Description : Arvind and Vinod have some erasers. Arvind said to Vinod, if you will give me 10 erasers, I will have twice the erasers left with you. Represent this situation as a linear equation in two variables. -Maths 9th
Last Answer : Solution :-
Description : Let cost of a pen and a pencil be “x” and “y” respectively. A girl pays ₹16 for 2 pens and 3 pencils. Write the given data in the form of a linear equation in two variables. Also represent it graphically. -Maths 9th
Description : Twice the number of marbles with Aman exceeds thrice the number of marbles with Vinay by 12. Assume the number of marbles with Aman and Vinay as x and y respectively .Express the statement in the form of a linear equation in two variables. -Maths 9th
Last Answer : answer:
Description : If the length of a rectangle is decreased by 3 units and breadth increased by 4 unit, then the area will increase by 9 sq. units. Represent this situation as a linear equation in two variables. -Maths 9th
Description : The length of a rectangular piece of fabric is twice its width . identify the geometrical representation of this situation when represented as an equation in two variables. Width and length be represented as x and y respectively . -Maths 9th
Description : Two batsman Rahul and Anil while playing a cricket match scored 120 runs. For this, write a linear equation in two variables and draw the graph. -Maths 9th
Description : On planet A , each alien has 3 eyes and on planet B , each alien has 4 eyes. A group of aliens from planets A and B landed on earth. They had 30 eyes in all. Assuming number of ... planets A and B respectively , express the situation in the form of linear equation in two variables. -Maths 9th
Description : Write the equation representing y-axis. -Maths 9th
Last Answer : Solution :- x =0
Description : Write the equation representing x-axis. -Maths 9th
Last Answer : Solution:- y=0
Description : The sum of twice the age of Ram and one-third the age of Shyam is 62 years. Express the statement as a linear equation in two variables. -Maths 9th
Last Answer : Let Ram's age be x and Shyam's age be y. Then, 2x+1/3y=62
Description : Force applied on a body of mass 5 kg is directly proportional to the acceleration produced in the body. Represent this solution as a linear equation in two variables. -Maths 9th
Last Answer : Solution :- Let the force be x and acceleration due to force be y.
Description : What is the standard deviation and what is the probability that a student scored higher than 322 if the mean test score is 312 and 16 percent of the scores are under 307?
Last Answer : Assuming a normal distribution:If 16% are less than 307, then 84% are greater than 307.Using single tailed normal tables we want the z value whichgives 84%-50% = 34% = 0.34 to the left of the mean; this is z ≈ ... 1 - 0.977 = 0.023 = 2.3 % are greater than 322→ probability greater than 322 is 2.3%
Description : Nandita scores 60% marks in five subjects together, viz., Hindi, Science, Mathematics, English and Sanskrit, where in the maximum marks of each subject were 105. How many marks did Nandita score in Science, if she scored 69 ... and 51 marks in English? a) 66 b) 68 c) 55 d) 65 e) None of these
Last Answer : Answer: D Total of maximum marks of all subjects=105×5=525 75% of 525=525 ×60/100= 315 Obtained marks of foru subjects (Hindi, Sanskrit, mathematics and English) =69+62+68+51=250 So, the obtained marks in Science=315-250=65
Description : The average score in a bank examination of 13 students of a class is 50. If the scores of the top five students are not considered, the average score of the remaining students falls by 5. The pass mark ... integral scores, the maximum possible score of the topper is. A) 85 B) 90 C) 95 D) 100
Last Answer : D Average = Sum of observations/Number of observations Given, average score in a bank examination of 13 students of a class is 50. Sum of total scores = 13 50= 650 Given, if the scores of the top five students are not ... b + c + d + e = 290 ⇒46+ 47 + 48+ 49 +e = 290 ⇒e = 100
Description : Five years hence , the age of Ram will be 10 more than the two thirds of Ravi’s age . Assume the present ages of Ram and Ravi as x and y respectively . Express the statement in the form of a linear equation in two variables. -Maths 9th
Description : Write the linear equation such that each point on its graph has an ordinate 3 times its abscissa. -Maths 9th
Last Answer : Let the abscissa of the point be x, According to the question, Ordinate (y) = 3 x Abscissa ⇒ y=3x When x = 1, then y = 3 x 1 = 3 and when x = 2, then y = 3 x 2 = 6. Here, ... the line AB. Hence, y = 3x is the required equation such that each point on its graph has an ordinate 3 times its abscissa.
Description : Let y varies directly as x. If y = 12 when x = 4, then write a linear equation. What is value of y when x = 5 ? -Maths 9th
Last Answer : Linear equation
Description : Write a solution of the linear equation 5x + 0y +8 = 0 in two variables. -Maths 9th
Last Answer : Solution : -
Description : Write any two solutions of the linear equation 3x + 2y =9. -Maths 9th
Description : Write the linear equation represented by line AB and PQ. Also find the co-ordinate of intersection of line AB and PQ. -Maths 9th
Description : he auto-rickshaw fare in a city is charged as ₹10 for the first kilometre and @ ₹4 per kilometre for subsequent distance covered. Write the linear equation to express the above statement. Draw the graph of linear equation. -Maths 9th
Last Answer : Solution :- Fig. 3.12 represents the graph of the linear equation y = 4x+6.
Description : A family spends ₹500 monthly as a fixed amount on milk and extra milk costs ₹ 20 per kg. Taking quantity of extra milk as x and total expenditure on milk as y. Write a linear equation and fill the table. -Maths 9th
Description : Half the perimeter of a rectangular garden in 36m. Write a linear equation which satisfies this data. Draw the graph for the same. -Maths 9th
Description : The cost of a table is 100 more than half the cost of the chair write the statement linear equation in two varible -Maths 9th
Last Answer : This answer was deleted by our moderators...
Description : Write any four solutions of the linear equation y = 4 x – 11. -Maths 9th
Description : Solve the equation 2x + 1 = x -3, and represent the solution(s) on (i) the number line. (ii) the Cartesian plane. -Maths 9th
Description : The weight of a man is four times the weight of a child. Write an equation in two variables for this situation. -Maths 9th
Description : The equation whose roots are twice the roots of the equation x^2 – 3x + 3 = 0 is -Maths 9th
Description : 3. ABCD is a rectangle and P, Q, R and S are mid-points of the sides AB, BC, CD and DA respectively. Show that the quadrilateral PQRS is a rhombus. -Maths 9th
Last Answer : Solution: Given in the question, ABCD is a rectangle and P, Q, R and S are mid-points of the sides AB, BC, CD and DA respectively. Construction, Join AC and BD. To Prove, PQRS is a rhombus. Proof: In ΔABC P and Q ... (ii), (iii), (iv) and (v), PQ = QR = SR = PS So, PQRS is a rhombus. Hence Proved
Description : 2. ABCD is a rhombus and P, Q, R and S are the mid-points of the sides AB, BC, CD and DA respectively. Show that the quadrilateral PQRS is a rectangle. -Maths 9th
Last Answer : Solution: Given in the question, ABCD is a rhombus and P, Q, R and S are the mid-points of the sides AB, BC, CD and DA respectively. To Prove, PQRS is a rectangle. Construction, Join AC and BD. Proof: In ΔDRS and ... , In PQRS, RS = PQ and RQ = SP from (i) and (ii) ∠Q = 90° , PQRS is a rectangle.
Description : If P,Q,R,S are respectively the mid - points of the sides of a parallelogram ABCD, if ar(||gm PQRS) = 32.5cm2 , then find ar(||gm ABCD). -Maths 9th
Last Answer : Join PR. ∵ △PSR and ||gm APRD are on the same base and between same parallel lines. ar(△PSR) = 1/2 ar(||gm APRD) Similarly, ar(△PQR) = 1/2 ar(||gm PBCR) ar(△PQRS) = ar(△PSR) + △(PQR) = 1/2 ar(||gm APRD) + 1 ... |gm PBCR) = 1/2 ar(||gm ABCD) ⇒ ar(||gm ABCD) = 2 ar(||gm PQRS) = 2 32.5 = 65cm2
Description : P, Q, R and S are respectively the mid-points of the sides AB, BC, CD and DA of a quadrilateral ABCD in which AC = BD. -Maths 9th
Last Answer : Given In a quadrilateral ABCD, P, Q, R and S are the mid-points of sides AB, BC, CD and DA, respectively. Also, AC = BD To prove PQRS is a rhombus.
Description : P, Q, R and S are respectively the mid-points of sides AB, BC, CD and DA of quadrilateral ABCD in which AC = BD and AC ⊥ BD. Prove that PQRS is a square. -Maths 9th
Last Answer : Given In quadrilateral ABCD, P, Q, R and S are the mid-points of the sides AB, BC, CD and DA, respectively. Also, AC = BD and AC ⊥ BD. To prove PQRS is a square. Proof Now, in ΔADC, S and R are the mid-points of the sides AD and DC respectively, then by mid-point theorem,
Description : ABCD is a rectangle and p q r s are the mid points of the side AB BC CD AND DA respectively. Show that the quadrilateral PQRS is a rhombus -Maths 9th
Description : If ABCD is a rectangle and P, Q, R and S are the mid-points of the sides AB, BC, CD and DA respectively, then quadrilateral PQRS is a rhombus. -Maths 9th
Last Answer : Here, we are joining A and C. In ΔABC P is the mid point of AB Q is the mid point of BC PQ∣∣AC [Line segments joining the mid points of two sides of a triangle is parallel to AC(third side) and ... RS=PS=RQ[All sides are equal] ∴ PQRS is a parallelogram with all sides equal ∴ So PQRS is a rhombus.
Description : ABCD is a trapezium in which AB || DC and AD = BC. If P, Q, R and S be respectively the mid-points of BA, BD, CD and CA, then PQRS is a -Maths 9th
Last Answer : Here is your First of all we will draw a quadrilateral ABCD with AD = BC and join AC, BD, P,Q,R,S are the mid points of AB, AC, CD and BD respectively. In the triangle ABC, P and Q are mid points of AB and AC respectively. All sides are equal so PQRS is a Rhombus.
Description : ABCD is a square. P, Q, R, S are the mid-points of AB, BC, CD and DA respectively. By joining AR, BS, CP, DQ, we get a quadrilateral which is a -Maths 9th
Last Answer : According to the given statement, the figure will be a shown alongside; using mid-point theorem: In △ABC,PQ∥AC and PQ=21 AC .......(1) In △ADC,SR∥AC and SR=21 AC .... ... are perpendicular to each other) ∴PQ⊥QR(angle between two lines = angle between their parallels) Hence PQRS is a rectangle.
Description : What is the general form of linear equation in two variables ? -Maths 9th
Last Answer : The general form of linear equation in two variables can be written as: ax+by+c=0
Description : The point (2,3) lies on the graph of the linear equation 3x - (a -1)y =2a -1. If the same point also lies on the graph of the linear equation 5x + (1-2a)y = 3b, then find the value of b. -Maths 9th
Last Answer : Given, point (2,3) lies on the line. So, the point (2, 3) is the solution of 3x - (a -1) y = 2a - 1 On putting x = 2 and y = 3 in given solution. ∴ 3 2 - (a-1) 3 = 2a - 1 ⇒ 6 - 3a + 3 = 2a - 1 ⇒ - 3a ... 2 2) 3 = 3b ⇒ 10 - 9 = 3b ⇒ 1 = 3b ⇒ 1 / 3 = b Hence, the value of b is 1 / 3.
Description : The linear equation 2x – 5y = 7 has -Maths 9th
Last Answer : (c) In the given equation 2x – 5y = 7, for every value of x, we get a corresponding value of y and vice-versa. Therefore, the linear equation has infinitely many solutions.
Description : If (2, 0) is a solution of the linear equation 2x + 3y = k, then the value of k is -Maths 9th
Last Answer : (a) Since, (2, 0) is a solution of the given linear equation 2x + 3y = k, then put x =2 and y= 0 in the equation. ⇒ 2 (2) + 3 (0) = k ⇒ k = 4 Hence, the value of k is 4.
Description : Any solution of the linear equation 2x + 0y + 9 = 0 in two variables is of the form -Maths 9th
Last Answer : (a) The given linear equation is 2x + 0y + 9 = 0 ⇒ 2x + 9 = 0 ⇒ 2x = -9 ⇒ x= - 9/2 and y can be any real number. Hence, (-9/2 , m) is the required form of solution of the given linear equation.
Description : The graph of the linear equation 2x + 3y = 6 cuts the Y-axis at the point. -Maths 9th
Last Answer : (d) Since, the graph of linear equation 2x + 3y = 6 cuts the Y-axis. So, we put x = 0 in the given equation 2x+ 3y = 6, we get 2 x 0+ 3y = 6 ⇒ 3y = 6 y = 2. Hence, at the point (0, 2), the given linear equation cuts the Y-axis.
Description : x = 5 and y = 2 is a solution of the linear equation. -Maths 9th
Last Answer : (c) (a) Take x + 2y, on putting x=5 and y = 2, we get 5 + 2(2) = 5+ 4 = 9≠7. So, (5, 2) is not a solution of x + 2y = 7 (b) Take 5x + 2y, on putting x = 5 and y = 2, we get 5x 5 + 2 x2 =25+ 4 = ... on putting x = 5 and y = 2, we get 5 5 + 2=25 + 2 =27 ≠7 So, (5, 2) is not a solution of 5x + y = 7.
Description : If a linear equation has solutions (-2, 2), (0, 0) and (2, – 2), then it is of the form. -Maths 9th
Last Answer : (b) Let us consider a linear equation ax + by + c = 0 (i) Since, (-2,2), (0, 0) and (2, -2) are the solutions of linear equation therefore it satisfies the Eq. (i), we get At point(-2,2), -2a + 2b + c ... b(x + y)= 0 ⇒ x + y = 0, b ≠ 0 Hence, x + y= 0 is the required form of the linear equation.