Description : 1.12 litre dry chlorine gas at STP was passed over a heated metal when 5.56 g of chloride of the metal was formed. What is the equivalent weight of th
Last Answer : 1.12 litre dry chlorine gas at STP was passed over a heated metal when 5.56 g of chloride of ... formed. What is the equivalent weight of the metal ?
Description : 3, 9, 17, 27, 39, 53, ? a) 64 b) 69 c) 74 d) 78 e) 81
Last Answer : Series is 1× 2 + 1, 2 × 3 + 3, 3 × 4 + 5, 4 × 5 + 7, 5 × 6 + 9 Answer: b)
Description : The percentage of P2O5 in diammonium hydrogen phosphate (NH4)2HPO4 is [CPMT 1992] (A) 23.48 (B) 46.96 (C) 53.78 (D) 71.00
Last Answer : (C) 53.78
Description : Which of the following pairs of substances illustrate the law of multiple proportions? [CPMT 1972, 78] (A) CO and CO2 (B) H2O and D2O (C) NaCl and NaBr (D) MgO and Mg(OH)2
Last Answer : (A) CO and CO2
Description : What is the % of H2O in Fe(CNS)3⋅3H2O [CPMT 1981] (A) 45 (B) 30 (C) 19 (D) 25
Last Answer : (C) 19
Description : What is 35.78 plus 39.51?
Last Answer : 75.29 - 39.51 = 35.78
Description : Assume postal rates for 'light letters' are: $0.25 up to 10 grams; $0.35 up to 50 grams; $0.45 up to 75 grams; $0.55 up to 100 grams. Which test inputs (in grams) would be selected using boundary value analysis? A. 0, 9,19, ... C. 0, 1,10,11, 50, 51, 75, 76,100,101 D. 25, 26, 35, 36, 45, 46, 55, 56
Last Answer : C. 0, 1,10,11, 50, 51, 75, 76,100,101
Description : `3 g` of an oxide of a metal is converted completely to `5 g` chloride. Equivalent weight of metal is:
Last Answer : `3 g` of an oxide of a metal is converted completely to `5 g` chloride. Equivalent weight of metal is: A. 33.25 B. 3.325 C. 12 D. 20
Description : Iodised salts contains the iodine salts of which metal? A. Iodine B. Potassium (Answer) C. Sodium Chloride D. Chlorine
Last Answer : B. Potassium (Answer)
Description : 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49, 50'. What number is missing? -Riddles
Last Answer : 22
Description : A molar solution is one that contains one mole of a solute in [IIT 1986] (A) 1000 g of the solvent (B) One litre of the solvent (C) One litre of the solution (D) 22.4 litres of the solution
Last Answer : (C) One litre of the solution
Description : Which property of an element is always a whole number? [MP PMT 1986] (A) Atomic weight (B) Equivalent weight (C) Atomic number (D) Atomic volume
Last Answer : (C) Atomic number
Description : What mass of sodium chloride is produced if 92.0 g of sodium reacts with excess chlorine?
Last Answer : Sodium has an atomic weight of 22.99 g/mol. Chlorine has an atomic weight of 35.45 g/mol. NaCl has an atomic weight of 58.44 g/mol. Therefore 92g of sodium would yield 233.86g of sodium chloride (NaCl).
Description : A grouped frequency distribution table with classes of equal sizes using 63-72 (72 included) as one of the class is constructed for the following data 30, 32, 45, 54, 74, 78, 108, 112, 66, 76, 88, -Maths 9th
Last Answer : NEED ANSWER
Last Answer : (b) We arrange the given data into groups like 13-22,23-32 103-112. (since, our data is from 14 to 112). The class width in this case is 9. Now, the given data can be arranged in tabular form as follows. Hence, the number of classes in distribution will be 10.
Description : Which one of the following Articles of Indian Constitution vests in the President of India the power to issue ordinances? (1) Article 74 (2) Article 78 (3) Article 123 (4) Article 124 (2)
Last Answer : (3) Article 123 Explanation: President can issue ordinance when one of the houses of the Parliament is not in session. The Article 123 deals with Power of President to promulgate Ordinances during recess of Parliament.
Description : If is in kilometres, the curvature correction is (A) 58.2 L2 mm (B) 64.8 L2 mm (C) 74.8 L2 mm (D) 78.4 L2 mm
Last Answer : (D) 78.4 L2 mm
Description : 67,74,78,?,92,94 a) 86 b) 85 c) 83 d) 84 e) 88
Last Answer : The next term is obtained by adding the unit’s digit to the number. Hence the missing number =78+8=86 Answer: a)
Description : A group of 210 students appeared in some test. The mean of of students is found to be 60. The mean of the remaining students is found to be 78. The mean of the whole group will be: (A) 80 (B) 76 (C) 74 (D) 72
Last Answer : Answer: D
Description : A dumper is normally filled in 18 hours but takes 6 hours longer to fill because of a leak in the bottom of the dumper. If the dumper is full the leak will empty it in how many hours? A) 76 hours B) 78 hours C) 72 hours D) 74 hours
Last Answer : C Work done by leak in 1 hr=(1/18-1/24) =>4-3/72 =>1/72 Leak will empty the dumper in 72 hours
Description : A sample of natural gas containing 80% methane (CH4 ) and rest nitrogen (N2 ) is burnt with 20% excess air. With 80% of the combustibles producing CO2 and the remainder going to CO, the Orsat analysis in volume percent is (A) CO2 : 6 ... 96, N2 :72.06 (D) CO2 : 7.60, CO : 1.90, O2 : 4.75, N2 : 85.74
Last Answer : (B) CO2 : 7.42, CO : 1.86, O2 : 4.64, N2 :86.02
Description : The percentage of oxygen in NaOH is [CPMT 1979] (A) 40 (B) 60 (C) 8 (D) 10
Last Answer : (A) 40
Description : In known elements, the maximum number is of [CPMT 1985] (A) Metals (B) Non-metals (C) Metalloids (D) None of these
Last Answer : (A) Metals
Description : Two samples of lead oxide were separately reduced to metallic lead by heating in a current of hydrogen. The weight of lead from one oxide was half the weight of lead obtained from the other oxide. ... (B) Law of constant proportions (C) Law of multiple proportions (D) Law of equivalent proportions
Last Answer : (C) Law of multiple proportions
Description : If 31.3 g of manganese(II) chloride 48.3 g of chlorine gas and 25.7 g of water react to produce manganese(IV) oxide and hydrochloric acid what is the limiting reactant and what mass of hydrochloric?
Last Answer : Need answer
Description : The median of the data 78, 56, 22, 34, 45, 54, 39, 68, 54 and 84 is -Maths 9th
Last Answer : According to question find the median of the data
Description : What is the greatest common factor of 39 36 42 and 78?
Last Answer : The GCF is 3.
Description : Find the internal field when the applied field is 12 units, molecular field constant is 0.1 units and the magnetization is 74 units. a) 86 b) 62 c) 752 d) 19.4
Last Answer : d) 19.4
Description : Non-metallic character increases from (1) Magnesium to Barium (2) Potassium to Cesium (3) Oxygen to Selenium (4) Sodium to Chlorine
Last Answer : (4) Sodium to Chlorine Explanation: The elements which lose electrons to form cations are known as metals. Metallic character decreases across a period as we move from left to right.
Description : A moist soil sample of volume 60 cc. weighs 108 g and its dried weight is 86.4 g. If its absolute density is 2.52, the degree of saturation is (A) 54 % (B) 64 % (C) 74 % (D) 84 %
Last Answer : (D) 84 %
Description : 0.3780g of organic chloro compound gave 0.5740g of silver chloride in carius estimation .Calculate the percentage of chlorine present in the compound.
Last Answer : % of chlorine = 35.5*mass of AgCl formed * 100/143.5 * mass of the substance = 35.5*0.5740*100/143.5*0.3780 = 19.6 %
Description : If D is the diameter of a circular sewer and D’ is the top horizontal diameter of an equivalent egg shaped section, the relationship which holds good, is A. D’ = 0.64 D B. D’ = 0.74 D C. D’ = 0.84 D D. D’ = 0.94 D
Last Answer : ANS: C
Description : Number of moles of CaO required to remove hardness from 1000 litre water having 324 ppm of calcuim bicarbonate and 74.5 ppm of potassium chloride is :
Last Answer : Number of moles of CaO required to remove hardness from 1000 litre water having 324 ppm of calcuim bicarbonate and 74.5 ppm ... : A. 8 B. 4 C. 3 D. 2
Description : A shot-put is a metallic sphere of radius 4.9 cm. If the density of the metal is 7.8 g/cm3. -Maths 9th
Last Answer : We have, the radius of a metallic sphere (r) = 4.9 cm ∴ Volume of the sphere = 4 / 3 πr3 = 4 / 3 × 22 / 7 × 4.9 × 4.9 × 4.9 = 493.005 cm3 ∵ Density of the metal used = 7.8 g/cm3 Hence, the mass of the shot - put = 493.005 × 7.8 = 3845.44
Description : What is the spectrum of stereophonic FM signal? A. 19 to 38 kHz B. 30 to 53 kHz C. 59.5 to 74.5 kHz D. 88 to 108 MHz
Last Answer : B. 30 to 53 kHz
Description : The frequency spectrum of the stereophonic FM signal. A. 67 kHz B. 59.5 to 74.5 kHz C. 19 to 38 kHz D. 30 to 53 kHz
Last Answer : D. 30 to 53 kHz
Description : What is the number that comes next in the sequence? 2, 5, 9, 19, 37, __ (A) 76 (B) 74 (C) 75 (D) 50
Last Answer : Answer: C
Description : The next number in the series 2, 5, 9, 19, 37, ? will be (A) 74 (B) 75 (C) 76 (D) None of the above
Last Answer : Answer: B 2 * 2 = 4 + 1 = 5, 5 * 2 = 10 - 1 = 9, 9 * 2 = 18 +1 = 19, 19*2 = 38 - 1 = 37, 37*2 = 74 + 1= 75.
Description : 1 mole of `OH^(-)` ions is obtained from 85 g of hydroxide of a metal. What is the equivalent weight of the metal ?
Last Answer : 1 mole of `OH^(-)` ions is obtained from 85 g of hydroxide of a metal. What is the equivalent weight of the metal ?
Description : How many times can 19 go into 74?
Last Answer : 3 R 17
Description : At 60° C, vapour pressure of methanol and water are 84.562 kPa and 19.953 kPa respectively. An aqueous solution of methanol at 60° C exerts a pressure of 39.223 kPa; the liquid phase and vapour phase mole ... respectively. Activity co-efficient of methanol is (A) 1.572 (B) 1.9398 (C) 3.389
Last Answer : (A) 1.572
Description : 0.98 g of the metal sulphate was dissolved in water and excess of barium chloride was added. The precipitated barium sulphate weighted 0.95 g. Calcula
Last Answer : 0.98 g of the metal sulphate was dissolved in water and excess of barium chloride was added. ... 95 g. Calculate the equivalent weight of the metal.
Description : 79.93 × 35.02 -59.93 × 85.08 + 74.98 × 44.04 =? a) 1420 b) 1000 c) 1580 d) 870 e) 1260
Last Answer : ? ≈ 80 × 35-60 × 85 + 75 × 44 =2800 – 5100 + 3300 = 1000 Answer: b)
Description : How many litres of `Cl_(2)` at STP will be liberated by the oxidation of `NaCl` with `10 g KMnO_(4)` in acidic medium: (Atomic weight: `Mn=55 and K=39
Last Answer : How many litres of `Cl_(2)` at STP will be liberated by the oxidation of `NaCl` with `10 g KMnO_(4)` in ... 3.54 B. 7.08 C. 1.77 D. None of these
Description : What are the answers to spelling practice book grade 5 lesson 19 page 78?
Last Answer : none
Description : (a) Define a balanced chemical equation. Why should an equation be balanced? (b) Write the balanced chemical equation for the following reaction: (i) Phosphorus burns in presence of chlorine to form phosphorus penta chloride. (ii) Burning of natural gas. (iii) The process of respiration. -Chemistry
Last Answer : Answer. (a) Balanced chemical equation has an equal number of atoms of different elements in the reactants and products. According to law of conservation of mass, matter can neither be created nor be destroyed in a chemical ... C6H12O6 (s) + 6O2 (g) + 6H2O ---> 6CO2 (aq) + 12H2O (l) + energy
Description : (a) Write electron dot diagram for chlorine (At No. 17) and calcium (At No. 20). Show the formation of calcium chloride by transfer of electrons. (b) Identify the nature of above compound’and explain three physical properties of such compound. -Chemistry
Last Answer : (b) It is ionic compound. Physical properties 1.It is hard and solid. 2.It has high melting and boiling point. 3.It soluble in water.