The Gaussian surface is
a) Real boundary
b) Imaginary surface
c) Tangential
d) Normal

1 Answer

Answer :

b) Imaginary surface

Related questions

Description : Which component of the electric field intensity is always continuous at the boundary? a) Tangential b) Normal c) Horizontal d) Vertical

Last Answer : a) Tangential

Description : In air, the tangential component of flux density is continuous at the boundary. State True/False. a) True b) False

Last Answer : a) True

Description : The tangential component of the magnetic field intensity is continuous at the boundary of separation of two media. State True/False. a) True b) False

Last Answer : a) True

Description : Gauss law can be evaluated in which coordinate system? a) Cartesian b) Cylinder c) Spherical d) Depends on the Gaussian surface

Last Answer : d) Depends on the Gaussian surface

Description : Gauss law can be used to compute which of the following? a) Permittivity b) Permeability c) Radius of Gaussian surface d) Electric potential

Last Answer : c) Radius of Gaussian surface

Description : The Gaussian surface for a point charge will be a) Cube b) Cylinder c) Sphere d) Cuboid

Last Answer : c) Sphere

Description : The Gaussian surface for a line charge will be a) Sphere b) Cylinder c) Cube d) Cuboid

Last Answer : b) Cylinder

Description : Find the flux density of line charge of radius (cylinder is the Gaussian surface) 2m and charge density is 3.14 units? a) 1 b) 0.75 c) 0.5 d) 0.25

Last Answer : d) 0.25

Description : Equipotential surface is a a) Real surface b) Complex surface c) Imaginary surface d) Not existing surface

Last Answer : c) Imaginary surface

Description : Which of the following is true regarding magnetic lines of force? a) Real b) Imaginary c) Does not exist d) Parallel to field

Last Answer : b) Imaginary

Description : The lines of force are said to be a) Real b) Imaginary c) Drawn to trace the direction d) Not significant

Last Answer : c) Drawn to trace the direction

Description : The boundaries of a control volume, which may either real or imaginary is called _____.  A. Control boundary  B. Control system  C. Interface  D. Control surface

Last Answer : Control surface

Description : What is the real or imaginary surface that separates the system from its surroundings?  A. Division  B. Wall  C. Boundary  D. Interface

Last Answer : Boundary

Description : The tangential component of electric field intensity is always continuous at the interface. State True/False. a) True b) False

Last Answer : a) True

Description : The normal component of magnetic field intensity at the boundary of separation of the medium will be a) Same b) Different c) Negative d) Inverse

Last Answer : a) Same

Description : The normal component of which quantity is always discontinuous at the boundary? a) E b) D c) H d) B

Last Answer : b) D

Description : Find the electric field if the surface density at the boundary of air is 10 -9 . a) 12π b) 24π c) 36π d) 48π

Last Answer : c) 36π

Description : A boundary of separation between two magnetic materials is identified by which factor? a) Change in the permeability b) Change in permittivity c) Change in magnetization d) Conduction

Last Answer : a) Change in the permeability

Description : By method of images, the problem can be easily calculated by replacing the boundary with which polygon? a) Rectangle b) Trapezoid c) Square d) Triangle

Last Answer : d) Triangle

Description : Find the flux density at the boundary when the charge density is given by 24 units. a) 12 b) 24 c) 48 d) 96

Last Answer : b) 24

Description : If the radius of the Gaussian surface enclosing a charge is halved, how does the electric flux through the Gaussian surface change ? -General Knowledge

Last Answer : Electic flux ϕE is given by E=∮E→⋅⃗=Q0 …. where [Q is total charge inside the closed surface ∴ On changing the radius of sphere, the electric flux through the Gaussian surface remains same.

Description : According to Gauss' Law, the magnitude of the electric field is zero everywhere inside a conductor if: w) electrostatic equilibrium is achieved x) the surface is a metal y) the conductor is moving z) the conductor is a non-Gaussian surface

Last Answer : ANSWER: W -- ELECTROSTATIC EQUILIBRIUM IS ACHIEVED

Description : The angle between normal stress and tangential stress is known as angle of ______ a. declination b. orientation c. obliquity d. rotation

Last Answer : c. obliquity

Description : An equipotential line is __________ to the velocity vector at every point. (A) Normal (B) Parallel (C) Tangential (D) None of these

Last Answer : (A) Normal

Description : The component of acceleration resulting due to unsteady nature of flow is called __________ acceleration. (A) Normal (B) Local (C) Convective (D) Tangential

Last Answer : (B) Local

Description : Principal planes are subjected to  (A) Normal stresses only  (B) Tangential stresses only  (C) Normal stresses as well as tangential stresses  (D) None of these

Last Answer : (A) Normal stresses only

Description : The locus of the end point of the resultant of the normal and tangential components of the stress  on an inclined plane, is  (A) Circle  (B) Parabola  (C) Ellipse  (D) Straight line 

Last Answer : (C) Ellipse 

Description : Shear stress in the beam acting on the cross section is (a) Normal to the cross section (b) Tangential to the cross section (c) Neither normal nor tangential (d) None

Last Answer : b) Tangential to the cross section

Description : Littoral drift (A) Is the raised line of sand, parallel to the sea coast (B) Is the slow movement of surface water at sea caused by the wind (C) Is a current parallel to the shore, caused due to tangential component of the wind (D) Is a current perpendicular to the shore line caused due to wind

Last Answer : (C) Is a current parallel to the shore, caused due to tangential component of the wind

Description : Compute the loss factor when the loss tangent is 0.88 and the real part of dielectric is 24. a) 12.12 b) 12.21 c) 21.21 d) 21.12

Last Answer : d) 21.12

Description : The flux density of medium 1 has a normal component of 2.4 units, then the normal component of the flux density in the medium 2 will be a) 1.2 b) 4.8 c) 2.4 d) 0

Last Answer : c) 2.4

Description : The normal component of the electric flux density is always discontinuous at the interface. State True/False. a) True b) False

Last Answer : a) True

Description : The distance vector can be used to compute which of the following? a) Dot product b) Cross product c) Unit normal vector d) Area

Last Answer : c) Unit normal vector

Description : Find a vector normal to a plane consisting of points p1(0,1,0), p2(1,0,1) and p3(0,0,1) a) –j – k b) –i – j c) –i – k d) –i – j – k

Last Answer : a) –j – k

Description : The total power of a wave with average power 15 units in a surface density of 0.5 units is a) 15 b) 30 c) 7.5 d) 0.75

Last Answer : c) 7.5

Description : The surface integral of which parameter is zero? a) E b) D c) B d) H

Last Answer : c) B

Description : Which equation will hold good for a magnetic material? a) Line integral of H is zero b) Surface integral of H is zero c) Line integral of B is zero d) Surface integral of B is zero

Last Answer : d) Surface integral of B is zero

Description : For a solenoidal field, the surface integral of D will be, a) 0 b) 1 c) 2 d) 3

Last Answer : a) 0

Description : In the conversion of line integral of H into surface integral, which theorem is used? a) Green theorem b) Gauss theorem c) Stokes theore d) It cannot be converted

Last Answer : c) Stokes theorem

Description : The current element of the magnetic vector potential for a surface current will be a) J dS b) I dL c) K dS d) J dV

Last Answer : c) K dS

Description : Find the current density on the conductor surface when a magnetic field H = 3cos x i + zcos x j A/m, for z>0 and zero, otherwise is applied to a perfectly conducting surface in xy plane. a) cos x i b) –cos x i c) cos x j d) –cos x j

Last Answer : b) –cos x i

Description : Calculate the electric field due to a surface charge of 20 units on a plate in air(in 10 12 order) a) 2.19 b) 1.12 c) 9.21 d) 2.91

Last Answer : b) 1.12

Description : Find the permittivity of the surface when a wave incident at an angle 60 is reflected by the surface at 45 in air. a) 1.41 b) 3.5 c) 2.2 d) 1.73

Last Answer : d) 1.73

Description : A wave incident on a surface at an angle 60 degree is having field intensity of 6 units. The reflected wave is at an angle of 30 degree. Find the field intensity after reflection. a) 9.4 b) 8.4 c) 10.4 d) 7.4

Last Answer : c) 10.4

Description : The electric field intensity of a surface with permittivity 3.5 is given by 18 units. What the field intensity of the surface in air? a) 5.14 b) 0.194 c) 63 d) 29

Last Answer : c) 63

Description : The electric flux density of a surface with permittivity of 2 is given by 12 units. What the flux density of the surface in air? a) 24 b) 6 c) 1/6 d) 0

Last Answer : b) 6

Description : The work done in moving a test charge from one point to another in an equipotential surface is zero. State True/False. a) True b) Fals

Last Answer : a) True

Description : The total charge of a surface with densities 1,2,...,10 is a) 11 b) 33 c) 55 d) 77

Last Answer : c) 55

Description : A circular disc of radius 5m with a surface charge density ρs = 10sinφ is enclosed by surface. What is the net flux crossing the surface? a) 3 b) 2 c) 1 d) 0

Last Answer : d) 0

Description : Electric flux density in electric field is referred to as a) Number of flux lines b) Ratio of flux lines crossing a surface and the surface area c) Direction of flux at a point d) Flux lines per unit area

Last Answer : b) Ratio of flux lines crossing a surface and the surface area