The volume of a gas under
standard atmospheric pressure & 76
cmHg is 200m³. What is the volume
when pressure is 80 cmHg if the
temperature is unchanged?
 a) 180 in³
 b) 170 in³
 c) 160 in³
 d) 190 in³
Formula: P2V2 = P1V1

1 Answer

Answer :

190 in³

Related questions

Description : Assuming compression is according to the Law PV = C, Calculate the initial volume of the gas at a pressure of 2 bars w/c will occupy a volume of 6m³ when it is compressed to a pressure of 42 Bars.  a) 130m³  b) 136m³  c) 120m³  d) 126m³ Formula: P1V1/T1 =P2V2/T2

Last Answer : 126m³

Description : The pressure gauge on a 2000 m³ tank of oxygen gas reads 600 kPa. How much volumes will the oxygen occupied at pressure of the outside air 100 kPa?  a) 14026.5 m³  b) 15026.5 m³  c) 13026.5 m³  d) 16026.5 m³ Formula: P1V1/T1 =P2V2/T2

Last Answer : 14026.5 m³

Description : A 1-kg steam-water mixture at 1.0 MPa is contained in an inflexible tank. Heat is added until the pressure rises to 3.5 MPa and the temperature to 400°. Determine the heat added.  a) 1378.7 kJ  b) 1348.5 kJ  c) 1278,7 kJ  d) 1246,5 kJ Formula: Q = (h2 – p2v2) –(h1 –p1v1)

Last Answer : 1378.7 kJ

Description : An ideal gas at 45psig and 80ºF is heated in the close container to 130ºF. What is the final pressure?  a. 65.10 psi  b. 65.11 psi  c. 65.23 psi  d. 61.16 psi P1V1/T1= P2V2/T2;V = Constant

Last Answer : 65.23 psi

Description : p1V1= p2V2  a. Charle's Law  b. Boyle's Law  c. Ideal Gas Law  d. Joule's Law

Last Answer : Boyle's Law

Description : Weight of one cotton bale is (A)170 Kg (B) 160 Kg (C) 180 Kg (D) 190 Kg

Last Answer : (A)170 Kg

Description : In the above problem, compute for the mass. (Formula: m = p1V1 / RT1)  a. 0.2148 lb  b. 0.2134 lb  c. 0.1248 lb  d. None of the above

Last Answer : 0.2148 lb

Description : What horse power is required to isothermally compress 800 ft^3 of Air per minute from 14.7 psia to 120 psia?  A. 28 hp  B.108 hp  C.256 hp  D.13900 hp Formula: W= p1V1 ln (p1/p2) Power = dW / dt

Last Answer : 108 hp

Description : A vertical column of water will be supported to what height by standard atmospheric pressure. If the Y w = 62.4lb/ft3 po = 14.7 psi.  a. 44.9 ft  b. 33.9 ft  c. 22.9 ft  d. 55.9 ft formula: ho= po/Yw

Last Answer : 33.9 ft

Description : While swimming at depth of120m in a fresh water lake, A fish emits an air bubbles of volume 2.0mm³ atmospheric pressure is 100kPa. What is the pressure of the bubble?  a) 217.7 kPa  b) 317.7 kPa  c) 417.7 kPa  d) 517.7 kPa Formula: P= δh

Last Answer : 217.7 kPa

Description : Oxygen at 15ºC and 10.3 Mpa gauge pressure occupies 600L. What is the occupied by the oxygen at 8.28 Mpa gauge pressure and 35ºC?  a. 789.32 L  b. 796.32 L  c. 699 L  d. 588 L V2= P1V1/T1P2

Last Answer : 796.32 L

Description : Two thick slices of bread, when completely oxidized by the body, can supply 200,000 cal of heat. How much work is this equivalent to?  a) 4,190,000 joules  b) 8,390,000 joules  c) 839, ... d) 419 000 joules Formula: J =Work/Heat J = mechanical equivalent of heat whose value is 4.19 joules/calorie

Last Answer : 419 000 joules

Description : If air is at pressure, p, of 3200 lbf/ft2 , and at a temperature, T, of 800 ˚R, what is the specific volume, v? (R=5303 ft-lbf/lbm-˚R, and air can be modeled as an ideal gas.)  A.9.8 ft^3/lbm  B.11.2 ft^3/lbm  C.13.33 ft^3/lbm  D.14.2 ft^3/lbm Formula: pv = RT v = RT / p

Last Answer : 13.33 ft^3/lbm

Description : The weight of an object is 50lb. What is its mass at standard condition?  a. 50 lbm  b. 60 lbm  c. 70 lbm  d. 80 lbm formula: m = Fgk /g

Last Answer : 50 lbm

Description : Gas is enclosed in a cylinder with a weighted piston as the stop boundary. The gas is heated and expands from a volume of 0.04 m^3 to 0.10 m^3 at a constant pressure of 200kPa.Calculate the work done by the system.  A. 8 kJ  B. 10 kJ  C.12 kJ  D.14 kJ Formula: W = p(V2-V1)

Last Answer : 12 kJ

Description : The standard reference atmospheric pressure  a. 760 mmHg  b. 1 atm  c. 14.696 psia  d. All of the above

Last Answer : All of the above

Description : A vertical column of water will be supported to what height by standard atmospheric pressure.  a. 33.9 ft  b. 45 ft  c. 67 ft  d. 25.46 ft ho= Po/Yo

Last Answer : 33.9 ft

Description : _________ is defined as that equivalent to the pressure due to a column of mercury 76cm long.  a. surface pressure  b. gage pressure  c. standard atmospheric pressure  d. isobaric pressure

Last Answer : standard atmospheric pressure

Description : The difference between the absolute pressure and the atmospheric pressure is called the _____ pressure.  A. Gage  B. Normal  C. Standard  D. Vacuum

Last Answer : Gage

Description : Which of the following is NOT a value of the standard atmospheric pressure?  A. 1 bar  B. 1 atm  C. 1 kgf/cm^2  D. 14.223 psi

Last Answer : 14.223 psi

Description : Twenty grams of oxygen gas are compressed at a constant temperature of 30 ˚C to 5%of their original volume. What work is done on the system.  A.824 cal  B.924 cal  C.944 cal  D.1124 cal Formula: W = -mRTln (V2/V1) Where R = (1.98 cal/gmole·K) (32 g/gmole)

Last Answer : 1124 cal

Description : The volume of a gas under constant pressure increases or decrease with temperature.  a. Gay- Lussac’s Law  b. Ideal Gas Law  c. Charles’ Law  d. Boyle’s Law

Last Answer : Charles’ Law

Description : According to Avogadro's Hypothesis  (a) the molecular weights of all the perfect gases occupy the same volume under same conditions of pressure and temperature  (b) the sum of partial pressure of ... gases have two values of specific heat  (e) all systems can be regarded as closed systems.

Last Answer : Answer : a

Description : While swimming a depth of 13m in a fresh water lake a fish emits an air bubble of volume 2 mm² atmospheric pressure is 100kpa what is the original pressure of the bubble.  a. 217.17 kpa  b. 119 kpa  c. 326.15 kpa  d. 210 kap Pabs = Pg + Patm

Last Answer : 217.17 kpa

Description : The flow energy of 5 ft3 of a fluid passing a boundary to a system is 80,000 ft-lb. Determine the pressure at this point.  a. 222 psi  b. 333 psi  c. 444 psi  d. 111 psi formula: Ef= pV

Last Answer : 111 psi

Description : The molecular number density of an ideal gas at standard temperature and pressure in cm3  a. Froude number  b. Loschmidt number  c. Mach number  d. Reynold number

Last Answer : Loschmidt number

Description : The ideal efficiency of a Brayton cycle with regeneration, with increase in pressure ratio will  (a) increase  (b) decrease  (c) remain unchanged  (d) increase/decrease depending on ap-plication  (e) unpredictable. “

Last Answer : Answer : b

Description : Ten cu ft. of air at 300 psia 400°F is cooled to 140°F at constant volume. What is the final pressure? (formula: p2 = p1T2/T1)  a. 0  b. 209 psia  c. - 420 psia  d. None of the above

Last Answer : 209 psia

Description : What is the resulting pressure when one pound of air at 15 psia and 200 ˚F is heated at constant volume to 800 ˚F?  A.15 psia  B. 28.6 psia  C. 36.4 psia.  D. 52.1 psia Formula : T1/p1 = T2/p2 p2= p1T2 / T1

Last Answer : 28.6 psia

Description : Steam at 1000 lbf/ft^2 pressure and 300˚R has specific volume of 6.5 ft^3/lbm and a specific enthalpy of 9800 lbf-ft/lbm. Find the internal energy per pound mass of steam.  A.2500 lbf-ft/lbm  B.3300 lbf-ft/lbm  C.5400 lbf-ft/lbm  D.6900 lbf-ft/lbm Formula: h= u+ pV u= h– pV

Last Answer : 3300 lbf-ft/lbm

Description : The low water datum for a lake is defined as the surface of the lake when it is at elevation (A) 180.5 m above M.S.L. (B) 190.5 m above M.S.L. (C) 170.5 m above M.S.L. (D) 200.0 m above M.S.L.

Last Answer : (A) 180.5 m above M.S.L.

Description : There are 1.36 kg of gas, for which R = 377 J/kg.k and k = 1.25, that undergo a nonflow constant volume process from p1 = 551.6 kPa and t1 = 60°C to p2 = 1655 kPa. During the process the gas is internally stirred and ... (Formula: T2= T1p2/ p1)  a. 999 K  b. 888 K  c. 456 K  d. One of the above

Last Answer : 999 K

Description : 3.0 lbm of air are contained at 25 psia and 100 ˚F. Given that Rair = 53.35 ft-lbf/lbm- ˚F, what is the volume of the container?  A.10.7 ft^3  B.14.7 ft^3  C.15 ft^3  D.24.9 ft^3 Formula: use the ideal gas law pV = mRT T = (100 +460) ˚R V = mRT/p

Last Answer : 24.9 ft^3

Description : For which of the following substances, the gas laws can be used with minimum error  (a) dry steam  (b) wet steam  (c) saturated steam  (d) superheated steam  (e) steam at atmospheric pressure.

Last Answer : Answer : d

Description : What is the temperature when water and vapor are in equilibrium with the atmospheric pressure?  a. Ice point  b. Steam point  c. Critical point  d. Freezing point

Last Answer : Steam point

Description : What is the temperature when water and vapor are in the equilibrium with the atmospheric pressure?  a. Ice point  b. Steam point  c. Critical point  d. Freezing point

Last Answer : Steam point

Description : Water boils when:  A. Its saturated vapor pressure equals to the atmospheric pressure  B. Its vapor pressure equals 76cm of mercury  C. Its temperature reaches 212 degree Celsius  D. Its vapor pressure is 1 gram per sq. cm

Last Answer : Its saturated vapor pressure equals to the atmospheric pressure

Description : A law relating the pressure, temperature and volume of an ideal gas  a. Gay-Lussac’s Law  b. Ideal gas Law  c. Charles’ Law  d. Boyle’s Law

Last Answer : Ideal gas Law

Description : If the initial volume of an ideal gas is compressed to one-half its original volume and to twice its original temperature, the pressure:  a. doubles  b. halves  c. quadruples  d. triples

Last Answer : quadruples

Description : What Law states that the pressure of gas is inversely proportional to its volume at constant temperature?  a. Charles’ law  b. Gay-Lussac’s Law  c. Boyle’s Law  d. Dalton’s Law

Last Answer : Boyle’s Law

Description : The volume of a confined gas is held constant, the pressure is directly proportional to the absolute temperature.  a. Charle’s Law  b. Boyle’s Law  c. Joule’s Law  d. Specific Heat

Last Answer : Boyle’s Law

Description : The pressure of the confined gas is held constant, the volume directly proportional to the absolute temperature.  a. Charle’s Law  b. Boyle’s Law  c. Zeroth Law  d. Gas Law

Last Answer : Charle’s Law

Description : “If the temperature o f a fixed quantity of a gas is held constant during a change of state, the volume varies inversely with the absolute pressure.  a. Charle’s Law  b. Boyle’s Law  c. Dalton’s Law  d. Amagat’s Law

Last Answer : Boyle’s Law

Description : A gas having a volume of100 ft³ at 27ºC is expanded to 120 ft³by heated at constant pressure to what temperature has it been heated to have this new volume?  a. 87°C  b. 85°C  c. 76°C  d. 97°C t2= T2–T1

Last Answer : 87°C

Description : An ideal gas is maintained at constant temperature. If the pressure on the gas is doubled, the volume is  a. increased fourfold  b. doubled  c. reduced by half  d. decreased by a quarter

Last Answer : reduced by half

Description : The volume of an ideal gas is directly proportional to its  a. pressure  b. Celsius temperature  c. Kelvin temperature  d. Fahrenheit temperature

Last Answer : Kelvin temperature

Description : The gas in a constant gas thermometer cooled to absolute zero would have _________.  a. no volume  b. no pressure  c. zero temperature at all scales  d. none of the above

Last Answer : no pressure

Description : What gas thermometer is based on the principle that at low pressure, the temperature of a gas is proportional to its pressure at constant volume?  A. Constant-pressure gas thermometer  B. Isobaric gas thermometer  C. Isometric gas thermometer  D. Constant-volume gas thermometer

Last Answer : Constant-volume gas thermometer

Description : The temperatures of the ideal gas temperature scale are measured by using a ______.  A. Constant-volume gas thermometer  B. Constant-mass gas thermometer  C. Constant-temperature gas thermometer  D. Constant-pressure gas thermometer

Last Answer : Constant-volume gas thermometer

Description : For a perfect gas, according to Boyle’s law (where p = Absolute pressure, v = Volume, and T = Absolute temperature)  A. p v = constant, if T is kept constant  B. v/T = constant, if p is kept constant  C. p/T = constant, if v is kept constant  D. T/p = constant, if v is kept constant

Last Answer : Answer: A