Description : The average age of students of a class is 15.8 years. The average age of boys in the class is 16.4 years and that of the girls is 15.4 years. The ratio of the number of boys to the number of girls in the class is: A. 1 : 4 B. 2 : 3 C. 3 : 4 D. 4 : 2 E. None of these
Last Answer : Answer – B (2 : 3) Explanation – Let the ratio be k:1 Then, k x 16.4 + 1 x 15.4 = (k + 1) x 15.8 (16.4 – 15.8) k = (15.8 – 15.4) k=2/3
Description : The average age of students of a college is 31.6 yrs. The average age of boys in the class is 32.8 yrs and that of girls is 30.8. The ratio of number of boys to the number of girls in the class. A) 2:3 B) 3:1 C) 1:3 D) 3:2
Last Answer : A) Let the ratio be D:1.then, (D * 32.8) + ( 1* 30.8)= (D+1) * 31.6 32.8 D +30.8 = 31.6 D + 31.6 32.8 D – 31.6D = 31.6 – 30.8 1.2D = 0.8 D = 0.8/1/2 = 0.4/0.6 D = 2/3 Required ratio = 2/3 :1 = 2:3.
Description : In a class, there are x girls and y boys, a student is selected at random, then find the probability of selecting a boy. -Maths 9th
Last Answer : Number of boys = y Total students = (x + y) Thus,P(a boy)= y/(x+y)
Description : The ratio of girls and boys in a class is 1: 3. Set up an equation between the students of a class and boys and then draw its graph. Also find the number of boys in a class of 40 students from the graph. -Maths 9th
Last Answer : Total number of boys and girl = 40, Ratio = 1 : 3 Number of girls be A and Number of boys be B. Ratio of number of girls and boys is 1 : 3, so Therefore 3A=B To find number of boys we ... the number 30 represents the number of girls. 40 as total on the line A = 10, which is the common equation.
Description : A class consists of 80 students, 25 of them are girls and 55 boys. 10 of them are rich and 20 are fair complexioned. -Maths 9th
Last Answer : Let P (A) = Probability of selecting a fair complexioned person. ThenP(A) = \(rac{20}{80}\) = \(rac{1}{4}\)Let P(B) = Probability of selecting a rich person. Then P(B) = \(rac{10}{80}\) = \(rac{1}{8}\)Let P (C) = ... ) = \(rac{1}{4}\)x \(rac{1}{8}\)x \(rac{5}{16}\) = \(rac{5}{512}\) = 0.009.
Description : In a class there are 15 boys and 10 girls. Three students are selected at random. The difference between the probability that 2 boys and 1 girl are selected compared to 1 boy and 2 girls are selected is: a) 23/78 b) 19/88 c) 15/92 d) 4/23 e) 7/46
Last Answer : 2 boys, 1 gi(Prl = (15c2×10c1) / 25c3 = 1050/2300 1 boy, 2 girls = (15c1×10c2) / 25c3 = 675/2300 Difference = (1050 - 675)/2300 = 375/2300 = 15/92 Answer: c)
Description : Number of students in 4th and 5th class is in the ratio 6 : 11. 40% in class 4 are girls and 48% in class 5 are girls. What percentage of students in both the classes are boys? A) 62.5% B) 54.8% C) 52.6% D) 55.8% E) 53.5%
Last Answer : Answer: B Total students in both = 6x+11x = 17x Boys in class 4 = (60/100)*6x = 360x/100 Boys in class 5 = (52/100)*11x = 572x/100 So total boys = 360x/100 + 572x/100 = 932x/100 = 9.32x % of boys = [9.32x/17x] * 100=54.8%
Description : If `20%` of the student in a school are girls and the number of boys is 3060, then find the total strength of the school.
Last Answer : If `20%` of the student in a school are girls and the number of boys is 3060, then find the total strength of the school.
Description : In a class of 24 students, each student shakes hand with everyone els. In another class of 32 students, each student shakes hand with all other students. What is the difference between total number of hand shakes in the 2 classes? a) 180 b) 200 c) 22 d) 240 e) 260
Last Answer : 1 st class : Total Hand shakes = 24 × 23 /2 = 12 × 23 =276 2nd class :Total Hand shakes =32 × 31 / 2 = 16 × 31 = 496 Difference =220 Answer : c
Description : The average marks of a class of 90 students is 126. Out Of them, 4 scores zero, first 60 students scored an average of 116, next 24 scored an average of 118. What is the mark obtained by the remaining student in the class? A) 750 B) 862 C) 774 D) 875
Last Answer : C) According to the question, 90*126=(4*0)+(60*116)+(24*118)+2y 11340=6960+2832+2y 2y=1548 y=774
Description : 70% of the students in a school are boys and the number of girls is 504. Find the number of boys in the school. -Maths
Last Answer : answer:
Description : Out of the students studying Homeopathy, what is the ratio between number of boys knowing English and the number of girls knowing Hindi respectively? (1) 3 : 5 (2) 2 : 3 (3) 9 : 11
Last Answer : (2) 2 : 3
Description : The ratio of the number of boys to the number of girls in a school is 6 : 5. If 20% of boys and 45% of girls come by bus to school, what percentage of students opt transport other than bus to come to school? A) 68 9/11% B) 68 7/11% C) 72 7/11% D) 73% E) 73 5/11%
Last Answer : Answer: B If 20% of boys and 45% of girls come by bus, then 80% of boys and 55% of girls opt transport other than bus. Let total number of students in school = x So boys who opt other transport are (80/100) * 6/(6+5 ... (24x/55) + (x/4) = 151x/220 So required % = [(151x/220)/x] * 100 = 68 7/11 %
Description : The ratio of the number of boys to that of girls in a school is 3:2. If 30% of boys and 70% of girls appeared in an examination, the ratio of students appeared in the examinations to that not appeared in the examination is A) 23:27 B) 22:25 C) 21:17 D) 18:17 E) None of these
Last Answer : Answer: A 3:2 = 30:20 30% boys = (30/100) × 30= 9 70% girls = (70/100) × 20 = 14 (9+14) : (50-23) = 23 : 27
Description : In a batch, there are 22 boys and 18 girls. Three students are selected at random. The probability that 1 girl and 2 boys are selected, is: a) 3754/8854 b) 4158/9880 c) 8514/9880 d) 2078/4920
Last Answer : Answer: B) Let , S - sample space E - event of selecting 1 girl and 2 boys. Then, n(S) = Number ways of selecting 3 students out of 40 = 40C3 = 9880 n(E) = 18C1 *22C2 = 18*231 = 4158 P(E) = n(E)/n(s) = 4158/9880
Description : In a college of 1335 students, 60 % are boys. Find the number of girls and number of boys in the college? a) 924,221 b) 691,404 c) 802,333 d) 441,564 e) 534,801
Last Answer : Answer: E Number of boys in the college = 60 % of 1335 = 60/100 × 1335 = 80100/100 = 801 Number of girls in the college = Total number of students in the college - Number of boys = 1335 – 801 =534
Description : Each Student of a class collected some money for the trip. The total money collected by each student was equal to the cube of the total number of students. If the total amount collected was Rs. 29791. find the total number of students. 1. 31 2. 30 3. 28 4. 37 5. 39
Last Answer : 1; Total number of students
Description : The number of boys and girls in a class are in the ratio of ` 3 : 4` Find the strength of the class if there are 10 more girls than there are boys.
Last Answer : The number of boys and girls in a class are in the ratio of ` 3 : 4` Find the strength of the class if there are 10 more girls than there are boys.
Description : The ratio of boys to girls in history class is to 4 to 5. How many girls are in the class is there are 12 boys in the class?
Last Answer : 5 to 4
Description : The average age of the whole class is 12.05 years. The average age of all girls is 12.5 years and the average age of boys is 11.75 years. If the total number of boys is 45 then what is the total number of girls in the class? a) 20 b) 25 c) 30 d) 35 e) 40
Last Answer : Let the number of girls be x. The number of boys is 45. :. Total age of boys and girls in the class = (x+45) × 12.05 or, (x+45) × 12.05 = 45 × 11.75 + x × 12.5 or, 12.05x + 542.25 = 528.75 + 12.5x or, 13.5 = 0.45x or, x = 13.5/0.45 = 30 Answer is: c)
Description : Write a C++ program to declare a class student with members as roll no, name and department. Declare a parameterized constructor with default value for department as ‘CO’ to initialize members of object. Initialize and display data for two students.
Last Answer : write a C plus plus program to declare a class which accept and display student information such as roll number division and percentage use get data and put data with required parameters
Description : In a school, maximum strength of each class is 60. In class VIII, the total number of students is a multiple of 5. On a certain day, four boys were ab
Last Answer : In a school, maximum strength of each class is 60. In class VIII, the total number of students is a multiple ... 4:3` C. `2:1` D. Data is insufficient
Description : When girl-students make a request, the other male students are annoyed with you on the pretext that you have been easily approached by them and do a favour. In such a situation how ... assistance D) You will try to improve the interaction in the class without emphasizing gender discrimination
Last Answer : B) You will justify that most of the girl students are more sincere towards their studies than the boys
Description : I am something that the naughty boys use to draw on, girls write beautifully on the side, you have to clap my defeaters every day, and I stand dumbly as the young children cry. What am I? -Riddles
Last Answer : A chalkboard. (When the young children cry, it means they are crying for a turn to write the answer and the defeaters are the erasers)
Description : In a monthly test, 10 students were awarded marks in a Mathematics examination as follows: 23, 25, 15, 20, 17, 10, 24, 15, 19 If a student is selected
Last Answer : In a monthly test, 10 students were awarded marks in a Mathematics examination as follows: 23, 25 ... the probability that he gets more than 18 marks?
Description : In how many ways can teacher seat 5 girls and 3 boys in a row of 8 seats if a boy must be seated in the first seat and a girl in the last seat?
Last Answer : Feel Free to Answer
Description : 6 boys and 5girls can do a job in 8 days. When 7 boys and 10 girls work on the same job, the work gets completed in 5 days. How many days will a boy take to do the job, if he works alone on it? a) A.25 b) B.50 c) C.75 d) D.100
Last Answer : D Let the amount of work done by a boy in a day be B′ and the amount of work done by a girl in a day be G′. Therefore, 6 boys and 5 girls will do 6B+5G amount of work in a day. If 6 boys and 5 ... 1/100 i.e. a boy does 1/100th of the work in a day. Hence he will take 100 days to do the work.
Description : A class consists of 50 students out of which 30 are girls. -Maths 9th
Last Answer : Mean marks scored by girls ( x̅1 ) = 73 Number of girls (n1) = 30 Mean marks scored by boys ( x̅2 ) = 71 Number of boys (n2) = 50 - 30 = 20 Mean score of the whole class ( x̅12 ) = n1 x̅1 + n2 x̅2 /n1 + n2 = 30 x 73 + 20 x 71/30 + 20 = 2190 + 1420/50 = 3610/50 x̅ 2 = 72.2
Description : In a class there are 16 girls out of 40 students in total. Girls as a percentage of total students are `"_____"`
Last Answer : In a class there are 16 girls out of 40 students in total. Girls as a percentage of total students are `"_____"`
Description : The male students of your class are annoyed with you' on the pretext you have been easily approached the girl students and do a favor to them (girls). In such an embarrassing situation how would you like ... it is difficult for you refuse the request made by female students. (d) None of the above.
Last Answer : (a) You will tell the male students that girls have no option except to depend on the school teacher for their academic assistance.
Description : The male students in your class are annoyed with you on the pretext you that have a favour to the female students. In such an embarrassing situation how would you like to control them in class? ... students that it is difficult for you refuse the request made by female students D) None of these
Last Answer : B) You will justify that most of the female students are more sincere towards their studies than male students.
Description : How do you write 122 as a fraction or a mixed number in simplest form?
Last Answer : You cannot because 122 is an integer. It is neither a fractionnor a mixed number.
Description : How do you write 76 as a fraction in simplest form?
Last Answer : You cannot because 76 is an integer. It is neither a fractionnor a mixed number.
Description : How do you write 50 as a fraction mixed number or whole number in simplest form?
Last Answer : 50 is an integer so its simplest form is 50.
Description : How do you write 350 percent as a fraction or mixed number in simplest form?
Last Answer : 350% = 7/2 or 31/2.
Description : How do you write 66 as a fraction in simplest form?
Last Answer : You cannot because 66 is an integer. It is neither a fractionnor a mixed number.
Description : How do you write 630 as a fraction mixed number or whole number in simplest form?
Last Answer : You cannot because 630 is an integer. It is neither a fractionnor a mixed number.
Description : How do you Write 810 in simplest form and then write another equivalent fraction for 810?
Last Answer : 810 is an integer and so it is in its simplest form. Anequivalent fraction is any number of the form (810*n)/n where n isa non-zero integer.
Description : How do you write 80 as a fraction simplest form?
Last Answer : 80 is an integer, not a fraction.
Description : How do you write 275 percent as a fraction or mixed number in simplest form?
Last Answer : 275% = 23/4.
Description : How do you Write 810 in simplest form and then then write another equivalent fraction for 810?
Last Answer : 16/20 and then 4/5
Description : How do you write 356 as a fraction or mixed number in simplest form?
Last Answer : It is simply 356/1 as an improper fraction
Description : How do you write 104 as a fraction mixed number or whole number in simplest form?
Last Answer : 104 is already expressed as a whole number
Description : How do you write 98 as a fraction in simplest form?
Last Answer : 98 is a whole number whose simplest form is 98.
Description : How do you write 81 as a fraction in simplest form?
Last Answer : 81 is a whole number whose simplest form is 81.
Description : How do you write 82 as a fraction in simplest form?
Last Answer : 82 is not a fraction or a mixed number. It is a whole number,and whole numbers cannot be simplified.
Description : How do you write 55 as a fraction or whole number in simplest form?
Last Answer : It is a whole number whose simplest form is 33.
Description : Why do you need to write a fraction in simplest form?
Last Answer : The simplest form has the smallest numbers and so may be easierto manipulate.