When they travel in same direction, suppose they meet when B travels for x m, then A will have travelled 70+x m in the same time Since, Speed =TimeDistanceSpeed of auto at A =7x+70And Speed of auto at B =7xAnd when they travel in the opposite direction, suppose they meet when A travels for y m, then B will have travelled 70−y m in the same time Speed of auto at A =1y=y And Speed of auto at B =170−y=70−y Equating the speeds of the autos in both the cases, Speed of car at A, 7x+70=y x+70=7y =>x−7y=−70 --- (1) Speed of car at B, 7x=70−y =>x+7y=490 --- (2) Adding equations 1 and 2, we get 2x=420=>x=210 So, Speed of auto at A =7x+70=7280=40km/hr Speed of auto at B =7x=7210=30km/hr