Description : Calculate the acceleration due to gravity at a height of 300 km from the surface of the Earth. (M = 5.98 × 10^24 kg, R = 6400 km).
Last Answer : Calculate the acceleration due to gravity at a height of 300 km from the surface of the Earth. (M = 5.98 × 1024 kg, R = 6400 km).
Description : A planet has mass 6.4 × 10^24 kg and radius 3.4 × 10^6 m. Calculate energy required to remove on object of mass 800 kg
Last Answer : A planet has mass 6.4 1024 kg and radius 3.4 106 m. Calculate energy required to remove ... 800 kg from the surface of the planet to infinity.
Description : The mass, in kg, of the earth if its radius is 6400 km, will be a.6 x 1024 b.6 x 1025 c.107 dynes d.6 x 1023 e.6 x 1022
Last Answer : a. 6 x 1024
Description : Mass of Earth when it's radius is 6400 km and gravitational field strength is 9.81 N kg-1 is A. 6.0 × 1024 kg B. 5 × 1023 kg C. 40 × 109 kg D. 9 × 1024 kg
Last Answer : 5 × 1023 kg
Description : A screw jack has 4 threads per inch. The mean radius of the thread is 2.338 inches. The mean diameter of the bearing surface under the cap is 3.25 inches. What is the turning moment required to raise the bload of 150 kg ( a.5.61 kg-inch b.50.6 kg-inch c.107 dynes d.30.3 kg-inch e.23.6 kg-inch
Last Answer : b. 50.6 kg-inch
Description : Calculate the mass and mean density of the earth from the following data : `{:(,"Gravitational constant",(G),=6.6xx10^(-11)Nm^(2)kg^(-2)),(,"Radius of
Last Answer : Calculate the mass and mean density of the earth from the following data : `{:(,"Gravitational constant",(G),=6. ... to gravity",(g),=9.8ms^(-2)):}`
Description : If is the speed of a locomotive in km per hour, g is the acceleration due to gravity, is the distance between running faces of the rails and is the radius of the circular curve, the required super elevation is (A) gV²/GR (B) Rg/GV² (C) GR/gV² (D) GV²/gR
Last Answer : (D) GV²/gR
Description : A imaginary planet has half the mass and half the radius of the earth. The acceleration of gravity at its surface would be a.9.8 m/s2 b.107 dynes c.4.9 m/s2 d.19.6 m/s2 e.2.45 m/s2
Last Answer : d. 19.6 m/s2
Description : A couple applied to a flywheel of mass 5 kg and of radius of gyration 20 cm produces an angular acceleration of 4 radians/sec2. The torque applied in dyne cm is a.8 x 104 b.8 x 106 c.8 x 107 d.8 x 108 e.8 x 1010
Last Answer : b. 8 x 106
Description : How far away from the surface of the Earth does the acceleration due to gravity become ½ of its value at the surface of Earth? It is at a (a) Distance equal to radius (b) Distance equal to half the radius (c) Distance equal to twice the radius (d) Distance equal to 0.414 times the radius
Last Answer : Ans:(d)
Description : If the coefficient of friction on the road surface is 0.15 and a maximum super-elevation 1 in 15 is provided, the maximum speed of the vehicles on a curve of 100 metre radius, is (A) 32.44 km/hour (B) 42.44 kg/hour (C) 52.44 km/hour (D) 62.44 km/hour
Last Answer : Answer: Option C
Description : A roller coaster reaches a velocity of 20 m/s at a location where the radius of curvature is 40 m. Calculate the acceleration in m/s2? a.10 b.9 c.11 d.8 e.107 dynes
Last Answer : a. 10
Description : Calculate the value of the universal gravitational constant from the given data. Mass of the Earth = 6 × 10^24 kg,
Last Answer : Calculate the value of the universal gravitational constant from the given data. Mass of the Earth = 6 ... to gravity on the surface = 9.8 m/s2.
Description : The static deflection of a spring under gravity, when a mass of 1 kg is suspended from it, is 1 mm. Assume the acceleration due to gravity g = 10 m/s^2. The natural frequency of this spring-mass system (in rad/s) is A 100 B 150 C 200 D 250
Last Answer : A 100
Description : If we want to calculate the pressure of a liquid at the bottom of a vessel, the quantity which is not required to determine it, is – (1) Height of the liquid column (2) Surface area of the bottom of the vessel (3) Density of the liquid (4) Acceleration due to gravity at the bottom of the vessel
Last Answer : (2) Surface area of the bottom of the vessel Explanation: The pressure exerted by a static fluid depends only upon the depth of the fluid, the density of the fluid, and the acceleration of gravity. Static fluid pressure does not depend on the shape, total mass, or surface area of the liquid.
Last Answer : (2) Surface area of the bottom of the vessel Explanation: The pressure exerted by a static fluid depends only upon the depth of the fluid, the density of the fluid, and the acceleration of gravity.
Description : If we want to calculate the pressure of a liquid at the bottom of a vessel, the quantity which is not required to determine it, is (1) Height of the liquid column (2) Surface area of the bottom of the vessel (3) Density of the liquid (4) Acceleration due to gravity at the bottom of the vessel
Last Answer : Surface area of the bottom of the vessel
Description : Calculate the radius of the first and second orbit of sodium atom `(Z=11)`. `(h=6.6xx10^(-34) J s, e=1.6xx10^(-19) C` and `m=9.1xx10^(-31) kg.)`
Last Answer : Calculate the radius of the first and second orbit of sodium atom `(Z=11)`. `(h=6.6xx10^(-34) J s, e=1.6xx10^(-19) C` and `m=9.1xx10^(-31) kg.)`
Description : Find the friction force due to air on a body of mass 1 kg falling with acceleration `8 m//s^(2)` :-
Last Answer : Find the friction force due to air on a body of mass 1 kg falling with acceleration `8 m//s^(2)` :- A. 2 N B. 4 N C. Zero D. None
Description : When your mass is 96 kg. The acceleration due to gravity is 9.8 ms 2 . How much work against gravity do you do when you climb a flight of stairs 3.8 m high Answer in units of J.?
Last Answer : 4
Description : An artificial satellite is moving in a circular orbit of radius 42.250 km (approx). Calculate its linear velocity if takes 24 hour to revolve around earth.? -Science
Last Answer : Given r =42.250 km , T= 24 hour Linear velocity in circular motion is given by v=2πrT=2×3.14×42.25024=11.05km/hrv=2πrT=2×3.14×42.25024=11.05km/hr
Description : An object with a mass of 5 kilograms is a distance of 5 meters above the surface of the earth. If the acceleration due to gravity is 10 meters per second squared, the potential energy of the object relative to the ... is: w) 10 joules x) 20 joules y) 100 joules z) 250 joules e) none of the above
Last Answer : ANSWER: Z -- 250 JOULES
Description : The period of revolutions of Mars around th esun is 1.881 year and its mean distance from the sun is `1.524AU`. Calculate the mass of sun `(1AU=1.496x
Last Answer : The period of revolutions of Mars around th esun is 1.881 year and its mean distance from the sun is `1. ... the mass of sun `(1AU=1.496xx10^(11)m)`.
Description : Momentum of electron having mass 9.1 × 10-31 kg and velocity 2.0 × 107 is A. 1.91 × 10-23 B. 2.34 × 10-23 C. 3.11 × 10-19 D. 7.88 × 10-34
Last Answer : 1.91 × 10-23
Description : A cantilever shaft has a diameter of 6 cm and the length is 40cm, it has a disc of mass 125 kg at its free end. The Young’s modulus for the shaft material is 250 GN/m2. Calculate the static deflection in nm. a) 0.001 b) 0.083c) 1.022 d) 0.065
Last Answer : a) 0.001
Description : Two bodies of equal mass are moving in circular paths at equal speed. The first body moves in a circle whose radius is twice as great as that of the second. The ratio of the centripetal or radial acceleration of the first body to that of the second is: w) 1 to 4 x) 1 to 3 y) 1 to 2 z) 1 to 1
Last Answer : ANSWER: Y -- 1 TO 2
Description : Calculate the frequency of revolution of an electron in the first orbit of an aluminum atom. Given that mass of electron `=9x10^(-31) kg, e= 1.6 xx10^
Last Answer : Calculate the frequency of revolution of an electron in the first orbit of an aluminum atom. Given that mass of ... of the orbit `=0.2xx10^(-11) m`.
Description : A body of mass 20 kg is suspended from a spring which deflects 20mm under this load. Calculate the frequency of free vibrations in Hz. a) 3.5 b) 5 c) 6 d) 7
Last Answer : a) 3.5
Description : What is the net force on on a dragster with a mass of 900 kg if its acceleration is 32.0 ms2 west?
Last Answer : Feel Free to Answer
Description : Calculate coefficient of viscous damper, if the system is critically damped. Consider the following data: 1. Mass of spring mass damper system = 350 kg 2. Static deflection = 2 x 10 -3 m 3. Natural frequency of the system = 60 rad/sec ... /m B. 80 x 10 3 N-s/m C. 42 x 10 3 N-s/m D. None of the above
Last Answer : C. 42 x 10 3 N-s/m
Description : Calculate coefficient of viscous damper, if the system is critically damped. Consider the following data: 1. Mass of spring mass damper system = 350 kg 2. Static deflection = 2 x 10 -3 m 3. Natural frequency of the system = 60 rad/sec ... /m b. 80 x 10 3 N-s/m c. 42 x 10 3 N-s/m d. None of the above
Last Answer : c. 42 x 10 3 N-s/m
Description : The atomic masses of three elements X, Y and Z having similar chemical properties are 7, 23 and 39 respectively. a) Calculate the average atomic mass of elements X and Z. b) How is the ... this example? d) Give another example of a set of elements which are classified according to this law.
Last Answer : a) The average atomic mass of X and Z = 7 39 2 46 2 23 b) The average atomic mass of X and Z is equal to the atomic mass of Y c) The law illustrated in this example is Dobereiner’s law of triads. d) Another example of Dobereiner’s law is Calcium, Strontium and Barium.
Description : Work done by a body of mass 100 kg moving along a circular path of radius 2 m with a uniform velocity of 10 m/sec is a.5000 J b.2500 J c.509.68 J d.None of the above e.Tapered bearing
Last Answer : d. None of the above
Description : The force which produces an acceleration of 1 m/sec2 in a mass of 1 kg is called a.100 ergs b.one Newton c.one watt d.One erg e.one joule
Last Answer : b. one Newton
Description : Force applied on a body of mass 5 kg is directly proportional to the acceleration produced in the body. Represent this solution as a linear equation in two variables. -Maths 9th
Last Answer : Solution :- Let the force be x and acceleration due to force be y.
Description : What is the acceleration of an object that has a force of N and the mass of kg?
Last Answer : What is the answer ?
Description : Acceleration of a rocket having mass 5000 kg and resultant force acting on it is 200,000 N is A. 50 m s-2 B. 56 m s-2 C. 70 m s-2 D. 40 m s-2
Last Answer : . 40 m s-2
Description : Calculate the flux density due to a circular conductor of radius 100nm and current 5A in air. a) 10 b) 100 c) 0.1 d) 1
Last Answer : a) 10
Description : At what distance below the surface of the Earth, the acceleration due to gravity decreases by 10% of its value at the surface,
Last Answer : At what distance below the surface of the Earth, the acceleration due to gravity decreases by 10% of ... surface, given radius of Earth is 6400 km.
Description : Critical speed of rotation, N (in rps - rotation per second) of a trammel is equal to (where, g = acceleration due to gravity = 9.81 m/sec 2 and, r = radius of trammel, metre.) (A) (1/2π). √(g/r) (B) (1/π). √(g/r) (C) ½ √(g/r) (D) 2π. √(g/r)
Last Answer : (A) (1/2π). √(g/r)
Description : Pick up the incorrect statement from the following. The super-elevation on roads is (A) Directly proportional to width of pavement (B) Directly proportional to velocity of vehicles (C) Inversely proportional to acceleration due to gravity (D) Inversely proportional to the radius of curvature
Last Answer : Answer: Option B
Description : If V is speed of a moving vehicle, r is radius of the curve, g is the acceleration due to gravity, W is the width of the carriageway, the super elevation is (A) WV/gr (B) W²V/gr (C) WV²/gr (D) WV/gr²
Description : Calculate the speed of a satellite in an orbit at a height of 1000 km from the Earth’s surface.
Last Answer : Calculate the speed of a satellite in an orbit at a height of 1000 km from the Earth’s surface. ME = 5.98 × 1024 kg, R = 6.4 × 106 m.
Description : A mass of 1 kg is attached to two identical springs each with stiffness k = 20 kN/m as shown in the figure. Under frictionless condition, the natural frequency of the system in Hz is close to * 1 point (A) 32 (B) 23 (C) 16 (D) 11
Last Answer : (A) 32
Description : A satellite orbits the earth 200 km above the surface. What speed, in m/s, is necessary for a circular orbit? The radius of the earth is 6400 km and g = 9.2 m/s2 a.7200 b.6600 c.7800 d.6000 e.107 dynes
Last Answer : c. 7800
Description : The speed of a motor car changes from 18 km/h to 72 km/h in 5 s. Its acceleration is (a) 6 m/s2 (b) 5 m/s2 (c) 4 m/s2 (d) 3 m/s2
Description : Calculate the drift velocity for the electrons in a silver wire which has a radius of 0.1 cm and carries a current of 2 A. Atomic mass of silver=108 a
Last Answer : Calculate the drift velocity for the electrons in a silver wire which has a radius of 0.1 cm and carries a ... silver `=10.5xx10^(3) kg//m^(3)`.
Description : Over taking time required for a vehicle with design speed 50 km ph and overtaking acceleration 1.25 m/sec2 to overtake a vehicle moving at a speed 30 km ph, is (A) 5.0 secs (B) 6.12 secs (C) 225.48 secs (D) 30 secs
Description : The combined mass of car and passengers travelling at 72 km/hr is 1500 kg. Find the kinetic energy of this combined mass. (Formula: K =mv2 / 2k ) a. 300 kJ b. 200 kJ c. 500 kJ d. None of the above
Last Answer : 300 kJ