Description : Solve the following inequlities `(i) sqrt(x-1) lt x-3` `(ii) sqrt(x-3) gt sqrt(7-x)` `(iii) sqrt (x^(2)+4x+9) gt x +2` `(iv) 4-x lt sqrt(2x-x^(2))` `(
Last Answer : Solve the following inequlities `(i) sqrt(x-1) lt x-3` `(ii) sqrt(x-3) gt sqrt(7-x)` `(iii) sqrt (x^(2)+4x+ ... (ix) (|x+2|-|x|)/(sqrt(8-x^(3))) ge 0`
Description : Solve the following in equalities `(i) |x+7| gt 5` `(ii) |x+3| lt 10` `(iii) (x+2) lt |x^(2)+3x+5|``(iv) |(2x-1)/(x-1)| gt 2` `(v) |x-6| le x^(2)-5x+9
Last Answer : Solve the following in equalities `(i) |x+7| gt 5` `(ii) |x+3| lt 10` `(iii) (x+2) lt |x^(2)+3x+5|``(iv) ... -5) lt 0` `(viii) |x-1|+|x-2|+|x-3| le 6`
Description : Solve the equation 2x + 1 = x -3, and represent the solution(s) on (i) the number line. (ii) the Cartesian plane. -Maths 9th
Last Answer : Solution :-
Description : Solve for x: Sol. 3x/7 + 2/7 + 4(x + 1)/5 = 2/3(2x + 1) -Maths 9th
Description : Solve for `x` (where `[*]` denotes greatest integer function and `{*}` represent fractional part function) `(i) [2x]=1` `(ii) {x}^(2)+[x]=2` `(iii) 6{
Last Answer : Solve for `x` (where `[*]` denotes greatest integer function and `{*}` represent fractional part function) `(i) [2x]=1 ... 0` `(iv) 6{x}^(2)-5{x}-1=0`
Description : Solve the following equations `(i) sgn({[x]})=0` `(ii) sgn(x^(2)-2x-8)=-1` `(iii)sgn((x^(2)-5x+4)/({x}))=-1`
Last Answer : Solve the following equations `(i) sgn({[x]})=0` `(ii) sgn(x^(2)-2x-8)=-1` `(iii)sgn((x^(2)-5x+4)/({x}))=-1`
Description : Solve the following equations : `(i) log_(x)(4x-3)=2` `(ii) log_2)(x-1)+log_(2)(x-3)=3` `(iii) log_(2)(log_(8)(x^(2)-1))=0` `(iv) 4^(log_(2)x)-2x-3=0`
Last Answer : Solve the following equations : `(i) log_(x)(4x-3)=2` `(ii) log_2)(x-1)+log_(2)(x-3)=3` `(iii) log_(2)(log_(8)(x^(2)-1))=0` `(iv) 4^(log_(2)x)-2x-3=0`
Description : Solve for `x` `(i) 2^(|x+1|)+2^(|x|)=6` and `x in I` `(ii) x^(2)+x+1+|x-3| le |x^(2)+2x-2|` `(iii) |2x-4|-2|x^(2)+x-3|+2|x-1||x+1|=0`
Last Answer : Solve for `x` `(i) 2^(|x+1|)+2^(|x|)=6` and `x in I` `(ii) x^(2)+x+1+|x-3| le |x^(2)+2x-2|` `(iii) |2x-4|-2|x^(2)+x-3|+2|x-1||x+1|=0`
Description : Solve for `x` `(i) |x+1|=4x+3` `(ii) |x+1|=|x+3|` `(iii) 7|x-2|-|x-7|=5` `(iv) ||x-1|-2|=6x+8` `(v) |2x^(2)-3x+1|=|x^(2)+x-3|`
Last Answer : Solve for `x` `(i) |x+1|=4x+3` `(ii) |x+1|=|x+3|` `(iii) 7|x-2|-|x-7|=5` `(iv) ||x-1|-2|=6x+8` `(v) |2x^(2)-3x+1|=|x^(2)+x-3|`
Description : Solve : `2x - 5 gt 4x - 3`
Last Answer : Solve : `2x - 5 gt 4x - 3`
Description : If x +1 is a factor of ax3 +x2 -2x + 4a - 9, then find the value of a. -Maths 9th
Last Answer : The value of a
Description : If (x+1) is a factor of ax(cube) + x(square) - 2x + 4a - 9,find the value of a. -Maths 9th
Last Answer : solution :-
Description : If the HCF of (x^2 + x – 12) and (2x^2 – kx – 9) is (x – k), then what is the value of k ? -Maths 9th
Last Answer : answer:
Description : If `(x^(2)-2|x|)(|2x|-2)-9((2|x|-2)/(x^(2)-2|x|)) le0` then
Last Answer : If `(x^(2)-2|x|)(|2x|-2)-9((2|x|-2)/(x^(2)-2|x|)) le0` then A. `x in (-oo,-1]uu(0,1]uu(2,3]` B. ` ... (-oo,3]` D. `x in [-3,-2)uu[-1,0)uu(0,1]uu(2,3]`
Description : The area of the triangular region, in the following figure, bounded by the lines 2x-y=1 and x+2y=13 and Y-axis is (a) 11.25 sq.units (b) 9.75 sq.units (c) 16.25 sq,units (d) 18.75 sq.units
Last Answer : (a) 11.25 sq.units
Description : how do i solve 4x-9=k for x?
Last Answer : 4x-9=k4x=k+9Divide by 4 to isolate the xx=(1/4)k+(9/4)x=1/4 k+ 9/4
Description : Solve the following inequalities `(i) |log_(3)x|-log_(3)x-3 lt 0` `(ii)(x-1)/(log_(3)(9-3^(x))-3) le 1` `(iii)log_((x-1)/(x-5))(x-2) gt 0` `(iv) log_(
Last Answer : Solve the following inequalities `(i) |log_(3)x|-log_(3)x-3 lt 0` `(ii)(x-1)/(log_(3)(9-3^(x))-3) le 1` ... gt 0` `(iv) log_(x)(x^(3)-x^(2)-2x) lt 3`
Description : Solve the following equations `(i) (log_(2)(9-2^(x)))/(3-x)=1` `(ii) x^((log_(10)x+7)/(4))=10^((log_(10)x+1)` `(iii) (log_(10)(100x))^(2)+(log_(10)(10
Last Answer : Solve the following equations `(i) (log_(2)(9-2^(x)))/(3-x)=1` `(ii) x^((log_(10)x+7)/(4))=10^((log_(10)x+1 ... 1)` `(v)5^(2x)=3^(2x)+2.5^(x)+2.3^(x)`
Description : Solve the following rational in equalities `(i) ((x-1)(x+2))/((x-3)(x+3)) lt 0` `(ii) ((1-x)^(3)(x+2)^(4))/((x+9)^(2)(x-8))ge0` `(iii) ((x^(2)-3x+1)^(
Last Answer : Solve the following rational in equalities `(i) ((x-1)(x+2))/((x-3)(x+3)) lt 0` `(ii) ((1-x)^(3)(x+2)^(4 ... ` `(vi) 1 lt (3x^(2)-7x+8)/(x^(2)+1) le2`
Description : Solve, `(x)/(3) + (x)/(6) + (x)/(9) = 11`
Last Answer : Solve, `(x)/(3) + (x)/(6) + (x)/(9) = 11`
Description : Solve for x and y: 1/x - 1/y = 1/3, 1/x2 + 1/y2 = 5/9.
Last Answer : Answer: x = 3/2 or -3 and y = 3 or -3/2.
Description : graph of 2x+9=0 in one variable -Maths 9th
Last Answer : 2x+9=0 2x=-9 x=-9/2 x=-4.5
Description : Any solution of the linear equation 2x + 0y + 9 = 0 in two variables is of the form -Maths 9th
Last Answer : (a) The given linear equation is 2x + 0y + 9 = 0 ⇒ 2x + 9 = 0 ⇒ 2x = -9 ⇒ x= - 9/2 and y can be any real number. Hence, (-9/2 , m) is the required form of solution of the given linear equation.
Description : At what point does the graph of the linear equation 2x + 3y = 9 meet a line which is parallel to the y-axis, at a distance of 4 units from the origin and on the right of the y-axis? -Maths 9th
Last Answer : hope its clear
Description : Simplify (9-4x^ 2 +2x^ 2 +8x^ 2 +1+6x^ 2?
Last Answer : 12x^2+10
Description : If `(2x-9)` is a factor of `2x^(2) + px - 9`, then `p = "_____"`.
Last Answer : If `(2x-9)` is a factor of `2x^(2) + px - 9`, then `p = "_____"`.
Description : If `5(tan^2x - cos^2x)=2cos 2x + 9`, then the value of cos4x is
Last Answer : If `5(tan^2x - cos^2x)=2cos 2x + 9`, then the value of cos4x is A. `(-3)/(5)` B. `(1)/(3)` C. `(2)/(9)` D. `-(7)/(9)`
Description : What is 2x plus 1x plus 9?
Last Answer : They are terms of an algebraic expression that can be simplifiedto: 3x+9 or factored to 3(x+3)
Description : One equation of a pair of dependent linear equation is -2x + 3y = 9 , the second equation can be e) 4x + 6y = 18 f) 4x - 6y = - 18 g) -4x – 6y = 18 h) None of these
Last Answer : f) 4x - 6y = - 18
Description : One equation of a pair of dependent linear equation is -2x + 3y = 9 , the second equation can be a) 4x + 6y = 18 b) 4x - 6y = - 18 c) -4x – 6y = 18 d) None of these
Last Answer : b) 4x - 6y = - 18
Description : Find the charge density when the electric flux density is given by 2x i + 3y j + 4z k. a) 10 b) 9 c) 24 d) 0
Last Answer : b) 9
Description : A rich man in Arabia died, leaving a note for his three sons. It reads: 'I have 17 camels. The big brother can get a half of all, the middle can get third of all, and the youngest can get a ... 17 cannot be divided by 2, 3 or 9 without anything left. How can the brothers solve the problem? -Riddles
Last Answer : 1. Borrow a camel from their neighbour to make 18 camels. 2. The big brother takes a half of it, so he takes 9. 3. The second brother takes a third of it, so he takes 6. 4. The youngest ... so he takes 2. 5. All the camels that the brothers took add up to 17, leaving the camel they borrowed!
Description : Solve log2x + 3 (6x^2 + 23x + 21) = 4 – log3x + 7 (4x^2 + 12x + 9). -Maths 9th
Description : http://www.hack-test.com
Last Answer : Here's how: http://blog.abhishekg.com/2012/01/level-9-where-is-the-password/?i=1
Description : Solve : `2m + 5 gt 9 - 4m, m in Q`
Last Answer : Solve : `2m + 5 gt 9 - 4m, m in Q`
Description : Solve : `0.3 (3y -4.5) + 2.9 (5.5 -5y) = 1`
Last Answer : Solve : `0.3 (3y -4.5) + 2.9 (5.5 -5y) = 1`
Description : How do you solve 5n6n plus 9?
Last Answer : Without an equality sign the given expression is not an equationand so therefore a solution is not possible.
Description : If each side of an equilateral triangle is 9 cm and you must find the height how would you solve in pythagorean theorem?
Last Answer : Divide the base in half and draw the median from the apex. Thismedian is also the altitude and so its length is the requiredheight. Also, since it is the altitude, it forms a right angledtriangle. Using Pythagoras on this triangle, the height is9*sqrt(3)/2.
Description : How do you solve 3.5 -0.9?
Last Answer : 4.4
Description : how do you solve h/9-19 = -10?
Last Answer : h is equal to 1 in that equation.
Description : How do i solve this Find three consecutive odd integers so that three times the second is 9 more than twice the third. What is the smallest number?
Last Answer : Yeah, I hate these too. Identify the unknowns. Three consecutive odd integers will be x, x + 2 and x + 4 Set up the equation with the information you know. Three times the second is 3 times (x + 2) ... Since 39 is 9 more than 30, we got it right. The answer asked for (the smallest integer) is 11.