Find the height of a cylinder with the volume of 452.16 and a radius of 4 in?

Find the height of a cylinder with the volume of 452.16 and a radius of 4 in?
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1 Answer

Answer :

V=πr^2hh = V/(πr^2)h = 452.16/(π*4^2)h = 8.99 in
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Last Answer : since curved surface of half of the spherical ball = 56.57 cm2 ∴ 2πr2 = 56.57 ⇒ r2 = 56.57 / 2 × 3.14 = 9 ⇒ r = 3 cm Now, volume of spherical ball = 4 / 3 πr3 = 4 / 3 × 3.14 × 3 × 3 × 3 = 113.04 cm3

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