Description : Need sample paper for fa2 -Maths 9th
Last Answer : This answer was deleted by our moderators...
Description : In a sample study of 642 people, it was found that 514 people have a high school certificate. -Maths 9th
Last Answer : Total number of persons = 642 Number of persons with high school certificate = 514 therefore Required probability=514 / 642 =0.80
Last Answer : NEED ANSWER
Last Answer : (d) The total number of people in sample study, n(S) = 642. The number of people who have high school certificate, n(E) = 514. So, the probability that the person selected has a high school certificate ... S)=514/642 = 0.8 Hence, the probability that the person has a high school certificate is 0.8.
Description : Is an element in the sample space for tossing a coin and then rolling a die?
Last Answer : I do'nt know
Description : Define Sample Space or possible outcomes.
Last Answer : Ans: All possible outcomes of an experiment are called sample space and is denoted by “S” i.e. in toss of coin the sample space will be two (Head & Tail) & in throwing a die it will be 6 (1, 2, 3, 4, 5, 6)
Description : In a time multiplexed space switching system, one speech sample appears every (A) 125 micro sec (B) 20 msec (C) 125 msec (D) 1 sec
Last Answer : (A) 125 micro sec
Description : When a single die is rolled, the sample space is {1,2,3,4,5,6}.What is the probability of getting a 3 when a die is rolled? A) 1/2 B) 1/6 C) 6/1 D) 3/6
Last Answer : Answer: B) No. of ways it can occur = 1 Total no. of possible outcomes = 6 So the probability of rolling a particular number (3) when a die is rolled = 1/6.
Description : find the mean of first five multiples of 10 -Maths 9th
Last Answer : This is the correct one...
Description : The mean of 200 items was 50. Later on, it was discovered that the two items were misread as 92 and 8 instead of 192 and 88.find the correct mean. -Maths 9th
Last Answer : Here's ur answer..
Description : 2 . If the mean of the following distribution is 6 . Find the value of p ? x 2 4 6 10 P + 5 f 3 2 3 1 2 -Maths 9th
Last Answer : Here's ur answer...
Description : Mean of 20 observations is 17. If in the observations, observation 40 is replaced by 12, find the new mean. -Maths 9th
Last Answer : Since mean of 20 observations is 17 Sum of the 20 observations = 17 x 20 = 340 New sum of 20 observations = 340 – 40 + 12 = 312 New mean=312 / 20 =15.6
Description : Mean of 36 observations is 12. One observation 47 was misread as 74. Find the correct mean. -Maths 9th
Last Answer : Mean of 36 observations = 12 Total of 36 observations = 36 x 12 = 432 Correct sum of 36 observations = 432 – 74 + 47 = 405 Correct mean of 36 observations = 405/ 36 =11.25
Description : If the mean of five observations x, x + 2, x + 4, x + 6, x + 8 is 11, then write the value of x. -Maths 9th
Last Answer : x + x + 2 + x + 4 + x + 6 + x + 8 / 5 = 11 5x + 20 = 55 5x = 35 ⇒ x = 7
Description : Determine the mean of first 10 natural numbers. -Maths 9th
Last Answer : Mean = 1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 + 10 / 10 = 55 / 10 = 5.5
Description : Find the mean of x, x + 2, x + 4, x + 6, x + 8. -Maths 9th
Last Answer : x + x + 2 + x + 4 + x + 6 + x + 8 / 5 = 5x + 20 / 5 = x + 4
Description : The mean of 8 observations is 40. If 5 is added to each observation, then what will be the new mean ? -Maths 9th
Last Answer : Let the 8 observations are x1, x2, x3, x4, x5, x6, x7, x8 ∴ x1 + x2 + x3 + x4 + x5 + x6 + x7 + x8 = 40 × 8 = 320 New mean = 320 + 5 × 8 = 360 / 8 = 45
Description : There are 50 numbers. Each number is subtracted from 53 and the mean of the numbers so obtained is found to be – 3.5. Find the mean of the given numbers. -Maths 9th
Last Answer : Let x be the mean of 50 numbers. ∴ sum of 50 numbers = 50x Since each number is subtracted from 53. According to question, we have 53 × 50 - 50x / 50 = - 3.5 ⇒ 2650 - 50x = -175 ⇒ 50x = 2825 ⇒ x = 2825 / 50 = 56.5
Description : Find the mean of the following distribution : -Maths 9th
Last Answer : Now, mean =(x̅) = Σfx / Σf = 1900 / 100 = 19
Description : The mean weight per student in a group of 7 students is 55 kg. -Maths 9th
Last Answer : x̅ = 1 / n (Σxi) ⇒ 55 = x1 + x2 + .......+ ⇒ x7 / 7 ⇒ x1 + x2 + ...... + x7 = 55 × 7 = 385 x1 + x2 + ...... + x6 = 52 + 54 + 55 + 53 + 56 + 54 = 324 ∴ x7 = 385 - 324 = 61 kg ∴ weight of the seventh student is 61 kg.
Description : Obtain the mean of the following distribution and also find the mode. -Maths 9th
Last Answer : fixi/fi 270/55 Mean=4.9
Description : The mean of five numbers is 30. If one number is excluded, their mean becomes 28. The excluded number is -Maths 9th
Description : If the mean of the observations x, x + 3, x + 5, x + 7and x + 10 is 9, then mean of the last three observations is -Maths 9th
Description : If each observation of the data is increased by 5, then their mean -Maths 9th
Description : Let x be the mean of x1, x2,….,xn and y be the mean of y1, y2, ……,yn the mean of z is x1, x2,….,xn , y1, y2, ……,yn then z is equal to -Maths 9th
Description : The mean of 100 observations is 50. If one of the observation which was 50 is replaced by 150, the resulting mean will be -Maths 9th
Description : There are 50 numbers. Each number is subtracted from 53 and the mean of the number so obtained is found to be – 3.5. -Maths 9th
Description : The mean of 25 observations is 36. Out of these observations, if the mean of first 13 observations is 32 and that of the last 13 observations is 40, the 13th observation is -Maths 9th
Description : What is the mean of 12,34,15,3,16? -Maths 9th
Last Answer : Excluded number is
Last Answer : According to question find the mean of the last three observations
Last Answer : Simplify the question
Last Answer : According to question find the value of z
Last Answer : Solution of this question
Last Answer : Find the mean of the given number is