A chord of a circle of radius 20 cm subtends an angle of 90° at the centre. Find the area of the corresponding major segment of the circle. -Maths 10th

1 Answer

Answer :

Area of the minor segment = { pi × 90 /360 - sin 45 × cos 45 } × r × r ={ 3.14 ×1/4 - 1÷√2 ×1÷√2 } × 20 × 20 = { 3.14 × 1/4 - 1÷2 } × 400 = 3.14 × 400 ÷ 4 - 400 ÷ 2 = 3.14 × 100 - 200 = 314-200 =114   Area of circle = pi × r × r = 3.14 × 20 × 20 = 3.14 × 400 = 1256   Area of major segment = area of circle - area of minor segment = 1256 - 114 = 1142   HOPE IT HELPS YOU

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