The sum of the radii of two spheres is 10 cm and the sum of their volumes is 880 cm^3. What will be the product of their radii ? -Maths 9th

The sum of the radii of two spheres is 10 cm and the sum of their volumes is 880 cm^3. What will be the product of their radii ? -Maths 9th
by

1 Answer

Answer :

answer:
by

Related questions

The volumes of two spheres are in the ratio 64 : 27. Find the difference of their surface areas, if the sum of their radii is 7 cm. -Maths 9th

Description : The volumes of two spheres are in the ratio 64 : 27. Find the difference of their surface areas, if the sum of their radii is 7 cm. -Maths 9th

Last Answer : answer:

If the radii of the two spheres is 5 8 what is the ratio of their volumes?

Description : If the radii of the two spheres is 5 8 what is the ratio of their volumes?

Last Answer : What is the answer ?

The radii of two cylinders of the same height are in the ratio 4 :5, then find the ratio of their volumes. -Maths 9th

Description : The radii of two cylinders of the same height are in the ratio 4 :5, then find the ratio of their volumes. -Maths 9th

Last Answer : Let r1 and r2 be radii of two cyclinder and V1, V2 be their volume . Let h be height of the two cyclinders, then V1 = πr2h and V2 = πr22h ∴ V1 / V2 = πr12h / πr22h = r12 / r22 = 16 / 25 .

The radii of two cylinders of the same height are in the ratio 4 :5, then find the ratio of their volumes. -Maths 9th

Description : The radii of two cylinders of the same height are in the ratio 4 :5, then find the ratio of their volumes. -Maths 9th

Last Answer : Let r1 and r2 be radii of two cyclinder and V1, V2 be their volume . Let h be height of the two cyclinders, then V1 = πr2h and V2 = πr22h ∴ V1 / V2 = πr12h / πr22h = r12 / r22 = 16 / 25 .

The radii of two cylinders are in the ratio of 2 : 3 and their heights are in the ratio of 5 : 3. The ratio of their volumes is -Maths 9th

Description : The radii of two cylinders are in the ratio of 2 : 3 and their heights are in the ratio of 5 : 3. The ratio of their volumes is -Maths 9th

Last Answer : The answer is (b) 20:27

The radii of two cylinders are in the ratio of 2 : 3 and their heights are in the ratio of 5 : 3. The ratio of their volumes is -Maths 9th

Description : The radii of two cylinders are in the ratio of 2 : 3 and their heights are in the ratio of 5 : 3. The ratio of their volumes is -Maths 9th

Last Answer : According to question find the ratio of their volumes =

A spherical metal of radius 10 cm is melted and made into 1000 smaller spheres of equal sizes. In this process the surface area of the -Maths 9th

Description : A spherical metal of radius 10 cm is melted and made into 1000 smaller spheres of equal sizes. In this process the surface area of the -Maths 9th

Last Answer : Option (C) is correct. Solution: Let the radius of the small spheres be r' cm. Volume of metal remains the same in both cases. So, vol of the spherical metal of radius 10 cm = total ... Total Surface area of 1000 smaller spheres: 1000*4π12 = 4000π Hence, the surface area increased by 10 times.

The outer and the inner radii of a hollow sphere are 12 cm and 10 cm. Find its volume. -Maths 9th

Description : The outer and the inner radii of a hollow sphere are 12 cm and 10 cm. Find its volume. -Maths 9th

Last Answer : This answer was deleted by our moderators...

The outer and the inner radii of a hollow sphere are 12 cm and 10 cm. Find its volume. -Maths 9th

Description : The outer and the inner radii of a hollow sphere are 12 cm and 10 cm. Find its volume. -Maths 9th

Last Answer : This answer was deleted by our moderators...

Metal spheres, each of radius 2 cm, are packed into a rectangular box of internal dimensions 16 cm x 8 cm x 8 cm. -Maths 9th

Description : Metal spheres, each of radius 2 cm, are packed into a rectangular box of internal dimensions 16 cm x 8 cm x 8 cm. -Maths 9th

Last Answer : Volume of rectangular box=lbh=16(64)=1024cm3 Volume of sphere=34​πr3=33.5238cm3 16 sphere=16(33.5238)=536.3808 Volume of liquid=1024−536.3808=488cm3

Metal spheres, each of radius 2 cm, are packed into a rectangular box of internal dimensions 16 cm x 8 cm x 8 cm. -Maths 9th

Description : Metal spheres, each of radius 2 cm, are packed into a rectangular box of internal dimensions 16 cm x 8 cm x 8 cm. -Maths 9th

Last Answer : According to question find the volume of this liquid.

ABCD is a square of side a cm. AB, BC, CD and AD are all chords of circles with equal radii each. -Maths 9th

Description : ABCD is a square of side a cm. AB, BC, CD and AD are all chords of circles with equal radii each. -Maths 9th

Last Answer : (b) \(\bigg[a^2+4\bigg[rac{\pi{a}^2}{9}-rac{a^2}{4\sqrt3}\bigg]\bigg]\)As shown in the given figures, if a' is each side of the square, then ∠DOC = 120º ⇒ ∠ODC = ∠OCD = 30ºNow in fig. (iii), \(rac{ ... of square + Total area of 4 segments = \(a^2+4\bigg(rac{\pi{a}^2}{9}-rac{a^2}{4\sqrt3}\bigg).\)

In a sphere of radius 2 cm a cone of height 3 cm is inscribed. What is the ratio of volumes of the cone and sphere ? -Maths 9th

Description : In a sphere of radius 2 cm a cone of height 3 cm is inscribed. What is the ratio of volumes of the cone and sphere ? -Maths 9th

Last Answer : answer:

A hollow sphere and a solid sphere of the same material and equal radii are heated to the same temperature. In this case, (A) The cooling rate will be the same for the two spheres and hence the two spheres will have equal temperatures at any instant (B) Both the spheres will emit equal amount of radiation per unit time in the beginning (C) Both will absorb equal amount of radiation from the surrounding in the beginning (D) Both (B) & (C)

Description : A hollow sphere and a solid sphere of the same material and equal radii are heated to the same temperature. In this case, (A) The cooling rate will be the same for the two spheres and hence the ... equal amount of radiation from the surrounding in the beginning (D) Both (B) & (C)

Last Answer : (D) Both (B) & (C)

How The ratio of the heights of two similar cones is 79 Find the ratio of the following Their Radii 2) Their Volumes 3) The areas of their bases?

Description : How The ratio of the heights of two similar cones is 79 Find the ratio of the following Their Radii 2) Their Volumes 3) The areas of their bases?

Last Answer : Not enough information has been given but the volume of a cone is 1/3*pi*radius squared *height and its base area is pi*radius squared

Two solid spheres made of the same metal have weights 5920 g and 740 g, respectively. -Maths 9th

Description : Two solid spheres made of the same metal have weights 5920 g and 740 g, respectively. -Maths 9th

Last Answer : NEED ANSWER

Two solid spheres made of the same metal have weights 5920 g and 740 g, respectively. -Maths 9th

Description : Two solid spheres made of the same metal have weights 5920 g and 740 g, respectively. -Maths 9th

Last Answer : Solution of this question

The volume of two spheres are in the -Maths 9th

Description : The volume of two spheres are in the -Maths 9th

Last Answer : Let r1 and r2 be the radii of two spheres . Then, the ratio of their volumes is given by 4/3πr13/4/3πr23 = 64/27 (r1/r2)3 = (4/3)3 ⇒ r1/r2 = 4/3 Now, ratios of surface areas of two spheres = 4/3πr12/4/3πr22 = (r1/r2)2 = (4/3)2 = 16/9 ∴ Required ratio = 16 : 9

Two solid spheres made of the same metal -Maths 9th

Description : Two solid spheres made of the same metal -Maths 9th

Last Answer : Let r and R be the radii of the smaller and larger spheres respectively. We have, r = 5/2 cm Volume of the smaller sphere = 4/3πr3 = 4/3π(5/2)3 cm3 = 4/3 x π x 125/8 cm3 Density of metal = Mass/Volume = 740/4/3 x 125/8π ... ⇒ R3 = 5920 x 125/740 x 8 = 125 ⇒ R3 = 53 ⇒ R = 5 cm

1. Recall that two circles are congruent if they have the same radii. Prove that equal chords of congruent circles subtend equal angles at their centres. -Maths 9th

Description : 1. Recall that two circles are congruent if they have the same radii. Prove that equal chords of congruent circles subtend equal angles at their centres. -Maths 9th

Last Answer : To recall, a circle is a collection of points whose every point is equidistant from its centre. So, two circles can be congruent only when the distance of every point of both the circles are equal from the centre ... ) So, by SSS congruency, ΔAOB ΔCOD ∴ By CPCT we have, AOB = COD. (Hence proved).

Twenty-seven solid iron spheres, -Maths 9th

Description : Twenty-seven solid iron spheres, -Maths 9th

Last Answer : (i) Volume of 27 solid sphere, each of radius, r = 27 x 4/3 πr3 = 36 πr3 According to statement, Volume of sphere of radius r' = Volume of 27 solid spheres ⇒ 4/3 π(r'3 ) = 36 πr3 ⇒ (r')3 = 27r3 = (3r)3 ⇒ r' = 3r ( ... πr'2 = 4 π(3r)2 = 36 πr2 ∴ S/S' = 4 πr2 /36 πr2 = 1/9 ⇒ S : S' = 1 : 9

Three identical balls fit snugly into a cylindrical can. The radius of the spheres is equal to the radius of the can and the balls just touch the -Maths 9th

Description : Three identical balls fit snugly into a cylindrical can. The radius of the spheres is equal to the radius of the can and the balls just touch the -Maths 9th

Last Answer : hope its clear

What Sum of the terms of Arithmetic Progression If a boy saved 25 on the first day 27 on the second day 29 the third day and so on how many days it will take him to save 880?

Description : What Sum of the terms of Arithmetic Progression If a boy saved 25 on the first day 27 on the second day 29 the third day and so on how many days it will take him to save 880?

Last Answer : On the 20th day, you would reach 880. ---------------------------------------- Sum(AP) = ½n(2a + (n-1)d) here: Sum(AP) = 880 a (first term) = 25 d (common difference) = 2 n (number of ... The sum of an AP can also be expressed as ½ Ã- n Ã- (first + last) since last = first + (n - 1) Ã- difference.

Surface Areas and Volumes Class 9th Formulas -Maths 9th

Description : Surface Areas and Volumes Class 9th Formulas -Maths 9th

Last Answer : Circle is the locus of all such points which are equidistant from a fixed point, this point is known as centre while distance of any point from centre defined as radius of circle. Here O is fixed ... the exterior angle is equal to the interior opposite angle. An isosceles trapezium is cyclic.

NCERT Solutions for class 9 Maths Chapter 13 Surface Areas and Volumes Exercise 13.1 -Maths 9th

Description : NCERT Solutions for class 9 Maths Chapter 13 Surface Areas and Volumes Exercise 13.1 -Maths 9th

Last Answer : 1. A plastic box 1.5 m long, 1.25 m wide and 65 cm deep is to be made. It is opened at the top. Ignoring the thickness of the plastic sheet, determine: (i) The area of the sheet required for making the box ... of a cylinder = 2πrh + 2πr2 = 2πr(h + r) Note: Unless it is mentioned assume π = (22/7)

NCERT Solutions for class 9 Maths Chapter 13 Surface Areas and Volumes Exercise 13.2 -Maths 9th

Description : NCERT Solutions for class 9 Maths Chapter 13 Surface Areas and Volumes Exercise 13.2 -Maths 9th

Last Answer : 1. The curved surface area of a right circular cylinder of height 14 cm is 88 cm2. Find the diameter of the base of the cylinder. 2. It is required to make a closed cylindrical tank of height 1 m ... open from the top. ∴ Surface area of a penholder (cylinder) = [Lateral surface area] + [Base area]

NCERT Solutions for class 9 Maths Chapter 13 Surface Areas and Volumes Exercise 13.3 -Maths 9th

Description : NCERT Solutions for class 9 Maths Chapter 13 Surface Areas and Volumes Exercise 13.3 -Maths 9th

Last Answer : 1. Diameter of the base of a cone is 10.5 cm and its slant height is 10 cm. Find its curved surface area. 2.Find the total surface area of a cone, if its slant height is 21 m and diameter of its base is 24 ... m2, what will be the cost of painting all these cones? (Use π = 3.14 and take √1.04= 1.02)

NCERT Solutions for class 9 Maths Chapter 13 Surface Areas and Volumes Exercise 13.4 -Maths 9th

Description : NCERT Solutions for class 9 Maths Chapter 13 Surface Areas and Volumes Exercise 13.4 -Maths 9th

Last Answer : 1. Find the surface area of a sphere of radius: (i) 10.5 cm (ii) 5.6 cm (iii) 14 cm 2. Find the surface area of a sphere of diameter: (i) 14 cm (ii) 21 cm (iii) 3.5 m 3. Find the ... area of the sphere, (ii) curved surface area of the cylinder, (iii) ratio of the areas obtained in (i) and (ii).

NCERT Solutions for class 9 Maths Chapter 13 Surface Areas and Volumes Exercise 13.5 -Maths 9th

Description : NCERT Solutions for class 9 Maths Chapter 13 Surface Areas and Volumes Exercise 13.5 -Maths 9th

Last Answer : 1. A matchbox measures 4 cm x 2.5 cm. x 1.5 cm. What will be the volume of a packet containing 12 such boxes ? 2. A cuboidal water tank is 6 m long, 5 m wide and 4.5 m deep. How many litres of ... 40 m wide is flowing at the rate of 2 km per hour. How much water will fall into the sea in a minute ?

NCERT Solutions for class 9 Maths Chapter 13 Surface Areas and Volumes Exercise 13.6 -Maths 9th

Description : NCERT Solutions for class 9 Maths Chapter 13 Surface Areas and Volumes Exercise 13.6 -Maths 9th

Last Answer : 1. The circumference of the base of a cylindrical vessel is 132 cm and its height is 25 cm. How many litres of water can it hold ? (1000 cm3 = 1 l) . 2. The inner diameter of a cylindrical ... with soup to a height of 4 cm, how much soup the hospital has to prepare daily to serve 250 patients ?

MCQ Questions for Class 9 Maths Chapter 13 Surface Area and Volumes with answers -Maths 9th

Description : MCQ Questions for Class 9 Maths Chapter 13 Surface Area and Volumes with answers -Maths 9th

Last Answer : Below you will find MCQ Questions of Chapter 13 Surface Areas and Volumes Class 9 Maths Free PDF Download that will help you in gaining good marks in the examinations and also cracking competitive ... Areas and Volumes MCQ Questions will help you in practising more and more questions in less time.

A right circular cylinder and a right circular cone have equal bases and equal volumes. But the lateral surface area of the right circular cone is -Maths 9th

Description : A right circular cylinder and a right circular cone have equal bases and equal volumes. But the lateral surface area of the right circular cone is -Maths 9th

Last Answer : answer:

A sphere and a right circular cone of same radius have equal volumes. By what percentage does the height of the cone exceed its diameter ? -Maths 9th

Description : A sphere and a right circular cone of same radius have equal volumes. By what percentage does the height of the cone exceed its diameter ? -Maths 9th

Last Answer : answer:

A right triangle when one side is 3.5 cm and sum of other sides and the hypotenuse is 5.5 cm. -Maths 9th

Description : A right triangle when one side is 3.5 cm and sum of other sides and the hypotenuse is 5.5 cm. -Maths 9th

Last Answer : Let given right triangle be ABC. Then, given BC = 3.5 cm, ∠B = 90° and sum of other side and hypotenuse i.e., AB + AC = 5.5 cm To construct ΔABC use the following steps 1.Draw the base BC = 3.5 cm 2.Make ... AB = BD - AD = BD - AC [from Eq. (i)] => BD = AB + AC Thus, our construction is justified.

A right triangle when one side is 3.5 cm and sum of other sides and the hypotenuse is 5.5 cm. -Maths 9th

Description : A right triangle when one side is 3.5 cm and sum of other sides and the hypotenuse is 5.5 cm. -Maths 9th

Last Answer : Let given right triangle be ABC. Then, given BC = 3.5 cm, ∠B = 90° and sum of other side and hypotenuse i.e., AB + AC = 5.5 cm To construct ΔABC use the following steps 1.Draw the base BC = 3.5 cm 2.Make ... AB = BD - AD = BD - AC [from Eq. (i)] => BD = AB + AC Thus, our construction is justified.

Construct a right triangle whose base is 12 cm and sum of its hypotenuse and other side is 18 cm. -Maths 9th

Description : Construct a right triangle whose base is 12 cm and sum of its hypotenuse and other side is 18 cm. -Maths 9th

Last Answer : Steps of Construction (i) Draw BC = 12 cm. (ii) Construct ÐCBY = 90°. (iii) From ray BY, cut-off line segment BD = 18 cm. (iv) Join CD. (v) Draw the perpendicular bisector of CD intersecting BD at A. (vi ... = AC Now, BD = BA + AD ⇒ BD = AB + AC Hence, △ABC is the required triangle.

According to Avogadro’s law  A. the product of the gas constant and the molecular mass of an ideal gas is constant  B. the sum of partial pressure of the mixture of two gases is sum of the two  C. equal volumes of all gases, at the same temperature and pressure, contain equal number of molecules  D. all of the above

Description : According to Avogadro's law  A. the product of the gas constant and the molecular mass of an ideal gas is constant  B. the sum of partial pressure of the mixture of two gases is sum of the ... all gases, at the same temperature and pressure, contain equal number of molecules  D. all of the above

Last Answer : Answer: C

In quadratic equation ax^2 + bx + c = 0 , Identities the sum and product of Roots? -Maths 9th

Description : In quadratic equation ax^2 + bx + c = 0 , Identities the sum and product of Roots? -Maths 9th

Last Answer : If the two roots of the quadratic equation ax2 + bx + c = 0 obtained by the quadratic formula be denoted by a and b, then we have α = \(\frac{-b+\sqrt{b^2-4ac}}{2a},\) β = \(\frac{-b-\sqrt{b^2-4ac}}{2a}\) ∴ Sum of roots ... then α + β = - (- \(\frac{5}{6}\)) = \(\frac{5}{6}\), ab = \(\frac{7}{6}\).

What is the ratio of sum of squares of roots to the product of the roots of the equation 7x^2 + 12x + 18 = 0? -Maths 9th

Description : What is the ratio of sum of squares of roots to the product of the roots of the equation 7x^2 + 12x + 18 = 0? -Maths 9th

Last Answer : Let α, β be the roots of the equation 7x2 + 12x + 18 = 0. ∴ Required ratio = α2 + β2 : αβ = ​​−10849187 = −67 = – 6 : 7.

The sum of the roots of the equation (1/(x+a))+(1/(x+b))=1/c is zero. What is the product of the roots of the equation ? -Maths 9th

Description : The sum of the roots of the equation (1/(x+a))+(1/(x+b))=1/c is zero. What is the product of the roots of the equation ? -Maths 9th

Last Answer : answer:

If the sum as well as the product of roots of a quadratic equation is 9, then the equation is: -Maths 9th

Description : If the sum as well as the product of roots of a quadratic equation is 9, then the equation is: -Maths 9th

Last Answer : answer:

If the sum and difference of two expressions are 5a^2 – a – 4and a^2 + 9a – 10 respectively, then what is their LCM ? -Maths 9th

Description : If the sum and difference of two expressions are 5a^2 – a – 4and a^2 + 9a – 10 respectively, then what is their LCM ? -Maths 9th

Last Answer : answer:

The focal length of a concave-convex lens of radii of curvature 5 cm and 10 cm is 20 cm. what will be its focal length in water ? Given `.^(a)mu_(w) =

Description : The focal length of a concave-convex lens of radii of curvature 5 cm and 10 cm is 20 cm. what will be its focal length in water ? Given `.^(a)mu_(w) =

Last Answer : The focal length of a concave-convex lens of radii of curvature 5 cm and 10 cm is 20 cm. what will be its ... water ? Given `.^(a)mu_(w) = 4//3`.

Draw the graph of the linear equation whose solutions are represented by the points having the sum of the coordinates as 10 units. -Maths 9th

Description : Draw the graph of the linear equation whose solutions are represented by the points having the sum of the coordinates as 10 units. -Maths 9th

Last Answer : As per question, the sum of the coordinates is 10 units. Let x and y be two coordinates, then we get x + y = 10. For x = 5, y = 5, therefore, (5, 5) lies on the graph of x + y = 10. For x = ... and (3, 7) on the graph paper and joining them by a line, we get graph of the linear equation x + y = 10.

Draw the graph of the linear equation whose solutions are represented by the points having the sum of the coordinates as 10 units. -Maths 9th

Description : Draw the graph of the linear equation whose solutions are represented by the points having the sum of the coordinates as 10 units. -Maths 9th

Last Answer : As per question, the sum of the coordinates is 10 units. Let x and y be two coordinates, then we get x + y = 10. For x = 5, y = 5, therefore, (5, 5) lies on the graph of x + y = 10. For x = ... and (3, 7) on the graph paper and joining them by a line, we get graph of the linear equation x + y = 10.

The minimum value of the sum of real numbers a^(–5), a^(–4), 3a^(–3), 1, a^8 and a^10 with a > 0 is -Maths 9th

Description : The minimum value of the sum of real numbers a^(–5), a^(–4), 3a^(–3), 1, a^8 and a^10 with a > 0 is -Maths 9th

Last Answer : answer:

Two concentric circular coils of ten turns each are situated in the same plane. Their radii are `20` and `40 cm` and they carry respectively `0.2` and

Description : Two concentric circular coils of ten turns each are situated in the same plane. Their radii are `20` and `40 cm` and they carry respectively `0.2` and

Last Answer : Two concentric circular coils of ten turns each are situated in the same plane. Their radii are `20` and `40 cm` ... /80)mu_(0)` D. `(25//2)mu_(0)`

“The total volume of a mixture of non-reacting gases is equal to the sum of the partial volumes.” This statement is known as ______.  A. Law of Dulong and Petit  B. Maxwell-Boltzmann law  C. Amagat’s law  D. Avogadro’s law

Description : “The total volume of a mixture of non-reacting gases is equal to the sum of the partial volumes.” This statement is known as ______.  A. Law of Dulong and Petit  B. Maxwell-Boltzmann law  C. Amagat’s law  D. Avogadro’s law

Last Answer : Amagat’s law

If a1, a2, .... an are positive numbers such that a1.a2.a3 .... an = 1, then their sum is -Maths 9th

Description : If a1, a2, .... an are positive numbers such that a1.a2.a3 .... an = 1, then their sum is -Maths 9th

Last Answer : answer:

If the sum of the roots of the equation ax^2 + bx + c = 0 is equal to the sum of their squares, then which one of the following is correct ? -Maths 9th

Description : If the sum of the roots of the equation ax^2 + bx + c = 0 is equal to the sum of their squares, then which one of the following is correct ? -Maths 9th

Last Answer : Given equation: ax2+bx+c=0 Let α and β be the roots of given quadratic equation Sum of the roots i.e. α+β=a−b Product of roots i.e. αβ=ac It is given that, Sum of the roots = Sum of squares of the roots i ... )2−2αβ i.e. a−b =(a−b )2−a2c i.e. −ab=b2−2ac i.e. ab+b2=2ac Hence, C is the correct option.