A vessel with a volume of cubic meter contains liquid water and water vapor ion equilibrium at 600 kPa. The liquid water has mass of1kg. Using the steam table, calculate the mass of the water vapor.
A. 0.99kg
B. 1.57 kg
C. 2.54 kg
D. 3.16 kg
Formula: from the steam table at 600kPa
vƒ = 0.001101 m^3 / kg
vg = 0.3157 m^3 / kg
Vtot = mƒ vƒ + mg vg
mg = (tot-mƒ vƒ) / vg
A. 0.99kg
B. 1.57 kg
C. 2.54 kg
D. 3.16 kg
Formula: from the steam table at 600kPa
vƒ = 0.001101 m^3 / kg
vg = 0.3157 m^3 / kg
Vtot = mƒ vƒ + mg vg
mg = (tot-mƒ vƒ) / vg