find the mean of first five multiples of 10 -Maths 9th

1 Answer

Answer :

This is the correct one...

Related questions

Description : find the mean of first five multiples of 10 -Maths 9th

Last Answer : This is the correct one...

Description : The width of each of five continuous classes in a frequency distribution is 5 and the lower class limit of the lowest class is 10. -Maths 9th

Last Answer : NEED ANSWER

Description : The width of each of five continuous classes in a frequency distribution is 5 and the lower class limit of the lowest class is 10. -Maths 9th

Last Answer : (c) Let x and y be the upper and lower class limit of frequency distribution. Given, width of the class = 5 ⇒ x-y= 5 (i) Also, given lower class (y) = 10 On putting y = 10 in Eq. (i), we get ... 20-25, 25-30 and 30-35. Thus, the highest class is 30-35, Hence, the upper limit of this class is 35.

Description : Five years hence , the age of Ram will be 10 more than the two thirds of Ravi’s age . Assume the present ages of Ram and Ravi as x and y respectively . Express the statement in the form of a linear equation in two variables. -Maths 9th

Last Answer : answer:

Description : What are the first five nonzero multiples of 6?

Last Answer : [6] 12 18 24 30 36

Description : What are the first five multiples of 12 greater than 0?

Last Answer : 1 x 12 = 122 x 12 = 243 x 12 = 364 x 12 = 485 x 12 = 60If you can't remember the 12 times table, just keep adding another 12 to the previous answer.

Description : Find the arithmetic mean of first-five natural numbers. -Maths 9th

Last Answer : Mean = 1 + 2 + 3 + 4 + 5/5 = 15/5 = 3

Description : What are five multiples of nine?

Last Answer : The product is 45

Description : Which of the following statements is true about terpenes? (a) They are a class of lipids that can be isolated from plants. (b) They contain carbon atoms in multiples of five. (c) They are composed of isoprene units joined together in a head-to-tail fashion. (d) All of the above

Last Answer : All of the above

Description : If the mean of five observations x, x + 2, x + 4, x + 6, x + 8 is 11, then write the value of x. -Maths 9th

Last Answer : x + x + 2 + x + 4 + x + 6 + x + 8 / 5 = 11 5x + 20 = 55 5x = 35 ⇒ x = 7

Description : If the mean of five observations x, x + 2, x + 4, x + 6, x + 8 is 11, then write the value of x. -Maths 9th

Last Answer : x + x + 2 + x + 4 + x + 6 + x + 8 / 5 = 11 5x + 20 = 55 5x = 35 ⇒ x = 7

Description : The mean of five numbers is 30. If one number is excluded, their mean becomes 28. The excluded number is -Maths 9th

Last Answer : NEED ANSWER

Description : The mean of five numbers is 30. If one number is excluded, their mean becomes 28. The excluded number is -Maths 9th

Last Answer : Excluded number is

Description : Find the five rational no. Between5/7 and9/11 -Maths 9th

Last Answer : 5/7 and 9/11 find the lcm of 7 and 11 lcm =77. 5/7 *11/11=55/77 , 9/11*7/7=63/77 therefore five rational no are 56/77 57/77 58/77 59/77 60/77

Description : Books are packed in piles each containing 20 books. Thirty five piles were examined for defective books and the results are given in the following table : -Maths 9th

Last Answer : Total number of books = 700 (i) P(no defective books) = 400 / 700 = 4 / 7 (ii) P(more than 0 but less than 4 defective books) = 269 / 700 (iii) P(more than 4 defective books) = 13 / 700

Description : Find the five rational no. Between5/7 and9/11 -Maths 9th

Last Answer : 5/7 and 9/11 find the lcm of 7 and 11 lcm =77. 5/7 *11/11=55/77 , 9/11*7/7=63/77 therefore five rational no are 56/77 57/77 58/77 59/77 60/77

Description : Books are packed in piles each containing 20 books. Thirty five piles were examined for defective books and the results are given in the following table : -Maths 9th

Last Answer : Total number of books = 700 (i) P(no defective books) = 400 / 700 = 4 / 7 (ii) P(more than 0 but less than 4 defective books) = 269 / 700 (iii) P(more than 4 defective books) = 13 / 700

Description : Find the value of 7plus root five ÷by seven minus root five minus seven minus root five ÷by seven plus root five equals to a+7÷11root five b -Maths 9th

Last Answer : This answer was deleted by our moderators...

Description : Hari has some two rupee and five rupee coins .The total amount with him is rs. 43. Express the given information as a linear equation in two variables. -Maths 9th

Last Answer : answer:

Description : The figure given besides shows five squares inside one another by joining the midpoints of the outer square. -Maths 9th

Last Answer : (c) \(rac{31}{16}a^2.\)Side of the square I = a ∴ Area of square I = a2= \(\sqrt{rac{a^2}{16}+rac{a^2}{16}}\) = \(\sqrt{rac{2a^2}{16}}\) = \(rac{a}{2\sqrt2}\)∴ Sum of the areas of the five squares= a2 + \( ... = a2 \(\bigg[1+ rac{1}{2} + rac{1}{4}+rac{1}{8}+rac{1}{16}\bigg]\) = \(rac{31}{16}a^2.\)

Description : A can hit a target three times in five shots, B two times in five shots and C three times in four shots. They fire a volley. -Maths 9th

Last Answer : P(A) = \(rac{3}{5}\), P(B) = \(rac{2}{5}\), P(C) = \(rac{3}{4}\). In order that two shots may hit the target the following three mutually exclusive events are possible,(i) A and B hit the target and not C. (ii) B ... {100}\) + \(rac{12}{100}\) + \(rac{27}{100}\) = \(rac{45}{100}\) = \(rac{9}{20}.\)

Description : A bag contains 30 tickets numbered from 1 to 30. Five tickets are drawn at random and arranged in ascending order -Maths 9th

Last Answer : Total number of ways in which 5 tickets can be drawn = n(S) = 30C5. The tickets are arranged in the form T1, T2, T3 (= 20), T4, T5 Where T1, T2 ∈{1, 2, 3, , 19} and T4, T5 ∈{21, 22, , 30 ... {10 imes9}{2}\) x \(rac{5 imes4 imes3 imes2 imes1}{30 imes29 imes28 imes27 imes26}\) = \(rac{285}{5278}.\)

Description : A five digit number is formed by the digits 0, 1, 2, 3, 4 (without repetition). Find the probability that the number formed is divisible by 4 ? -Maths 9th

Last Answer : Without repetition, a five -digit number can be formed using the five digits in 5! ways (5 4 3 2 1) Out of these 5! numbers, 4! numbers will be starting with digit 0. (0 (fixed) 4 3 2 1) ∴ Total ... + 6 + 6 + 4 + 4 + 4 = 30∴ Required probability = \(rac{30}{96}\) = \(rac{5}{16}.\)

Description : Five horses are in a race. Mr A. Selects two of the horses at random and bets on them. The probability that Mr A selected the winning horse is -Maths 9th

Last Answer : (b) \(rac{2}{5}\)As each horse has equal chance of winning the race, Number of ways in which one of the five horses wins the race = 5C1 ∴ n(S) =5C1 = \(rac{|\underline5}{|\underline4|\underline1}\) 5To find the chance ... n(E) = 2C1 = 2 ∴ Required probability = \(rac{n(E)}{n(S)}\) = \(rac{2}{5}\).

Description : In how many ways can a committee of five persons be formed out of 8 members when a particular member is taken every time? -Maths 9th

Last Answer : ∴Required number of ways = 7C4 = 7!

Description : There are 18 points in a plane such that no three of them are in the same line except five points which are collinear. -Maths 9th

Last Answer : answer:

Description : Five balls of different colours are to be placed in three boxes of different sizes. Each box can hold all five. In how many different ways -Maths 9th

Last Answer : According to the question, we have 5 balls to be placed in 3 boxes where no box remains emptyHence, we can have the following kinds of distribution firstly, where the distribution will be (3,1,1) that is, one box gets three ... go in second box is = 4 C 2 . Total no. of ways =90 Total:60+90=150.

Description : Explain five major factors which contributed to the making of our constitution. -Maths 9th

Last Answer : The white minority and the black majority agreed to draw up a common constitution for South Africa in the following ways.The white regime changed its repressive policies and repealed its ... the solution irrespective of the differences and whatever they had done or represented in the past

Description : Points P, Q, R and S divide a line segment joining A (2, 6) and B (7, -4) in five equal parts. Find the coordinates of P and R. -Maths 9th

Last Answer : this is the ans hope its clear

Description : What is the first 5 multiples of 10?

Last Answer : 10,20,30,40,50

Description : what is the first 10 multiples of 2?

Last Answer : 2,4,6,8,10,12,14,16,18,20

Description : Determine the mean of first 10 natural numbers. -Maths 9th

Last Answer : Mean = 1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 + 10 / 10 = 55 / 10 = 5.5

Description : Determine the mean of first 10 natural numbers. -Maths 9th

Last Answer : Mean = 1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 + 10 / 10 = 55 / 10 = 5.5

Description : What are the multiples of 2 8 and 10 between the numbers 55 and 101?

Last Answer : Just 80

Description : What multiples of 10 are factors of 280?

Last Answer : Feel Free to Answer

Description : 2 . If the mean of the following distribution is 6 . Find the value of p ? x 2 4 6 10 P + 5 f 3 2 3 1 2 -Maths 9th

Last Answer : Here's ur answer...

Description : 2 . If the mean of the following distribution is 6 . Find the value of p ? x 2 4 6 10 P + 5 f 3 2 3 1 2 -Maths 9th

Last Answer : Here's ur answer...

Description : If the mean of the observations x, x + 3, x + 5, x + 7and x + 10 is 9, then mean of the last three observations is -Maths 9th

Last Answer : NEED ANSWER

Description : If the mean of the observations x, x + 3, x + 5, x + 7and x + 10 is 9, then mean of the last three observations is -Maths 9th

Last Answer : According to question find the mean of the last three observations

Description : Find the lateral surface area and total surface area of a cube of edge 10 cm. -Maths 9th

Last Answer : Edge of cube (a) = 10 cm (i) ∴ Lateral surface area = 4a² = 4 x (10)² = 4 x 100 cm²= 400 cm² (ii) Total surface area = 6a² = 6 x(10)² cm² = 6 x 100 = 600 cm²

Description : A field is in the shape of a trapezium whose parallel sides are 25 m and 10 m. The non-parallel sides are 14 m and 13 m. Find the area of the field. -Maths 9th

Last Answer : Let the given field is in the form of a trapezium ABCD such that parallel sides are AB = 10 m and DC = 25 m Non-parallel sides are AD = 13 m and BC = 14 m. We draw BE || AD, such that BE = 13 m. ... = 112 m2 So, area of the field = area of ∆BCE + area of parallelogram ABED = 84 m2 + 112 m2 = 196 m2

Description : An umbrella is made by stitching 10 triangular pieces of cloth of two different colours (see figure), each piece measuring 20 cm, 50 cm and 50 cm. -Maths 9th

Last Answer : Let the sides of each triangular piece be a = 20 cm, b = 50 cm, c = 50 cm

Description : The capacity of a cuboidal tank is 50000 litres of water. Find the breadth of the tank, if its length and depth are respectively 2.5 m and 10 m -Maths 9th

Last Answer : Length (l) and depth (h) of tank is 2.5 m and 10 m respectively. To find: The value of breadth, say b. Formula to find the volume of a tank = l b h = (2.5 b 10) m3= 25b m3 Capacity ... of water (Given) Therefore, 25000 b = 50000 This implies, b = 2 Therefore, the breadth of the tank is 2 m.

Description : A hemispherical bowl made of brass has inner diameter 10.5cm. Find the cost of tin-plating it on the inside at the rate of Rs 16 per 100 cm2. -Maths 9th

Last Answer : Inner radius of hemispherical bowl, say r = diameter/2 = (10.5)/2 cm = 5.25 cm Formula for Surface area of hemispherical bowl = 2πr2 = 2 (22/7) (5.25)2 = 173.25 Surface area of hemispherical ... of tin-plating the inner side of the hemispherical bowl at the rate of Rs 16 per 100 cm2 is Rs 27.72.

Description : Find the total surface area of a hemisphere of radius 10 cm -Maths 9th

Last Answer : Radius of hemisphere, r = 10cm Formula: Total surface area of hemisphere = 3πr2 = 3×3.14×102 = 942 The total surface area of given hemisphere is 942 cm2.

Description : Find the surface area of a sphere of radius: (i) 10.5cm (ii) 5.6cm (iii) 14cm -Maths 9th

Last Answer : Formula: Surface area of sphere (SA) = 4πr2 (i) Radius of sphere, r = 10.5 cm SA = 4 (22/7) 10.52 = 1386 Surface area of sphere is 1386 cm2 (ii) Radius of sphere, r = 5.6cm Using formula, SA = 4 (22 ... 75 cm Surface area of sphere = 4πr2 = 4 (22/7) 1.752 = 38.5 Surface area of a sphere is 38.5 cm2

Description : A joker’s cap is in the form of right circular cone of base radius 7 cm and height 24cm. Find the area of the sheet required to make 10 such caps. -Maths 9th

Last Answer : Radius of conical cap, r = 7 cm Height of conical cap, h = 24cm Slant height, l2 = (r2+h2) = (72+242) = (49+576) = (625) Or l = 25 cm CSA of 1 conical cap = πrl = (22/7)×7×24 = 550 CSA of 10 caps = (10×550) cm2 = 5500 cm2 Therefore, the area of the sheet required to make 10 such caps is 5500 cm2.

Description : A conical tent is 10 m high and the radius of its base is 24 m. Find (i) slant height of the tent. -Maths 9th

Last Answer : : Ncert solutions class 9 chapter 13-5 Let ABC be a conical tent Height of conical tent, h = 10 m Radius of conical tent, r = 24m Let the slant height of the tent be l. (i) In right triangle ... (13728/7) 70 = Rs 137280 Therefore, the cost of the canvas required to make such a tent is Rs 137280.

Description : Diameter of the base of a cone is 10.5 cm and its slant height is 10 cm. Find its curved surface area -Maths 9th

Last Answer : Radius of the base of cone = diameter/ 2 = (10.5/2)cm = 5.25cm Slant height of cone, say l = 10 cm CSA of cone is = πrl = (22/7)×5.25×10 = 165

Description : A cubical box has each edge 10 cm and another cuboidal box is 12.5cm long, 10 cm wide and 8 cm high -Maths 9th

Last Answer : From the question statement, we have Edge of a cube = 10cm Length, l = 12.5 cm Breadth, b = 10cm Height, h = 8 cm (i) Find the lateral surface area for both the figures Lateral surface ... . Therefore, the total surface area of the cubical box is smaller than that of the cuboidal box by 10 cm2