Description : In `Delta ABC`, if `/_ A lt /_B lt 45^(@)`, then ABC is a`//` an `"__________________"` triangle.
Last Answer : In `Delta ABC`, if `/_ A lt /_B lt 45^(@)`, then ABC is a`//` an `"__________________"` triangle.
Description : ABCD is a quadrilateral in which `/_A= 60^(@), /_ B= 70^(@), /_ C =110^(@)` and `/_ D =120^(@)`. The number of pairs of parallel lines is `"__________
Last Answer : ABCD is a quadrilateral in which `/_A= 60^(@), /_ B= 70^(@), /_ C =110^(@)` and ... )`. The number of pairs of parallel lines is `"________________"`.
Description : In the above `Delta ABC` ( not to scale ), OA is the angle bisector of `/_ BAC` . If `OB=OC,/_OAC=40^(@)` and `/_ ABO=20^(@)`. If `/_ OCB=(1)/(2) /_ A
Last Answer : In the above `Delta ABC` ( not to scale ), OA is the angle bisector of `/_ BAC` . If `OB=OC,/_OAC=40^(@) ... OCB=(1)/(2) /_ ACO,` then find `/_ BOC.`
Description : In the above figure ( not to scale ) the sides BA,BC and CA of` Delta ABC` are produced to D,F, and E respectively such that `/_ ACF= 120^(@)` and `/_
Last Answer : In the above figure ( not to scale ) the sides BA,BC and CA of` Delta ABC` are produced to D,F, and E ... /_ BAE= 150^(@)`. Then `/_ ABC = ________`.
Description : In `Delta ABC, /_ A= /_C= 50^(@)`. The longest side of `Delta ABC `is `__________________`.
Last Answer : In `Delta ABC, /_ A= /_C= 50^(@)`. The longest side of `Delta ABC `is `__________________`.
Description : In the given figure, AB is the diameter and `/_ADC = 2 /_BDC`. If `/_ BCD =70^(@)`, then find the angle made by AC at the centre of the circle.
Last Answer : In the given figure, AB is the diameter and `/_ADC = 2 /_BDC`. If `/_ BCD =70^(@)`, then find the angle made by AC at the centre of the circle.
Description : In the figure below ( not to scale), ABC is a straight line. If `/_ FBE =60^(@), /_ CBG =120^(@), /_ ABG = x^(@), /_ ABF= gamm^(@)` and `/_ CBE = z^(@
Last Answer : In the figure below ( not to scale), ABC is a straight line. If `/_ FBE =60^(@), /_ CBG =120^(@), /_ ABG ... )`, then `( x^(@)+z^(@)) : gamma^(@)` is
Description : In the figure above (not to scale), AB is the diameter of the circle with centre O. If `/_ ACO=30^(@),` then find `/_ BOC`.
Last Answer : In the figure above (not to scale), AB is the diameter of the circle with centre O. If `/_ ACO=30^(@),` then find `/_ BOC`.
Description : In the above figure, O is the centre of the circle AB,AD and CD are the chords . If `/_ ADC=130^(@)` then fid `/_ ACB`.
Last Answer : In the above figure, O is the centre of the circle AB,AD and CD are the chords . If `/_ ADC=130^(@)` then fid `/_ ACB`.
Description : D and E are respectively the points on the sides AB and AC of a triangle ABC such that AD = 2 cm, BD = 3 cm, BC = 7.5 cm and DE || BC. Then, length of DE (in cm) is (a) 2.5 (b) 3 (c) 5 (d) 6
Last Answer : (b) 3
Description : What are X and Y in the reaction `C_(2)H_(4) + H_(2)SO_(4) overset(80^(@)C)rarr X overset(H_(2)O//Delta)rarr Y`
Last Answer : What are X and Y in the reaction `C_(2)H_(4) + H_(2)SO_(4) overset(80^(@)C)rarr X overset(H_(2)O//Delta) ... C_(2)H_(5)OH` D. `C_(2)H_(2), CH_(3)CHO`
Description : In the above figure (not to scale) , `AB||DE` and `EC||GF`. If `/_ EGF=100^(@)` and `/_ ECF=40^(@),` find the following . (i) `/_ABC` (ii) `/_GFC` (ii
Last Answer : In the above figure (not to scale) , `AB||DE` and `EC||GF`. If `/_ EGF=100^(@)` and `/_ ECF=40^ ... following . (i) `/_ABC` (ii) `/_GFC` (iii) `/_GDF`
Description : ABC is a triangle right angled at C. A line through the mid-point M of hypotenuse AB and parallel to BC intersects AC at D. Show that (i) D is the mid-point of AC (ii) MD ⊥ AC (iii) CM = MA = ½ AB -Maths 9th
Last Answer : Solution: (i) In ΔACB, M is the midpoint of AB and MD || BC , D is the midpoint of AC (Converse of mid point theorem) (ii) ∠ACB = ∠ADM (Corresponding angles) also, ∠ACB = 90° , ∠ADM = 90° and MD ⊥ AC (iii ... SAS congruency] AM = CM [CPCT] also, AM = ½ AB (M is midpoint of AB) Hence, CM = MA = ½ AB
Description : ABC is an isosceles triangle in which AB=AC.AD bisects exterior angles PAC and CD parallel AB.Prove that-i)angle DAC=angle BAC ii)∆BCD is a parallelogram -Maths 9th
Last Answer : AB =AC(given) Angle ABC =angle ACB (angle opposite to equal sides) Angle PAC=Angle ABC +angle ACB (Exterior angle property) Angle PAC =2 angle ACB - - - - - - (1) AD BISECTS ANGLE PAC. ANGLE ... AND AC IS TRANSVERSAL BC||AD BA||CD (GIVEN ) THEREFORE ABCD IS A PARALLEGRAM. HENCE PROVED........
Description : ABC is a triangle right-angled at C. A line through the mid-point M of hypotenuse AB parallel to BC intersects AC ad D. -Maths 9th
Last Answer : Given: A △ABC , right - angled at C. A line through the mid - point M of hypotenuse AB parallel to BC intersects AC at D. To Prove: (i) D is the mid - point of AC (ii) MD | AC (iii) CM = MA = 1 / 2 ... congruence axiom] ⇒ AM = CM Also, M is the mid - point of AB [given] ⇒ CM = MA = 1 / 2 = AB.
Description : ABC is an isosceles triangle with AB = AC and BD, CE are its two medians. Show that BD = CE. -Maths 9th
Last Answer : Given ΔABC is an isosceles triangle in which AB = AC and BD, CE are its two medians. To show BD = CE.
Description : ABC is an isosceles triangle in which altitude BE and CF are drawn to equal sides AC and AB respectively (Fig. 7.15). Show that these altitudes are equal. -Maths 9th
Last Answer : In △ABE and △ACF, we have ∠BEA=∠CFA (Each 90 0 ) ∠A=∠A (Common angle) AB=AC (Given) ∴△ABE≅△ACF (By SAS congruence criteria) ∴BF=CF [C.P.C.T]
Description : ABC and DBC are two triangles on the same BC such that A and D lie on the opposite sides of BC,AB=AC and DB = DC.Show that AD is the perpendicular bisector of BC. -Maths 9th
Last Answer : Solution :-
Description : ABC is a triangle right-angled at C. A line through the mid-point of hypotenuse AB and parallel to BC intersects AC at D. Show that -Maths 9th
Description : In the diagram AB and AC are the equal sides of an isosceles triangle ABC, in which is inscribed equilateral triangle DEF. -Maths 9th
Last Answer : answer:
Description : In the given figure, ABC is an equilateral triangle of side length 30 cm. XY is parallel to BC, XP is parallel to AC and YQ is parallel to AB. -Maths 9th
Description : Side AC of a right triangle ABC is divided into 8 equal parts. Seven line segments parallel to BC are drawn to AB from the points of division. -Maths 9th
Description : In the following figure, (not to scale) ABC is triangle, where AB=1 unit, BC=`sqrt(3)` units and AC=2 units What is the relationship among AB,BC and C
Last Answer : In the following figure, (not to scale) ABC is triangle, where AB=1 unit, BC=`sqrt(3)` units ... units What is the relationship among AB,BC and CA?
Description : Figure abc is rectangle. segment AB is 6cm long , segment BC is 8 cm long , and segment AC is 10 cm long. what is the area of triangle abc?
Last Answer : 28
Description : The simplified form of a Boolean equation (AB’+AB’C+AC)(A’C’+B’) is : (A) AB’ (B) AB’C (C) A’B (D) ABC
Last Answer : (A) AB’
Description : In the figure above (not to scale), `AB=AC` and `/_BAO=25^(@)`. Find `/_BOC,` if O is the centre of the circle.
Last Answer : In the figure above (not to scale), `AB=AC` and `/_BAO=25^(@)`. Find `/_BOC,` if O is the centre of the circle.
Description : If all the sides of a polygon ABCDE are equal, then `/_A = /_C.` ( Yes `//` No `//` May or May not be )
Last Answer : If all the sides of a polygon ABCDE are equal, then `/_A = /_C.` ( Yes `//` No `//` May or May not be )
Description : If G is the centroid of `Delta ABC`, then the area of `Delta BGC` is `"_______________"` times the area of quadrilateral ABCG.
Last Answer : If G is the centroid of `Delta ABC`, then the area of `Delta BGC` is `"_______________"` times the area of quadrilateral ABCG.
Description : If, `H_(2)(g)+Cl_(2)(g)rarr 2HCl(g) , Delta H^(@)=-44` Kcal `2Na(s)+2HCl(g)rarr 2NaCl(s)+H_(2)(g), Delta H=-152` Kcal Then, `Na(s)+0.5Cl_(2)(g)rarr Na
Last Answer : If, `H_(2)(g)+Cl_(2)(g)rarr 2HCl(g) , Delta H^(@)=-44` Kcal `2Na(s)+2HCl(g)rarr 2NaCl(s)+H_(2)( ... ` A. 108 Kcal B. 196 Kcal C. `-98` Kcal D. 54 Kcal
Description : If `Delta G^(@)gt 0` for a reaction then :
Last Answer : If `Delta G^(@)gt 0` for a reaction then : A. `K_(P) gt 1` B. `K_(P) lt 1` C. The products predominate in the equilibrium mixture D. None
Description : For `CaCO_(3)(s)rarr CaO(s)+CO_(2)(g)` at `977^(@)C, Delta H = 174` KJ/mol , then `Delta E` is :-
Last Answer : For `CaCO_(3)(s)rarr CaO(s)+CO_(2)(g)` at `977^(@)C, Delta H = 174` KJ/mol , then `Delta E` is :- A. 160 KJ B. 163.6 KJ C. 186.4 KJ D. 180 KJ
Description : `AB` is a wire of uniform resistance. The galvanometer `G` shows no deflection when the length `AC = 20 cm` and `CB = 80 cm`. The resistance `R` is eq
Last Answer : `AB` is a wire of uniform resistance. The galvanometer `G` shows no deflection when the length `AC = 20 cm ... ` B. `8Omega` C. `20Omega` D. `40Omega`
Description : in triangle abc bd =1/3 bd then prove that 9(ad)^2=7(ab)^2 -Maths 9th
Last Answer : This answer was deleted by our moderators...
Description : Let ABC be a triangle of area 16 cm^2 . XY is drawn parallel to BC dividing AB in the ratio 3 : 5. If BY is joined, then the area of triangle BXY is -Maths 9th
Description : If a + b + c = 9 and ab + bc + ca = 23, then a3 + b3 + c3 – 3 abc = (a) 108 (b) 207 (c) 669 (d) 729 -Maths 9th
Last Answer : a+b+c=9 and a2+b2+c2=35 Using formula, (a+b+c)2=a2+b2+c2+2(ab+bc+ca) 92=35+2(ab+bc+ca) 2(ab+bc+ca)=81−35=46 (ab+bc+ca)=23 using formula, (a3+b3+c3)−3abc=(a2+b2+c2−ab−bc−ca)(a+b+c) a3+b3+c3−3abc=(35−23)×9=9×12=108
Description : Sum of angles of triangle ABC is `180^(@)`. Express the statement using symbols.
Last Answer : Sum of angles of triangle ABC is `180^(@)`. Express the statement using symbols.
Description : In a circle , chord AB subtends an angle of `60^(@)` at the centre and chord CD subtends `120^(@)`, at it. Then which chord is longer ?
Last Answer : In a circle , chord AB subtends an angle of `60^(@)` at the centre and chord CD subtends `120^(@)`, at it. Then which chord is longer ?
Description : Which of the following is invalid? a) _a = 1 b) __a = 1 c) __str__ = 1 d) none of the mentioned
Last Answer : c) str = 1 In Python, __str__ is a special method that is used to define how an object should be represented as a string. It is a predefined method in Python and cannot be used as a ... those starting with __ are considered protected. They are valid names but have some specific uses in the code.
Description : In the figure below, `bar(MN)` is the diameter of the circle with centre O. `bar(NP)` bisects the `/_ANM`. If `/_ NMA =33^(@)`, then find `/_ ANP`.
Last Answer : In the figure below, `bar(MN)` is the diameter of the circle with centre O. `bar(NP)` bisects the `/_ANM`. If `/_ NMA =33^(@)`, then find `/_ ANP`.
Description : In the following figure, if `/_ AOB =60^(@)` then `/_ ACB=30^(@)`. [True `//` False `//` Cannot say ]
Last Answer : In the following figure, if `/_ AOB =60^(@)` then `/_ ACB=30^(@)`. [True `//` False `//` Cannot say ]
Description : Assertion :- At constant temp `0^(@)C` and 1 atm, the change `H_(2)O(s)rarr H_(2)O(l)Delta H` and `Delta E` both are zero. Reason :- During isothermal
Last Answer : Assertion :- At constant temp `0^(@)C` and 1 atm, the change `H_(2)O(s)rarr H_(2)O(l) ... Reason is False. D. If both Assertion & Reason are false.
Description : The Gibbs free energy change of a reaction at `27^(@)C` is -26 Kcal. and its entropy change is -60 Cals/K. `Delta H` for the reaction is :-
Last Answer : The Gibbs free energy change of a reaction at `27^(@)C` is -26 Kcal. and its entropy change is -60 Cals/K. ... Cals. C. 34 K. Cals. D. `-24` K. Cals.
Description : Calculate the entropy of `Br_(2)(g)` in the reaction `H_(2)(g)+Br_(2)(g)rarr2HBr(g), Delta S^(@)=20.1 JK^(-1)` given, entropy of `H_(2)` and HBr is 13
Last Answer : Calculate the entropy of `Br_(2)(g)` in the reaction `H_(2)(g)+Br_(2)(g)rarr2HBr(g), Delta S^(@)=20.1 JK^(-1 ... ` C. `24.63 JK^(-1)` D. `20 KJK^(-1)`
Description : The difference in `Delta H` and `Delta E` for the combustion of methane at `25^(@)C` would be :-
Last Answer : The difference in `Delta H` and `Delta E` for the combustion of methane at `25^(@)C` would be :- A ... Cals C. `2xx298xx -3` Cals D. `2xx25xx -3` Cals
Last Answer : The difference in `Delta H` and `Delta E` for the combustion of methane at `25^(@)C` would be :- A ... cals C. `2xx298xx -3` cals D. `2xx25xx -3` cals
Description : For reversible melting of ice at `0^(@)C` and 1 atm. Pressure, the value of `Delta G` will be :-
Last Answer : For reversible melting of ice at `0^(@)C` and 1 atm. Pressure, the value of `Delta G` will be :- A. `lt ... 0` (zero) C. 0 (zero) D. `oo` (infinity)
Description : `C_(6)H_(5)NH_(2) overset(NaNO_(2)+HCl)underset(0-5^(@)C) X overset(H_(2)O)underset(Delta)toY,` the product is :
Last Answer : `C_(6)H_(5)NH_(2) overset(NaNO_(2)+HCl)underset(0-5^(@)C) X overset(H_(2)O) ... : A. Benzenediazonium chloride B. Nitrobenzene C. Phenol D. Cresol