If the radius of the Gaussian surface enclosing a charge is halved, how does the electric flux through the Gaussian surface change ? -General Knowledge

If the radius of the Gaussian surface enclosing a charge is halved, how does the electric flux through the Gaussian surface change ? -General Knowledge
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1 Answer

Answer :

Electic flux ϕE is given by E=∮E→⋅⃗=Q0 …. where [Q is total charge inside the closed surface ∴ On changing the radius of sphere, the electric flux through the Gaussian surface remains same.
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