Description : In the reaction , `4A+2B+3CtoA_(4)B_(2)C_(3)` what will be the number of moles of product formed , starting from 1 mole of A,06 mole of B and 0.72 mol
Last Answer : In the reaction , `4A+2B+3CtoA_(4)B_(2)C_(3)` what will be the number of moles of product formed , starting from 1 ... A. 0.25 B. 0.3 C. 2.4 D. 0.24
Description : The number of moles of sodium oxide in 620 g is [BHU 1992] (A) 1 mol (B) 10 moles (C) 18 moles (D) 100 moles
Last Answer : (B) 10 moles
Description : For the given reaction , `A(g) rarr 2B(g) , Delta_(r)H= 30 kJ//"mole" Delta_(r)S = 150 J//mol` at `300 K` If `C_(P,A) = 20 J//K mol` and `C_(P,B) = 20
Last Answer : For the given reaction , `A(g) rarr 2B(g) , Delta_(r)H= 30 kJ//"mole" Delta_(r)S = 150 J//mol` at ... G` is negative D. At `T = 200, Delta G` is zero
Description : For the reaction `Ag_(2)O(s)rarr 2Ag(s)+1//2O_(2)(g)` the value of `Delta H=30.56 KJ mol^(_1)` and `Delta S = 66 JK^(-1)mol^(-1)`. The temperature at
Last Answer : For the reaction `Ag_(2)O(s)rarr 2Ag(s)+1//2O_(2)(g)` the value of `Delta H=30.56 KJ mol^(_1)` and `Delta ... :- A. 373 K B. 413 K C. 463 K D. 493 K
Description : The temperature at which the reaction : `Ag_(2)O(s)rarr 2Ag(s)+1//2O_(2)(g)` is at equilibrium is …….., Given `Delta H=30.5 KJ mol^(-1)` and `Delta S
Last Answer : The temperature at which the reaction : `Ag_(2)O(s)rarr 2Ag(s)+1//2O_(2)(g)` is at equilibrium is .., ... 362.12 K` C. `262.12 K` D. `562.12 K`
Description : Total aldol condensation products (including stereosimers) formed by the reaction between acetaldehyde and acetophenone is :
Last Answer : Total aldol condensation products (including stereosimers) formed by the reaction between acetaldehyde and acetophenone is :
Description : What number of moles of O2 is required to react with 3.6 mol SO2 in the following reaction 2S02 plus O2 2SO3?
Last Answer : 1,8 of moles of O2 are required.
Description : In the reaction M g C I 2 plus 2 KO H - and gt MG OH 2 plus 2 K CI if 1 mole Mg CI 2 is added to 3 moles KO H what is the limiting reagent?
Last Answer : Feel Free to Answer
Description : Silver (atomic weight `108 g mol^(-1))` has a density of `10.5 g cm^(-3)`. The number of silver atoms on a surfaces of area `10^(-12) m^(2)` can be ex
Last Answer : Silver (atomic weight `108 g mol^(-1))` has a density of `10.5 g cm^(-3)`. The number of silver atoms on a ... `Y xx 10^(-x)`, The value of `x` is .
Description : The enthalpy changes at 298 K in successive breaking of `O-H` bonds of water, are `H_(2)O(g) rarr H(g)+OH(g),DeltaH=498kJ mol^(-1)` `OH(g) rarr H(g)+O
Last Answer : The enthalpy changes at 298 K in successive breaking of `O-H` bonds of water, are `H_(2)O(g) rarr H(g)+OH(g), ... KJ mol"^(-1)` D. `463 "KJ mol"^(-1)`
Description : For `CaCO_(3)(s)rarr CaO(s)+CO_(2)(g)` at `977^(@)C, Delta H = 174` KJ/mol , then `Delta E` is :-
Last Answer : For `CaCO_(3)(s)rarr CaO(s)+CO_(2)(g)` at `977^(@)C, Delta H = 174` KJ/mol , then `Delta E` is :- A. 160 KJ B. 163.6 KJ C. 186.4 KJ D. 180 KJ
Description : One moles of anhydrous `AB` dissolves in water and liberates `21.0 J mol^(-1)` of heat. The valueof `DeltaH^(Theta)` (hydration) of `AB` is `-29.4 J m
Last Answer : One moles of anhydrous `AB` dissolves in water and liberates `21.0 J mol^(-1)` of heat. The valueof `DeltaH^(Theta) ... mol^(-1)` D. `-8.4 J mol^(-1)`
Description : An adult human lung has a volume of 2.9 liters. If its volume decreases to 1.2 liters and it contains 0.049 mole of air after it exhales, how many moles of air does it contain when full A. 0.025 mol B. 0.041 mol C. 0.083 mol D. 0.12 mol E. 0.14 mol?
Last Answer : An adult human lung has a volume of 2.9 liters. If its volume decreases to 1.2 liters and it contains 0.049 mole of air after it exhales, how many moles of air does it contain when full? A. 0.025 mol B. 0.041 mol C. 0.083 mol D. 0.12 mol E. 0.14 mol
Description : how many moles of NO2 are in 7.4 mol N2O5?
Last Answer : N2O5(g) → 4NO2(g) + O2(g)
Description : Normality is defined as the number of: w) moles of solute per 1000 grams of solvent x) equivalent weights of solute per liter of solution y) kilograms of solute per liter of solution z) moles of solute per 1000 grams of solution
Last Answer : ANSWER: X -- EQUIVALENT WEIGHTS OF SOLUTE PER LITER OF SOLUTION
Description : How many moles are there in 140 g of Si (atomic mass of silicon is 28)?
Last Answer : 5
Description : Can anyone help me with this? Chlorine and carbon monoxide gases are mixed in a 1.00L container and the following equilibrium is established: CO(g) + Cl2(g) COCl2(g).. Initially 1.5 mol of ... monoxide. At equilibrium, 0.8 mol of COCl2(g) was found. How do you calculate the percent reaction?
Last Answer : For a start, your equation isn't balanced; it should be Cl2 (Cl2, not 2Cl, because of HONClBrIF). Given this, if we assume the reaction goes to completion, 1.5 mol Cl2 will produce 1.5 mol ... .3% Incidentally, is that supposed to be CO or Co? It has no effect on the calculation, just curious.
Description : The enthalpy of formation of ammonia is `-46.0 KJ mol^(-1)` . The enthalpy change for the reaction `2NH_(3)(g)rarr N_(2)(g)+3H_(2)(g)` is :
Last Answer : The enthalpy of formation of ammonia is `-46.0 KJ mol^(-1)` . The enthalpy change for the reaction `2NH_(3)(g) ... mol^(-1)` D. `-92.0 KJ mol^(-1)`
Description : For a reaction `2X(s)+2Y(s)rarr 2Cl(l)+D(g)` The `q_(p)` at `27^(@)C` is -28 K Cal. `mol^(-1)`. The `q_(V)` is ___________ K. Cal. `mol^(-1)` :-
Last Answer : For a reaction `2X(s)+2Y(s)rarr 2Cl(l)+D(g)` The `q_(p)` at `27^(@)C` is -28 K Cal. `mol^(-1)`. The `q_( ... . `-27.4` B. `+27.4` C. `-28.6` D. `28.6`
Description : For a gaseous reaction, `A(g)+3B(g)to3C(g)+3D(g),DeltaU` is 17 kcal at `27^(@)C`. Assuming `R=2cal" "K^(-1)mol^(-1)`, the value of `DeltaH` for the ab
Last Answer : For a gaseous reaction, `A(g)+3B(g)to3C(g)+3D(g),DeltaU` is 17 kcal at `27^(@)C`. Assuming `R=2cal" " ... Kcal B. 18.2 Kcal C. 20.0 Kcal D. 16.4 Kcal
Description : The value of enthalpy change `(DeltaH)` for the reaction `C_(2)H_(5)OH (l)+3O_(2) (g) rarr 2CO_(2) (g) +3H_(2)O (l)` at `27^(@)C` is `-1366.5 kJ mol^(
Last Answer : The value of enthalpy change `(DeltaH)` for the reaction `C_(2)H_(5)OH (l)+3O_(2) (g) rarr 2CO_(2) (g) + ... 1369. kJ` C. `-1364.0 kJ` D. `-1361.5 kJ`
Description : The enthalpy of formation of `CO(g), CO_(2)(g),N_(2)O(g)` and `N_(2)O_(4)(g)` is `-110,-393,+81` and 10 kJ / mol respectively. For the reaction `N_(2)
Last Answer : The enthalpy of formation of `CO(g), CO_(2)(g),N_(2)O(g)` and `N_(2)O_(4)(g)` is `-110,-393,+81` and 10 ... is A. `-212` B. `+212` C. `+778` D. `-778`
Description : The enthalpy and entropy change for the reaction, `Br_(2)(l)+Cl_(2)(g)rarr2BrCl(g)` are `30KJmol^(-1)` and `105JK^(-1)mol^(-1)` respectively. The temp
Last Answer : The enthalpy and entropy change for the reaction, `Br_(2)(l)+Cl_(2)(g)rarr2BrCl(g)` are `30KJmol^(-1)` and ` ... 285.7 K B. 273 K C. 450 K D. 300 K
Description : In the balanced equation `MnO_(4)^(-)+H^(+)+C_(2)O_(4)^(2-)rarr Mn^(2+)+CO_(2)+H_(2)O`, the moles of `CO_(2)` formed are :-
Last Answer : In the balanced equation `MnO_(4)^(-)+H^(+)+C_(2)O_(4)^(2-)rarr Mn^(2+)+CO_(2)+H_(2)O`, the moles of `CO_(2)` formed are :- A. 2 B. 4 C. 5 D. 10
Description : When 22.4 litres of `H_(2)(g)` is mixed with 11.2 litres of `CI_(2)(g)`, eacg at STP, the moles of HCI(g) formed is equal to :-
Last Answer : When 22.4 litres of `H_(2)(g)` is mixed with 11.2 litres of `CI_(2)(g)`, eacg at STP, the moles of HCI(g ... ) C. 1 mol of HCI (g) D. 2 mol of HCI (g)
Description : If 3 moles of a compound use 12 j of energy in a reaction what is the h f in kjmol?
Last Answer : Need answer
Description : For a reaction `H_(2(g))+I_(2(g))rArr2HI_((g))at 721^(@)C` the value of equilibrium constant is 50 . If 0.5 moles each of `H_(2)` & `I(2)` is added to
Last Answer : For a reaction `H_(2(g))+I_(2(g))rArr2HI_((g))at 721^(@)C` the value of equilibrium constant is 50 . ... constant will be . A. 100 B. 25 C. 50 D. 200
Description : For the reversible reaction A ⇌ 2B, if the equilibrium constant K is 0.05 mole/litre; starting from initially 2 moles of A and zero moles of B, how many moles will be formed at equilibrium? (A) 0.253 (B) 0.338 (C) 0.152 (D) 0.637
Last Answer : (B) 0.338
Description : Which of the following is not a unit of reaction rate? (A) Moles for med/(surface of catalyst) (time) (B) Moles formed/volume of reactor) (time) (C) Mole formed/volume of catalyst) (time) (D) None of these
Last Answer : (D) None of these
Description : Given that standard heat enthalpy of `CH_(4), C_(2)H_(4)` and `C_(3)H_(8)` are -17.9, 12.5, -24.8 Kcal/mol. The `Delta H` for `CH_(4)+C_(2)Hrarr C_(3)
Last Answer : Given that standard heat enthalpy of `CH_(4), C_(2)H_(4)` and `C_(3)H_(8)` are -17.9, 12.5, -24.8 Kcal ... . `-30.2` Kcal C. 55.2 Kcal D. `-19.4` Kcal
Description : In an organic compound of molar mass `108 gm mol^-1 C, H and N` atoms are presents in `9 : 1 : 3.5` by mass. Molecular can be
Last Answer : In an organic compound of molar mass `108 gm mol^-1 C, H and N` atoms are presents in `9 : 1 : 3.5` by mass. ... (5)H_(6)N_(3)` D. `C_(4)H_(18)N_(3)`
Description : The order of reaction is the number of moles whose concentrations determine the rate of a reaction at a given temperature Give the integrated equation for first order reaction. K = (2.303 / t) * log (a ... a' is the initial concentration of reactants x' is the amount reacted in time t seconds
Last Answer : What is Threshold energy ?
Description : The cause of fractional atomic weights of elements? -Do You Know?
Last Answer : Atomic masses of most of the elements in atomic mass units involve fractions because atomic mass of an element is the average of relative masses of its various isotopes. While taking average, the result appears as a fraction.
Description : What atoms of the same element but with various atomic weights?
Last Answer : These are the isotopes.
Description : The cause of periodicity of properties (a) Increasing atomic radius (b) Increasing atomic weights (c) Number of electrons in the valency orbit (d) The recurrence of similar outer electronic configuration
Last Answer : Ans:(d)
Description : In which of the following groups, are the elements written in the descending order of their respective atomic weights? (a) Nitrogen, carbon, oxygen, hydrogen (b) Oxygen, argon, nitrogen, hydrogen (c) Oxygen, nitrogen, helium, hydrogen (d) Oxygen, nitrogen, helium, bromine
Last Answer : Ans:(c)
Description : The cause of fractional atomic weights of elements?
Last Answer : The presence of Isotopes
Description : Which one is different for the neutral atoms of the isotopes of an element? (A) Atomic weights (B) Atomic numbers (C) Number of protons (D) Number of electrons
Last Answer : (A) Atomic weights
Last Answer : e presence of Isotopes
Description : Who was the first American chemist to receive a Nobel Prize? He was selected in 1914 for his precise determination of atomic weights. w) Edward Frankland x) Theodore Richards y) John Bardeen z) Paul Dirac
Last Answer : ANSWER: X -- THEODORE RICHARDS
Description : 1. Where do Sweat glands occur in greatest number? 2. What is the electorate for a Panchayat? 3. The cause of fractional atomic weights of elements? 4. The second largest river basin in India is ... 19. Why does Mumbai receives more rainfall than Pune? 20. What was the real name of Tantiya Tope?
Last Answer : Answer : 1 1. In the skin of the armpits 2. The Gram Sabha 3. The presence of Isotopes 4. Godavari 5. Guru Hargovind 6. Friedrich Engels 7. Cooperation 8. 30 9. Krishna Basin 10. ... Birds from reptiles 18. Dr. Rajendra Prasad 19. Because mumbai is on the windward side 20. Ramchandra Panduranga
Description : Arrange the following carboxyl compounds in increasing order of their reactivity in nucleophilic addition reactions. Explain with proper reasoning : Benzaldehyde. p-tolualdeyde, p-nitrobenzaldehyde, Acetophenone.
Last Answer : Ans. Acetophenone is a ketone while all others are aldehydes, therefore it is least reactive. In p-tolualdehyde, there is methyl group (CH3 ) at para position w.r.t. to the ... overall order of increasing reactivity : acetophenone < p-tolualdehyde < benzaldehyde < p-nitrobenzaldehyde.
Description : Phenylmagnesium bromide reacts with CO2 followed by acid-hydrolysis to form : (a) Phenol (b) Benzoic acid (c) Bromobenzene (d) Acetophenone
Last Answer : Benzoic acid
Description : Which of the following compounds yields a yellow precipitate when warmed with a mixture of iodine in aqueous sodium hydroxide? (a) Acetophenone (b) Benzaldehyde (c) Benzophenone (d) Propanal
Last Answer : Acetophenone
Description : Benzaldehyde can be distinguished from acetophenone by using : (a) Tollens' reagent (b) Lucas reagent (c) Fehling's reagent (d) All of these
Last Answer : Tollens' reagent
Description : Acetophenone reacts with Br2 in the presence of FeCl3 to form : (a) m-Bromoacetophenone (b) m-Dibromobenzene (c) o- + p-Bromoacetophenone (d) p-Dibromobenzene
Last Answer : m-Bromoacetophenone
Description : Benzaldehyde reacts with methylmagnesium iodide (followed by hydrolysis) to form (a) 1-Phenylethanol (b) Acetophenone (c) 2-Phenylethanol (c) Benzophenone
Last Answer : 1-Phenylethanol
Description : Benzene reacts with acetic anhydride in the presence of AlCl3 to form (a) Acetophenone (b) Benzophenone (c) Phenylacetic acid (d) Phenyl acetate