Description : If the motion of an object is described by x = f(t) write formulae for instantaneous velocity and acceleration.
Last Answer : If the motion of an object is described by x = f(t) write formulae for instantaneous velocity and acceleration.
Description : A car travelled south-west for 200 miles depicts A. distance B. speed C. velocity D. displacement
Last Answer : displacement
Description : At time t=0, a body has a velocity of 5 meters per second, EASTWARD; at time t=2 seconds, its velocity is 7 meters per second WESTWARD. What is the MAGNITUDE of the body's average acceleration?
Last Answer : ANSWER: 6 METERS PER SECOND SQUARED
Description : Speed of a body in particular direction can be called A. acceleration B. displacement C. velocity D. distance
Last Answer : velocity
Description : Horizontal distance travelled by a ball if it's thrown with initial velocity of 20 m s-1 at an angle of 30° is A. 24 m B. 56 m C. 35.3 m D. 36.3 m
Last Answer : 35.3 m
Description : Which of the following are scalars or vectors? Displacements, distance travelled, velocity, speed, force, work done, energy
Last Answer : Which of the following are scalars or vectors? Displacements, distance travelled, velocity, speed, force, work done, energy
Description : Obtain a relation for the distance travelled by an object moving with a uniform acceleration in the interval between 4th and 5th seconds -Physics 9th
Last Answer : Uniform acceleration in the interval between 4th and 5th seconds = = (5u + 1/2 * a * 5^2) - (4u + 1/2 * a * 4^2) = 5u + 1/2 *a * 25 - 4u + 1/2 * a * 16 = u + 1/2 * a * (25-16) = u + 1/2 * a * 9 = u + 9/2 * a If it starts from rest then the displacement will be 9/2a. hope this helps!
Description : A train accelerates from 36 km/h to 54 km/h in 10 sec. (i) Acceleration (ii) The distance travelled by car. -Science
Last Answer : a. Acceleration is given by a=ΔvΔta=ΔvΔt Δv=54−36=18km/hr=18×10003600m/s=5m/sΔv=54−36=18km/hr=18×10003600m/s=5m/s So a=.5 m/s2 b. Distance is given by S=ut+12at2S=ut+12at2 Now u=36 km/hr =10m/s s=10×10+12×.5×102s=10×10+12×.5×102 So s=125m
Description : The average speed of a moving object during a given interval of time is always: A. the magnitude of its average velocity over the interval B. the distance covered during the time ... its acceleration multiplied by the time interval E. one-half its acceleration multiplied by the time interval
Last Answer : B. the distance covered during the time interval divided by the time interval (Answer)
Description : A satellite is observed to move in a circle about the earth at a constant speed. This means that the force acting upon it is: w) zero x) parallel to the direction of the satellite ... velocity y) perpendicular to the direction of the satellite's instantaneous velocity z) none of the above
Last Answer : ANSWER: Y -- PERPENDICULAR TO THE INSTANTANEOUS DIRECTION OF THE SATTELITE’S VELOCITY
Description : The slope of a velocity-time graph represents – (1) acceleration (2) displacement (3) distance (4) speed
Last Answer : (1) acceleration Explanation: A plot of velocity-time is used to determine the acceleration of an object (the slope). If the acteleration is zero, then the velocity-time graph is a horizontal line (i.e ... is positive, then the line is an upward sloping line (i.e., the slope is positive).
Description : The slope of a velocity-time graph represents (1) acceleration (2) displacement (3) distance (4) speed
Last Answer : acceleration
Description : Explain the terms: 1. Acceleration 2. Average acceleration 3. Instantaneous acceleration
Last Answer : Explain the terms: 1. Acceleration 2. Average acceleration 3. Instantaneous acceleration
Description : The rate of change of displacement is called: (1) Acceleration (2) Speed (3) Distance (4) Velocity
Last Answer : (4) Velocity Explanation: In considering motions of objects over time the instantaneous velocity of the object is the rate of change of the displacement as a function of time.
Description : For an object moving in uniform circular motion, the direction of the instantaneous acceleration vector is: w) tangent to the path of motion x) equal to zero y) directed radially outward z) directed radially inward
Last Answer : ANSWER: Z -- DIRECTED RADIALLY INWARD
Description : The motion of a body around a circular path is an example of – (1) Uniform velocity, variable acceleration (2) Uniform speed, uniform velocity (3) Uniform speed, variable velocity (4) Uniform speed, variable acceleration
Last Answer : (1) Uniform velocity, variable acceleration Explanation: Uniform circular motion occurs when a body moves in a circular path with constant velocity.
Description : If a body moves with a constant speed in a circle – (1) no work is done on it (2) no force acts on it (3) no acceleration is produced in it (4) its velocity remains constant
Last Answer : (4) its velocity remains constant Explanation: A body moving with a constant speed in a circle is an example of uniform circular motion. The velocity vector is constant in magnitude but ... magnitude or the direction constitutes a change in the velocity which leads to change in acceleration.
Description : A body moving in a circular path with a constant speed has a – (1) constant velocity (2) constant acceleration (3) constant kinetic energy (4) constant displacement
Last Answer : (3) constant kinetic energy Explanation: In circular motion, the magnitude of the velocity of the body is constant but the direction is constantly changing. This means that, even though the speed is ... accelerating. At any instant, the direction of the velocity is a tangent to the circular path.
Description : A body moving in a circular path with a constant speed has a (1) constant velocity (2) constant acceleration (3) constant kinetic energy (4) constant displacement
Last Answer : constant kinetic energy
Description : If a body moves with a constant speed in a circle (1) no work is done on it (2) no force acts on it (3) no acceleration is produced in it (4) its velocity remains constant
Last Answer : its velocity remains constant
Description : The motion of a body around a circular path is an example of (1) Uniform velocity, variable acceleration (2) Uniform speed, uniform velocity (3) Uniform speed, variable velocity (4) Uniform speed, variable acceleration
Last Answer : Uniform velocity, variable acceleration
Description : Derive the expression for average velocity and instantaneous velocity for the motion of an object in x-y plane.
Last Answer : Derive the expression for average velocity and instantaneous velocity for the motion of an object in x-y plane.
Description : Define average velocity and instantaneous velocity. When are they same?
Last Answer : Define average velocity and instantaneous velocity. When are they same?
Description : Rubesh generally takes 80 minutes to reach home from office. Due to rain, he travelled at 2/3rd of his usual speed for the 1st half of the distance. At what speed should rubesh travel the remaining distance ... c) 2.5 times the original speed d) 3 times the original speed e) Cannot reach on time
Last Answer : Under the normal speed, 40 minutes for half the distance Due to rain, time taken will be 40 / (2/3) = 40 × (3/2) = 60 minutes So, in 20 minutes he has to cover the distance he usually covers in 40 minutes. So, he has to travel at twice the original speed. Answer: b)
Description : 2 bus start from A & B respectively and travel towards each other at a speed of 150 km/hr and 120 km/hr respectively. By the time they meet, the first bus has travelled by 300km more than the second. The distance between A & B is a) 2700 b) 2800 c) 2750 d) 2457
Last Answer : A At the time of meeting, Let the distance travelled by the second bus be xkm Then distance covered by the 1st bus is (x+300)km x/120= (x+300) /150 150x = 120(x+300) 150x = 120x +36000 30x = ... X=36000/30 X=1200 So the distance covered between A & B =(x+x+300) =(1200+1200+300) =2700km.
Description : Mr.Aneesh left for city 1 from city 2 at 3.00 pm. He travelled at the speed of 60km/hr for 1 and half hours. After that the speed was reduced to 15 km/hr. If the distance between two cities is 120 kms, at what time did Mr.Aneesh reach city 1 ? a) 6.30 pm. b) 5.30 pm. c) 7.30 pm. d) 8.30 pm.
Last Answer : A Mr.Aneesh travelled 60 km/hr for 1 1/2 hours (3/2 hours). Distance covered in 3/2 hours = 60 x 3/2 = 90 km. Therefore, remaining distance = 120 -90 = 30 km After 3/2 hours, the speed was ... village 2 at 3.00 pm + 3 hours 30 minutes = 6.30pm Hence the required answer is 6.30 pm.
Description : A train travelling at 20 m s-1 accelerates at 0.5 m s-2 for 30 s, the distance travelled by train is A. 825 m B. 700 m C. 650 m D. 600 m
Last Answer : 825 m
Description : Gradient of velocity-time graph tells us about object's A. velocity B. displacement C. distance D. acceleration
Description : : Gradient of line of velocity-time graph is tells us the A. velocity B. acceleration C. distance D. time
Description : The speed of a car increases by 2 kms after every one hour. If the distance travelled in the first one hour was 35 kms, what was the total distance traveled in 12 hours? A.456 kms B.482 kms C.552 kms D.556 kms E.None of these
Last Answer : Answer – C (552 kms) Explanation – Total distance travelled in 12 hours = (35 + 37 + 39 + …… upto 12 terms) This is an A.P. with first term, a = 35, number of terms, n = 12, common difference, d =2. Required distance =12/2 (2 x 35 + (12 – 1) x 2) = 6(70 + 22) = 552 kms
Description : The speed of a van increases by 5 kmph after every one hour. If the distance travelled in the first one hour was 55 km, what was the total distance travelled in 8 hours? a) 580km b) 116km c) 147km d) 240km
Last Answer : A Distance travelled in 1ST hour =55 km Speed of the van increases by 5 kmph after every one hour. Hence, distance travelled in 2nd hour =60 km distance travelled in 3rd hour =65 km and so on Total distance travelled =(55+60+……..+(8 terms)) =8/2(2*55+(8-1)5) =4(110+35) =580km
Description : The angular velocity depends upon the rate of change of the _______. (1) Angular Distance (2) Angular acceleration (3) Angular Displacement (4) torque
Last Answer : (3) Angular Displacement Explanation: The angular velocity is defined as the rate of change of angular displacement and is a vector quantity which specifies the angular speed of an object and the axis about which the object is rotating.
Description : In simple harmonic motion, the acceleration is: w) constant x) proportional to the distance from the central position y) greatest when the velocity is greatest z) none of the above
Last Answer : ANSWER: X -- PROPORTIONAL TO THE DISTANCE FROM THE CENTRAL POSITION
Description : The work done by a body on application of a constant force is the product of the constant force and distance travelled by the body in the direction of force. Express this in the form of a linear equation in two variables and draw its graph by taking the constant force as 3 units. -Maths 9th
Last Answer : Solution :-
Description : If the velocity-time graph of a particle is represented by y = mt + c, then the particle is moving with– (1) constant speed (2) constant velocity (3) constant acceleration (4) varying acceleration
Last Answer : (3) constant acceleration Explanation: In this case the given equation shows that that the velocity is linear with time and therefore the particle is moving with constant acceleration because for a ... acceleration the graph of the velocity time graph should be in linear with the time function.
Description : If the velocity-time graph of a particle is represented by y = mt + c, then the particle is moving with (1) constant speed (2) constant velocity (3) constant acceleration (4) varying acceleration
Last Answer : constant acceleration
Description : Explain the terms: i. Average velocity ii. Instantaneous velocity iii. Average speed iv. Instantaneous speed
Last Answer : Explain the terms: i. Average velocity ii. Instantaneous velocity iii. Average speed iv. Instantaneous speed
Description : What is meant by instantaneous speed ?
Last Answer : The speed of a particular moment of a moving object is called the instantaneous speed of the object.
Description : What is instantaneous speed ?
Description : For body moving with non-uniform velocity and uniform acceleration – (1) Displacement – Time graph (2) Displacement – Time graph (3) Velocity - Time graph is non-linear (4) Velocity - Time graph is linear
Last Answer : (2) Displacement - Time graph Explanation: Displacement-time graph is non linear. Linear motion (also called rectilinear motion) is motion along a straight line, and can therefore be described ... linear motion with variable velocity or non-zero acceleration. The motion of a particle (a point
Description : For a body moving with non-uniform velocity and uniform acceleration (1) Displacement – Time graph is linear (2) Displacement – Time graph is non-linear (3) Velocity – Time graph is nonlinear (4) Velocity – Time graph is linear
Last Answer : Displacement – Time graph is non-linear
Description : The angle between the velocity and acceleration of a body is: w) never 90 degrees x) never 180 degrees y) sometimes 180 degrees z) never 0 degrees
Last Answer : ANSWER: Y -- SOMETIMES 180 DEGREES
Description : A body moving in a circular path with a constant speed has a - (1) constant velocity (2) constant acceleration (3) constant kinetic energy (4) constant displacement
Last Answer : (3) constant kinetic energy Explanation: In circular motion, the magnitude of the velocity of the body is constant but the direction is constantly changing.
Description : What is the distance travelled by an object over a certain period of time?
Last Answer : There are two pieces of data that need to be recorded. The distance and the time it takes to complete the known distance, gives you the speed. For an example, your car travels at a steady 60 miles, in one hour you would expect to have travelled 60 miles.
Description : What effect does only distance travelled have on light?
Last Answer : Light, like any other form of electromagnetic radiation, decreases in intensity the further it travels from the point of emission. The mathematical relation that describes this is an inverse square- ... laser) does not decay over distance according to the inverse-square relation, but some other.
Description : Numerical Questions and answers on Motion for Class 9 physics a. What is the distance travelled by the SUV is first 2 seconds? b. What is the braking force at the end of 5 seconds to bring the SUV to a stop within one seconds? -Science
Last Answer : a. The distance travelled by the SUV is first 2 seconds = Area of ΔABEΔABE =12 AE BE=12 AE BE =12 2 15=15m=12 2 15=15m b. Acceleration will be given by the slope of the line CD a=0−156−5= ... =−15m/s2 Now mass of the SUV =1000 Kg Braking Force will be F=ma=1000 −15=−15000NF=ma=1000 −15=−15000N
Description : What is the difference between displacement and distance travelled?
Last Answer : What is the difference between displacement and distance travelled?
Description : The distance travelled per turn of α-helix in nm is (A) 0.34 (B) 0.44 (C) 0.54 (D) 0.64
Last Answer : Answer : C
Description : The distance travelled by a moving vehicle during perception and brake reaction times, is known as (A) Sight distance (B) Stopping distance (C) Lag distance (D) None of these
Last Answer : Answer: Option C
Description : The distance travelled by revolving the wheel of a vehicle more than its circumferential movement, is known as (A) Slip (B) Skid (C) Neither (a) nor (b) (D) Both (a) and (b)
Last Answer : Answer: Option B