A four digit number is formed by the digits 1, 2, 3, 4 with no repetition. The probability that the number is odd is -Maths 9th

A four digit number is formed by the digits 1, 2, 3, 4 with no repetition. The probability that the number is odd is -Maths 9th
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Answer :

(a) \(rac{1}{2}\) Let S be the sample spaceThen n(S) = Number of four digit numbers that can be formed with out repetition1 of 4 digits1 of 3 digits1 of 2 digits1 of 1 digitThHTO= 4! = 4 × 3 × 2 × 1 ways = 24 ways. Let E : Event of forming odd 4 digit numbers with the digits 1, 2, 3, 4 without repetition. Then, the ones place can be filled by the odd digits 1 or 3, in 2 ways. The thousands place can be filled with the remaining 3 digits in 3 ways The hundreds place can be filled with the remaining 2 digits in 2 ways The tens place can be filled with the remaining 1 digit in 1 way∴ n(E) = 2 × 3 × 2 × 1 = 12∴ P(E) = \(rac{n(E)}{n(S)}\) = \(rac{12}{24}\) = \(rac{1}{2}\).
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Related questions

A five digit number is formed by the digits 0, 1, 2, 3, 4 (without repetition). Find the probability that the number formed is divisible by 4 ? -Maths 9th

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Last Answer : Without repetition, a five -digit number can be formed using the five digits in 5! ways (5 4 3 2 1) Out of these 5! numbers, 4! numbers will be starting with digit 0. (0 (fixed) 4 3 2 1) ∴ Total ... + 6 + 6 + 4 + 4 + 4 = 30∴ Required probability = \(rac{30}{96}\) = \(rac{5}{16}.\)

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Last Answer : The two digit numbers can be formed by putting any of 5 digits at the one 's place and also one of the 5 digits at ten's place. So, Total number of 2-digit numbers that can be formed using these 5-digits = 5 5 = ... 52}, i.e, 5 in number. ∴ Required probability = \(rac{5}{25}\) = \(rac{1}{5}.\)

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What is the formula for the quiz-What is the 4 digit number in which the first digit is one-fifth of the last and the second and third digits are the last digit multiplied by 3?

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How did you arrive at the answer of 1155 for What is the 4 digit number in which the first digit is one-fifth of the last and the second and third digits are the last digit multiplied by 3?

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Last Answer : There are only two single-digit numbers where one is 1/5 of theother. Those are 1 and 5 and they become the outside numbers. Fromthere, it's relatively easy to multiply 5 by 3 to get 15 for theinside numbers.

What is a two digit number whose sum of those digits is the square root of that number?

Description : What is a two digit number whose sum of those digits is the square root of that number?

Last Answer : The number is 81.

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Last Answer : 121

What is a number that has 2 digits less than 10 the tenths digit is one more than the ones digit nad the digits add up to 7?

Description : What is a number that has 2 digits less than 10 the tenths digit is one more than the ones digit nad the digits add up to 7?

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10.) A two-digit number is prime. When you reverse the digits, that number is also prime. What could the number be List three possibilities.?

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The 2 digit number which becomes (5/6)th of itself when its digits are reversed. The difference in the digits of the number being 1, then the two digits number is (a) 45 (b) 54 (c) 36 (d) None of these

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Last Answer : Cannot be determined Answer: d)

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The digits of a two-digit number are in the ratio of 2 : 3 and the number obtained by interchanging the digits is bigger than the original number by 27.What is the original number? 1. 63 2. 48 3. 96 4. 69 5. 66

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The square of a two digit number is divided by half the number. After 36 is added to the quotient, this sum is then divided by 2. The digits of the resulting number are the same as those in the original number, but they are in reverse order. The ten's place of the original number is equal to twice the difference between its digits. What is the number?

Description : The square of a two digit number is divided by half the number. After 36 is added to the quotient, this sum is then divided by 2. The digits of the resulting number are the same as those in ... 's place of the original number is equal to twice the difference between its digits. What is the number?

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In an examination mahi scores 64% of marks, nitesh scores 52% of marks and ritesh scores 48% of marks. The maximum mark of the exam is a three digit number, whose sum is 10 and the middle digit is equal to the sum of the other two digits. The number will decreased by 297, if its digit are reversed. approximately what is the average mark obtained by mahi, nitesh and ritesh? A) 247 B) 248 C) 264 D) 284

Description : In an examination mahi scores 64% of marks, nitesh scores 52% of marks and ritesh scores 48% of marks. The maximum mark of the exam is a three digit number, whose sum is 10 and the middle digit is equal to ... what is the average mark obtained by mahi, nitesh and ritesh? A) 247 B) 248 C) 264 D) 284

Last Answer : A) Maximum mark consist of a three digit number let's consider Unit digit place is Z,ten's place digit is Y and hundred's place digit is X. According to the question, Y=x+z---------1 X+Y ... Total number of Mahi, Nitesh and Ritesh =164/100 451=739.61 Required average =739.64/3=246.54~247.

Two coin are tossed 400 times and we get a. Two Heads : 112 times b. One Head : 160 times c. No Head : 128 times. When two coins are tossed at random, what is the probability of getting a. Two Heads b. One Head c. No Head -Maths 9th

Description : Two coin are tossed 400 times and we get a. Two Heads : 112 times b. One Head : 160 times c. No Head : 128 times. When two coins are tossed at random, what is the probability of getting a. Two Heads b. One Head c. No Head -Maths 9th

Last Answer : Given, Total number of events = 400 (a) No. of times two heads occur = 112 Probability of getting two heads = 112/400 = 7/25 (b) No. of times one heads occur = 160 Probability of getting one heads = 160/400 = 2/5 (c) No. of times no heads occur = 128 Probability of getting no heads = 128/400 = 8/25

Two coin are tossed 400 times and we get a. Two Heads : 112 times b. One Head : 160 times c. No Head : 128 times. When two coins are tossed at random, what is the probability of getting a. Two Heads b. One Head c. No Head -Maths 9th

Description : Two coin are tossed 400 times and we get a. Two Heads : 112 times b. One Head : 160 times c. No Head : 128 times. When two coins are tossed at random, what is the probability of getting a. Two Heads b. One Head c. No Head -Maths 9th

Last Answer : Given, Total number of events = 400 (a) No. of times two heads occur = 112 Probability of getting two heads = 112/400 = 7/25 (b) No. of times one heads occur = 160 Probability of getting one heads = 160/400 = 2/5 (c) No. of times no heads occur = 128 Probability of getting no heads = 128/400 = 8/25