Solve, `(x)/(3) + (x)/(6) + (x)/(9) = 11`

Solve, `(x)/(3) + (x)/(6) + (x)/(9) = 11`
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Solve, `(x)/(3) + (x)/(6) + (x)/(9) = 11`
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Description : Solve the following in equalities `(i) |x+7| gt 5` `(ii) |x+3| lt 10` `(iii) (x+2) lt |x^(2)+3x+5|``(iv) |(2x-1)/(x-1)| gt 2` `(v) |x-6| le x^(2)-5x+9

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Last Answer : An easy way to solve this question is use x = 3, y=4 7x – 4y = 21 – 16 = 5 3x + y = 9+4 = 13 Required ratio = 5:13 Answer: c)

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Description : Let P = {2, 3, 4, 5, 6, 7}. Insert the correct symbol inside the given blank spaces below: (a). 2 . . . . . . . . . . P (b). 9 . . . . . . . . . P (c). 11 . . . . . . . . P (d). 4 . . . . . . . . P (e). 0 . . . . . . . . P (f). 7 . . . . . . . . P -Do You Know?

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Description : Calculate the radius of the first and second orbit of sodium atom `(Z=11)`. `(h=6.6xx10^(-34) J s, e=1.6xx10^(-19) C` and `m=9.1xx10^(-31) kg.)`

Last Answer : Calculate the radius of the first and second orbit of sodium atom `(Z=11)`. `(h=6.6xx10^(-34) J s, e=1.6xx10^(-19) C` and `m=9.1xx10^(-31) kg.)`

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Description : Serum magnesium level ranges between (A) 2–3 mg/dl (B) 3–5 mg/dl (C) 6–8 mg/dl (D) 9–11 mg/dl

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Description : The value of the universal gravitational constant, G is (a) 6.67 × 1011 Nm2/kg2 (b) 6.67 × 10+9 Nm2/kg2 (c) 6.67 × 10–9 Nm2/kg2 (d) 6.67 × 10–11 Nm2/kg2

Last Answer : Ans:(d)

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Description : Out of 24 hours the human heart works, ventricles contact for (a) 6 hours (b) 9 hours (c) 11 hours (d) 12 hours

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Description : Force per meter on two wires carrying a current of 1 A placed 1 m apart is equal to A. 6.7 × 10-11 N B. 9.0 × 109 N C. 2.0 × 10-7 N D. 3.0 × 10-4 N

Last Answer :  2.0 × 10-7 N

In India, which one of the following should be considered the right combination of the age in days and live body weight in kg for a lamb for its weaning ? (A) 20 days to 30 days and 6 kg to 7 kg (B) 45 days to 60 days and 8 kg to 10 kg (C) 105 days to 120 days and 18 kg to 21 kg (D) 75 days to 90 days and 12 kg to 15 kg (E) 55 days to 70 days and 9 kg to 11 kg

Description : In India, which one of the following should be considered the right combination of the age in days and live body weight in kg for a lamb for its weaning ? (A) 20 days to 30 days and 6 kg to 7 kg (B) 45 days to 60 ... (D) 75 days to 90 days and 12 kg to 15 kg (E) 55 days to 70 days and 9 kg to 11 kg

Last Answer : (C) 105 days to 120 days and 18 kg to 21 kg

What is the ideal pH range for Pluses? a. 6.0-8.5 b. 2. 5 to 6 c. 3. 9 to 11 d. 4. 9 t0 12

Description : What is the ideal pH range for Pluses? a. 6.0-8.5 b. 2. 5 to 6 c. 3. 9 to 11 d. 4. 9 t0 12

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Description : For high flood estimates the average value of the constant C in Dicken's formula Q =CA3/4, is (A) 6.5 (B) 8.5 (C) 9.5 (D) 11.5

Last Answer : Answer: Option D

A,B and C can do piece of work in 11 days,20 days and 55 days respectively, working alone. How soon can the work be done if a is assisted by B and C on alternate days/ a) 6 b) 7 c) 8 d) 9 e) 10

Description : A,B and C can do piece of work in 11 days,20 days and 55 days respectively, working alone. How soon can the work be done if a is assisted by B and C on alternate days/ a) 6 b) 7 c) 8 d) 9 e) 10

Last Answer : Work done by A and B in one day = 1/11 + 1/20 =31/220 Work done by A and C in one day = 1/11 + 1/55 =6/55 Work done in 2 days = 31 /220+6/55=55/220 = ¼ Hence, 1/4 of the work is done in 2 days Hence, it takes 8 days to finish the work Answer : c

A,B and C can do piece of work in 11 days,20 days and 55 days respectively, working alone. How soon can the work be done if a is assisted by B and C on alternate days/ a) 6 b) 7 c) 8 d) 9 e) 10

Description : A,B and C can do piece of work in 11 days,20 days and 55 days respectively, working alone. How soon can the work be done if a is assisted by B and C on alternate days/ a) 6 b) 7 c) 8 d) 9 e) 10

Last Answer : Work done by A and B in one day = 1/11 + 1/20 =31/220 Work done by A and C in one day = 1/11 + 1/55 =6/55 Work done in 2 days = 31 /220+6/55=55/220 = ¼ Hence, 1/4 of the work is done in 2 days Hence, it takes 8 days to finish the work Answer : c

The rainfall on five successive days on a catchment was 3, 6, 9, 5 and 1 cm respectively. If the  -index for the storm can be assumed to be 3 cm/day, the total direct runoff from the catchment due to this storm is (a) 11 cm (b) 24 cm (c) 9 cm (d) 20 cm

Description : The rainfall on five successive days on a catchment was 3, 6, 9, 5 and 1 cm respectively. If the  -index for the storm can be assumed to be 3 cm/day, the total direct runoff from the catchment due to this storm is (a) 11 cm (b) 24 cm (c) 9 cm (d) 20 cm

Last Answer : (a) 11 cm

In a pressure penstock 4500 m long, water is flowing at a velocity of 4 m/s. If the velocity of the pressure wave traveling in the pipe, due sudden complete closure of a valve at the downstream end, is given as 1500 m/s, what would be the period of oscillation in second under frictionless conditions? (a) 6 (b) 8 (c) 9 (d) 11

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Last Answer : (a) 6

What is the output of the following? i = 1 while True: if i%2 == 0: break print(i) i += 2 a) 1 Page No 13 b) 1 2 c) 1 2 3 4 5 6 … d) 1 3 5 7 9 11 …

Description : What is the output of the following? i = 1 while True: if i%2 == 0: break print(i) i += 2 a) 1 Page No 13 b) 1 2 c) 1 2 3 4 5 6 … d) 1 3 5 7 9 11 …

Last Answer : d) 1 3 5 7 9 11 …

What is the output of the following? i = 5 while True: if i%0O9 == 0: break print(i) i += 1 a) 5 6 7 8 b) 5 6 7 8 9 c) 5 6 7 8 9 10 11 12 13 14 15 …. d) error

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Last Answer : d) error

How many lanes are there in a standard track? (a) 6 to 9 (b) 8 to 9 (c) 10 to 12 (d) 11 to 13

Description : How many lanes are there in a standard track? (a) 6 to 9 (b) 8 to 9 (c) 10 to 12 (d) 11 to 13

Last Answer : (a) 6 to 9

Four pipes can fill a reservoir in 15, 20, 30 and 60 hours respectively. The first one was opened at 6 AM, second at 7 AM, thir da t 8 AM and the fourth at 9 AM. When will the reservoir be filled ? (A) 11 AM (B) 12 Noon (C) 1 PM (D) 1:30 PM

Description : Four pipes can fill a reservoir in 15, 20, 30 and 60 hours respectively. The first one was opened at 6 AM, second at 7 AM, thir da t 8 AM and the fourth at 9 AM. When will the reservoir be filled ? (A) 11 AM (B) 12 Noon (C) 1 PM (D) 1:30 PM

Last Answer : Answer: C

Suppose that the virtual Address space has eight pages and physical memory with four page frames. If LRU page replacement algorithm is used, .............. number of page faults occur with the reference string. 0 2 1 3 5 4 6 3 7 4 7 3 3 5 5 3 1 1 1 7 2 3 4 1 (A) 11 (B) 12 (C) 10 (D) 9

Description : Suppose that the virtual Address space has eight pages and physical memory with four page frames. If LRU page replacement algorithm is used, .............. number of page faults occur with the reference string. 0 2 1 3 5 4 6 3 7 4 7 3 3 5 5 3 1 1 1 7 2 3 4 1 (A) 11 (B) 12 (C) 10 (D) 9

Last Answer : (A) 11

Siva leaves chennai at 3 am and reaches Hyderabad at 11 am . Anirudh leaves Hyderabad at 5 am and reaches chennai at 12:00 noon. At what time do they cross each other? a) 7 : 52am b) 8 : 25am c) 6 : 52am d) 9 : 25am

Description : Siva leaves chennai at 3 am and reaches Hyderabad at 11 am . Anirudh leaves Hyderabad at 5 am and reaches chennai at 12:00 noon. At what time do they cross each other? a) 7 : 52am b) 8 : 25am c) 6 : 52am d) 9 : 25am

Last Answer : C Time taken by Siva = 8 h Time taken by Anirudh = 7 h For your convenience take the product of times taken by both as a distance. Then the distance = 56km Since, Siva covers half of the distance in 2 ... by them = 28/15 = 1 hr 52 min Thus , they will cross each other at 6 : 52am.

The ratio between the present ages of M and N is 8:9. If N is 6 years old than M, what will be the ratio of the ages of M and N after 6 years a) 9:10 b) 7:9 c) 9:8 d) 11:10

Description : The ratio between the present ages of M and N is 8:9. If N is 6 years old than M, what will be the ratio of the ages of M and N after 6 years a) 9:10 b) 7:9 c) 9:8 d) 11:10

Last Answer : A Let M age and N age be 8x years and 9x years. Then 9x - 8x = 6 <=> x = 6 So required ratio will be (8x+6): (9x+6) 54:60 9:10

Two vessels contains equal quantity of solution contains milk and water in the ratio of 7:2 and 4:5 respectively. Now the solutions are mixed with each other then find the ratio of milk and water in the final solution? A) 11:7 B) 11:6 C) 11:5 D) 11:9 E) None of these

Description : Two vessels contains equal quantity of solution contains milk and water in the ratio of 7:2 and 4:5 respectively. Now the solutions are mixed with each other then find the ratio of milk and water in the final solution? A) 11:7 B) 11:6 C) 11:5 D) 11:9 E) None of these

Last Answer : Answer: A milk = 7/9 and water = 2/9 – in 1st vessel milk = 4/9 and water = 5/9 – in 2nd vessel (7/9 + 4/9)/ (2/9 + 5/9) = 11:7

Three friends A, B and C started a business by investing a sum of money in the ratio of 5 : 7 : 6. After 6 months C withdraws half of his capital. If the sum invested by ‘A’ is Rs 40,000, out of a total annual profit of Rs 33,000, C’s share will be a) Rs 9,000 b) Rs 12,000 c) Rs 11,000 d) Rs 10,000 e) None of these

Description : Three friends A, B and C started a business by investing a sum of money in the ratio of 5 : 7 : 6. After 6 months C withdraws half of his capital. If the sum invested by A' is Rs 40,000, out of a total annual ... share will be a) Rs 9,000 b) Rs 12,000 c) Rs 11,000 d) Rs 10,000 e) None of these

Last Answer : Answer: A Sum invested by A , B and C is 5 * 12:7 * 12:6 * 6 + 3 * 6 or 60 : 84 : 54 or 10 : 14 : 9 :: Share of C = ( 9 / 33 ) * 33000 = Rs. 9000

Ravi and kavi are partners in a business. Ravi contributes 3/7th of the total capital for 20 months and kavi received 3/4 th of the profit. Then how long kavi invest the money in the business? A) 5 B) 11 C) 6 D) 9

Description : Ravi and kavi are partners in a business. Ravi contributes 3/7th of the total capital for 20 months and kavi received 3/4 th of the profit. Then how long kavi invest the money in the business? A) 5 B) 11 C) 6 D) 9

Last Answer : Answer: A)  Total profit be X  kavi’s profit is 3/4x  Ravi’s profit is 1/4x Ratio of ravi & kavi profit =3/4 x: 1/4x=3:1  Let Ravi's investment =3/7 *P(for 20 months then, kavi’s investment =4/7 P)  Ratio of ravi & kavi  Profit =3:1=3/7*P*20 :4/7*p*T  T=5 months= kavi investment time

The average of 12 numbers is 7.9. The average of 5 of them is 6.8, while the average of other five is 7.7. what is the average of the remaining 2 numbers? A) 10.25 B) 11.15 C) 12.65 D) 13.25

Description : The average of 12 numbers is 7.9. The average of 5 of them is 6.8, while the average of other five is 7.7. what is the average of the remaining 2 numbers? A) 10.25 B) 11.15 C) 12.65 D) 13.25

Last Answer : B) Sum of the remaining 2 numbers = [(12 * 7.9) – (586.8) – (5*7.7)]  = 94.8 – 34 – 38.5  = 22.3  Required average = 22.3 / 2  = 11.15

There are 2 vessels. 1st vessel contains 5white and 5 blue thread roll. 2nd vessel contains 4 white and 6 black thread roll. One roll is taken at random from first vessel and put to second vessel without noticing its color. Now a roll is chosen at random from 2nd vessel. What is the probability of the second roll being a white colored roll? A) 11/13 B) 9/11 C) 13/11 D) 5/12

Description : There are 2 vessels. 1st vessel contains 5white and 5 blue thread roll. 2nd vessel contains 4 white and 6 black thread roll. One roll is taken at random from first vessel and put to second vessel without noticing its color ... second roll being a white colored roll? A) 11/13 B) 9/11 C) 13/11 D) 5/12

Last Answer : Answer: B) Case 1: first was a white roll Now it is put in second vessel, so total white rolls in second vessel = 4+1 = 5, and total rolls in second vessel = 10+1 = 11 So probability of white roll ... = 5/11+4/11 = 9/11 (added the cases because we want one of these cases to happen and not both)

A rich man in Arabia died, leaving a note for his three sons. It reads: 'I have 17 camels. The big brother can get a half of all, the middle can get third of all, and the youngest can get a ninth of all.' The brothers are left dumbfounded, since 17 cannot be divided by 2, 3 or 9 without anything left. How can the brothers solve the problem? -Riddles

Description : A rich man in Arabia died, leaving a note for his three sons. It reads: 'I have 17 camels. The big brother can get a half of all, the middle can get third of all, and the youngest can get a ... 17 cannot be divided by 2, 3 or 9 without anything left. How can the brothers solve the problem? -Riddles

Last Answer : 1. Borrow a camel from their neighbour to make 18 camels. 2. The big brother takes a half of it, so he takes 9. 3. The second brother takes a third of it, so he takes 6. 4. The youngest ... so he takes 2. 5. All the camels that the brothers took add up to 17, leaving the camel they borrowed!

Solve log2x + 3 (6x^2 + 23x + 21) = 4 – log3x + 7 (4x^2 + 12x + 9). -Maths 9th

Description : Solve log2x + 3 (6x^2 + 23x + 21) = 4 – log3x + 7 (4x^2 + 12x + 9). -Maths 9th

Last Answer : answer:

How to solve Level 9 of http://www.hack-test.com?

Description : http://www.hack-test.com 

Last Answer : Here's how: http://blog.abhishekg.com/2012/01/level-9-where-is-the-password/?i=1