What is the hcf of 32 56 and 80?

1 Answer

Answer :

The GCF is 8.

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Description : What is the hcf 64 and 80?

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Description : The median of the data 26,56,32,33,60,17,34,29,45 is 33. If 26 is replaced by 62, then find the new median. -Maths 9th

Last Answer : Here, the given data in ascending order is 17, 29, 32, 33, 34, 45, 56, 60, 62 Now median is (9 + 1 / 2)th term i.e. , 5th term Hence, new median is 34.

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Description : You are measuring noise in a voice channel at 7 dB test point level. The meter reads -56 dBm (FIA weighted). What is the reading in dBrnc? A. 20 B. 32 C. 35 D. 25

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Description : Which of the following couldnot be an Ethernet multicast destination? A) B7:7B:6C:DE:10:00 B) 7B:AA:C1:23:45:32 C) 7C:56:21:1A:DE:F4 D) 83:32:21:21:4D:34

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Description : Which of the following couldnot be an Ethernet unicast destination? A) 43:7B:6C:DE:10:00 B) 44:AA:C1:23:45:32 C) 46:56:21:1A:DE:F4 D) 48:32:21:21:4D:34

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Description : What is the decimal value of 26? A) 128 B) 36 C) 32 D) 64

Last Answer : D) 64

Description :  The average age of K and L is 48 years. If M replaced K, the average age would be 40 and if M replaced L, the average would be 44. What are the ages of K,L,M repectively? A) 58, 46, 22 B) 32, 44, 36 C) 52,44,36 D) 56, 22,38

Last Answer : Answer: C)  Total age of K& L = 48*2 = 96 yrs----->1 Total age of L& M = 40*2 = 80yrs----->2 Total age of K& M = 44*2 = 88 yrs----->3 from 1, 2, 3 K+L+M =132---->4 from 1 & 4, M= 36 from 2 & 4, K=52 from 3 & 4, L=44 Hence the required answer is 52,44,36 

Description : There are three different categories of jobs A, B and C. The average salary of the students who got the job of A and B categories is Rs.32 lakh per annum. The average salary of the student who got the job of B ... 30 & 44 B) lies between 48 & 56 C) lies between 38 & 45 D) lies between 49 & 50

Last Answer : Answer: C) Let the number of students who got the jobs of A, B and C categories is a, b and c respectively, ∴Total salary of Aand B = 32 (a +b) ∴Total salary of B and C = 54 (b+ ... the minimum salary must be Rs.38 lakh and the maximum salary cannot exceed 45, which is the highest of the three..

Description : A shopkeeper bought 1800 blackberry and 1200 blueberry. He found 45% of blackberry and 24% of blueberry were rotten. Find the percentage of fruits in good condition. a) 63.4 b) 32.9 c) 48.5 d) 56.3

Last Answer :  Answer: A Total number of fruits shopkeeper bought = 1800 + 1200 = 1000 Number of rotten blackberry = 45% of 1800  = 45/100 1800  = 81000/100  = 810 Number of rotten blueberry = 24% of 1200 ... Therefore Percentage of fruits in good condition = (1902/3000 100)  = (190200/3000)  = 63.4%

Description : Find the median of the data 35, 28, 49, 56, 79, 81, 73 and 80.

Last Answer : Find the median of the data 35, 28, 49, 56, 79, 81, 73 and 80. A. 64.5 B. 65 C. 65.5 D. 66

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Last Answer : 9.86 x 10^4 N/m^2

Description : ?% of 725 + 14% of 2100 = 700 a) 64 b) 80 c) 72 d) 56 e) 48

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Description : In a 100 quadrat study of 1 sqm each Cyperus rotundus was found in 80 quadrats with overall of 5640 individuals. The frequency (%), abun dance and density (m2) would be a). 70.5, 80.0 and 56.4 b). 56.4, 70.5 and 80.0 c). 80.0, 70.5 and 56.4 d). 80.0, 56.4 and 70.5

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Description : Use Euclid’s division algorithm to find the HCF of: i. 135 and 225 ii. 196 and 38220 iii. 867 and 225 -Maths 10th

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