Rationalise the denominator in each of the following and hence evaluate by taking √2 = 1.414, √3 = 1.732 and √5 = 2.236 up to three places of decimal. -Maths 9th

1 Answer

Answer :

Rationalisation of denominator

Related questions

Description : Rationalise the denominator in each of the following and hence evaluate by taking √2 = 1.414, √3 = 1.732 and √5 = 2.236 up to three places of decimal. -Maths 9th

Last Answer : Rationalisation of denominator

Description : √3-1÷√3+1 rationalise (can solve by finding the rationalizing factor of denominator -Maths 9th

Last Answer : This answer was deleted by our moderators...

Description : √3-1÷√3+1 rationalise (can solve by finding the rationalizing factor of denominator -Maths 9th

Last Answer : This answer was deleted by our moderators...

Description : 4×(√3 + √4)2 + 6(√5 +√6)2 -3(√2 + √3)2 =? a) 167 b) 123 c) 157 d) 153 e) 149

Last Answer : ? =4(3+4+2√12) + 6(5+6+2√30)-3(2+3+2√6) =4(7+2√12)+6(11+2√30)-3(5+2√6) =28 + 8√12 + 66 + 12√30 – 15 - 6√6 =(28+66-15) + (8√12+12√30-6√6) =79 + (8√4 × 3 + 12√30 - 6√6) =79+16√3 + 12√30 - 6√6 =79 + 16 ×1.7 + 12 × 5.4 – 6 ×2.4 =79+27.2 + 64.8-14.4 = 156.6 = 157 Answer: c)

Description : If `sqrt(2)=1.414, sqrt(3)=1.732` and `sqrt(5)=2.236`, find the values of the following. (i) `sqrt(98)` (ii) `sqrt(300)` (iii) `sqrt(128)+sqrt(48)` (i

Last Answer : If `sqrt(2)=1.414, sqrt(3)=1.732` and `sqrt(5)=2.236`, find the values of the following. (i) ` ... `sqrt(128)+sqrt(48)` (iv) `2sqrt(75)-3sqrt(12)`

Description : Rationalise the denominator of the following -Maths 9th

Last Answer : Denominator of the following

Description : Rationalise the denominator of the following -Maths 9th

Last Answer : Denominator of the following

Description : The magnitude of the conduction current density for a magnetic field intensity of a vector yi + zj + xk will be a) 1.414 b) 1.732 c) -1.414 d) -1.732

Last Answer : b) 1.732

Description : The ratio of the actual mesh dimension of Taylor series to that of the next smaller screen is (A) 2 (B) √2 (C) 1.5 (D) √3

Last Answer : (B) √2

Description : Sphericity of a cubical particle, when its equivalent diameter is taken as the height of the cube, is (A) 0.5 (B) 1 (C) √2 (D) √3

Last Answer : (B) 1

Description : According to maximum shear stress failure criterion, yielding in material occurs, when the maximum shear stress is equal to __________ times the yield stress. (A) 0.5 (B) 2 (C) √2 (D) √3/2

Last Answer : (A) 0.5

Description : The sum of a positive number and its reciprocal is twice the difference of the number and its reciprocal. The number is : (A) √2 (B) 1/√2 (C) √3 (D) 1/√3

Last Answer : Answer: C

Description : A circle has radius √2 cm. It is divided into two segments by a chord of length 2cm.Prove that the angle subtended by the chord at a point in major segment is 45 degree . -Maths 9th

Last Answer : Given radius =2 cm Therefore AO=2 cm Let OD be the perpendicular from O on AB And AB =2cm Therefore AD=1cm (perpendicular from the centre bisects the chord) Now in triangle AOD, AO=2 cm ... by a chord at the centre is double of the angle made by the chord at any poin on the circumference)

Description : Visualize the representation of 5.3777... on the number line upto 5 decimal places, that is, up to 5.37777. -Maths 9th

Last Answer : Solution :-

Description : Evaluate: 2+√2 + 1/(2√2) + 1/(√2 - 2) a) 1 + 0.75√2 b) 2 + 1.5√2 c) 2 + √2 d) 2 - √2 e) None of these

Last Answer : 1/(√2 - 2) = (√2 + 2)/(2 - 4) = (√2 + 2)/ -2 1/(2√2) = √2/4 The given equation becomes: 2 + √2 +√2/4 – (√2 + 2) / 2 = (4(2 + √2) + √2 – 2(√2 + 2)) / 4 = (4 + 3√2) / 4 = 1 + 0.75√2 Answer: a)

Description : Rationalize the denominator -Maths 9th

Last Answer : open the bracket and change signs and multiply it by both denominator as well as numerator.

Description : Simplify by rationalizing the denominator : -Maths 9th

Last Answer : Rationalizing the denominator

Description : Rationalize the denominator -Maths 9th

Last Answer : open the bracket and change signs and multiply it by both denominator as well as numerator.

Description : Simplify by rationalizing the denominator : -Maths 9th

Last Answer : Rationalizing the denominator

Description : Evaluate each of the following: (i) 1113 – 893 (ii) 463 + 343 (iii) 1043 + 963 (iv) 933 – 1073 -Maths 9th

Last Answer : answer:

Description : Evaluate each of the following: (i) (103)3 (ii) (98)3 (iii) (9.9)3 (iv) (10.4)3 (v) (598)3 (vi) (99)3 -Maths 9th

Last Answer : answer:

Description : Evaluate each of the following using identities: (i) (2x –1x)2 (ii) (2x + y) (2x – y) (iii) (a2b – b2a)2 (iv) (a – 0.1) (a + 0.1) (v) (1.5.x2 – 0.3y2) (1.5x2 + 0.3y2) -Maths 9th

Last Answer : (i) (2x - 1/x)2 [Use identity: (a - b)2 = a2 + b2 - 2ab ] (2x - 1/x)2 = (2x) 2 + (1/x)2 - 2 (2x)(1/x) = 4x2 + 1/x2 - 4 (ii) (2x + y) (2x - y) [Use identity: (a - b)(a + b) = a2 - b 2 ] (2x + y) (2x - ... ) = a2 - b 2 ](1.5 x 2 - 0.3y2 ) (1.5x2 + 0.3y2 ) = (1.5 x 2 ) 2 - (0.3y2 ) 2 = 2.25 x4 - 0.09y4

Description : Evaluate each of the following using identities: (i) (399)2 (ii) (0.98)2 (iii) 991 x 1009 (iv) 117 x 83 -Maths 9th

Last Answer : answer:

Description : A(5,0) and B(0,8) are two vertices of triangle OAB. a). What is the equation of the bisector of angle OAB. b). If E is the point of intersection of this bisector and the line through A and B,find the coordinates of E. Hence show that OA:OB = AE:EB -Maths 9th

Last Answer : NEED ANSWER

Description : A(5,0) and B(0,8) are two vertices of triangle OAB. a). What is the equation of the bisector of angle OAB. b). If E is the point of intersection of this bisector and the line through A and B,find the coordinates of E. Hence show that OA:OB = AE:EB -Maths 9th

Last Answer : This answer was deleted by our moderators...

Description : Five years hence , the age of Ram will be 10 more than the two thirds of Ravi’s age . Assume the present ages of Ram and Ravi as x and y respectively . Express the statement in the form of a linear equation in two variables. -Maths 9th

Last Answer : answer:

Description : Evaluate using identities -Maths 9th

Last Answer : (i) 1023 = (100 + 2)3 = (100)3 + 3(100)2 (2) + 3(100) (2)2 + 23 = 10,00,000 + 60,000 + 1200 + 8 = 10,61,208 (ii) 993 = (100 - 1)3 = 1003 - 3(100)2 (1) + 3(100) (1)2 - 13 = 10,00,000 - 30,000 + 300 - 1 = 9,70,299

Description : Evaluate using the identities -Maths 9th

Last Answer : (i) 505 × 503 = (500 + 5) (500 + 3) = 5002 + (5 + 3) (500) + 5 × 3 = 250000 + 4000 + 15 = 254015 (ii) 37 × 16 = (30 + 7) (30 - 4) = 302 + (7 - 4) (30) - 7 × 4 = 900 + 90 - 28 = 962

Description : If p (x) = x2 – 4x + 3, then evaluate p(2) – p (-1) + p (1/2). -Maths 9th

Last Answer : Solution of this question

Description : Using suitable identity, evaluate the following. -Maths 9th

Last Answer : Evaluate the following

Description : Using suitable identity, evaluate the following -Maths 9th

Last Answer : Evaluation of following

Description : Evaluate using identities -Maths 9th

Last Answer : (i) 1023 = (100 + 2)3 = (100)3 + 3(100)2 (2) + 3(100) (2)2 + 23 = 10,00,000 + 60,000 + 1200 + 8 = 10,61,208 (ii) 993 = (100 - 1)3 = 1003 - 3(100)2 (1) + 3(100) (1)2 - 13 = 10,00,000 - 30,000 + 300 - 1 = 9,70,299

Description : Evaluate using the identities -Maths 9th

Last Answer : (i) 505 × 503 = (500 + 5) (500 + 3) = 5002 + (5 + 3) (500) + 5 × 3 = 250000 + 4000 + 15 = 254015 (ii) 37 × 16 = (30 + 7) (30 - 4) = 302 + (7 - 4) (30) - 7 × 4 = 900 + 90 - 28 = 962

Description : If p (x) = x2 – 4x + 3, then evaluate p(2) – p (-1) + p (1/2). -Maths 9th

Last Answer : Solution of this question

Description : Using suitable identity, evaluate the following. -Maths 9th

Last Answer : Evaluate the following

Description : Using suitable identity, evaluate the following -Maths 9th

Last Answer : Evaluation of following

Description : Evaluate: 25 to the power 1/3 × 5 to the power 1/3. -Maths 9th

Last Answer : NEED ANSWER

Description : Evaluate: 25 to the power 1/3 × 5 to the power 1/3. -Maths 9th

Last Answer : Solution :-

Description : Evaluate 185 x 185 - 15 x 15 -Maths 9th

Last Answer : Solution :-

Description : Evaluate 105 x 108 without multiplying directly. -Maths 9th

Last Answer : Solution :-

Description : Evaluate x if log3 (3 + x) + log3 (8 – x) – log3 (9x – 8) = 2 – log39 -Maths 9th

Last Answer : (c) 4log3 (3 + x) + log3 (8 - x) - log3 (9x - 8) = 2 - log39 ⇒ log3 (3 + x) + log3 (8 - x) - log3 (9x - 8) + log39 = 2⇒ log3 \(\bigg[rac{(3+x)(8-x)(9)}{(9x-8)}\bigg]=2\)⇒ \(rac{9(24+8x-3x-x^2)}{(9x- ... = 9x - 8 ⇒ x2 + 4x - 32 = 0 ⇒ (x + 8) (x - 4) = 0 ⇒ x = - 8, 4. Taking the positive value x = 4.

Description : Maths | Complex Numbers | If √3 + i =  r (cosθ + i sinθ), then find the value of θ in radian measure.

Last Answer : Solution :

Description : Class 12 | Maths | Complex Numbers | Express the complex numbers modulus-amplitude form  - √3 + i

Last Answer : Solution : 

Description : What is the greatest number that divides 364 414 and 539 with the same remainder in each case?

Last Answer : The number is 25.

Description : If -√5 and √5 are the roots of the quadratic polynomial. Find the quadratic polynomial. (a) x-5 (b) (x-5)(x+5) (c) x 2 – 5 (d) x 2 – 25

Last Answer : (c) x 2 – 5

Description : The perimeter of a triangle with vertices (0, 4), (0, 0) and (3, 0) is: (a) 12 units (b) 11 units (c) 5units (d) (7 + √5)units

Last Answer : (a) 12 units

Description : Consider a hash table of size m=100 and the hash function h(k) = floor(m(kA mod 1)) for A = (√5 − 1)/2 = 0.618033. Compute the location to which the key k = 123456 is placed in hash table. (A) 77 (B) 82 (C) 88 (D) 89

Last Answer : (C) 88

Description : What the Denominator of a proper fraction is 99 what do you notice about the repeating digit in its decimal form?

Last Answer : I don’t understand the question

Description : When the Denominator of a proper fraction is 99 what do you notice about the repeating digit in its decimal form?

Last Answer : I don’t understand the question

Description : Determine the relationship between the pair of words NUMERATOR : DENOMINATOR and then select the pair of words from the following which have a similar relationship: (A) fraction : decimal (B) divisor : quotient (C) top : bottom (D) dividend : divisor

Last Answer : (C) top : bottom