q r s are the mid points of the side AB BC CD AND DA respectively. Show that the quadrilateral PQRS is a rhombus -Maths 9th

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