A car starts from rest and moves with constant acceleration. In first t seconds it covers distance x. Then distance covered by it in next t seconds wi

A car starts from rest and moves with constant acceleration. In first t seconds it covers distance x. Then distance covered by it in next t seconds wi
by

1 Answer

Answer :

A car starts from rest and moves with constant acceleration. In first t seconds it covers distance x. Then distance covered ... x B. 2 x C. 3 x D. 4 x
by

Related questions

A car starts from rest and moves on a straight road with a uniform acceleration of 10 m/s2 for the first 10 s. During the next 10 s, the car move s with the velocity it has attained. What is the total distance covered by the car in 20 s? (a) 500 m (b) 1000 m (c) 1,500 m (d) 2,000 m

Description : A car starts from rest and moves on a straight road with a uniform acceleration of 10 m/s2 for the first 10 s. During the next 10 s, the car move s with the velocity it has attained. What is the total distance covered by the car in 20 s? (a) 500 m (b) 1000 m (c) 1,500 m (d) 2,000 m

Last Answer : Ans:(c)

If a sled has a constant acceleration of 2 meters per second squared and starts from rest, the distance in meters that it will have covered after 5 seconds is: w) 10 meters x) 20 meters y) 25 meters z) 50 meters

Description : If a sled has a constant acceleration of 2 meters per second squared and starts from rest, the distance in meters that it will have covered after 5 seconds is: w) 10 meters x) 20 meters y) 25 meters z) 50 meters

Last Answer : ANSWER: Y -- 25 METERS

A body moves, from rest with a constant acceleration of 5 m per sec. The distance covered in 5 sec is most nearly (A) 38 m (B) 62.5 m (C) 96 m (D) 124 m

Description : A body moves, from rest with a constant acceleration of 5 m per sec. The distance covered in 5 sec  is most nearly  (A) 38 m  (B) 62.5 m  (C) 96 m  (D) 124 m

Last Answer : (B) 62.5 m 

A particle experiences constant acceleration for 20 seconds after starting from rest. If it travels a distance D1 in the first 10 seconds and distance D2 in the next 10 seconds then, (a) D2 = D1 (b) D2 = 2D1 (c) D2 = 3D1 (d) D2 = 4D1 -Science

Description : A particle experiences constant acceleration for 20 seconds after starting from rest. If it travels a distance D1 in the first 10 seconds and distance D2 in the next 10 seconds then, (a) D2 = D1 (b) D2 = 2D1 (c) D2 = 3D1 (d) D2 = 4D1 -Science

Last Answer : (c) is the answer

An aeroplane has a run of 500 m to take off from the runway. It starts from rest and moves with constant acceleration

Description : An aeroplane has a run of 500 m to take off from the runway. It starts from rest and moves with constant acceleration

Last Answer : An aeroplane has a run of 500 m to take off from the runway. It starts from rest and moves with ... is the velocity of the aeroplane at the take off ?

A car traveling at a constant velocity of 20 meters per second passes a second car which is initially at rest. The car which was at rest starts accelerating at 10 meters per second squared the instant it is passed by the first car. They will meet again in: w) 2 seconds x) 4 seconds y) 6 seconds z) 8 seconds

Description : A car traveling at a constant velocity of 20 meters per second passes a second car which is initially at rest. The car which was at rest starts accelerating at 10 meters per second squared the instant it is passed ... car. They will meet again in: w) 2 seconds x) 4 seconds y) 6 seconds z) 8 seconds

Last Answer : ANSWER: X -- 4 SECONDS

A particle starts from rest and moves in a straight line whose equation of motion is given by S = 2t3 - t2 - 1. The acceleration of the particle after one sec will be a.6 m/sec2 b.4 m/sec2 c.12 m/sec2 d.10 m/sec2 e.8 m/sec2

Description : A particle starts from rest and moves in a straight line whose equation of motion is given by S = 2t3 - t2 - 1. The acceleration of the particle after one sec will be a.6 m/sec2 b.4 m/sec2 c.12 m/sec2 d.10 m/sec2 e.8 m/sec2

Last Answer : d. 10 m/sec2

The velocity-time graph shows the motion of a cyclist. Find (i) its acceleration (ii) its velocity (iii) the distance covered by the cyclist in 15 seconds Numerical Questions and answers on Motion for Class 9 physics -Science

Description : The velocity-time graph shows the motion of a cyclist. Find (i) its acceleration (ii) its velocity (iii) the distance covered by the cyclist in 15 seconds Numerical Questions and answers on Motion for Class 9 physics -Science

Last Answer : (i) We can see from the graph that velocity is not changing So,acceleration is equal to zero. (ii) By Reading the graph, velocity = 20 m/s (iii) Distance covered in 15 seconds, s=u×t=20×15=300s=u×t=20×15=300 m

An object covers distance which is directly proportional to the square of the time. Its acceleration is – (1) increasing (2) decreasing (3) zero (4) constant

Description : An object covers distance which is directly proportional to the square of the time. Its acceleration is – (1) increasing (2) decreasing (3) zero (4) constant

Last Answer : (4) constant Explanation: When an object covers distance which is directly proportional to the square of the time, its acceleration is constant. This is seen in the cases of falling objects. This connection between time and distance was first observed by Galileo.

The average person passes out at an acceleration of 7g (that is, seven times the gravitational acceleration on Earth). Suppose a car is designed to accelerate at this rate. How much time (in seconds) would be required for the car to accelerate from rest to 56.3 miles per hour?

Description : The average person passes out at an acceleration of 7g (that is, seven times the gravitational acceleration on Earth). Suppose a car is designed to accelerate at this rate. How much time (in seconds) would be required for the car to accelerate from rest to 56.3 miles per hour?

Last Answer : I think the Fluther policy is not to help students with their homework, but I always hate this kind of problem and it seems to me that the g is just in there to provide some background and to confuse you.

A bike starts with a speed of 60 km/hr at 8a.m. Due to the problem in engine it reduces its speed as 20 km/hr for every 1 hour. After 9 am, the time taken to covers 15 km is: a) 13 minutes and 20 seconds b) 15 minutes and 09 seconds c) 18 minutes and 15 seconds d) 22 minutes and 30 seconds

Description : A bike starts with a speed of 60 km/hr at 8a.m. Due to the problem in engine it reduces its speed as 20 km/hr for every 1 hour. After 9 am, the time taken to covers 15 km is: a) 13 minutes and 20 seconds b) 15 minutes and 09 seconds c) 18 minutes and 15 seconds d) 22 minutes and 30 seconds

Last Answer : 15 min

A car and lorry are both moving with equal kinetic energy. If equal breaking force is applied on both, then before coming to rest the (a) Car will cover a greater distance (b) Lorry will cover a greater distance (c) Both will cover the same distance (d) The distance covered by them will depend only on their respective velocities

Description : A car and lorry are both moving with equal kinetic energy. If equal breaking force is applied on both, then before coming to rest the (a) Car will cover a greater distance (b) Lorry ... will cover the same distance (d) The distance covered by them will depend only on their respective velocities

Last Answer : Ans:(c)

A car accelerates from rest at a constant rate of `2 m//s^(2)` and comes to rest. If it remains in motion for 3 seconds, then the maximum speed attain

Description : A car accelerates from rest at a constant rate of `2 m//s^(2)` and comes to rest. If it remains in motion for 3 seconds, then the maximum speed attain

Last Answer : A car accelerates from rest at a constant rate of `2 m//s^(2)` and comes to rest. If it remains in motion for 3 ... s B. 3 m/s C. 4 m/s D. 6 m/s

In a 2280 m race Dinesh beats Aarav by 360 m or 6 seconds. In another race on the same track at the same speeds. Aarav and karthick start at one end while Dinesh starts at the opposite end. How many metres would Aarav have covered ,by the time Dinesh meets karthick given that Dinesh speed is 16 m/sec more than that of karthick a) 1140 m b) 2280 m c) 2460 m d) 1180 m

Description : In a 2280 m race Dinesh beats Aarav by 360 m or 6 seconds. In another race on the same track at the same speeds. Aarav and karthick start at one end while Dinesh starts at the opposite end. How many metres would Aarav ... is 16 m/sec more than that of karthick a) 1140 m b) 2280 m c) 2460 m d) 1180 m

Last Answer : B Aarav 's speed =360/6 =60 m/s Time taken by Aarav to cover 2280 m =2280/60= 38 seconds Dinesh 's speed = 2280/60=38 m/s karthick 's speed = 22m/s Time taken by Dinesh to meet karthick in ... direction: Distance covered by Aarav: =2280/(38+22) =2280/60 =38 seconds =(38*60)m =2280 m

A man pulls a cart with 100 N force from rest with an acceleration of 10 m/sec2 for 10 seconds. The work done by him is a.500 KJ b.50.96 KJ c.101.92 KJ d.None of the above e.Tapered bearing

Description : A man pulls a cart with 100 N force from rest with an acceleration of 10 m/sec2 for 10 seconds. The work done by him is a.500 KJ b.50.96 KJ c.101.92 KJ d.None of the above e.Tapered bearing

Last Answer : a. 500 KJ

A wheel accelerates from rest with an acceleration of 6 rad/sec2. How many revolutions are experienced in 4 seconds? a.12.36 b.25.6 c.9.82 d.107 dynes e.7.64

Description : A wheel accelerates from rest with an acceleration of 6 rad/sec2. How many revolutions are experienced in 4 seconds? a.12.36 b.25.6 c.9.82 d.107 dynes e.7.64

Last Answer : e. 7.64

When a proton is released from rest in a room, it starts with an initial acceleration `a_(0)` towards west. When it is projected towards north with a

Description : When a proton is released from rest in a room, it starts with an initial acceleration `a_(0)` towards west. When it is projected towards north with a

Last Answer : When a proton is released from rest in a room, it starts with an initial acceleration `a_(0)` towards west. ... e) "east"(3ma_(0))/(ev_(0))"down"`

Raghu starts a bike at 40 km/hr and he increases his speed in every hour by 4 km/hr. Then the maximum distance covered by him in 12 hours is: a) 744 km b) 658 km c) 436 km d) 512 km

Description : Raghu starts a bike at 40 km/hr and he increases his speed in every hour by 4 km/hr. Then the maximum distance covered by him in 12 hours is: a) 744 km b) 658 km c) 436 km d) 512 km

Last Answer : A Speed of the rider = 40km/hr. Distance covered in 1st hour = 40 km. He increased his speed in every 1 hour by 4 km/hr. Distance covered in every 1 hours will be, 44, 48, ,... upto 12 terms.(for 12 hours). ... (2(40)+(11)4) = 6(80 + 44) = 6(124) = 744. Hence, he covers 744 km in 12 hours.

The number of revolutions through which a pulley will rotate from rest if its angular acceleration is increased uniformly from zero to 12 rad per sec2 during 4 sec and then uniformly decreased to 0 rad per sec2 during the next 3 sec would be a.46.4 b.26.74 c.11.6 d.3.2 e.17.7

Description : The number of revolutions through which a pulley will rotate from rest if its angular acceleration is increased uniformly from zero to 12 rad per sec2 during 4 sec and then uniformly decreased to 0 rad per sec2 during the next 3 sec would be a.46.4 b.26.74 c.11.6 d.3.2 e.17.7

Last Answer : b. 26.74

The position of a particle with respect to time is given by the equation: x = t3 + 2 where x is in feet and t is in seconds. What is the acceleration of the particle at a time of 2 seconds?

Description : The position of a particle with respect to time is given by the equation: x = t3 + 2 where x is in feet and t is in seconds. What is the acceleration of the particle at a time of 2 seconds?

Last Answer : ANSWER: 12 FEET PER SECOND SQUARED

A particle moving in a straight line covers half the distance with speed of 3 m/s. The other half of the distance covered in two equal time intervals

Description : A particle moving in a straight line covers half the distance with speed of 3 m/s. The other half of the distance covered in two equal time intervals

Last Answer : A particle moving in a straight line covers half the distance with speed of 3 m/s. The other half of the distance covered ... /s C. 5.5 m/s D. 4.8 m/s

Which of the following statements dealing with simple harmonic motion of a mass-spring system is TRUE? w) The acceleration is largest when the oscillating mass is instantaneously at rest. x) The larger the spring force constant the larger the period. y) The period of the motion depends linearly on the amplitude of the motion. z) The acceleration is larger when the oscillating mass has its greatest velocity.

Description : Which of the following statements dealing with simple harmonic motion of a mass-spring system is TRUE? w) The acceleration is largest when the oscillating mass is instantaneously at rest. x) The ... of the motion. z) The acceleration is larger when the oscillating mass has its greatest velocity.

Last Answer : ANSWER: W -- THE ACCELERATION IS LARGEST WHEN THE OSCILLATING MASS IS INSTANTANEOUSLY AT REST 

A flywheel rotating at 5 revolutions per second is brought to rest by a constant torque in 10 seconds. How many revolutions does the flywheel make while coming to a stop? w) 25 x) 50 y) 75 z) 100

Description : A flywheel rotating at 5 revolutions per second is brought to rest by a constant torque in 10 seconds. How many revolutions does the flywheel make while coming to a stop? w) 25 x) 50 y) 75 z) 100

Last Answer : ANSWER: W -- 25

A particle is acted upon by a force of constant magnitude which is always perpendicular to the velocity of the particle. The motion of the particle takes place in a plane. It follows that (a) Its velocity is constant (b) Its acceleration is constant (c) Its kinetic energy is constant (d) It moves in a circular path

Description : A particle is acted upon by a force of constant magnitude which is always perpendicular to the velocity of the particle. The motion of the particle takes place in a plane. It follows that (a) Its ... ) Its acceleration is constant (c) Its kinetic energy is constant (d) It moves in a circular path

Last Answer : Ans:(d)

If a body moves with a constant speed in a circle – (1) no work is done on it (2) no force acts on it (3) no acceleration is produced in it (4) its velocity remains constant

Description : If a body moves with a constant speed in a circle – (1) no work is done on it (2) no force acts on it (3) no acceleration is produced in it (4) its velocity remains constant

Last Answer : (4) its velocity remains constant Explanation: A body moving with a constant speed in a circle is an example of uniform circular motion. The velocity vector is constant in magnitude but ... magnitude or the direction constitutes a change in the velocity which leads to change in acceleration.

If a body moves with a constant speed in a circle (1) no work is done on it (2) no force acts on it (3) no acceleration is produced in it (4) its velocity remains constant

Description : If a body moves with a constant speed in a circle (1) no work is done on it (2) no force acts on it (3) no acceleration is produced in it (4) its velocity remains constant

Last Answer :  its velocity remains constant

Obtain a relation for the distance travelled by an object moving with a uniform acceleration in the interval between 4th and 5th seconds -Physics 9th

Description : Obtain a relation for the distance travelled by an object moving with a uniform acceleration in the interval between 4th and 5th seconds -Physics 9th

Last Answer : Uniform acceleration in the interval between 4th and 5th seconds = = (5u + 1/2 * a * 5^2) - (4u + 1/2 * a * 4^2) = 5u + 1/2 *a * 25 - 4u + 1/2 * a * 16 = u + 1/2 * a * (25-16) = u + 1/2 * a * 9 = u + 9/2 * a If it starts from rest then the displacement will be 9/2a. hope this helps!

The average speed of a moving object during a given interval of time is always: A. the magnitude of its average velocity over the interval B. the distance covered during the time interval divided by the time interval (Answer) C. one-half its speed at the end of the interval D. its acceleration multiplied by the time interval E. one-half its acceleration multiplied by the time interval

Description : The average speed of a moving object during a given interval of time is always: A. the magnitude of its average velocity over the interval B. the distance covered during the time ... its acceleration multiplied by the time interval E. one-half its acceleration multiplied by the time interval

Last Answer : B. the distance covered during the time interval divided by the time interval (Answer)

At time t=0, a body has a velocity of 5 meters per second, EASTWARD; at time t=2 seconds, its velocity is 7 meters per second WESTWARD. What is the MAGNITUDE of the body's average acceleration?

Description : At time t=0, a body has a velocity of 5 meters per second, EASTWARD; at time t=2 seconds, its velocity is 7 meters per second WESTWARD. What is the MAGNITUDE of the body's average acceleration? 

Last Answer : ANSWER: 6 METERS PER SECOND SQUARED

A car moves at a constant speed of 60 km/hr for 1 km and 40 km/hr for next 1 km. What is the average speed of the car?

Description : A car moves at a constant speed of 60 km/hr for 1 km and 40 km/hr for next 1 km. What is the average speed of the car?

Last Answer : A car moves at a constant speed of 60 km/hr for 1 km and 40 km/hr for next 1 km. What is the average speed of the car?

What is the initial velocity of an object if it is moving 10 meters per second after 2 seconds with a constant acceleration of 4 meters per second squared?

Description : What is the initial velocity of an object if it is moving 10 meters per second after 2 seconds with a constant acceleration of 4 meters per second squared?

Last Answer : ANSWER: 2 METERS PER SECOND

While traveling in a straight line, a car uniformly changes its speed from 50 kilometers per hour to 110 kilometers per hour in 5 seconds. The acceleration of the car during this time is: w) 5 kilometers per hour per second x) 12 kilometers per hour per second y) 50 kilometers per hour per second z) 60 kilometers per hour per second

Description : While traveling in a straight line, a car uniformly changes its speed from 50 kilometers per hour to 110 kilometers per hour in 5 seconds. The acceleration of the car during this time is: w) 5 ... per hour per second y) 50 kilometers per hour per second z) 60 kilometers per hour per second

Last Answer : ANSWER: X -- 12 KILOMETERS PER HOUR PER SECOND

A scheduling Algorithm assigns priority proportional to the waiting time of a process. Every process starts with priority zero (lowest priority). The scheduler re-evaluates the process priority for every 'T' time units and decides next process to be scheduled. If the process have no I/O operations and all arrive at time zero, then the scheduler implements .............. criteria. (A) Priority scheduling (B) Round Robin Scheduling (C) Shortest Job First (D) FCFS

Description : A scheduling Algorithm assigns priority proportional to the waiting time of a process. Every process starts with priority zero (lowest priority). The scheduler re-evaluates the process priority for every 'T' time ... (A) Priority scheduling (B) Round Robin Scheduling (C) Shortest Job First (D) FCFS

Last Answer : (B) Round Robin Scheduling

If a car starting from rest reaches a velocity of 18 m s-1 after 6.0 s then its acceleration is A. 1 m s-2 B. 2 m s-2 C. 3 m s-2 D. 4 m s-2

Description : If a car starting from rest reaches a velocity of 18 m s-1 after 6.0 s then its acceleration is A. 1 m s-2 B. 2 m s-2 C. 3 m s-2 D. 4 m s-2

Last Answer : 3 m s-2

A ball tied with a string to a rotating shaft revolves at uniform speed. As the shaft is suddenly brought to rest, the string starts getting round the shaft with the angular velocity of the ball (a) increasing (b) decreasing (c) remaining constant (d) becoming zero

Description : A ball tied with a string to a rotating shaft revolves at uniform speed. As the shaft is suddenly brought to rest, the string starts getting round the shaft with the angular velocity of the ball (a) increasing (b) decreasing (c) remaining constant (d) becoming zero

Last Answer : Ans:(a)

When a tank containing liquid moves with an acceleration in the horizontal direction, then the free surface of the liquid (A) Remains horizontal (B) Becomes curved (C) Falls on the front end (D) Falls on the back end

Description : When a tank containing liquid moves with an acceleration in the horizontal direction, then the free surface of the liquid (A) Remains horizontal (B) Becomes curved (C) Falls on the front end (D) Falls on the back end

Last Answer : Answer: Option C

In simple harmonic motion, the acceleration is: w) constant x) proportional to the distance from the central position y) greatest when the velocity is greatest z) none of the above

Description : In simple harmonic motion, the acceleration is: w) constant x) proportional to the distance from the central position y) greatest when the velocity is greatest z) none of the above

Last Answer : ANSWER: X -- PROPORTIONAL TO THE DISTANCE FROM THE CENTRAL POSITION

A particle moves in a straight line for 20 seconds with velocity 3 m/s and then moves with velocity 4 m/s for another 20 seconds and finally moves wit

Description : A particle moves in a straight line for 20 seconds with velocity 3 m/s and then moves with velocity 4 m/s for another 20 seconds and finally moves wit

Last Answer : A particle moves in a straight line for 20 seconds with velocity 3 m/s and then moves with velocity 4 m/s for another ... /s B. 4 m/s C. 5 m/s D. zero

Two bodies of equal mass are moving in circular paths at equal speed. The first body moves in a circle whose radius is twice as great as that of the second. The ratio of the centripetal or radial acceleration of the first body to that of the second is: w) 1 to 4 x) 1 to 3 y) 1 to 2 z) 1 to 1

Description : Two bodies of equal mass are moving in circular paths at equal speed. The first body moves in a circle whose radius is twice as great as that of the second. The ratio of the centripetal or radial acceleration of the first body to that of the second is: w) 1 to 4 x) 1 to 3 y) 1 to 2 z) 1 to 1

Last Answer : ANSWER: Y -- 1 TO 2

If a particle charges its angular velocity from 30 to 35 rpm in 20 seconds then it has angular acceleration of a.107 dynes b.30 rev/min2 c.10 rev/min2 d.20 rev/min2 e.15 rev/min2

Description : If a particle charges its angular velocity from 30 to 35 rpm in 20 seconds then it has angular acceleration of a.107 dynes b.30 rev/min2 c.10 rev/min2 d.20 rev/min2 e.15 rev/min2

Last Answer : e. 15 rev/min2

An object covers distance which is directly proportional to the square of the time. Its accelaration is (1) increasing (2) decreasing (3) zero (4) constant

Description : An object covers distance which is directly proportional to the square of the time. Its accelaration is (1) increasing (2) decreasing (3) zero (4) constant

Last Answer : constant

The acceleration due to gravity on the moon is 1.6 meters per second squared. If a pendulum is whose length is 6.4 meters is placed on the moon, its period will be: w) 1.57 seconds x) 3.14 seconds y) 12.56 seconds z) 25.12 seconds

Description : The acceleration due to gravity on the moon is 1.6 meters per second squared. If a pendulum is whose length is 6.4 meters is placed on the moon, its period will be: w) 1.57 seconds x) 3.14 seconds y) 12.56 seconds z) 25.12 seconds

Last Answer : not real

Are divorce laws in Milwaukee, WI the same as the rest of the state?

Description : Are divorce laws in Milwaukee, WI the same as the rest of the state?

Last Answer : Divorce laws are the same throughout the entire state of Wisconsin.

A point moves in such a manner that its distance from a fixed point is equal to its distance from a fixed line multiplied by a constant greater than one. The locus of the path traced by the point will be a a.Cycloid b.Hyperbola c.Circle d.Involute e.Ellipsc

Description : A point moves in such a manner that its distance from a fixed point is equal to its distance from a fixed line multiplied by a constant greater than one. The locus of the path traced by the point will be a a.Cycloid b.Hyperbola c.Circle d.Involute e.Ellipsc

Last Answer : d. Involute

Which of the following is the locus of a point that moves in such a manner that its distance from a fixed point is equal to its distance from a fixed line multiplied by a constant greater than one (A) Ellipse (B) Hyperbola (C) Parabola (D) Circle

Description : Which of the following is the locus of a point that moves in such a manner that its distance from a  fixed point is equal to its distance from a fixed line multiplied by a constant greater than one  (A) Ellipse  (B) Hyperbola  (C) Parabola  (D) Circle 

Last Answer : (B) Hyperbola 

A proton moves at a speed `v = 2xx10^(6) m//s` in a region of constant magnetic field of magnitude B = 0.05 T. The direction of the proton when it ent

Description : A proton moves at a speed `v = 2xx10^(6) m//s` in a region of constant magnetic field of magnitude B = 0.05 T. The direction of the proton when it ent

Last Answer : A proton moves at a speed `v = 2xx10^(6) m//s` in a region of constant magnetic field of magnitude B = 0.05 T. ... `0.209 m` C. `2.82 m` D. `2.41 m`

An α particle moves perpendicular to a constant magnetic field of strength 1.2 T in a circular path of radius 0.7 m. The speed of α particle in ms-1 is ______________ a) 2.7 × 107 b) 2.6 × 107 c) 3.2 × 107 d) 2.0 × 107

Description : An α particle moves perpendicular to a constant magnetic field of strength 1.2 T in a circular path of radius 0.7 m. The speed of α particle in ms-1 is ______________ a) 2.7 × 107 b) 2.6 × 107 c) 3.2 × 107 d) 2.0 × 107

Last Answer : a) 2.7 × 107

A car travelling at a speed of 60 km/hour is braked and comes to rest 6 seconds after the brakes are applied. The minimum coefficient of driction between the wheels and the road would be a.0.107 b.0.3 c.0.283 d.0.417 e.0.5

Description : A car travelling at a speed of 60 km/hour is braked and comes to rest 6 seconds after the brakes are applied. The minimum coefficient of driction between the wheels and the road would be a.0.107 b.0.3 c.0.283 d.0.417 e.0.5

Last Answer : c. 0.283

How fast will a car be going after 5 seconds when the car accelerates from rest at a rate of 6 meters per second squared?

Description : How fast will a car be going after 5 seconds when the car accelerates from rest at a rate of 6 meters per second squared?

Last Answer : 30 m/sUse the kinematic equation: vf = vi + at,where:vf is final velocity (?), vi is initial velocity (0 m/s), a is acceleration (6 m/s2), and t is time (5 s).Plug the known values into the equation and solve.vf = 0 + (6 m/s21)(5 s) = (6 m/s)(5) = 30 m/s

Distance travelled by a body in time ‘t’ is A. instantaneous speed B. average velocity C. average acceleration D. instantaneous acceleration

Description : Distance travelled by a body in time ‘t’ is A. instantaneous speed B. average velocity C. average acceleration D. instantaneous acceleration

Last Answer : average velocity