The ratio of the number of boys to that of girls in a school is 3:2. If 30% of boys and 70% of girls appeared in an examination, the ratio of students appeared in the examinations to that not appeared in the examination is A) 23:27 B) 22:25 C) 21:17 D) 18:17 E) None of these

The ratio of the number of boys to that of girls in a school is 3:2. If 30% of boys and 70% of girls appeared in an examination, the ratio of students appeared in the examinations to that not appeared in the examination is A) 23:27 B) 22:25 C) 21:17 D) 18:17 E) None of these 
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1 Answer

Answer :

 Answer: A

3:2 = 30:20

30% boys = (30/100) × 30= 9

70% girls = (70/100) × 20 = 14

(9+14) : (50-23) = 23 : 27
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Related questions

The ratio between the number of boys and girls in a school is 4:5. If the number of boys are increased by 30 % and the number of girls increased by 40 %, then what will the new ratio of boys and girls in the school. A) 13/35 B) 26/35 C) 26/41 D) 23/13 E) None of these

Description : The ratio between the number of boys and girls in a school is 4:5. If the number of boys are increased by 30 % and the number of girls increased by 40 %, then what will the new ratio of boys and girls in the school. A) 13/35 B) 26/35 C) 26/41 D) 23/13 E) None of these

Last Answer : Answer: B boys = 4x and girls = 5x. Required ratio = [(130/100)*4x]/ [(140/100)*5x] 26/35

The ratio of the number of boys to the number of girls in a school is 6 : 5. If 20% of boys and 45% of girls come by bus to school, what percentage of students opt transport other than bus to come to school? A) 68 9/11% B) 68 7/11% C) 72 7/11% D) 73% E) 73 5/11%

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Last Answer : Answer: B If 20% of boys and 45% of girls come by bus, then 80% of boys and 55% of girls opt transport other than bus. Let total number of students in school = x So boys who opt other transport are (80/100) * 6/(6+5 ... (24x/55) + (x/4) = 151x/220 So required % = [(151x/220)/x] * 100 = 68 7/11 %

The sum of the three number is 68.If the ratio of the first to second is 3:2 and that of the second to the third is 5:3 , then the second number is approximately A) 21 B) 22 C) 23 D) 24 E) None of these

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Last Answer : Answer: B A: B = 3:2 B:C = 5 : 3 B:C =(5×[2/5]) : (3×[2/5])= 2: (6/5) A:B:C = 3:2:(6/5) = 15:10:6 Second number = (10/31)×68 = 21.9 = 22

Number of students in 4th and 5th class is in the ratio 6 : 11. 40% in class 4 are girls and 48% in class 5 are girls. What percentage of students in both the classes are boys? A) 62.5% B) 54.8% C) 52.6% D) 55.8% E) 53.5%

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An employer reduces the number of his employees in the ratio of 7:4 and increases their wages in the ratio 3:5. State whether his bill of total wages increases or decreases and in what ratio. a) increases 20:21 b) decreases 21:20 c) increases 21:22 d) decreases 22:21 e) None of these

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A sum of Rs 315 consists of 25 paise, 50 paise and 1 Re coins in the ratio 3 : 4 :6. What is the number of each kind of coin respectively? A) 216, 144, 27 B) 108, 144, 216 C) 27, 72, 216 D) 120, 35, 108 E) 102, 150, 210

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1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49, 50'. What number is missing? -Riddles

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Last Answer : 22

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Last Answer : answer:

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Last Answer : Answer: A

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A school has 4 sections of class 12, such that half the number of students of 1st section, 1/3rd of 2nd section, 1/4th of 3rd section and 1/5th of the 4th section are equal. If total number of students in class 12 is 420, find the number of students in sections 1st and 2nd. A) 180 B) 120 C) 240 D) 150 E) 260

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In a monthly test, 10 students were awarded marks in a Mathematics examination as follows: 23, 25, 15, 20, 17, 10, 24, 15, 19 If a student is selected

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Three friends Alice, Bond and Charlie divide $1105 amongst them in such a way that if $10, $20 and $15 are removed from the sums that Alice, Bond and Charlie received respectively, then the share of the sums that they got will be in the ratio of 11 : 18 : 24. How much did Charlie receive? a) $495 b) $510 c) $480 d) $375 e) $360

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Saravanan has scored an total of 90% in an examination with five subjects in the ratio 18:14:15:21:22. If 85% is the marks required to get an ‘A’ grade in each subject, then find in how many subjects did he get an ‘A’ grade. Given that the maximum marks in each subject is 120. A) 2 B) 3 C) 4 D) 5

Description : Saravanan has scored an total of 90% in an examination with five subjects in the ratio 18:14:15:21:22. If 85% is the marks required to get an ‘A’ grade in each subject, then find in how many subjects did he get an ‘A’ grade. Given that the maximum marks in each subject is 120. A) 2 B) 3 C) 4 D) 5 

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Rs 5750 is divided among A, B, and C such that if their share be reduced by Rs 10, Rs 15 and Rs 25 respectively, the reminder amounts with them shall be in the ratio 4 : 6 : 9. What was C’s share then? A) Rs 2700 B) Rs 2725 C) Rs 2750 D) Rs 2625 E) None of these

Description : Rs 5750 is divided among A, B, and C such that if their share be reduced by Rs 10, Rs 15 and Rs 25 respectively, the reminder amounts with them shall be in the ratio 4 : 6 : 9. What was C’s share then? A) Rs 2700 B) Rs 2725 C) Rs 2750 D) Rs 2625 E) None of these

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A bag contains one rupee, 50 paise and 25 paise coins in the ratio 2 : 3 : 5. Their total value is Rs. 144. The value of 50-paise coins is: a) Rs. 24 b) Rs. 36 c) Rs. 48 d) Rs. 72 e) None of these

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The monthly incomes of A and B are in the ratio 4:5, their expenses are in the ratio 5 : 6. If 'A' saves Rs.25 per month and 'B' saves Rs.50 per month, what are their respective incomes? A) Rs.400 and Rs.500 B) Rs.240 and Rs.300 C) Rs.320 and Rs.400 D) Rs.440 and Rs.550 E) NONE

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Last Answer : Answer: A Let AA's income be = 4x AA's expenses, therefore = 4x–25 Let BB's income be = 5x BB's expenses, therefore = 5x–50 We know that the ratio of their expenses = 5:6 ⇒24x−150=25x−250 ⇒ Therefore, x=100 A's income =4x=400 and B's income =5x=500 

What is the total number of literate people in city 'A'? 1) 21.62 lakh 2) 22.18 lakh 3) 23.94 lakh 4) 24.63 lakh 5) 25.02 lakh

Description : What is the total number of literate people in city 'A'? 1) 21.62 lakh 2) 22.18 lakh 3) 23.94 lakh 4) 24.63 lakh 5) 25.02 lakh

Last Answer : 3) 23.94 lakh

Given are the scores (out of 25) of 9 students in a Monday test : 14, 25, 17, 22, 20, 19, 10, 8 and 23 -Maths 9th

Description : Given are the scores (out of 25) of 9 students in a Monday test : 14, 25, 17, 22, 20, 19, 10, 8 and 23 -Maths 9th

Last Answer : Ascending orders of scores is : 8, 10, 14, 17, 19, 20, 22, 23, 25 Now, new score = 8 + 10 + 14 + 17 + 19 + 20 + 22 + 23 + 25 / 9 = 158 / 9 = 17.5 marks Median = (n + 1 / 2)th observation because n is odd = (9 + 1 / 2)th observation = 5th observation = 19 marks.

Given are the scores (out of 25) of 9 students in a Monday test : 14, 25, 17, 22, 20, 19, 10, 8 and 23 -Maths 9th

Description : Given are the scores (out of 25) of 9 students in a Monday test : 14, 25, 17, 22, 20, 19, 10, 8 and 23 -Maths 9th

Last Answer : Ascending orders of scores is : 8, 10, 14, 17, 19, 20, 22, 23, 25 Now, new score = 8 + 10 + 14 + 17 + 19 + 20 + 22 + 23 + 25 / 9 = 158 / 9 = 17.5 marks Median = (n + 1 / 2)th observation because n is odd = (9 + 1 / 2)th observation = 5th observation = 19 marks.

Seats for Mathematics, Science and arts in a school are in the ratio 5:7:8. There is a proposal to increase these seats by X%, Y% and Z% respectively. And the ratio of increased seats is 2:3:4, which of the following is true? A) X = 50; Z = 40 B) Y = 40; Z = 50 C) X = 40; Z = 75 D) X = 50; Z = 40 E) Y = 50; X = 75

Description : Seats for Mathematics, Science and arts in a school are in the ratio 5:7:8. There is a proposal to increase these seats by X%, Y% and Z% respectively. And the ratio of increased seats is 2:3:4, which of the following is true? A) X = ... ; Z = 50 C) X = 40; Z = 75 D) X = 50; Z = 40 E) Y = 50; X = 75

Last Answer : Answer: C Number of increased seats are (140% of 5x), (150% of 7x) and (175% of 8x) i.e., (140/100 * 5x), (150/100 * 7x) and (175/100 * 8x) i.e., 7x, 21x/2 and 14x Required ratio = 7x:21x/2: ... of 8 = 6 total seats 8+6=14 Now compare ratios of all 7:21/2:14=>14:21:28 =>2:3:4

In a Examination a candidate has to score minimum of 24 marks inorder to clear the exam. The maximum that he can score is 40 marks. Identify the Valid Equivalance values if the student clears the exam. A. 22,23,26 B. 21,39,40 C. 29,30,31 D. 0,15,22

Description : In a Examination a candidate has to score minimum of 24 marks inorder to clear the exam. The maximum that he can score is 40 marks. Identify the Valid Equivalance values if the student clears the exam. A. 22,23,26 B. 21,39,40 C. 29,30,31 D. 0,15,22

Last Answer : C. 29,30,31

Find the mode of the following scores : 14, 25, 14, 28, 18, 17, 18, 14, 23, 22, 14, 18 -Maths 9th

Description : Find the mode of the following scores : 14, 25, 14, 28, 18, 17, 18, 14, 23, 22, 14, 18 -Maths 9th

Last Answer : 14 repeat maximum number of times (4 times) in the given data. Mode = 14

Find the mode of the following scores : 14, 25, 14, 28, 18, 17, 18, 14, 23, 22, 14, 18 -Maths 9th

Description : Find the mode of the following scores : 14, 25, 14, 28, 18, 17, 18, 14, 23, 22, 14, 18 -Maths 9th

Last Answer : 14 repeat maximum number of times (4 times) in the given data. Mode = 14

A national random sample of 20 ACT scores from 2010 is listed below. Calculate the sample mean and standard deviation. 29, 26, 13, 23, 23, 25, 17, 22, 17, 19, 12, 26, 30, 30, 18, 14, 12, 26, 17, 18 a. 20.50, 5.79 b. 20.50, 5.94 c. 20.85, 5.79 d. 20.85, 5.94

Description : A national random sample of 20 ACT scores from 2010 is listed below. Calculate the sample mean and standard deviation. 29, 26, 13, 23, 23, 25, 17, 22, 17, 19, 12, 26, 30, 30, 18, 14, 12, 26, 17, 18 a. 20.50, 5.79 b. 20.50, 5.94 c. 20.85, 5.79 d. 20.85, 5.94

Last Answer : Katie earned 84,92,84,75 and 70 on her first 5 tests. What is the minimum grade Katie needs to earn on the next test to have a mean of 84?

On what dates of April 1994 did SUNDAYfall? (A) 2,9,16,23,30 (B) 3,10,17,24 (C) 4,11,18,25 (D) 1,8,15,22,29

Description : On what dates of April 1994 did SUNDAYfall? (A) 2,9,16,23,30 (B) 3,10,17,24 (C) 4,11,18,25 (D) 1,8,15,22,29

Last Answer : Answer: B Solution:. Let us find the day on 1st April, 1994. 2000 years have 0 odd day. We have to calculate day on 1st April, 1994. 2000-1994 = 6 Years. 1996 is leap year and have 4 odd days Ordinary years ... was Friday Thus, on 3 rd , 10 th , 17 th , 24 th will be Sunday fall on April 1994.

Teaching in higher education implies Options: A) presenting the information given in the text book B) asking questions in the class and conducting examinations C) helping students prepare for and pass the examination D) helping students how to learn

Description : Teaching in higher education implies Options: A) presenting the information given in the text book B) asking questions in the class and conducting examinations C) helping students prepare for and pass the examination D) helping students how to learn

Last Answer : D) helping students how to learn 

f the temperature falls below 18 degrees, the heating is switched on. When the temperature reaches 21 degrees, the heating is switched off. What is the minimum set of test input values to cover all valid equivalence partitions? A. 15, 19 and 25 degrees B. 17, 18, 20 and 21 degrees C. 18, 20 and 22 degrees D. 16 and 26 degrees

Description : f the temperature falls below 18 degrees, the heating is switched on. When the temperature reaches 21 degrees, the heating is switched off. What is the minimum set of test input values to cover all valid equivalence ... 17, 18, 20 and 21 degrees C. 18, 20 and 22 degrees D. 16 and 26 degrees

Last Answer : A. 15, 19 and 25 degrees

In a class there are 15 boys and 10 girls. Three students are selected at random. The difference between the probability that 2 boys and 1 girl are selected compared to 1 boy and 2 girls are selected is: a) 23/78 b) 19/88 c) 15/92 d) 4/23 e) 7/46

Description : In a class there are 15 boys and 10 girls. Three students are selected at random. The difference between the probability that 2 boys and 1 girl are selected compared to 1 boy and 2 girls are selected is: a) 23/78 b) 19/88 c) 15/92 d) 4/23 e) 7/46

Last Answer : 2 boys, 1 gi(Prl = (15c2×10c1) / 25c3 = 1050/2300 1 boy, 2 girls = (15c1×10c2) / 25c3 = 675/2300 Difference = (1050 - 675)/2300 = 375/2300 = 15/92 Answer: c)

If 40 percent of a number is subtracted from the second number then the second number is reduced to its 3/5. Find the ratio between the first number and the second number. A) 1:3 B) 1:2 C) 1:1 D) 2:3 E) None of these

Description :  If 40 percent of a number is subtracted from the second number then the second number is reduced to its 3/5. Find the ratio between the first number and the second number. A) 1:3 B) 1:2 C) 1:1 D) 2:3 E) None of these

Last Answer : Answer: C [ b – (40/100)a] = (3/5)b. So we get a = b. 1:1

The sum of the squares between three numbers is 5000. The ratio between the first and the second number is 3:4 and that of second and third number is 4:5. Find the difference between first and the third number. A) 20 B) 30 C) 40 D) 50 E) None of these

Description : The sum of the squares between three numbers is 5000. The ratio between the first and the second number is 3:4 and that of second and third number is 4:5. Find the difference between first and the third number. A) 20 B) 30 C) 40 D) 50 E) None of these

Last Answer : Answer: A a^2 + b^2 + c^2 = 5000 a:b:c = 3:4:5 50x^2 = 5000. X = 10. 5x – 3x = 2*10 = 20

180 sweets are divided among friends A, B, C and D in which B and C are brothers also such that sweets divided between A and B are in the ratio 2 : 3, between B and C in the ratio 2 : 5 and between C and D in ratio 3 : 4. What is the number of sweets received by the brothers together? A) 78 B) 84 C) 92 D) 102 E) 88

Description : 180 sweets are divided among friends A, B, C and D in which B and C are brothers also such that sweets divided between A and B are in the ratio 2 : 3, between B and C in the ratio 2 : 5 and between C ... . What is the number of sweets received by the brothers together? A) 78 B) 84 C) 92 D) 102 E) 88

Last Answer : Answer: B A : B : C : D 2*2*3 : 3*2*3 : 3*5*3 : 3*5*4 4 : 6 : 15 : 20 B and C together = [(6+15)/(4+6+15+20)] * 180 = 84