Solve for `x` `(i) 2^(|x+1|)+2^(|x|)=6` and `x in I` `(ii) x^(2)+x+1+|x-3| le |x^(2)+2x-2|` `(iii) |2x-4|-2|x^(2)+x-3|+2|x-1||x+1|=0`

Solve for `x` `(i) 2^(|x+1|)+2^(|x|)=6` and `x in I` `(ii) x^(2)+x+1+|x-3| le |x^(2)+2x-2|` `(iii) |2x-4|-2|x^(2)+x-3|+2|x-1||x+1|=0`
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Solve for `x` `(i) 2^(|x+1|)+2^(|x|)=6` and `x in I` `(ii) x^(2)+x+1+|x-3| le |x^(2)+2x-2|` `(iii) |2x-4|-2|x^(2)+x-3|+2|x-1||x+1|=0`
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Last Answer : a) 0.531i – 0.6373j – 0.177k

`(i) int " x sec"^(2) " 2x dx "" "(ii) int " x sin"^(3) " x dx "`

Description : `(i) int " x sec"^(2) " 2x dx "" "(ii) int " x sin"^(3) " x dx "`

Last Answer : `(i) int " x sec"^(2) " 2x dx "" "(ii) int " x sin"^(3) " x dx "`

Evaluate: (i) `int(sinx)/(1+cos^2x) dx` (ii) `int(2x^3)/(4+x^8) dx`

Description : Evaluate: (i) `int(sinx)/(1+cos^2x) dx` (ii) `int(2x^3)/(4+x^8) dx`

Last Answer : Evaluate: (i) `int(sinx)/(1+cos^2x) dx` (ii) `int(2x^3)/(4+x^8) dx`

`(i) int sin 2x. cos5x dx " "(ii) int(sin 4x)/(sin x) dx`

Description : `(i) int sin 2x. cos5x dx " "(ii) int(sin 4x)/(sin x) dx`

Last Answer : `(i) int sin 2x. cos5x dx " "(ii) int(sin 4x)/(sin x) dx`

Find the equation of tangents of the following curves at the given points: (i) Curve`x^(2) = 25` at point (3, 4) (ii) Curve `y = 2x^(3) + 2x^(2) - 8x+

Description : Find the equation of tangents of the following curves at the given points: (i) Curve`x^(2) = 25` at point (3, 4) (ii) Curve `y = 2x^(3) + 2x^(2) - 8x+

Last Answer : Find the equation of tangents of the following curves at the given points: (i) Curve`x^(2) = 25` at point (3, 4) ... 2)(x-1) = 4x^(2)` at point (5, 5)

Find the intervals in which the following functions are: (i) increasing (ii) decreasing. (a) `f(x) = 10-6x+x^(2)` (b) `f(x) = 2x^(2)-6x` (c) `f(x) = 2

Description : Find the intervals in which the following functions are: (i) increasing (ii) decreasing. (a) `f(x) = 10-6x+x^(2)` (b) `f(x) = 2x^(2)-6x` (c) `f(x) = 2

Last Answer : Find the intervals in which the following functions are: (i) increasing (ii) decreasing. (a) `f(x) = 10-6x+x^(2)` (b ... ) `f(x) = (x+2)^(3)(x-3)^(3)`

Two students A and B solve an equation of the form x^2 + px + q = 0. A starts with a wrong value of p and obtains the roots as 2 and 6. -Maths 9th

Description : Two students A and B solve an equation of the form x^2 + px + q = 0. A starts with a wrong value of p and obtains the roots as 2 and 6. -Maths 9th

Last Answer : Let αα and ββ be the roots of the quadratic equation x2+px+q=0x2+px+q=0 Given that, A starts with a wrong value of p and obtains the roots as 2 and 6. But this time q is correct. i.e., a product of roots ... 1 Now, from Eqs. (ii) and (iii), we get α=−3 and β=−4α=−3 and β=−4 which are correct roots.

Portmanteaux le slogan publicitaire? Can you come up with a portmanteau for an advertisement slogan?

Description : Portmanteaux le slogan publicitaire? Can you come up with a portmanteau for an advertisement slogan?

Last Answer : answer:Nightclubs – Noiseating Spam – Canvenient Pringles – Fatisfying . Can’t believe no one’s contributed to this yet. The potential answers are so not lame at all!

Anyone know what kind of coffee they serve at Le Pain Quotidienne? What kind of beans? French press?

Description : Anyone know what kind of coffee they serve at Le Pain Quotidienne? What kind of beans? French press?

Last Answer : (Shouldn’t that be Le Pain Quotidien?) And is it a chain or can you tell us the location?