In the following figure, if `/_ AOB =60^(@)` then `/_ ACB=30^(@)`. [True `//` False `//` Cannot say ]

In the following figure, if `/_ AOB =60^(@)` then `/_ ACB=30^(@)`. [True `//` False `//` Cannot say ]
by

1 Answer

Answer :

In the following figure, if `/_ AOB =60^(@)` then `/_ ACB=30^(@)`. [True `//` False `//` Cannot say ]
by
selected by

Related questions

In the figure (not to scale ), O is the centre of the circle and `/_OBA=30^(@)`. Find `/_ ACB`

Description : In the figure (not to scale ), O is the centre of the circle and `/_OBA=30^(@)`. Find `/_ ACB`

Last Answer : In the figure (not to scale ), O is the centre of the circle and `/_OBA=30^(@)`. Find `/_ ACB`

In the above figure, O is the centre of the circle AB,AD and CD are the chords . If `/_ ADC=130^(@)` then fid `/_ ACB`.

Description : In the above figure, O is the centre of the circle AB,AD and CD are the chords . If `/_ ADC=130^(@)` then fid `/_ ACB`.

Last Answer : In the above figure, O is the centre of the circle AB,AD and CD are the chords . If `/_ ADC=130^(@)` then fid `/_ ACB`.

In the figure above (not to scale), AB is the diameter of the circle with centre O. If `/_ ACO=30^(@),` then find `/_ BOC`.

Description : In the figure above (not to scale), AB is the diameter of the circle with centre O. If `/_ ACO=30^(@),` then find `/_ BOC`.

Last Answer : In the figure above (not to scale), AB is the diameter of the circle with centre O. If `/_ ACO=30^(@),` then find `/_ BOC`.

In the figure below ( not to scale), ABC is a straight line. If `/_ FBE =60^(@), /_ CBG =120^(@), /_ ABG = x^(@), /_ ABF= gamm^(@)` and `/_ CBE = z^(@

Description : In the figure below ( not to scale), ABC is a straight line. If `/_ FBE =60^(@), /_ CBG =120^(@), /_ ABG = x^(@), /_ ABF= gamm^(@)` and `/_ CBE = z^(@

Last Answer : In the figure below ( not to scale), ABC is a straight line. If `/_ FBE =60^(@), /_ CBG =120^(@), /_ ABG ... )`, then `( x^(@)+z^(@)) : gamma^(@)` is

In the given figure, AB is the diameter and `/_ADC = 2 /_BDC`. If `/_ BCD =70^(@)`, then find the angle made by AC at the centre of the circle.

Description : In the given figure, AB is the diameter and `/_ADC = 2 /_BDC`. If `/_ BCD =70^(@)`, then find the angle made by AC at the centre of the circle.

Last Answer : In the given figure, AB is the diameter and `/_ADC = 2 /_BDC`. If `/_ BCD =70^(@)`, then find the angle made by AC at the centre of the circle.

In the figure below, `bar(MN)` is the diameter of the circle with centre O. `bar(NP)` bisects the `/_ANM`. If `/_ NMA =33^(@)`, then find `/_ ANP`.

Description : In the figure below, `bar(MN)` is the diameter of the circle with centre O. `bar(NP)` bisects the `/_ANM`. If `/_ NMA =33^(@)`, then find `/_ ANP`.

Last Answer : In the figure below, `bar(MN)` is the diameter of the circle with centre O. `bar(NP)` bisects the `/_ANM`. If `/_ NMA =33^(@)`, then find `/_ ANP`.

In figure, AOB is a diameter of the circle and C, D, E are any three points on the semi-circle. -Maths 9th

Description : In figure, AOB is a diameter of the circle and C, D, E are any three points on the semi-circle. -Maths 9th

Last Answer : Since, A, C, D and E are four point on a circle, then ACDE is a cyclic quadrilateral. ∠ACD+ ∠AED = 180° …(i) [sum of opposite angles in a cyclic quadrilateral is 180°]

In figure, AOB is a diameter of the circle and C, D, E are any three points on the semi-circle. -Maths 9th

Description : In figure, AOB is a diameter of the circle and C, D, E are any three points on the semi-circle. -Maths 9th

Last Answer : Since, A, C, D and E are four point on a circle, then ACDE is a cyclic quadrilateral. ∠ACD+ ∠AED = 180° …(i) [sum of opposite angles in a cyclic quadrilateral is 180°]

triangle ABC is right angled at A. AL is drawn perpendicular to BC. Prove that /_ BAL = /_ ACB -Maths 9th

Description : triangle ABC is right angled at A. AL is drawn perpendicular to BC. Prove that /_ BAL = /_ ACB -Maths 9th

Last Answer : NEED ANSWER

triangle ABC is right angled at A. AL is drawn perpendicular to BC. Prove that /_ BAL = /_ ACB -Maths 9th

Description : triangle ABC is right angled at A. AL is drawn perpendicular to BC. Prove that /_ BAL = /_ ACB -Maths 9th

Last Answer : This answer was deleted by our moderators...

In a uniform ring of resistance `R` there are two points `A` and `B` such that `/_ ACB = theta`, where `C` is the centre of the ring. The equivalent r

Description : In a uniform ring of resistance `R` there are two points `A` and `B` such that `/_ ACB = theta`, where `C` is the centre of the ring. The equivalent r

Last Answer : In a uniform ring of resistance `R` there are two points `A` and `B` such that `/_ ACB = theta`, where `C` ... ))` D. `(R )/(4pi^(2))(2pi-theta)theta`

In the figure below ( not to scale) `bar(CD)||bar(RS) /_EMG=90^(@),/_GMD= gamma^(@),/_CME= x^(@) ` and `gamma^(@)=(x^(@))/(2)`. `/_ FNS : /_FNR `is

Description : In the figure below ( not to scale) `bar(CD)||bar(RS) /_EMG=90^(@),/_GMD= gamma^(@),/_CME= x^(@) ` and `gamma^(@)=(x^(@))/(2)`. `/_ FNS : /_FNR `is

Last Answer : In the figure below ( not to scale) `bar(CD)||bar(RS) /_EMG=90^(@),/_GMD= gamma^(@),/_CME= x^(@) ` and `gamma^(@)=(x^(@))/(2)`. `/_ FNS : /_FNR `is

In the above figure ( not to scale ) the sides BA,BC and CA of` Delta ABC` are produced to D,F, and E respectively such that `/_ ACF= 120^(@)` and `/_

Description : In the above figure ( not to scale ) the sides BA,BC and CA of` Delta ABC` are produced to D,F, and E respectively such that `/_ ACF= 120^(@)` and `/_

Last Answer : In the above figure ( not to scale ) the sides BA,BC and CA of` Delta ABC` are produced to D,F, and E ... /_ BAE= 150^(@)`. Then `/_ ABC = ________`.

In the above figure (not to scale) , `AB||DE` and `EC||GF`. If `/_ EGF=100^(@)` and `/_ ECF=40^(@),` find the following . (i) `/_ABC` (ii) `/_GFC` (ii

Description : In the above figure (not to scale) , `AB||DE` and `EC||GF`. If `/_ EGF=100^(@)` and `/_ ECF=40^(@),` find the following . (i) `/_ABC` (ii) `/_GFC` (ii

Last Answer : In the above figure (not to scale) , `AB||DE` and `EC||GF`. If `/_ EGF=100^(@)` and `/_ ECF=40^ ... following . (i) `/_ABC` (ii) `/_GFC` (iii) `/_GDF`

ABCD is a quadrilateral in which `/_A= 60^(@), /_ B= 70^(@), /_ C =110^(@)` and `/_ D =120^(@)`. The number of pairs of parallel lines is `"__________

Description : ABCD is a quadrilateral in which `/_A= 60^(@), /_ B= 70^(@), /_ C =110^(@)` and `/_ D =120^(@)`. The number of pairs of parallel lines is `"__________

Last Answer : ABCD is a quadrilateral in which `/_A= 60^(@), /_ B= 70^(@), /_ C =110^(@)` and ... )`. The number of pairs of parallel lines is `"________________"`.

In Fig. 6.14, if x+y = w+z,then then prove that AOB is a line. -Maths 9th

Description : In Fig. 6.14, if x+y = w+z,then then prove that AOB is a line. -Maths 9th

Last Answer : Solution :-

If AOB is a diameter of a circle [Fig. 10.8] and C is a point on the circle, then prove that AC* +BC*=AB*. -Maths 9th

Description : If AOB is a diameter of a circle [Fig. 10.8] and C is a point on the circle, then prove that AC* +BC*=AB*. -Maths 9th

Last Answer : Solution :- As, ∠ C = 90° (Angle in the semicircle) ∴ AC2 + BC2 = AB2 (By Pythagoras Theorem)

In `Delta ABC`, if `/_A=80^(@)` and `AB=AC`, then `/_ B = ___________________`.

Description : In `Delta ABC`, if `/_A=80^(@)` and `AB=AC`, then `/_ B = ___________________`.

Last Answer : In `Delta ABC`, if `/_A=80^(@)` and `AB=AC`, then `/_ B = ___________________`.

In `Delta ABC`, if `/_ A lt /_B lt 45^(@)`, then ABC is a`//` an `"__________________"` triangle.

Description : In `Delta ABC`, if `/_ A lt /_B lt 45^(@)`, then ABC is a`//` an `"__________________"` triangle.

Last Answer : In `Delta ABC`, if `/_ A lt /_B lt 45^(@)`, then ABC is a`//` an `"__________________"` triangle.

A ray of light is incident at an angle of `60^(@)` on one face of a prism of angle `30^(@)`. The ray emerging out of the prism makes an angle of `30^(

Description : A ray of light is incident at an angle of `60^(@)` on one face of a prism of angle `30^(@)`. The ray emerging out of the prism makes an angle of `30^(

Last Answer : A ray of light is incident at an angle of `60^(@)` on one face of a prism of angle `30^(@)` ... of `30^(@)` with the incident ray. The emergent ray is

If O is the centre of the circle and chord AB = OA and the area of triangle AOB -Maths 9th

Description : If O is the centre of the circle and chord AB = OA and the area of triangle AOB -Maths 9th

Last Answer : (b) 16π cm2.AB = OA ⇒ AB = OA = OB (radii of circle are equal) ⇒ ΔAOB is equilateral. ∴ If ‘r’ is the radius of the circle,then area of ΔAOB = \(rac{\sqrt3}{4}\)side2⇒ \(rac{\sqrt3}{4}\)(r)2 = 4√3 (given)⇒ r2 = 16 ⇒ r = 4∴ Area of circle = πr2 = 16π cm2.

Two identical conducting wires `AOB and COD` are placed at right angles to each other. The wire `AOB` carries an electric current `I_(1) and COD` carr

Description : Two identical conducting wires `AOB and COD` are placed at right angles to each other. The wire `AOB` carries an electric current `I_(1) and COD` carr

Last Answer : Two identical conducting wires `AOB and COD` are placed at right angles to each other. The wire `AOB` carries an electric ... )^(2)+I_(2)^(2))^(1//2)`

(3) Conversion of ammonia to nitrites Explanation: Nitrification is the biological oxidation of ammonia or ammonium to nitrite followed by the oxidation of the nitrite to nitrate. The oxidation of ammonia into nitrite is performed by two groups of organisms, ammonia-oxidizing bacteria AOB) and ammonia-oxidizing archaea (AOA). Nitrification is an important step in the nitrogen cycle in soil.

Description : (3) Conversion of ammonia to nitrites Explanation: Nitrification is the biological oxidation of ammonia or ammonium to nitrite followed by the oxidation of the nitrite to nitrate. The oxidation of ammonia ... -oxidizing archaea (AOA). Nitrification is an important step in the nitrogen cycle in soil.

Last Answer : Acid rain is caused due to pollution of atmosphere by – (1) oxides of carbon and nitrogen (2) oxides of nitrogen and sulphur (3) oxides of nitrogen and phosphorous (4) None of these

In a circle , chord AB subtends an angle of `60^(@)` at the centre and chord CD subtends `120^(@)`, at it. Then which chord is longer ?

Description : In a circle , chord AB subtends an angle of `60^(@)` at the centre and chord CD subtends `120^(@)`, at it. Then which chord is longer ?

Last Answer : In a circle , chord AB subtends an angle of `60^(@)` at the centre and chord CD subtends `120^(@)`, at it. Then which chord is longer ?

In the above `Delta ABC` ( not to scale ), OA is the angle bisector of `/_ BAC` . If `OB=OC,/_OAC=40^(@)` and `/_ ABO=20^(@)`. If `/_ OCB=(1)/(2) /_ A

Description : In the above `Delta ABC` ( not to scale ), OA is the angle bisector of `/_ BAC` . If `OB=OC,/_OAC=40^(@)` and `/_ ABO=20^(@)`. If `/_ OCB=(1)/(2) /_ A

Last Answer : In the above `Delta ABC` ( not to scale ), OA is the angle bisector of `/_ BAC` . If `OB=OC,/_OAC=40^(@) ... OCB=(1)/(2) /_ ACO,` then find `/_ BOC.`

In `Delta ABC, /_ A= /_C= 50^(@)`. The longest side of `Delta ABC `is `__________________`.

Description : In `Delta ABC, /_ A= /_C= 50^(@)`. The longest side of `Delta ABC `is `__________________`.

Last Answer : In `Delta ABC, /_ A= /_C= 50^(@)`. The longest side of `Delta ABC `is `__________________`.

On a common hypotenuse AB, two right angled triangles, ACB and ADB are situated on opposite sides. -Maths 9th

Description : On a common hypotenuse AB, two right angled triangles, ACB and ADB are situated on opposite sides. -Maths 9th

Last Answer : According to question ∠BAC = ∠BDC.

On a common hypotenuse AB, two right angled triangles, ACB and ADB are situated on opposite sides. -Maths 9th

Description : On a common hypotenuse AB, two right angled triangles, ACB and ADB are situated on opposite sides. -Maths 9th

Last Answer : According to question ∠BAC = ∠BDC.

Why use the VCB at High Transmission System? Why can't use ACB?

Description : Why use the VCB at High Transmission System? Why can't use ACB?

Last Answer : Actually the thing is vacuum has high arc quenching property compare to air because in VCB, the die electric strengths equal to 8 times of air. That y always vacuum used as in HT breaker and air used as in LT.

What do ABCB and ACB mean?

Description : What do ABCB and ACB mean? 

Last Answer : ABCB – Air blast circuit breaker. ACB – Air circuit breaker. 

String Processing --- Write out a function that prints out all the permutations of a string. For example, abc would give you abc, acb, bac, bca, cab, cba.

Description : String Processing --- Write out a function that prints out all the permutations of a string. For example, abc would give you abc, acb, bac, bca, cab, cba.

Last Answer : void PrintPermu (char *sBegin, char* sRest) { int iLoop; char cTmp; char cFLetter[1]; char *sNewBegin; char *sCur; int iLen; static int iCount; iLen = strlen(sRest); if (iLen == 2) { iCount++; ... printf("\nEnter a string:"); scanf("%s%*c",sIn); memset(s,0,255); PrintPermu(s, sIn); }

What is the meaning of ACB, MCCB, NFB?

Description : What is the meaning of ACB, MCCB, NFB?

Last Answer : Air circuit breaker for 400V higher current ratings. Moulded case circuit breaker for 400V medium current ratings. No Fuse Breaker – 75 A capacity

If you press the ACB Close button on an idle generator what will happen?

Description : If you press the ACB Close button on an idle generator what will happen?

Last Answer : Ask E/O. Normally, the breaker won’t close until you synchronise, so even if you press the breaker close, it will not close. The breaker has under-voltage protection which will not let you close it.

What is the full form of ACB?

Description : What is the full form of ACB?

Last Answer : Air circuit breaker. It is normally used at 400V and higher current applications (generator breakers).

Standard disc Plough consists of steel disc of _ diameter a) 20 to 40 cm. c) 60 to 90 cm b) 30 to 60 cm. d) 70 to 100 cm

Description : Standard disc Plough consists of steel disc of _ diameter a) 20 to 40 cm. c) 60 to 90 cm b) 30 to 60 cm. d) 70 to 100 cm

Last Answer :  60 to 90 cm

A light ray is incident on a plane mirror placed in a horizontal plane, making an angle of `30^(@)` with the vertical, then the angle between the refl

Description : A light ray is incident on a plane mirror placed in a horizontal plane, making an angle of `30^(@)` with the vertical, then the angle between the refl

Last Answer : A light ray is incident on a plane mirror placed in a horizontal plane, making an angle of `30^(@)` with the vertical, ... @)` C. `90^(@)` D. `30^(@)`

Can't seem to figure out the @ reply in red, sorry for my stupid head. Can someone help?

Description : Can't seem to figure out the @ reply in red, sorry for my stupid head. Can someone help?

Last Answer : answer:@babaji The comment is directed to someone else in the question. as I am directing this response to you Type it….it will happen. :)

In the figure above (not to scale), `AB=AC` and `/_BAO=25^(@)`. Find `/_BOC,` if O is the centre of the circle.

Description : In the figure above (not to scale), `AB=AC` and `/_BAO=25^(@)`. Find `/_BOC,` if O is the centre of the circle.

Last Answer : In the figure above (not to scale), `AB=AC` and `/_BAO=25^(@)`. Find `/_BOC,` if O is the centre of the circle.

A long conducting wire carrying a current I is bent at `120^(@) `( see figure). The magnetic field B at a point P on the right bisector of bending ang

Description : A long conducting wire carrying a current I is bent at `120^(@) `( see figure). The magnetic field B at a point P on the right bisector of bending ang

Last Answer : A long conducting wire carrying a current I is bent at `120^(@) `( see figure). The magnetic field B at a ... (3pid))` D. `(sqrt(3mu_(0)I))/(2pid)`

The cost of the earthwork in excavation for the surface drain of cross-section shown in the given figure for a total length of 5 metres @ Rs. 450% cum, is (A) Rs. 400 (B) Rs. 425 (C) Rs. 450 (D) Rs. 500

Description : The cost of the earthwork in excavation for the surface drain of cross-section shown in the given figure for a total length of 5 metres @ Rs. 450% cum, is (A) Rs. 400 (B) Rs. 425 (C) Rs. 450 (D) Rs. 500

Last Answer : (C) Rs. 450

The Gibbs free energy change of a reaction at `27^(@)C` is -26 Kcal. and its entropy change is -60 Cals/K. `Delta H` for the reaction is :-

Description : The Gibbs free energy change of a reaction at `27^(@)C` is -26 Kcal. and its entropy change is -60 Cals/K. `Delta H` for the reaction is :-

Last Answer : The Gibbs free energy change of a reaction at `27^(@)C` is -26 Kcal. and its entropy change is -60 Cals/K. ... Cals. C. 34 K. Cals. D. `-24` K. Cals.

An electron starting at angle `alpha=60^(@)` with a uniform magnetic induction `B=0.1 T` moves with velocity `v=10^(6) m s^(-1)`. A screen is held at

Description : An electron starting at angle `alpha=60^(@)` with a uniform magnetic induction `B=0.1 T` moves with velocity `v=10^(6) m s^(-1)`. A screen is held at

Last Answer : An electron starting at angle `alpha=60^(@)` with a uniform magnetic induction `B=0.1 T` ... to the point on the screen where the electron strikes.

A non-relativistic enters into a right-handed coordinate space with velocity `10^(4) m s^(-1)` at an angle of `60^(@)` with the x-axis in the xy-plane

Description : A non-relativistic enters into a right-handed coordinate space with velocity `10^(4) m s^(-1)` at an angle of `60^(@)` with the x-axis in the xy-plane

Last Answer : A non-relativistic enters into a right-handed coordinate space with velocity `10^(4) m s^(-1)` ... helical trajectory. What is the axis of the helix?

A glass prism has a refracting angle of `60^@`. The angle of minimum deviation is `40^@`. If velocity of light in vacuum is `3 xx 10^8 m//s`. Calculat

Description : A glass prism has a refracting angle of `60^@`. The angle of minimum deviation is `40^@`. If velocity of light in vacuum is `3 xx 10^8 m//s`. Calculat

Last Answer : A glass prism has a refracting angle of `60^@`. The angle of minimum deviation is `40^@`. If ... of light in glass. What is the angle of incidence ?

The refractive index of the material of a prism of `60^(@)` angle for yellow light is `sqrt(2)`. Calculate angle of minimum deviation, angle of incide

Description : The refractive index of the material of a prism of `60^(@)` angle for yellow light is `sqrt(2)`. Calculate angle of minimum deviation, angle of incide

Last Answer : The refractive index of the material of a prism of `60^(@)` angle for yellow light is ... deviation, angle of incidence and angle of refraction.

The refracting angle of a glass prism is `60^(@)`. The value of minium deviation for light passing through the prism is `40^(@)`. Calculate the value

Description : The refracting angle of a glass prism is `60^(@)`. The value of minium deviation for light passing through the prism is `40^(@)`. Calculate the value

Last Answer : The refracting angle of a glass prism is `60^(@)`. The value of minium deviation for light passing through the ... prism. Given `sin 50^(@) = 0.766`.

A ray of light is inclined to one face of a prism at an angle of `60^@`. If angle of prism is `60^@` and the ray deviated through an angle of `42^@` f

Description : A ray of light is inclined to one face of a prism at an angle of `60^@`. If angle of prism is `60^@` and the ray deviated through an angle of `42^@` f

Last Answer : A ray of light is inclined to one face of a prism at an angle of `60^@`. If angle of ... which the emergent ray makes with second face of the prism.

A ray of light is incident on the glass prism at an angle of `40^(@)`. Find the angle of emergence, if the angle of prism is `60^(@)` and refractive i

Description : A ray of light is incident on the glass prism at an angle of `40^(@)`. Find the angle of emergence, if the angle of prism is `60^(@)` and refractive i

Last Answer : A ray of light is incident on the glass prism at an angle of `40^(@)`. Find the angle of emergence, ... prism is `60^(@)` and refractive index is 1.5.

A proton of mass `1.67xx10^(-27)` kg charge `1.6xx10^(-19) C` is projected in xy-plane with a speed of `2xx10^(6) m//s` at an angle of `60^(@)` to the

Description : A proton of mass `1.67xx10^(-27)` kg charge `1.6xx10^(-19) C` is projected in xy-plane with a speed of `2xx10^(6) m//s` at an angle of `60^(@)` to the

Last Answer : A proton of mass `1.67xx10^(-27)` kg charge `1.6xx10^(-19) C` is projected in xy-plane with a speed ... radius 0.14 m and time period `1.0xx10^(-7)s`

A conducting stick of length 2L and mass m is moving down a smooth inclined plane of inclination `60^(@)` with constant speed 5m/s. A current 2A is fl

Description : A conducting stick of length 2L and mass m is moving down a smooth inclined plane of inclination `60^(@)` with constant speed 5m/s. A current 2A is fl

Last Answer : A conducting stick of length 2L and mass m is moving down a smooth inclined plane of inclination `60^(@)` with ... )/(4L)` D. `(sqrt(3)mg)/(2L)`