When 22.4 litres of `H_(2)(g)` is mixed with 11.2 litres of `CI_(2)(g)`, eacg at STP, the moles of HCI(g) formed is equal to :-

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When 22.4 litres of `H_(2)(g)` is mixed with 11.2 litres of `CI_(2)(g)`, eacg at STP, the moles of HCI(g ... ) C. 1 mol of HCI (g) D. 2 mol of HCI (g)

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