Description : If (–2, 6) is the image of the point (4, 2) with respect to the line L = 0, then L is equal to -Maths 9th
Last Answer : (b) 3x - 2y + 5 Let the equation of the L be y = mx + c Since O′ (-2, 6) is the image of the point O (4, 2) in line L = 0, the mid-point of OO′, i.e., \(\bigg(rac{-2+4}{2},rac{6+2}{2}\bigg)\), i.e.,(1, ... ∴ Required equation is y = \(rac{3}{2}x\) + \(rac{5}{2}\)⇒ 3x - 2y + 5 = 0 ∴ L = 3x - 2y + 5.