Circle Volume Diagnosis Formula What ?

by

1 Answer

Answer :

of the circle Area Diagnosis Source : r ^ 2
by

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Last Answer : Cash given for business purposes is called capital or real. Keeping money in the bank also falls under the business policy. Suppose you have deposited Rs. And keep it in the bank. Then that 5000 rupees is ... capital , a profit is real. I profit. Profit Loss Selling Price - Profit = Real or Capital.

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True statements concerning hypoadrenal shock include which of the following? A. Adrenocortical insufficiency may manifest itself as severe shock refractory to volume and pressor therapy. B. The presence of hyperglycemia and hypotension may suggest the diagnosis of shock due to adrenocortical insufficiency. C. Hydrocortisone does not interfere with the serum cortisol assay and should be given to hemodynamically unstable patients suspected of having hypoadrenal shock. D. The rapid adrenocorticotropic hormone (ACTH) stimulation test should be performed to help establish the diagnosis of acute adrenocortical insufficiency.

Description : True statements concerning hypoadrenal shock include which of the following? A. Adrenocortical insufficiency may manifest itself as severe shock refractory to volume and pressor therapy. B. ... test should be performed to help establish the diagnosis of acute adrenocortical insufficiency.

Last Answer : Answer: AD DISCUSSION: Shock due to acute adrenocortical insufficiency is relatively uncommon but must be considered when shock refractory to volume replacement and pressor therapy is present. ... and it is the corticosteroid of choice while the ACTH stimulation test is being performed

What is the formula for the area of a circle?

Description : What is the formula for the area of a circle?

Last Answer : Answer: A = πr^2

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Last Answer : circle circumference = 2 pi r . Pi = 3.1416 .

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Last Answer : A wire of length a units is cut into two equal pieces and make a circle of radius r with one piece. Frame the formula by making r the subject.

If r is the radius of a circle and d is its diameter is an equivalent formula for the circumference C 2r?

Description : If r is the radius of a circle and d is its diameter is an equivalent formula for the circumference C 2r?

Last Answer : Circumference of a circle: 2*pi*radius or diameter*pi

If r is the radius of a circle and d is its diameter is an equivalent formula for the circumference C 2r?

Description : If r is the radius of a circle and d is its diameter is an equivalent formula for the circumference C 2r?

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The output on my Mac has a white circle with a line through it and the volume wont work, why?

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Description : What is the formula for the volume of a square pyramid?

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Last Answer : Cylinder Volume Get out To do Source: ?r ^ 2h

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Frame the formula for the volume (v) of a cylinder given by the product of `pi`, square of radius (r) and height (h).

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What is the formula for volume of trapezoid prism?

Description : What is the formula for volume of trapezoid prism?

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The formula to calculate maximum urea clearance is U V× B , where U denotes (A) Concentration of urea in urine in gm/24hr (B) Concentration of urea in urine in mg/100 ml (C) Concentration of urea in blood in mg/100 ml (D) Volume of urine in ml/mt

Description : The formula to calculate maximum urea clearance is U V× B , where U denotes (A) Concentration of urea in urine in gm/24hr (B) Concentration of urea in urine in mg/100 ml (C) Concentration of urea in blood in mg/100 ml (D) Volume of urine in ml/mt

Last Answer : Answer : B

What is the formula for compression (rk) ratio of the Otto cycle? a. rk = Volume of cylinder at the beginning of compression / Volume of cylinder at the end of compression b. rk = Volume of cylinder at the end of compression / Volume of cylinder at the beginning of compression c. rk = Volume of cylinder at the end of compression / clearance volume d. none of the above

Description : What is the formula for compression (rk) ratio of the Otto cycle? a. rk = Volume of cylinder at the beginning of compression / Volume of cylinder at the end of compression b. rk = Volume of cylinder ... c. rk = Volume of cylinder at the end of compression / clearance volume d. none of the above

Last Answer : ANSWER a. rk = Volume of cylinder at the beginning of compression / Volume of cylinder at the end of compression

The correct Prismoidal formula for volume is (A) D [first area + last area + Even area + 2 odd areas] (B) D/3 [first area + last area + 4 Even area + 2 odd areas] (C) D/3 [first area + last area + 2 Even area + 4 odd areas] (D) D/6 [first area + odd areas]

Description : The correct Prismoidal formula for volume is (A) D [first area + last area + Even area + 2 odd areas] (B) D/3 [first area + last area + 4 Even area + 2 odd areas] (C) D/3 [first area + last area + 2 Even area + 4 odd areas] (D) D/6 [first area + odd areas]

Last Answer : (B) D/3 [first area + last area + 4 Even area + 2 odd areas]

In the mid-section formula (A) The mean depth is the average of depths of two consecutive sections (B) The area of mid-sections is calculated by using mean depth (C) The volume of the earth work is calculated by multiplying the mid-section area by the distance between the two original sections (D) All of the above

Description : In the mid-section formula (A) The mean depth is the average of depths of two consecutive sections (B) The area of mid-sections is calculated by using mean depth (C) The volume of the ... multiplying the mid-section area by the distance between the two original sections (D) All of the above

Last Answer : (D) All of the above

The assumption on which the trapezoidal formula for volumes is based, is (A) The end sections are parallel planes (B) The mid-area of a pyramid is half the average area of the ends (C) The volume of the Prismoidal is over-estimated and hence a Prismoidal correction is applied (D) All the above

Description : The assumption on which the trapezoidal formula for volumes is based, is (A) The end sections are parallel planes (B) The mid-area of a pyramid is half the average area of the ends (C) The volume of the Prismoidal is over-estimated and hence a Prismoidal correction is applied (D) All the above

Last Answer : (D) All the above

While swimming at depth of120m in a fresh water lake, A fish emits an air bubbles of volume 2.0mm³ atmospheric pressure is 100kPa. What is the pressure of the bubble?  a) 217.7 kPa  b) 317.7 kPa  c) 417.7 kPa  d) 517.7 kPa Formula: P= δh

Description : While swimming at depth of120m in a fresh water lake, A fish emits an air bubbles of volume 2.0mm³ atmospheric pressure is 100kPa. What is the pressure of the bubble?  a) 217.7 kPa  b) 317.7 kPa  c) 417.7 kPa  d) 517.7 kPa Formula: P= δh

Last Answer : 217.7 kPa

The volume of a gas under standard atmospheric pressure & 76 cmHg is 200m³. What is the volume when pressure is 80 cmHg if the temperature is unchanged?  a) 180 in³  b) 170 in³  c) 160 in³  d) 190 in³ Formula: P2V2 = P1V1

Description : The volume of a gas under standard atmospheric pressure & 76 cmHg is 200m³. What is the volume when pressure is 80 cmHg if the temperature is unchanged?  a) 180 in³  b) 170 in³  c) 160 in³  d) 190 in³ Formula: P2V2 = P1V1

Last Answer : 190 in³

Assuming compression is according to the Law PV = C, Calculate the initial volume of the gas at a pressure of 2 bars w/c will occupy a volume of 6m³ when it is compressed to a pressure of 42 Bars.  a) 130m³  b) 136m³  c) 120m³  d) 126m³ Formula: P1V1/T1 =P2V2/T2

Description : Assuming compression is according to the Law PV = C, Calculate the initial volume of the gas at a pressure of 2 bars w/c will occupy a volume of 6m³ when it is compressed to a pressure of 42 Bars.  a) 130m³  b) 136m³  c) 120m³  d) 126m³ Formula: P1V1/T1 =P2V2/T2

Last Answer : 126m³

Ten cu. ft of air at 300psia and 400°F is cooled to 140°F at constant volume. What is the transferred heat?  a.-120Btu  b. -220Btu  c.-320Btu  d. -420Btu formula: Q= mcv(T2-T1)

Description : Ten cu. ft of air at 300psia and 400°F is cooled to 140°F at constant volume. What is the transferred heat?  a.-120Btu  b. -220Btu  c.-320Btu  d. -420Btu formula: Q= mcv(T2-T1)

Last Answer : -420Btu

There are 1.36 kg of gas, for which R = 377 J/kg.k and k = 1.25, that undergo a nonflow constant volume process from p1 = 551.6 kPa and t1 = 60°C to p2 = 1655 kPa. During the process the gas is internally stirred and there are also added 105.5 kJ of heat. Determine t2. (Formula: T2= T1p2/ p1)  a. 999 K  b. 888 K  c. 456 K  d. One of the above

Description : There are 1.36 kg of gas, for which R = 377 J/kg.k and k = 1.25, that undergo a nonflow constant volume process from p1 = 551.6 kPa and t1 = 60°C to p2 = 1655 kPa. During the process the gas is internally stirred and ... (Formula: T2= T1p2/ p1)  a. 999 K  b. 888 K  c. 456 K  d. One of the above

Last Answer : 999 K

Ten cu ft. of air at 300 psia 400°F is cooled to 140°F at constant volume. What is the final pressure? (formula: p2 = p1T2/T1)  a. 0  b. 209 psia  c. - 420 psia  d. None of the above

Description : Ten cu ft. of air at 300 psia 400°F is cooled to 140°F at constant volume. What is the final pressure? (formula: p2 = p1T2/T1)  a. 0  b. 209 psia  c. - 420 psia  d. None of the above

Last Answer : 209 psia

Gas is enclosed in a cylinder with a weighted piston as the stop boundary. The gas is heated and expands from a volume of 0.04 m^3 to 0.10 m^3 at a constant pressure of 200kPa.Calculate the work done by the system.  A. 8 kJ  B. 10 kJ  C.12 kJ  D.14 kJ Formula: W = p(V2-V1)

Description : Gas is enclosed in a cylinder with a weighted piston as the stop boundary. The gas is heated and expands from a volume of 0.04 m^3 to 0.10 m^3 at a constant pressure of 200kPa.Calculate the work done by the system.  A. 8 kJ  B. 10 kJ  C.12 kJ  D.14 kJ Formula: W = p(V2-V1)

Last Answer : 12 kJ

Twenty grams of oxygen gas are compressed at a constant temperature of 30 ˚C to 5%of their original volume. What work is done on the system.  A.824 cal  B.924 cal  C.944 cal  D.1124 cal Formula: W = -mRTln (V2/V1) Where R = (1.98 cal/gmole·K) (32 g/gmole)

Description : Twenty grams of oxygen gas are compressed at a constant temperature of 30 ˚C to 5%of their original volume. What work is done on the system.  A.824 cal  B.924 cal  C.944 cal  D.1124 cal Formula: W = -mRTln (V2/V1) Where R = (1.98 cal/gmole·K) (32 g/gmole)

Last Answer : 1124 cal

What is the resulting pressure when one pound of air at 15 psia and 200 ˚F is heated at constant volume to 800 ˚F?  A.15 psia  B. 28.6 psia  C. 36.4 psia.  D. 52.1 psia Formula : T1/p1 = T2/p2 p2= p1T2 / T1

Description : What is the resulting pressure when one pound of air at 15 psia and 200 ˚F is heated at constant volume to 800 ˚F?  A.15 psia  B. 28.6 psia  C. 36.4 psia.  D. 52.1 psia Formula : T1/p1 = T2/p2 p2= p1T2 / T1

Last Answer : 28.6 psia

A problem Drum ( 3 ft. diameter ; 6 ft. height ) is field with a fluid whose density is 50 lb/ft^3. Determine the total volume of the fluid.  A. 42.41 ft^3  B.44.35 ft^3  C.45.63 ft^3  D.41.23 ft^3 Formula: Vf = (pi d^2 h) / 4

Description : A problem Drum ( 3 ft. diameter ; 6 ft. height ) is field with a fluid whose density is 50 lb/ft^3. Determine the total volume of the fluid.  A. 42.41 ft^3  B.44.35 ft^3  C.45.63 ft^3  D.41.23 ft^3 Formula: Vf = (pi d^2 h) / 4

Last Answer : 42.41 ft^3

A vessel with a volume of cubic meter contains liquid water and water vapor ion equilibrium at 600 kPa. The liquid water has mass of1kg. Using the steam table, calculate the mass of the water vapor.  A. 0.99kg  B. 1.57 kg  C. 2.54 kg  D. 3.16 kg Formula: from the steam table at 600kPa vƒ = 0.001101 m^3 / kg vg = 0.3157 m^3 / kg Vtot = mƒ vƒ + mg vg mg = (tot-mƒ vƒ) / vg

Description : A vessel with a volume of cubic meter contains liquid water and water vapor ion equilibrium at 600 kPa. The liquid water has mass of1kg. Using the steam table, calculate the mass of the water vapor.  A. 0.99kg  B. 1.57 kg  C ... / kg vg = 0.3157 m^3 / kg Vtot = mƒ vƒ + mg vg mg = (tot-mƒ vƒ) / vg

Last Answer : 3.16 kg

3.0 lbm of air are contained at 25 psia and 100 ˚F. Given that Rair = 53.35 ft-lbf/lbm- ˚F, what is the volume of the container?  A.10.7 ft^3  B.14.7 ft^3  C.15 ft^3  D.24.9 ft^3 Formula: use the ideal gas law pV = mRT T = (100 +460) ˚R V = mRT/p

Description : 3.0 lbm of air are contained at 25 psia and 100 ˚F. Given that Rair = 53.35 ft-lbf/lbm- ˚F, what is the volume of the container?  A.10.7 ft^3  B.14.7 ft^3  C.15 ft^3  D.24.9 ft^3 Formula: use the ideal gas law pV = mRT T = (100 +460) ˚R V = mRT/p

Last Answer : 24.9 ft^3

Steam at 1000 lbf/ft^2 pressure and 300˚R has specific volume of 6.5 ft^3/lbm and a specific enthalpy of 9800 lbf-ft/lbm. Find the internal energy per pound mass of steam.  A.2500 lbf-ft/lbm  B.3300 lbf-ft/lbm  C.5400 lbf-ft/lbm  D.6900 lbf-ft/lbm Formula: h= u+ pV u= h– pV

Description : Steam at 1000 lbf/ft^2 pressure and 300˚R has specific volume of 6.5 ft^3/lbm and a specific enthalpy of 9800 lbf-ft/lbm. Find the internal energy per pound mass of steam.  A.2500 lbf-ft/lbm  B.3300 lbf-ft/lbm  C.5400 lbf-ft/lbm  D.6900 lbf-ft/lbm Formula: h= u+ pV u= h– pV

Last Answer : 3300 lbf-ft/lbm

If air is at pressure, p, of 3200 lbf/ft2 , and at a temperature, T, of 800 ˚R, what is the specific volume, v? (R=5303 ft-lbf/lbm-˚R, and air can be modeled as an ideal gas.)  A.9.8 ft^3/lbm  B.11.2 ft^3/lbm  C.13.33 ft^3/lbm  D.14.2 ft^3/lbm Formula: pv = RT v = RT / p

Description : If air is at pressure, p, of 3200 lbf/ft2 , and at a temperature, T, of 800 ˚R, what is the specific volume, v? (R=5303 ft-lbf/lbm-˚R, and air can be modeled as an ideal gas.)  A.9.8 ft^3/lbm  B.11.2 ft^3/lbm  C.13.33 ft^3/lbm  D.14.2 ft^3/lbm Formula: pv = RT v = RT / p

Last Answer : 13.33 ft^3/lbm

Differentiate between trapezoidal and prismoidal formula for computation of volume.

Description : Differentiate between trapezoidal and prismoidal formula for computation of volume.

Last Answer : Sr.No. Trapezoidal Formula Prismoidal Formula 1 This formula is suitable for any number of sections.  This formula is applicable when there are an odd number of sections ... due to prismoidal consideration. 5 Simple in calculation. Comparatively difficult calculation

State the procedure for computing the volume by prismodial formula.

Description : State the procedure for computing the volume by prismodial formula. 

Last Answer : Procedure: 1. The total length of plane is divided into no of strips. 2. Calculate the areas at ends (A1&An) 3. Calculate area of intermediate strips A2,A3,A4 An So that,A1, A2, A3 .An are areas of ... 4A4+ .+2A(n-2)+4A(n-1)+An)  5 To use this formula it requires odd number of section.