In the above figure (not to scale) , `AB||DE` and `EC||GF`. If `/_ EGF=100^(@)` and `/_ ECF=40^(@),` find the following . (i) `/_ABC` (ii) `/_GFC` (ii

In the above figure (not to scale) , `AB||DE` and `EC||GF`. If `/_ EGF=100^(@)` and `/_ ECF=40^(@),` find the following . (i) `/_ABC` (ii) `/_GFC` (ii
by

1 Answer

Answer :

In the above figure (not to scale) , `AB||DE` and `EC||GF`. If `/_ EGF=100^(@)` and `/_ ECF=40^ ... following . (i) `/_ABC` (ii) `/_GFC` (iii) `/_GDF`
by
selected by

Related questions

In the figure above (not to scale), AB is the diameter of the circle with centre O. If `/_ ACO=30^(@),` then find `/_ BOC`.

Description : In the figure above (not to scale), AB is the diameter of the circle with centre O. If `/_ ACO=30^(@),` then find `/_ BOC`.

Last Answer : In the figure above (not to scale), AB is the diameter of the circle with centre O. If `/_ ACO=30^(@),` then find `/_ BOC`.

Sohan wants to show gratitude towards his teacher by giving her a card made by him. He has three pieces of trapezium pasted one above the other as shown in fig. These pieces are arranged in a way that AB||HC || GD || FE. Also BC=CD=DE, and GF=6 cm... -Maths 9th

Description : Sohan wants to show gratitude towards his teacher by giving her a card made by him. He has three pieces of trapezium pasted one above the other as shown in fig. These pieces are arranged in a way that AB||HC || GD || FE. Also BC=CD=DE, and GF=6 cm... -Maths 9th

Last Answer : Given : Sohan wants to show gratitude towards his teacher by giving her a card made by him. He has three pieces of trapezium pasted one above the other as shown in the fig. These pieces are arranged ... length of coloured tape required = 30 cm (b) The values are : Happiness, beauty, Knowledge.

Sohan wants to show gratitude towards his teacher by giving her a card made by him. He has three pieces of trapezium pasted one above the other as shown in fig. These pieces are arranged in a way that AB||HC || GD || FE. Also BC=CD=DE, and GF=6 cm. He wants to decorate the card by putting up a colored tape on the non-parallel sides of the trapezium.. -Maths 9th

Description : Sohan wants to show gratitude towards his teacher by giving her a card made by him. He has three pieces of trapezium pasted one above the other as shown in fig. These pieces are arranged in a way that ... the card by putting up a colored tape on the non-parallel sides of the trapezium.. -Maths 9th

Last Answer : Let us consider the following lay out of the greeting card. Trapeziums are arranged in such a way that AB || HC || GD || FE. Also BC=CD=DE and GF=6 cm and DE = 4cm. If three parallel lines make equal ... HG+GF+BC+CD+DE = 6+6+6+4+4+4=30 cm. (b) The values are: Happiness, beauty, Knowledge.

In the given figure, AB is the diameter and `/_ADC = 2 /_BDC`. If `/_ BCD =70^(@)`, then find the angle made by AC at the centre of the circle.

Description : In the given figure, AB is the diameter and `/_ADC = 2 /_BDC`. If `/_ BCD =70^(@)`, then find the angle made by AC at the centre of the circle.

Last Answer : In the given figure, AB is the diameter and `/_ADC = 2 /_BDC`. If `/_ BCD =70^(@)`, then find the angle made by AC at the centre of the circle.

In the above figure, O is the centre of the circle AB,AD and CD are the chords . If `/_ ADC=130^(@)` then fid `/_ ACB`.

Description : In the above figure, O is the centre of the circle AB,AD and CD are the chords . If `/_ ADC=130^(@)` then fid `/_ ACB`.

Last Answer : In the above figure, O is the centre of the circle AB,AD and CD are the chords . If `/_ ADC=130^(@)` then fid `/_ ACB`.

In the figure above (not to scale), `AB=AC` and `/_BAO=25^(@)`. Find `/_BOC,` if O is the centre of the circle.

Description : In the figure above (not to scale), `AB=AC` and `/_BAO=25^(@)`. Find `/_BOC,` if O is the centre of the circle.

Last Answer : In the figure above (not to scale), `AB=AC` and `/_BAO=25^(@)`. Find `/_BOC,` if O is the centre of the circle.

In the figure below ( not to scale) `bar(CD)||bar(RS) /_EMG=90^(@),/_GMD= gamma^(@),/_CME= x^(@) ` and `gamma^(@)=(x^(@))/(2)`. `/_ FNS : /_FNR `is

Description : In the figure below ( not to scale) `bar(CD)||bar(RS) /_EMG=90^(@),/_GMD= gamma^(@),/_CME= x^(@) ` and `gamma^(@)=(x^(@))/(2)`. `/_ FNS : /_FNR `is

Last Answer : In the figure below ( not to scale) `bar(CD)||bar(RS) /_EMG=90^(@),/_GMD= gamma^(@),/_CME= x^(@) ` and `gamma^(@)=(x^(@))/(2)`. `/_ FNS : /_FNR `is

In the figure below ( not to scale), ABC is a straight line. If `/_ FBE =60^(@), /_ CBG =120^(@), /_ ABG = x^(@), /_ ABF= gamm^(@)` and `/_ CBE = z^(@

Description : In the figure below ( not to scale), ABC is a straight line. If `/_ FBE =60^(@), /_ CBG =120^(@), /_ ABG = x^(@), /_ ABF= gamm^(@)` and `/_ CBE = z^(@

Last Answer : In the figure below ( not to scale), ABC is a straight line. If `/_ FBE =60^(@), /_ CBG =120^(@), /_ ABG ... )`, then `( x^(@)+z^(@)) : gamma^(@)` is

In the figure (not to scale ), O is the centre of the circle and `/_OBA=30^(@)`. Find `/_ ACB`

Description : In the figure (not to scale ), O is the centre of the circle and `/_OBA=30^(@)`. Find `/_ ACB`

Last Answer : In the figure (not to scale ), O is the centre of the circle and `/_OBA=30^(@)`. Find `/_ ACB`

In the above figure ( not to scale ) the sides BA,BC and CA of` Delta ABC` are produced to D,F, and E respectively such that `/_ ACF= 120^(@)` and `/_

Description : In the above figure ( not to scale ) the sides BA,BC and CA of` Delta ABC` are produced to D,F, and E respectively such that `/_ ACF= 120^(@)` and `/_

Last Answer : In the above figure ( not to scale ) the sides BA,BC and CA of` Delta ABC` are produced to D,F, and E ... /_ BAE= 150^(@)`. Then `/_ ABC = ________`.

In the above `Delta ABC` ( not to scale ), OA is the angle bisector of `/_ BAC` . If `OB=OC,/_OAC=40^(@)` and `/_ ABO=20^(@)`. If `/_ OCB=(1)/(2) /_ A

Description : In the above `Delta ABC` ( not to scale ), OA is the angle bisector of `/_ BAC` . If `OB=OC,/_OAC=40^(@)` and `/_ ABO=20^(@)`. If `/_ OCB=(1)/(2) /_ A

Last Answer : In the above `Delta ABC` ( not to scale ), OA is the angle bisector of `/_ BAC` . If `OB=OC,/_OAC=40^(@) ... OCB=(1)/(2) /_ ACO,` then find `/_ BOC.`

In `Delta ABC`, if `/_A=80^(@)` and `AB=AC`, then `/_ B = ___________________`.

Description : In `Delta ABC`, if `/_A=80^(@)` and `AB=AC`, then `/_ B = ___________________`.

Last Answer : In `Delta ABC`, if `/_A=80^(@)` and `AB=AC`, then `/_ B = ___________________`.

In the figure below, `bar(MN)` is the diameter of the circle with centre O. `bar(NP)` bisects the `/_ANM`. If `/_ NMA =33^(@)`, then find `/_ ANP`.

Description : In the figure below, `bar(MN)` is the diameter of the circle with centre O. `bar(NP)` bisects the `/_ANM`. If `/_ NMA =33^(@)`, then find `/_ ANP`.

Last Answer : In the figure below, `bar(MN)` is the diameter of the circle with centre O. `bar(NP)` bisects the `/_ANM`. If `/_ NMA =33^(@)`, then find `/_ ANP`.

In the following figure, if `/_ AOB =60^(@)` then `/_ ACB=30^(@)`. [True `//` False `//` Cannot say ]

Description : In the following figure, if `/_ AOB =60^(@)` then `/_ ACB=30^(@)`. [True `//` False `//` Cannot say ]

Last Answer : In the following figure, if `/_ AOB =60^(@)` then `/_ ACB=30^(@)`. [True `//` False `//` Cannot say ]

5. In a parallelogram ABCD, E and F are the mid-points of sides AB and CD respectively (see Fig. 8.31). Show that the line segments AF and EC trisect the diagonal BD. -Maths 9th

Description : 5. In a parallelogram ABCD, E and F are the mid-points of sides AB and CD respectively (see Fig. 8.31). Show that the line segments AF and EC trisect the diagonal BD. -Maths 9th

Last Answer : . Solution: Given that, ABCD is a parallelogram. E and F are the mid-points of sides AB and CD respectively. To show, AF and EC trisect the diagonal BD. Proof, ABCD is a parallelogram , AB || CD also, ... (i), DP = PQ = BQ Hence, the line segments AF and EC trisect the diagonal BD. Hence Proved.

In (a) 7.5 cm (b) 3 cm (c) 4.5 cm (d) 6 cm || AB. If CD = 3 cm, EC = 4 cm, BE = 6 cm, then DA is equal to

Description : In|| AB. If CD = 3 cm, EC = 4 cm, BE = 6 cm, then DA is equal to (a) 7.5 cm (b) 3 cm (c) 4.5 cm (d) 6 cm

Last Answer : (c) 4.5 cm

Ab and Ac are the cross sections of bronze and copper bars of equal lengt b c are their respective stresses due to load P. If Pb and Pc are the loads shared by them, (where Eb and Ec are their modulii). (A) b c = Eb /Ec (B) P = Pb + Pc (C) P = Ab b + Ac b (D) All the above

Description : Ab and Ac  are the cross sections of bronze and copper bars of equal lengt b c  are their  respective stresses due to load P. If Pb and Pc  are the loads shared by them, (where Eb and Ec  are  their modulii) ... /Ec (B) P = Pb + Pc (C) P = Ab b + Ac b (D) All the above 

Last Answer : (D) All the above 

ABCE is an isosceles trapezoid and ACDE is a rectangle. AB = 10 and EC = 20. What is the length of AE?

Description : ABCE is an isosceles trapezoid and ACDE is a rectangle. AB = 10 and EC = 20. What is the length of AE?

Last Answer : Answer: AE = 10.

One of the potent st imu lators of aldosterone secretion is (A) Increased sodium concentration (B) Decreased potassium concentration (C) Increased potassium concentration (D) Increased ECF volume

Description : One of the potent st imu lators of aldosterone secretion is (A) Increased sodium concentration (B) Decreased potassium concentration (C) Increased potassium concentration (D) Increased ECF volume

Last Answer : Answer : C

In figure, AB || DE, AB = DE, AC|| DF and AC = OF. Prove that BC || EF and BC = EF. -Maths 9th

Description : In figure, AB || DE, AB = DE, AC|| DF and AC = OF. Prove that BC || EF and BC = EF. -Maths 9th

Last Answer : Given In figure AB || DE and AC || DF, also AB = DE and AC = DF To prove BC ||EF and BC = EF Proof In quadrilateral ABED, AB||DE and AB = DE So, ABED is a parallelogram. AD || BE and AD = BE Now, ... = CF and BE||CF [from Eq. (iii)] So, BCFE is a parallelogram. BC = EF and BC|| EF . Hence proved.

In figure, AB || DE, AB = DE, AC|| DF and AC = OF. Prove that BC || EF and BC = EF. -Maths 9th

Description : In figure, AB || DE, AB = DE, AC|| DF and AC = OF. Prove that BC || EF and BC = EF. -Maths 9th

Last Answer : Given In figure AB || DE and AC || DF, also AB = DE and AC = DF To prove BC ||EF and BC = EF Proof In quadrilateral ABED, AB||DE and AB = DE So, ABED is a parallelogram. AD || BE and AD = BE Now, ... = CF and BE||CF [from Eq. (iii)] So, BCFE is a parallelogram. BC = EF and BC|| EF . Hence proved.

In the given figure, line DE is parallel to line AB. CD = 3 while DA = 6. Which of the following must be true? -Maths 9th

Description : In the given figure, line DE is parallel to line AB. CD = 3 while DA = 6. Which of the following must be true? -Maths 9th

Last Answer : answer:

In given figure, AD = 3 cm, AE = 5 cm, BD = 4 cm, CE = 4 cm, CF = 2 cm, BF = 2.5 cm, then (a) DE || BC (b) DF || AC (c) EF || AB (d) none of

Description : In given figure, AD = 3 cm, AE = 5 cm, BD = 4 cm, CE = 4 cm, CF = 2 cm, BF = 2.5 cm, then (a) DE || BC (b) DF || AC (c) EF || AB (d) none of

Last Answer : (c) EF || AB

Ras proto-oncogene encodes (A) Epidermal growth factor (EGF) (B) Receptor for EGF (C) Signal transducer for EGF (D) Nuclear transcription factor

Description : Ras proto-oncogene encodes (A) Epidermal growth factor (EGF) (B) Receptor for EGF (C) Signal transducer for EGF (D) Nuclear transcription factor

Last Answer : Answer : C

Which of the following statements regarding fibroblasts and their function in wound healing are true? a. IL-1 has both inhibitory and promotional effects on fibroblast growth b. TNFa stimulates fibroblast collagen synthesis c. IL-1 and TNFa have opposite effects on the healing of bone d. In human clinical trials, EGF (epithelial growth factor) has been demonstrated to accelerate epidermal regeneration in cutaneous wounds

Description : Which of the following statements regarding fibroblasts and their function in wound healing are true? a. IL-1 has both inhibitory and promotional effects on fibroblast growth b. TNFa ... EGF (epithelial growth factor) has been demonstrated to accelerate epidermal regeneration in cutaneous wounds

Last Answer : Answer: a, d IL-1 appears to be important in the process of normal wound repair. IL-1 has been shown to stimulate skin fibroblast and keratinocyte growth, as well as ... that recombinant EGF enhances keratinocyte migration. EGF is also a potent chemoattractant for granulation tissue fibroblasts

In the figure below, CD is a chord of the semi circle with centre O. OA is the radius of the circle. If `CD=10` cm, `AB=2` cm and `bar(OA)_|_bar(CD)`

Description : In the figure below, CD is a chord of the semi circle with centre O. OA is the radius of the circle. If `CD=10` cm, `AB=2` cm and `bar(OA)_|_bar(CD)`

Last Answer : In the figure below, CD is a chord of the semi circle with centre O. OA is the radius of the ... |_bar(CD)` the length of OB is `"_____________"`

In the given figure, (not drawn to scale), P is a point on AB such that AP : PB = 4 : 3. PQ is parallel to AC and QD -Maths 9th

Description : In the given figure, (not drawn to scale), P is a point on AB such that AP : PB = 4 : 3. PQ is parallel to AC and QD -Maths 9th

Last Answer : answer:

In the following figure, (not to scale) ABC is triangle, where AB=1 unit, BC=`sqrt(3)` units and AC=2 units What is the relationship among AB,BC and C

Description : In the following figure, (not to scale) ABC is triangle, where AB=1 unit, BC=`sqrt(3)` units and AC=2 units What is the relationship among AB,BC and C

Last Answer : In the following figure, (not to scale) ABC is triangle, where AB=1 unit, BC=`sqrt(3)` units ... units What is the relationship among AB,BC and CA?

In ΔABC and ΔDEF, AB = DE, AB || DE, BC = EF and BC || EF. Vertices A, B and C are joined to vertices D, E and F respectively (see Fig. 8.22). Show that (i) quadrilateral ABED is a parallelogram (ii) quadrilateral BEFC is a parallelogram (iii) AD || CF and AD = CF (iv) quadrilateral ACFD is a parallelogram (v) AC = DF (vi) ΔABC ≅ ΔDEF. -Maths 9th

Description : In ΔABC and ΔDEF, AB = DE, AB || DE, BC = EF and BC || EF. Vertices A, B and C are joined to vertices D, E and F respectively (see Fig. 8.22). Show that (i) quadrilateral ABED is a parallelogram ( ... CF and AD = CF (iv) quadrilateral ACFD is a parallelogram (v) AC = DF (vi) ΔABC ≅ ΔDEF. -Maths 9th

Last Answer : . Solution: (i) AB = DE and AB || DE (Given) Two opposite sides of a quadrilateral are equal and parallel to each other. Thus, quadrilateral ABED is a parallelogram (ii) Again BC = EF and BC || EF ... (Given) BC = EF (Given) AC = DF (Opposite sides of a parallelogram) , ΔABC ≅ ΔDEF [SSS congruency]

For a gaseous reaction, `A(g)+3B(g)to3C(g)+3D(g),DeltaU` is 17 kcal at `27^(@)C`. Assuming `R=2cal" "K^(-1)mol^(-1)`, the value of `DeltaH` for the ab

Description : For a gaseous reaction, `A(g)+3B(g)to3C(g)+3D(g),DeltaU` is 17 kcal at `27^(@)C`. Assuming `R=2cal" "K^(-1)mol^(-1)`, the value of `DeltaH` for the ab

Last Answer : For a gaseous reaction, `A(g)+3B(g)to3C(g)+3D(g),DeltaU` is 17 kcal at `27^(@)C`. Assuming `R=2cal" " ... Kcal B. 18.2 Kcal C. 20.0 Kcal D. 16.4 Kcal

In a circle , chord AB subtends an angle of `60^(@)` at the centre and chord CD subtends `120^(@)`, at it. Then which chord is longer ?

Description : In a circle , chord AB subtends an angle of `60^(@)` at the centre and chord CD subtends `120^(@)`, at it. Then which chord is longer ?

Last Answer : In a circle , chord AB subtends an angle of `60^(@)` at the centre and chord CD subtends `120^(@)`, at it. Then which chord is longer ?

Explain the following instructions. SWAP A ADD C MUL AB CJNE A, add, radd MOV A, R0 MOVX A, @ A + DPTR.

Description : Explain the following instructions. SWAP A ADD C MUL AB CJNE A, add, radd MOV A, R0 MOVX A, @ A + DPTR.

Last Answer : SWAP A Description: This instruction exchanges bits 0-3 of the Accumulator with bits 4-7 of the Accumulator. This instruction is identical to executing "RR A" or "RL A four times ... referred to as the base address and the accumulator value is referred to as the index address.

ABCD is a quadrilateral in which `/_A= 60^(@), /_ B= 70^(@), /_ C =110^(@)` and `/_ D =120^(@)`. The number of pairs of parallel lines is `"__________

Description : ABCD is a quadrilateral in which `/_A= 60^(@), /_ B= 70^(@), /_ C =110^(@)` and `/_ D =120^(@)`. The number of pairs of parallel lines is `"__________

Last Answer : ABCD is a quadrilateral in which `/_A= 60^(@), /_ B= 70^(@), /_ C =110^(@)` and ... )`. The number of pairs of parallel lines is `"________________"`.

In `Delta ABC, /_ A= /_C= 50^(@)`. The longest side of `Delta ABC `is `__________________`.

Description : In `Delta ABC, /_ A= /_C= 50^(@)`. The longest side of `Delta ABC `is `__________________`.

Last Answer : In `Delta ABC, /_ A= /_C= 50^(@)`. The longest side of `Delta ABC `is `__________________`.

In `Delta ABC`, if `/_ A lt /_B lt 45^(@)`, then ABC is a`//` an `"__________________"` triangle.

Description : In `Delta ABC`, if `/_ A lt /_B lt 45^(@)`, then ABC is a`//` an `"__________________"` triangle.

Last Answer : In `Delta ABC`, if `/_ A lt /_B lt 45^(@)`, then ABC is a`//` an `"__________________"` triangle.

AB is a potentiometer wire of length 100 cm and its resistance is `10Omega`. It is connected in series with a resistance R = 40 `Omega` and a battery

Description : AB is a potentiometer wire of length 100 cm and its resistance is `10Omega`. It is connected in series with a resistance R = 40 `Omega` and a battery

Last Answer : AB is a potentiometer wire of length 100 cm and its resistance is `10Omega`. It is connected in series with a ... `1.6V` C. `0.08V` D. `0.16V`

Standard disc Plough consists of steel disc of _ diameter a) 20 to 40 cm. c) 60 to 90 cm b) 30 to 60 cm. d) 70 to 100 cm

Description : Standard disc Plough consists of steel disc of _ diameter a) 20 to 40 cm. c) 60 to 90 cm b) 30 to 60 cm. d) 70 to 100 cm

Last Answer :  60 to 90 cm

Can't seem to figure out the @ reply in red, sorry for my stupid head. Can someone help?

Description : Can't seem to figure out the @ reply in red, sorry for my stupid head. Can someone help?

Last Answer : answer:@babaji The comment is directed to someone else in the question. as I am directing this response to you Type it….it will happen. :)

A long conducting wire carrying a current I is bent at `120^(@) `( see figure). The magnetic field B at a point P on the right bisector of bending ang

Description : A long conducting wire carrying a current I is bent at `120^(@) `( see figure). The magnetic field B at a point P on the right bisector of bending ang

Last Answer : A long conducting wire carrying a current I is bent at `120^(@) `( see figure). The magnetic field B at a ... (3pid))` D. `(sqrt(3mu_(0)I))/(2pid)`

The cost of the earthwork in excavation for the surface drain of cross-section shown in the given figure for a total length of 5 metres @ Rs. 450% cum, is (A) Rs. 400 (B) Rs. 425 (C) Rs. 450 (D) Rs. 500

Description : The cost of the earthwork in excavation for the surface drain of cross-section shown in the given figure for a total length of 5 metres @ Rs. 450% cum, is (A) Rs. 400 (B) Rs. 425 (C) Rs. 450 (D) Rs. 500

Last Answer : (C) Rs. 450

In Fig. 8.31, D is the mid-point of AB and PC = 1/2AP = 3 cm. If AD = DB = 4 cm and DE||BP. Find AE. -Maths 9th

Description : In Fig. 8.31, D is the mid-point of AB and PC = 1/2AP = 3 cm. If AD = DB = 4 cm and DE||BP. Find AE. -Maths 9th

Last Answer : Solution :-

l,m and n are three parallel lines intersected by transversal p and q such that l,m and n cut-off equal intersepts AB and BC on p (Fig.8.55). Show that l,m and n cut - off equal intercepts DE and EF on q also. -Maths 9th

Description : l,m and n are three parallel lines intersected by transversal p and q such that l,m and n cut-off equal intersepts AB and BC on p (Fig.8.55). Show that l,m and n cut - off equal intercepts DE and EF on q also. -Maths 9th

Last Answer : Given:l∥m∥n l,m and n cut off equal intercepts AB and BC on p So,AB=BC To prove:l,m and n cut off equal intercepts DE and EF on q i.e.,DE=EF Proof:In △ACF, B is the mid-point of ... a triangle, parallel to another side, bisects the third side. Since E is the mid-point of DF DE=EF Hence proved.

In Fig. 7.21, AC = AE, AB = AD and BAD = EAC. Show that BC = DE. -Maths 9th

Description : In Fig. 7.21, AC = AE, AB = AD and BAD = EAC. Show that BC = DE. -Maths 9th

Last Answer : It is given that ∠BAD=∠EAC ∠BAD+∠DAC=∠EAC+∠DAC [add ∠DAC on both sides] ∴∠BAC=∠DAE In △BAC and △DAE AB=AD (Given) ∠BAC=∠DAE (Proved above) AC=AE (Given) ∴△BAC≅△DAE (By SAS congruence rule) ∴BC=DE (By CPCT)

When did AB de Villiers retire from international cricket ?

Description : When did AB de Villiers retire from international cricket ?

Last Answer : AB de Villiers of South Africa holds the world record for the fastest ODI century and the fastest ODI fifty known as ' Mr 3600 ' , saying goodbye to international cricket on 23 May 2018 .

On just 31 balls _________ hit a century in 2015 vs West Indies. A. Mark Boucher (RSA) B. Shahid Afridi (PAK) C. Corey Anderson (NZ) D. AB de Villiers (RSA)

Description : On just 31 balls _________ hit a century in 2015 vs West Indies. A. Mark Boucher (RSA) B. Shahid Afridi (PAK) C. Corey Anderson (NZ) D. AB de Villiers (RSA)

Last Answer : ANSWER: D

Only played 16 balls for 50 runs which is a world record in ODI history. A. AB de Villiers (RSA) B. Corey Anderson (NZ) C. Shahid Afridi (PAK) D. Sanath Jayasuriya (SL)

Description : Only played 16 balls for 50 runs which is a world record in ODI history. A. AB de Villiers (RSA) B. Corey Anderson (NZ) C. Shahid Afridi (PAK) D. Sanath Jayasuriya (SL)

Last Answer : ANSWER: A

Only played 16 balls for 50 runs which is a world record in ODI history. A. AB de Villiers (RSA) B. Corey Anderson (NZ) C. Shahid Afridi (PAK) D. Sanath Jayasuriya (SL)

Description : Only played 16 balls for 50 runs which is a world record in ODI history. A. AB de Villiers (RSA) B. Corey Anderson (NZ) C. Shahid Afridi (PAK) D. Sanath Jayasuriya (SL)

Last Answer : ANSWER: A

On just 31 balls _________ hit a century in 2015 vs West Indies. A. Mark Boucher (RSA) B. Shahid Afridi (PAK) C. Corey Anderson (NZ) D. AB de Villiers (RSA)

Description : On just 31 balls _________ hit a century in 2015 vs West Indies. A. Mark Boucher (RSA) B. Shahid Afridi (PAK) C. Corey Anderson (NZ) D. AB de Villiers (RSA)

Last Answer : ANSWER: D

On just 31 balls _________ hit a century in 2015 vs West Indies. A. Corey Anderson (NZ) B. Shahid Afridi (PAK) C. AB de Villiers (RSA) D. Mark Boucher (RSA)

Description : On just 31 balls _________ hit a century in 2015 vs West Indies. A. Corey Anderson (NZ) B. Shahid Afridi (PAK) C. AB de Villiers (RSA) D. Mark Boucher (RSA)

Last Answer : ANSWER: C

Only played 16 balls for 50 runs which is a world record in ODI history. A. Corey Anderson (NZ) B. Shahid Afridi (PAK) C. AB de Villiers (RSA) D. Sanath Jayasuriya (SL)

Description : Only played 16 balls for 50 runs which is a world record in ODI history. A. Corey Anderson (NZ) B. Shahid Afridi (PAK) C. AB de Villiers (RSA) D. Sanath Jayasuriya (SL)

Last Answer : ANSWER: C