For the reaction `CO(g) + CI_(2)(g) hArr COCI_(2)(g)` the value of `(K_(c))/(K_(P))`is equal to :-

For the reaction `CO(g) + CI_(2)(g) hArr COCI_(2)(g)` the value of `(K_(c))/(K_(P))`is equal to :-
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For the reaction `CO(g) + CI_(2)(g) hArr COCI_(2)(g)` the value of `(K_(c))/(K_(P))`is equal to :- A. `sqrt(RT)` B. RT C. `(1)/(RT)` D. 1.0
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Description : What is the standard enthalpy change at 298 K for the following reaction? `CO_(2) (g)+ C("diamond") rarr 2CO(g)` Given : `DeltaH_(f)^(@)(CO,g) = - 110

Last Answer : What is the standard enthalpy change at 298 K for the following reaction? `CO_(2) (g)+ C("diamond") rarr 2CO(g ... `+172.5 kJ//mol` D. `170.5 kJ//mol`

For a reaction `CH_(3)OCH_(3) (g) rarr CH_(4) (g)+H_(2) (g)+CO(g)` at 750K, the rate constant is `3.52xx10^(-3)" min"^(-1)`. Starting with a pressure

Description : For a reaction `CH_(3)OCH_(3) (g) rarr CH_(4) (g)+H_(2) (g)+CO(g)` at 750K, the rate constant is `3.52xx10^(-3)" min"^(-1)`. Starting with a pressure

Last Answer : For a reaction `CH_(3)OCH_(3) (g) rarr CH_(4) (g)+H_(2) (g)+CO(g)` at 750K, the rate constant ... to become 760 mm Hg ? (Take log 2.25 = 0.352)

According to the following reaction `C(S)+1//2O_(2)(g)rarr CO(g), Delta H=-26.4` Kcal

Description : According to the following reaction `C(S)+1//2O_(2)(g)rarr CO(g), Delta H=-26.4` Kcal

Last Answer : According to the following reaction `C(S)+1//2O_(2)(g)rarr CO(g), Delta H=-26.4` Kcal ... compound C. The reaction is endothermic D. None of the above

The enthalpy of formation of `CO(g), CO_(2)(g),N_(2)O(g)` and `N_(2)O_(4)(g)` is `-110,-393,+81` and 10 kJ / mol respectively. For the reaction `N_(2)

Description : The enthalpy of formation of `CO(g), CO_(2)(g),N_(2)O(g)` and `N_(2)O_(4)(g)` is `-110,-393,+81` and 10 kJ / mol respectively. For the reaction `N_(2)

Last Answer : The enthalpy of formation of `CO(g), CO_(2)(g),N_(2)O(g)` and `N_(2)O_(4)(g)` is `-110,-393,+81` and 10 ... is A. `-212` B. `+212` C. `+778` D. `-778`

When volume of the equilibrium reaction C(s) + H2O(g) ⇌ CO(g) + H2(g) is increased at constant temperature the equilibrium will :

Description : When volume of the equilibrium reaction C(s) + H2O(g) ⇌ CO(g) + H2(g) is increased at constant temperature the equilibrium will :

Last Answer : When volume of the equilibrium reaction C(s) + H2O(g) ⇌ CO(g) + H2(g) is increased at constant ... left c. be unaltered d. can not be predicted