The Gibbs free energy change of a reaction at `27^(@)C` is -26 Kcal. and its entropy change is -60 Cals/K. `Delta H` for the reaction is :-

The Gibbs free energy change of a reaction at `27^(@)C` is -26 Kcal. and its entropy change is -60 Cals/K. `Delta H` for the reaction is :-
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The Gibbs free energy change of a reaction at `27^(@)C` is -26 Kcal. and its entropy change is -60 Cals/K. ... Cals. C. 34 K. Cals. D. `-24` K. Cals.
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Last Answer : Identify the products in the following disproportional reaction and also mention rate determining step. `2H-overset ... ")+underset("(Q)")("Alcohol")`

Identify the products in the following disproportional reaction and also mention rate determining step. `2H-overset(D)overset(|)(C)=O + overset(@)(O)H

Description : Identify the products in the following disproportional reaction and also mention rate determining step. `2H-overset(D)overset(|)(C)=O + overset(@)(O)H

Last Answer : Identify the products in the following disproportional reaction and also mention rate determining step. `2H-overset ... ")+underset("(Q)")("Alcohol")`

For reversible melting of ice at `0^(@)C` and 1 atm. Pressure, the value of `Delta G` will be :-

Description : For reversible melting of ice at `0^(@)C` and 1 atm. Pressure, the value of `Delta G` will be :-

Last Answer : For reversible melting of ice at `0^(@)C` and 1 atm. Pressure, the value of `Delta G` will be :- A. `lt ... 0` (zero) C. 0 (zero) D. `oo` (infinity)

`C_(6)H_(5)NH_(2) overset(NaNO_(2)+HCl)underset(0-5^(@)C) X overset(H_(2)O)underset(Delta)toY,` the product is :

Description : `C_(6)H_(5)NH_(2) overset(NaNO_(2)+HCl)underset(0-5^(@)C) X overset(H_(2)O)underset(Delta)toY,` the product is :

Last Answer : `C_(6)H_(5)NH_(2) overset(NaNO_(2)+HCl)underset(0-5^(@)C) X overset(H_(2)O) ... : A. Benzenediazonium chloride B. Nitrobenzene C. Phenol D. Cresol

In the above `Delta ABC` ( not to scale ), OA is the angle bisector of `/_ BAC` . If `OB=OC,/_OAC=40^(@)` and `/_ ABO=20^(@)`. If `/_ OCB=(1)/(2) /_ A

Description : In the above `Delta ABC` ( not to scale ), OA is the angle bisector of `/_ BAC` . If `OB=OC,/_OAC=40^(@)` and `/_ ABO=20^(@)`. If `/_ OCB=(1)/(2) /_ A

Last Answer : In the above `Delta ABC` ( not to scale ), OA is the angle bisector of `/_ BAC` . If `OB=OC,/_OAC=40^(@) ... OCB=(1)/(2) /_ ACO,` then find `/_ BOC.`

In the above figure ( not to scale ) the sides BA,BC and CA of` Delta ABC` are produced to D,F, and E respectively such that `/_ ACF= 120^(@)` and `/_

Description : In the above figure ( not to scale ) the sides BA,BC and CA of` Delta ABC` are produced to D,F, and E respectively such that `/_ ACF= 120^(@)` and `/_

Last Answer : In the above figure ( not to scale ) the sides BA,BC and CA of` Delta ABC` are produced to D,F, and E ... /_ BAE= 150^(@)`. Then `/_ ABC = ________`.