How to calculate mass of an Atom ? -Chemistry

How to calculate mass of an Atom ? -Chemistry
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Answer :

The sum of Protons and Neutrons ( Nucleons ) gives the mass number of an atom.
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A solution containing 30 g of non-volatile solute exactly in 90 g of water has a vapour pressure of 2.8 kPa at 298 K. Further 18 g of water is added to this solution. The new vapour pressure becomes 2.9 kPa at 298 K. Calculate (i) the molecular mass of solute and (ii) vapour pressure of water at 298 K -Chemistry

Description : A solution containing 30 g of non-volatile solute exactly in 90 g of water has a vapour pressure of 2.8 kPa at 298 K. Further 18 g of water is added to this solution. The new vapour pressure ... K. Calculate (i) the molecular mass of solute and (ii) vapour pressure of water at 298 K -Chemistry

Last Answer : For a very dilute solution ∴ Molecular mass, MB = 34 g/mol.

Calculate the mass of 12.044 × 1023 carbon atoms -Chemistry 9th

Description : Calculate the mass of 12.044 × 1023 carbon atoms -Chemistry 9th

Last Answer : No. of moles of Carbon atoms = No. of atoms/Avogadro constant = 12.044 × 1023/6.022 × 1023 = 2 mole Mass of carbon atoms = No. of moles × atomic mass = 2 × 12 = 24 g

Calculate the mass of 6.022 × 1023 molecule of Calcium carbonate (CaCO3) -Chemistry 9th

Description : Calculate the mass of 6.022 × 1023 molecule of Calcium carbonate (CaCO3) -Chemistry 9th

Last Answer : Molar mass (Molecular mass in gram) of CaCO3 = 40+12+3×16 = 100 g No. of moles of CaCO3 = No. of molecules/Avogadro constant = 6.022 × 1023/ 6.022 × 1023 = 1 mole Mass of CaCO3 = No. of moles × molar mass = 1 × 100 g = 100 g

Calculate the formula unit mass of NaCl and CaCl2. -Chemistry 9th

Description : Calculate the formula unit mass of NaCl and CaCl2. -Chemistry 9th

Last Answer : hii Here's your answer Molar mass of Na=23g/mol " " " Cl=35.5g/mol Formula unit mass of NaCl=23 + 35.5 = 58.5 gm per mole Molar mass of Ca=40g/mol Molar mass of Cl2= 35.5g/mol*2=70gm per mole F. U. M. = 40+70=110 gm per mole

Calculate the binding energy of the lithium atom `(._(3)^(7)Li)` from the following data: `{:("mass of proton",= 1.00759,am u,),("mass of neutron",= 1

Description : Calculate the binding energy of the lithium atom `(._(3)^(7)Li)` from the following data: `{:("mass of proton",= 1.00759,am u,),("mass of neutron",= 1

Last Answer : Calculate the binding energy of the lithium atom `(._(3)^(7)Li)` from the following data: `{:("mass of ... "mass of lithium atom",= 7.01818,am u,):}`

Calculate the frequency of revolution of an electron in the first orbit of an aluminum atom. Given that mass of electron `=9x10^(-31) kg, e= 1.6 xx10^

Description : Calculate the frequency of revolution of an electron in the first orbit of an aluminum atom. Given that mass of electron `=9x10^(-31) kg, e= 1.6 xx10^

Last Answer : Calculate the frequency of revolution of an electron in the first orbit of an aluminum atom. Given that mass of ... of the orbit `=0.2xx10^(-11) m`.

Two half-reactions of an electrochemical cell are given below : MnO–4 (aq) + 8H+ (aq) + 5e– → Mn2+ (aq) + 4H2O (I), E° = 1.51 V Sn2+ (aq) → Sn4+ (aq) + 2e–, E° = + 0.15 V. Construct the redox reaction equation from the two half-reactions and calculate the cell potential from the standard potentials and predict if the reaction is reactant or product favoured. -Chemistry

Description : Two half-reactions of an electrochemical cell are given below : MnO-4 (aq) + 8H+ (aq) + 5e- → Mn2+ (aq) + 4H2O (I), E° = 1.51 V Sn2+ (aq) → Sn4+ (aq) + ... -reactions and calculate the cell potential from the standard potentials and predict if the reaction is reactant or product favoured. -Chemistry

Last Answer : The reactions can be represented at anode and at cathode in the following ways : At anode (oxidation) : Sn2+ → Sn4+ (aq) + 2e- ] 5 E° = + 0.15 V Af cathode (reduction) : MnO-4(aq) + 8H+ ( ... = E°cathode - E°anode = 1.51 - 0.15 = + 1.36 V ∴ Positive value of E°cell favours formation of product.

Calculate the number of atoms in 100 u of He. -Chemistry

Description : Calculate the number of atoms in 100 u of He. -Chemistry

Last Answer : Atomic mass of He = 4 u So, mass of one He atom = 4 u ∴ No. of atoms in 100 u of He = 100/4 = 25 He atoms.

Calculate the number of Cu atoms in 0.635g of Cu. -Chemistry

Description : Calculate the number of Cu atoms in 0.635g of Cu. -Chemistry

Last Answer : No. of moles of Cu = Mass of Cu/Atomic mass = 0.635/63.5 =0.01 mole No. of Cu atoms = No. of moles × Avogadro constant = 0.01 × 6.022 × 1023 = 6.022 × 1023 Cu atoms.

a) 110 g of salt is present in 550g of solution. Calculate the concentration of solution. b) 10 ml of H2SO 4 is dissolved in 90 ml of H2O. Calculate the concentration of solution. -Chemistry

Description : a) 110 g of salt is present in 550g of solution. Calculate the concentration of solution. b) 10 ml of H2SO 4 is dissolved in 90 ml of H2O. Calculate the concentration of solution. -Chemistry

Last Answer : The concentration of salt is determined by the division of mass of the solute by the mass of the solution and the percentage is obtained by multiplying the value by 100. The quotient of the division of 110 by 550 is 0.2 here. So after multiplying it with 100, it is 20%. So the concentration is 20%.

4.A solution of acetone contains 30 ml of acetone in 570 ml of water. Calculate the percentage concentrationof the solute in the solution. -Chemistry

Description : 4.A solution of acetone contains 30 ml of acetone in 570 ml of water. Calculate the percentage concentrationof the solute in the solution. -Chemistry

Last Answer : Volume of acetone =30 ml Volume of water =570 ml Volume of solution = 30 + 570 = 600 ml Concentration of solute in solution = 30 / 600 x 100 ... = 30 / 600 x 100 = 5%

2. An object 50 cm tall is placed on the principal axis of a convex lens. Its 20 cm tall image is formed on the screen placed at a distance of 10 cm from the lens. Calculate the focal length of the lens. [All India] -Chemistry-10

Description : 2. An object 50 cm tall is placed on the principal axis of a convex lens. Its 20 cm tall image is formed on the screen placed at a distance of 10 cm from the lens. Calculate the focal length of the lens. [All India] -Chemistry-10

Last Answer : this is the answer for the respected question

1. A concave lens has focal length of 20 cm. At what distance from the lens a 5 cm tall object be placed so that it forms an image at 15 cm from the lens? Also calculate the size of the image formed. [Delhi] -Chemistry-10

Description : 1. A concave lens has focal length of 20 cm. At what distance from the lens a 5 cm tall object be placed so that it forms an image at 15 cm from the lens? Also calculate the size of the image formed. [Delhi] -Chemistry-10

Last Answer : Answer. hope this helps youu

Calculate the number of oxygen atoms in 1 mole of O2. -Chemistry 9th

Description : Calculate the number of oxygen atoms in 1 mole of O2. -Chemistry 9th

Last Answer : 1 molecule of O2 = 2 oxygen atoms So, 1 mole of O2 = 2 mole oxygen atoms = 2 × 6.022 × 1023 = 12.044 ×1023 oxygen atoms.

Class 9th CBSE Chemistry CBQ'S (Case Base Study) Structure of an Atom -Science

Description : Class 9th CBSE Chemistry CBQ'S (Case Base Study) Structure of an Atom -Science

Last Answer : The electronic configuration of an element Z is 2, 8, 8. (a) What is the atomic number of the element ? (b) State whether element Z is a metal or a non-metal. (c) What type of ion (if any) will be formed by an atom of ... -------------------------------------- More questions to be added shortly...

An atom has atomic number 12, what is its valency and name the element? -Chemistry 9th

Description : An atom has atomic number 12, what is its valency and name the element? -Chemistry 9th

Last Answer : Element with atomic number 12 is Magnesium (Mg). Electronic configuration of magnesium is 1s2 2s2 2p6 3s2. It has 2 e- in its outermost orbit and can donate these to form a stable octet. Hence, its valency is +2.

Draw the atomic structure of (i) an atom with same number of sub-atomic particles, (ii) an atom with same number of electrons in L and M shell. -Chemistry 9th

Description : Draw the atomic structure of (i) an atom with same number of sub-atomic particles, (ii) an atom with same number of electrons in L and M shell. -Chemistry 9th

Last Answer : (i) Oxygen Number of electrons = 8 Number of protons= 8 Number of neutron= 8 (ii) Argon Atomic number =18=2,8,8 No of electrons in L shell = 8 No of electrons in M shell = 8

Find the number of atoms in 0.5 mole of C atom. -Chemistry 9th

Description : Find the number of atoms in 0.5 mole of C atom. -Chemistry 9th

Last Answer : 0.5 mole of C=6.022×10*23 no. of atoms = 6.022×10*23/2 =3.011×10*23 hope this helps u

The concentration of a salt solution in terms of mass by mass percentage is 20 and the mass of the solution is 550 g. Determine the mass of solute present in the solution. -Chemistry

Description : The concentration of a salt solution in terms of mass by mass percentage is 20 and the mass of the solution is 550 g. Determine the mass of solute present in the solution. -Chemistry

Last Answer : Mass by mass percentage = 20% Mass of solution= 550gram Mass of solute/mass of solution multipled by 100 Therefore, 20/100 = 1/5 Hence, Mass of solute=Mass of solution/5 = 550gram/5 = 110Gram Therefore, The mass of solute is 110gm

Calculate the EAN of central atom in the following complexes `(a) [Cr(CO)_(6)]" "(b) [Fe(CN)_(6)]^(4-)" " (c ) [Fe(CO)_(5)] " " (d) [Co(NH_(3))_(6)]^(

Description : Calculate the EAN of central atom in the following complexes `(a) [Cr(CO)_(6)]" "(b) [Fe(CN)_(6)]^(4-)" " (c ) [Fe(CO)_(5)] " " (d) [Co(NH_(3))_(6)]^(

Last Answer : Calculate the EAN of central atom in the following complexes `(a) [Cr(CO)_(6)]" "(b) [Fe(CN)_(6)]^(4-)" " (c ... ))_(6)]^(4+)" " (h) [PtCl_(6)]^(2-)`

Calculate the energy released by fission of 1 g of `._(92)^(235)U`, assuming that an energy of 200 MeV is released by fission of each atom of `.^(235)

Description : Calculate the energy released by fission of 1 g of `._(92)^(235)U`, assuming that an energy of 200 MeV is released by fission of each atom of `.^(235)

Last Answer : Calculate the energy released by fission of 1 g of `._(92)^(235)U`, assuming that an energy of 200 MeV is ... `= 6.023 xx 10^(26) kg mol^(-1)`)

An electron , in a hydrogen-like atom, is in excited state. It has a total energy of -3.4 eV. Calculate (a) the kinetic energy and (b) the de Broglie

Description : An electron , in a hydrogen-like atom, is in excited state. It has a total energy of -3.4 eV. Calculate (a) the kinetic energy and (b) the de Broglie

Last Answer : An electron , in a hydrogen-like atom, is in excited state. It has a total energy of -3.4 ... and (b) the de Broglie wavelength of the electron.

Calculate the separation of the particles and the binding energy of a positronium (an atom consisting of an electron and a position revolving around t

Description : Calculate the separation of the particles and the binding energy of a positronium (an atom consisting of an electron and a position revolving around t

Last Answer : Calculate the separation of the particles and the binding energy of a positronium (an atom ... position revolving around their centre of mass).

Calculate the radius of the first and second orbit of sodium atom `(Z=11)`. `(h=6.6xx10^(-34) J s, e=1.6xx10^(-19) C` and `m=9.1xx10^(-31) kg.)`

Description : Calculate the radius of the first and second orbit of sodium atom `(Z=11)`. `(h=6.6xx10^(-34) J s, e=1.6xx10^(-19) C` and `m=9.1xx10^(-31) kg.)`

Last Answer : Calculate the radius of the first and second orbit of sodium atom `(Z=11)`. `(h=6.6xx10^(-34) J s, e=1.6xx10^(-19) C` and `m=9.1xx10^(-31) kg.)`

Calculate the energy of hydrogen atom in the ground state given that the after Bohr orbit og hydrogen is `5xx10^(-11)m` and electronic charge is `1.6x

Description : Calculate the energy of hydrogen atom in the ground state given that the after Bohr orbit og hydrogen is `5xx10^(-11)m` and electronic charge is `1.6x

Last Answer : Calculate the energy of hydrogen atom in the ground state given that the after Bohr orbit og hydrogen is ` ... electronic charge is `1.6xx10^(-19) C`.

What is the mass of 1/2 mole oxygen atom ?

Description : What is the mass of 1/2 mole oxygen atom ?

Last Answer : Mole Oxygen Atomic Mass = 18 grams So , 1/2 Mole Oxygen Atomic Mass = 6 grams

(3) two light nuclei combine to form a heavy nucleus Explanation: Nuclear fusion is the process of making a single heavy nucleus (part of an atom) from two lighter nuclei. The difference in mass between the products and reactants is manifested as the release of large amounts of energy. Fusion is the process that powers active or "main sequence" stars, or other high magnitude stars.

Description : (3) two light nuclei combine to form a heavy nucleus Explanation: Nuclear fusion is the process of making a single heavy nucleus (part of an atom) from two lighter nuclei. The difference in mass ... . Fusion is the process that powers active or "main sequence" stars, or other high magnitude stars.

Last Answer : Helium is added to the oxygen supply of deep sea divers because it is - (1) less poisonous than nitrogen (2) (2) Lighter than nitrogen (3) Readily miscible with oxygen (4) less soluble in blood than nitrogen at high pressure

An atom of an element with mass number 23 and atomic number 11 will have- (1) 11 neutrons, 12 protons and 11 electrons (2) 11 protons, 12 neutrons and 11 electrons (3) 11 protons, 12 electrons and 11 neutrons (4) 23 protons and 11 electrons

Description : An atom of an element with mass number 23 and atomic number 11 will have- (1) 11 neutrons, 12 protons and 11 electrons (2) 11 protons, 12 neutrons and 11 electrons (3) 11 protons, 12 electrons and 11 neutrons (4) 23 protons and 11 electrons

Last Answer : (2) 11 protons, 12 neutrons and 11 electrons

An atom of an element has atomic number 17 and mass number 36. The number of neutrons in its nucleus is– (1) 17 (2) 19 (3) 36 (4) 53

Description : An atom of an element has atomic number 17 and mass number 36. The number of neutrons in its nucleus is– (1) 17 (2) 19 (3) 36 (4) 53

Last Answer : (2) 19 Explanation: Mass Number = number of protons (atomic number) + nu.sriber of neutrons. So as per the question, 36= number of neutrons + 17. Number of neutrons= 36 -17= 19

An atom of an element has atomic number 17 and mass number 36. The number of neutrons in its nucleus is (1) 17 (2) 19 (3) 36 (4) 53

Description : An atom of an element has atomic number 17 and mass number 36. The number of neutrons in its nucleus is (1) 17 (2) 19 (3) 36 (4) 53

Last Answer : 19

Find the mass of 1.5 mole of CO2 molecule. -Chemistry 9th

Description : Find the mass of 1.5 mole of CO2 molecule. -Chemistry 9th

Last Answer : Let: n be the number of moles m be the mass M be the molecular weight n=1.5mol By definition: n=mM m=n⋅M M(C)=12g/mol M(O2)=2⋅16g/mol=32g/mol M=12g/mol+32g/mol M=44g/mol m=1.5mol⋅44g/mol m=66g

Find the mass of 1.5 mole of CO2 molecule -Chemistry 9th

Description : Find the mass of 1.5 mole of CO2 molecule -Chemistry 9th

Last Answer : Hi! Here is the answer to your question: To find the mass of 1.5 moles of CO2, you need to find first its molar mass. Atomic mass of C = 12 g/mol Atomic mass of O = 16 for O2 = (16 x 2) = 32g/mol ... number of moles x molar mass = 1.5 mol x 44 g/mol mass = 66 g Hope this Helps ! hope this helps u

Find the molecular mass of H2O. -Chemistry 9th

Description : Find the molecular mass of H2O. -Chemistry 9th

Last Answer : The average mass of one H2O molecule is 18.02 amu. The number of atoms is an exact number, the number of mole is an exact number; they do not affect the number of significant figures. The average mass of one ... 18.02 grams. This is stated: the molar mass of water is 18.02 g/mol. hope this helps u

What is Law of conservation of mass and Law of constant proportions? -Chemistry 9th

Description : What is Law of conservation of mass and Law of constant proportions? -Chemistry 9th

Last Answer : What is the Law of conservation of mass? Laws of conservation of mass - It states that mass can neither created nor destroyed. The total mass before and after a chemical reaction remains constant. ... that in a chemical substance the elements are always present in a fixed proportion by their mass.

What is formula unit of mass? How is it different from molecular mass? -Chemistry 9th

Description : What is formula unit of mass? How is it different from molecular mass? -Chemistry 9th

Last Answer : The formula unit mass in chemistry is the empherical formula of any ionic or covalent network solid compound used as an independent entity for stoichiometry calculations. It is the lowest whole number ratio ... atoms in its emperical formula while molar mass is the mass of 1 gram mole of substance.

Find the mass of 0.5 moles of CaCO3 -Chemistry 9th

Description : Find the mass of 0.5 moles of CaCO3 -Chemistry 9th

Last Answer : 50 Grams Explaination : Molar mass of CaCO3 = 40(mass of Calcium ) + 12(mass of Carbon ) + 16(mass of Oxygen )*3 No of moles = Given mass / Molar mass 0.5 = Given mass / 100gm Mass = 100 x 0.5 = 50 gms

How we will calculate Body Mass Index ? -SST 10th

Description : How we will calculate Body Mass Index ? -SST 10th

Last Answer : Dividing the weight by the square of the height in meters.

Calculate the molecular mass of the following -General Knowledge

Description : Calculate the molecular mass of the following -General Knowledge

Last Answer : The molecular mass of water, H2O: = (2 Atomic mass of hydrogen) + (1 Atomic mass of oxygen) = [2(1.0084) + 1(16.00 u)] = 2.016 u + 16.00 u = 18.016 = 18.02 u The molecular mass of carbon dioxide, CO2: = ... mass of hydrogen) = [1(12.011 u) + 4 (1.008 u)] = 12.011 u + 4.032 u = 16.043 u

How do scientists calculate the mass of a supermassive black hole? -Space

Description : How do scientists calculate the mass of a supermassive black hole? -Space

Last Answer : To determine the mass of NGC's black hole, Gallo and her fellow researchers employed reverberation mapping. This technique measures mass by monitoring radiation thrown off by what's called an accretion ... An accretion disk is a mass of matter collected by the gravitational pull of black holes.

Certain force acting on a 20 Kg mass changes its velocity from 5 m/s to 2 m/s. Calculate the work done by the force ? -Physics 9th

Description : Certain force acting on a 20 Kg mass changes its velocity from 5 m/s to 2 m/s. Calculate the work done by the force ? -Physics 9th

Last Answer : Certain force acting on 20 kg mass changes its velocity from 5 m s-1 to 2 m s-1. Calculate the work done by the force. (E k)2 = (1 )/2x 20 — (2)2 = 40 J.

how do you calculate the mass of a cube?

Description : how do you calculate the mass of a cube?

Last Answer : This is the question:Please help me

Calculate the number of atoms present in one drop of water having mass 1.8 g .

Description : Calculate the number of atoms present in one drop of water having mass 1.8 g .

Last Answer : Calculate the number of atoms present in one drop of water having mass 1.8 g . A. `0.3N_(A)` B. `0.2N_(A)` C. `0.1N_(A)` D. `0.01N_(A)`

Calculate the mass loss in the following: `._(1)^(2)H + ._(1)^(3)H to ._(2)^(4)He + ._(0)^(1)n` given the masses: `._(1)^(2)H = 2.014` amu, `._(1)^(3)

Description : Calculate the mass loss in the following: `._(1)^(2)H + ._(1)^(3)H to ._(2)^(4)He + ._(0)^(1)n` given the masses: `._(1)^(2)H = 2.014` amu, `._(1)^(3)

Last Answer : Calculate the mass loss in the following: `._(1)^(2)H + ._(1)^(3)H to ._(2)^(4)He + ._(0)^(1)n` ... amu A. 0.018amu B. 0.18 amu C. 18 amu D. 1.8 amu

Calculate the coefficient of static friction for an object of mass 50 kg placed on horizontal table

Description : Calculate the coefficient of static friction for an object of mass 50 kg placed on horizontal table

Last Answer : Calculate the coefficient of static friction for an object of mass 50 kg placed on horizontal ... object just moves when spring balance shows 50N.

Calculate the value of the universal gravitational constant from the given data. Mass of the Earth = 6 × 10^24 kg,

Description : Calculate the value of the universal gravitational constant from the given data. Mass of the Earth = 6 × 10^24 kg,

Last Answer : Calculate the value of the universal gravitational constant from the given data. Mass of the Earth = 6 ... to gravity on the surface = 9.8 m/s2.

A planet has mass 6.4 × 10^24 kg and radius 3.4 × 10^6 m. Calculate energy required to remove on object of mass 800 kg

Description : A planet has mass 6.4 × 10^24 kg and radius 3.4 × 10^6 m. Calculate energy required to remove on object of mass 800 kg

Last Answer : A planet has mass 6.4 1024 kg and radius 3.4 106 m. Calculate energy required to remove ... 800 kg from the surface of the planet to infinity.

Calculate the value of acceleration due to gravity on the surface of Mars if the radius of Mars = 3.4 × 10^3 km and its mass is 6.4 × 10^23 kg.

Description : Calculate the value of acceleration due to gravity on the surface of Mars if the radius of Mars = 3.4 × 10^3 km and its mass is 6.4 × 10^23 kg.

Last Answer : Calculate the value of acceleration due to gravity on the surface of Mars if the radius of Mars = 3.4 × 103 km and its mass is 6.4 × 1023 kg.

Calculate the kinetic energy, potential energy, total energy and binding energy of an artificial satellite of mass 2000 kg

Description : Calculate the kinetic energy, potential energy, total energy and binding energy of an artificial satellite of mass 2000 kg

Last Answer : Calculate the kinetic energy, potential energy, total energy and binding energy of an artificial satellite of mass 2000 ... 6400 km M = 6 1024 kg

Calculate the energy released in kilowatt-hours when 100g of `._(3)^(7)Li` are converted into `._(2)^(4)He` by proton bombardment. Mass of `._(3)^(7)L

Description : Calculate the energy released in kilowatt-hours when 100g of `._(3)^(7)Li` are converted into `._(2)^(4)He` by proton bombardment. Mass of `._(3)^(7)L

Last Answer : Calculate the energy released in kilowatt-hours when 100g of `._(3)^(7)Li` are converted into `. ... = 1.0081 amu. Write down the nuclear reaction.

Calculate the amount of energy set free by the annigilation of an electron and a positron. Given that mass of electron `= 0.00055` amu and positron =

Description : Calculate the amount of energy set free by the annigilation of an electron and a positron. Given that mass of electron `= 0.00055` amu and positron =

Last Answer : Calculate the amount of energy set free by the annigilation of an electron and a positron. Given that ... 0.00055` amu and positron = 0.00055 amu.