what is the hcf 153 And 85?

what is the hcf 153 And 85?
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What are 153 candies in a bag. Each candy has 4 calories. If you ate the whole bag, what is the best estimate for how many calories you consumed ?

Description : What are 153 candies in a bag. Each candy has 4 calories. If you ate the whole bag, what is the best estimate for how many calories you consumed ?

Last Answer : That would be 153 times 4 which is 612 calories total.

What is 153.86 rounded to tenths?

Description : What is 153.86 rounded to tenths?

Last Answer : Need answer

Are 153 and 35 relatively prime?

Description : Are 153 and 35 relatively prime?

Last Answer : Yes, because their only common factor is 1.

How many times can 3 go into 153?

Description : How many times can 3 go into 153?

Last Answer : fifty-one150 = 50 x 3153 = 51 x 3

How many times does 20 go into 153?

Description : How many times does 20 go into 153?

Last Answer : 7 with 13 remaining153 - 13 = 140 = 20 x 7

What does the U.S. Law Title 10 USC Section 153 give?

Description : What does the U.S. Law Title 10 USC Section 153 give?

Last Answer : What is the answer ?

What is the next number in 146 153 157 165?

Description : What is the next number in 146 153 157 165?

Last Answer : What is the answer ?

What is the rate unit of 153 in 10 minutes?

Description : What is the rate unit of 153 in 10 minutes?

Last Answer : 15.3 per minute

What is 2.153 to the nearest hundred?

Description : What is 2.153 to the nearest hundred?

Last Answer : It is zero but to the nearest hundredth it is 2.15

Round 392,153 to the nearest hundred thousand?

Description : Round 392,153 to the nearest hundred thousand?

Last Answer : 400000

The glycerol for fatty acid esterification in adipocytes is (A) For the most part, derived from glucose (B) Obtained primarily from phosphorylation of glycerol by glycerol kinase (C) Formed from gluconeogenesis (D) Formed from glycogenolysis ENZYMES 153

Description : The glycerol for fatty acid esterification in adipocytes is (A) For the most part, derived from glucose (B) Obtained primarily from phosphorylation of glycerol by glycerol kinase (C) Formed from gluconeogenesis (D) Formed from glycogenolysis ENZYMES 153

Last Answer : Answer : A

The appointment of a Governor in a state is made as per the provision in the Constitution under article. (1) 153 (2) 154 (3) 155 (4) 156

Description : The appointment of a Governor in a state is made as per the provision in the Constitution under article. (1) 153 (2) 154 (3) 155 (4) 156

Last Answer : (3) 155 Explanation: Appointment of the Governor of Indian state is described under Article 155 of the Indian constitution.

The provision for Constitution of Legislatures in states is enshrined in which article of the Indian Constitution? (1) Article 168 (2) Article 174 (3) Article 197 (4) Article 153

Description : The provision for Constitution of Legislatures in states is enshrined in which article of the Indian Constitution? (1) Article 168 (2) Article 174 (3) Article 197 (4) Article 153

Last Answer : (1) Article 168 Explanation: The provision for Constitution of Legislatures in states is enshrined in Article 168 of the Indian Constitution.

104 153 189 214 ? a) 239 b) 225 c) 264 d) 235 e) None of these

Description : 104 153 189 214 ? a) 239 b) 225 c) 264 d) 235 e) None of these

Last Answer : Answer: e)

4×(√3 + √4)2 + 6(√5 +√6)2 -3(√2 + √3)2 =? a) 167 b) 123 c) 157 d) 153 e) 149

Description : 4×(√3 + √4)2 + 6(√5 +√6)2 -3(√2 + √3)2 =? a) 167 b) 123 c) 157 d) 153 e) 149

Last Answer : ? =4(3+4+2√12) + 6(5+6+2√30)-3(2+3+2√6) =4(7+2√12)+6(11+2√30)-3(5+2√6) =28 + 8√12 + 66 + 12√30 – 15 - 6√6 =(28+66-15) + (8√12+12√30-6√6) =79 + (8√4 × 3 + 12√30 - 6√6) =79+16√3 + 12√30 - 6√6 =79 + 16 ×1.7 + 12 × 5.4 – 6 ×2.4 =79+27.2 + 64.8-14.4 = 156.6 = 157 Answer: c)

Limiting moment of resistance of a singly reinforced section for mild steel is [ A ] Mu = 0.133 fck bd2 [ B ] Mu = 0.138 fck bd2 [ C ] Mu = 0.148 fck bd2 [ D ] Mu = 0.153 fck bd2

Description : Limiting moment of resistance of a singly reinforced section for mild steel is [ A ] Mu = 0.133 fck bd2 [ B ] Mu = 0.138 fck bd2 [ C ] Mu = 0.148 fck bd2 [ D ] Mu = 0.153 fck bd2

Last Answer : [ C ] Mu = 0.148 fck bd2

You are given the following address: 153.50.6.27/25. Determine the subnet mask, address class, subnet address, and broadcast address. * 255.255.255.128, B,153.50.6.0, 153.50.6.127 * 255.255.255.128, C,153.50.6.0, 153.50.6.127 * 255.255.255.128, C,153.50.6.127, 153.50.6.0 * 255.255.255.224, C,153.50.6.0, 153.50.6.127

Description : You are given the following address: 153.50.6.27/25. Determine the subnet mask, address class, subnet address, and broadcast address. * 255.255.255.128, B,153.50.6.0, 153.50.6.127 * 255.255.255.128, C,153.50.6.0, 153 ... .128, C,153.50.6.127, 153.50.6.0 * 255.255.255.224, C,153.50.6.0, 153.50.6.127

Last Answer : Correct answer: A 255.255.255.224,

Find out the wrong number in the sequence: 125, 127, 130, 135, 142, 153, 165 (A) 130 (B) 142 (C) 153 (D) 165

Description : Find out the wrong number in the sequence: 125, 127, 130, 135, 142, 153, 165 (A) 130 (B) 142 (C) 153 (D) 165

Last Answer : Answer: C Difference 125 and 127 is 2, then 3, 5, 7, 11, and 12. Except 12 all are prime numbers so 165 is wrong in series.

What is the bit rate for transmitting uncompressed 800x600 pixel colour frames with 8 bits/pixel at 40 frames/second ? (A) 2.4 Mbps (B) 15.36 Mbps (C) 153.6 Mbps (D) 1536 Mbps

Description : What is the bit rate for transmitting uncompressed 800x600 pixel colour frames with 8 bits/pixel at 40 frames/second ? (A) 2.4 Mbps (B) 15.36 Mbps (C) 153.6 Mbps (D) 1536 Mbps 

Last Answer : (C) 153.6 Mbps Explanation: The number of bits/sec is just 800x600x40x8 or 153.6 Mbps.

Redgram worth Rs. 112 per kg and Rs.123 per kg are mixed with a third variety in the ratio 1: 1 : 2. If the mixture is worth Rs. 142 per kg, the price of the third variety per kg will be a) 153 b) 175.50 c) 43.9 d) 227.9 e) 166.5

Description : Redgram worth Rs. 112 per kg and Rs.123 per kg are mixed with a third variety in the ratio 1: 1 : 2. If the mixture is worth Rs. 142 per kg, the price of the third variety per kg will be a) 153 b) 175.50 c) 43.9 d) 227.9 e) 166.5 

Last Answer : E  Since first second varieties are mixed in equal proportions  so their average price = Rs.(112 + 123/2)  = Rs. 117.5  So, the mixture is formed by mixing two varieties, one at Rs. 117.50 per kg and the ... ratio 2 : 2, i.e., 1 : 1. We have to find x.  By the rule of allgation 

In an examination, 900 students appeared. Out of these students; 56 % got first division, 27 % got second division and the remaining just passed. Assuming that no student failed; find the number of students who just passed. a) 225 b) 153 c) 245 d) 148 e) 298

Description : In an examination, 900 students appeared. Out of these students; 56 % got first division, 27 % got second division and the remaining just passed. Assuming that no student failed; find the number of students who just passed. a) 225 b) 153 c) 245 d) 148 e) 298

Last Answer : Answer: B The number of students with first division = 56 % of 900  = 56/100 × 900 = 50400/100  = 504 And, the number of students with second division = 27 % of 900  = 27/100 × 900  =24300/100  = 243 Therefore, the number of students who just passed = 900 – (504 + 243)  = 900- 747  = 153

Use Euclid’s division algorithm to find the HCF of: i. 135 and 225 ii. 196 and 38220 iii. 867 and 225 -Maths 10th

Description : Use Euclid’s division algorithm to find the HCF of: i. 135 and 225 ii. 196 and 38220 iii. 867 and 225 -Maths 10th

Last Answer : 135 and 225 As you can see, from the question 225 is greater than 135. Therefore, by Euclid's division algorithm, we have, 225 = 135 1 + 90 Now, remainder 90 ≠ 0, thus again using division lemma for 90, we get, ... (867,225) = HCF(225,102) = HCF(102,51) = 51. Hence, the HCF of 867 and 225 is 51

Use Euclid’s division algorithm to find the HCF of : (i) 135 and 225 (ii) 196 and 38220 (iii) 867 and 255 -Maths 10th

Description : Use Euclid’s division algorithm to find the HCF of : (i) 135 and 225 (ii) 196 and 38220 (iii) 867 and 255 -Maths 10th

Last Answer : (i) Given numbers are 135 and 225. On applying Euclid's division algorithm, we have 225 = 135 x 1 + 90 Since the remainder 90 ≠ 0, so again we apply Euclid's division algorithm to 135 and 90, to get 135 = 90 x ... division lemma, to a =867 and b=255 to find q and r such that 867 = 255q + r, 0 ≤ r

If the HCF of (x^2 + x – 12) and (2x^2 – kx – 9) is (x – k), then what is the value of k ? -Maths 9th

Description : If the HCF of (x^2 + x – 12) and (2x^2 – kx – 9) is (x – k), then what is the value of k ? -Maths 9th

Last Answer : answer:

If (x + k) is the HCF of ax^2 + ax + b and x^2 + cx + d, then what is the value of k ? -Maths 9th

Description : If (x + k) is the HCF of ax^2 + ax + b and x^2 + cx + d, then what is the value of k ? -Maths 9th

Last Answer : answer:

What is the full form of 'HCF' ? -How To ?

Description : What is the full form of 'HCF' ? -How To ?

Last Answer : The full form of 'HCF' is Highest Common Factor

what is the hcf of 33 and 15?

Description : what is the hcf of 33 and 15?

Last Answer : 3

What is the HCF of 45 and 81?

Description : What is the HCF of 45 and 81?

Last Answer : \Theta } (N), but usually it will go much faster. For multiplication, the most straightforward algorithms used for multiplying numbers by hand (as taught in primary school) ... along with complexity estimates, see computational complexity of mathematical operations. For examples in x86 assembly

hcf of 9 and 18?

Description : hcf of 9 and 18?

Last Answer : 9

What is the hcf of 4 3 5?

Description : What is the hcf of 4 3 5?

Last Answer : the GCF of 4 3 5 is 1

what is the hcf for 150 and 180?

Description : what is the hcf for 150 and 180?

Last Answer : 30

what is the HCF for 150 and 250?

Description : what is the HCF for 150 and 250?

Last Answer : 50

What is the full form of HCF ?

Last Answer : HCF - Highest Common Factor

What is the HCF of 2440 and 72?

Description : What is the HCF of 2440 and 72?

Last Answer : The HCF of the given two numbers is 8

What is the HCF 3 x 13 and 2 cubed x 13?

Description : What is the HCF 3 x 13 and 2 cubed x 13?

Last Answer : The GCF is 13.

What is the HCF of 50 and 55?

Description : What is the HCF of 50 and 55?

Last Answer : It is 5.

What is the hcf of 32 56 and 80?

Description : What is the hcf of 32 56 and 80?

Last Answer : The GCF is 8.

What is the hcf for 21 and 49?

Description : What is the hcf for 21 and 49?

Last Answer : The GCF is 7.

What is the HCF for 12 and 24?

Description : What is the HCF for 12 and 24?

Last Answer : Since 12 is a factor of 24, it is automatically the GCF.

What is the HCF of 4a and 10a?

Description : What is the HCF of 4a and 10a?

Last Answer : The GCF is 2a.

What is the HCF of 39 65 91?

Description : What is the HCF of 39 65 91?

Last Answer : It is: 13

What is HCF of 35 and 45?

Description : What is HCF of 35 and 45?

Last Answer : The GCF is 5.

WHAT IS THE HCF of 52 and 143 and 156?

Description : WHAT IS THE HCF of 52 and 143 and 156?

Last Answer : The GCF is 13.

What is thr hcf of 84 154 and 182?

Description : What is thr hcf of 84 154 and 182?

Last Answer : It is: 14

What is the HCF of 16x27x49 and 8x27x125?

Description : What is the HCF of 16x27x49 and 8x27x125?

Last Answer : hcf(16×27×49, 8×2725) = 8×27 = 216Using prime factorisation:16×27×49 = 2⁴ × 3³ × 7²8×27×125 = 2³ × 3³ × 5³→ hcf = 2³ × 3³ = 8×27 = 216

What is the HCF of 160 and 90?

Description : What is the HCF of 160 and 90?

Last Answer : The GCF is 10.

What is the hcf of 81 and 45?

Description : What is the hcf of 81 and 45?

Last Answer : The GCF is 9.

What are the prime factor of HCF?

Description : What are the prime factor of HCF?

Last Answer : Each HCF has its own set of prime factors.

What is the hcf of 284984?

Description : What is the hcf of 284984?

Last Answer : If you mean 28, 49 and 84 then the hcf is 7

What is the hcf of 270?

Description : What is the hcf of 270?

Last Answer : You need at least two numbers to find a GCF.