Nandita scores 60% marks in five subjects together, viz., Hindi, Science, Mathematics, English and Sanskrit, where in the maximum marks of each subject were 105. How many marks did Nandita score in Science, if she scored 69 marks in Hindi, 62 marks in Sanskrit, 68 marks in Mathematics and 51 marks in English? a) 66 b) 68 c) 55 d) 65 e) None of these

Nandita scores 60% marks in five subjects together, viz., Hindi, Science, Mathematics, English and Sanskrit, where in the maximum marks of each subject were 105. How many marks did Nandita score in Science, if she scored 69 marks in Hindi, 62 marks in Sanskrit, 68 marks in Mathematics and 51 marks in English? a) 66 b) 68 c) 55 d) 65 e) None of these
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1 Answer

Answer :

Answer: D

Total of maximum marks of all subjects=105×5=525

75% of 525=525 ×60/100= 315

Obtained marks of foru subjects (Hindi, Sanskrit, mathematics and English)

=69+62+68+51=250

So, the obtained marks in Science=315-250=65
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Related questions

Nesha scored 120 out of 150 in English, 120 out of 180 in mathematics and 160 out of 200 in Science. Find Nesha’s score as percentage: (i) in Mathematics (ii) in all the three subjects (on the whole). a) 66 2/3, 78 22/51 b) 71 23/5, 45 7/31 c) 54 13/33, 82 3/4 d) 60 3/4, 76 32/41

Description : Nesha scored 120 out of 150 in English, 120 out of 180 in mathematics and 160 out of 200 in Science. Find Nesha’s score as percentage: (i) in Mathematics (ii) in all the three subjects (on the whole). a) 66 2/3, 78 22/51 b) 71 23/5, 45 7/31 c) 54 13/33, 82 3/4 d) 60 3/4, 76 32/41 

Last Answer :  Answer: A (i) Percentage scored in Mathematics = 120/180 100  = 12000/180  =1200/18  = 66 2 /3 % (ii) Total maximum of all the three subjects = 150 + 160 + 200 = 510 and Total score in the ... percentage on the whole = (400/510 100)  = (40000/510)  = 4000/51  = 78 22/51 %

The ratio of the monthly salaries of A and B is in the ratio 15 : 16 and that of B and C is in the ratio 17 : 18. Find the monthly income of C if the total of their monthly salary is Rs 1,87,450. A) Rs 66,240 B) Rs 72,100 C) Rs 62,200 D) Rs 65,800 E) Rs 60,300

Description : The ratio of the monthly salaries of A and B is in the ratio 15 : 16 and that of B and C is in the ratio 17 : 18. Find the monthly income of C if the total of their monthly salary is Rs 1,87,450. A) Rs 66,240 B) Rs 72,100 C) Rs 62,200 D) Rs 65,800 E) Rs 60,300

Last Answer : Answer: A A/B = 15/16 and B/C = 17*18 So A : B : C = 15*17 : 16*17 : 16*18 = 255 : 272 : 288 So C’s salary = [288/(255+272+288)] * 1,87,450= Rs 66,240

on analyzing the result of an competitive exam the teacher found that the average for the entire the class was 69 marks. If we say that average of 10 % of the students scored 77 marks and average of 28 % of the students scored 66 marks, then calculate average marks of the remaining students of the class A) 67.54 B) 68.26 C) 66.91 D) 69.06

Description :  on analyzing the result of an competitive exam the teacher found that the average for the entire the class was 69 marks. If we say that average of 10 % of the students scored 77 marks and average of 28 % of the ... marks of the remaining students of the class A) 67.54 B) 68.26 C) 66.91 D) 69.06 

Last Answer : D) average of entire class = 69marks average of 28 % of the students = 66 marks average of 10% of the students = 77 marks then % of remaining students = (100- 10 - 28) = 62% let the average of 62% of the ... (62*x)+770+1848= 6900 62 * x = 6900-770-1848 62*x = 4282 x = 69.06

Saravanan has scored an total of 90% in an examination with five subjects in the ratio 18:14:15:21:22. If 85% is the marks required to get an ‘A’ grade in each subject, then find in how many subjects did he get an ‘A’ grade. Given that the maximum marks in each subject is 120. A) 2 B) 3 C) 4 D) 5

Description : Saravanan has scored an total of 90% in an examination with five subjects in the ratio 18:14:15:21:22. If 85% is the marks required to get an ‘A’ grade in each subject, then find in how many subjects did he get an ‘A’ grade. Given that the maximum marks in each subject is 120. A) 2 B) 3 C) 4 D) 5 

Last Answer : Answer: B) Maximum total marks = 5 120 = 600 Marks scored by Saravanan = 90/100*600=540 Let the marks scored by him in the 5 subjects be 18x,14x,15x,21x and 22x respectively. 18x + 14x + 15x + 21x + ... A' grade i.e. 0.85 120 = 102 Therefore, he has got an A' grade in 3 subjects.

The ratio of marks obtained by Vinod and Basu is 6:5. If the combined average of their percentage is 68.75 and their sum of the marks is 275, find the total marks for which exam was conducted. A) 150 B) 200 C) 400 D) 450 E) None

Description : The ratio of marks obtained by Vinod and Basu is 6:5. If the combined average of their percentage is 68.75 and their sum of the marks is 275, find the total marks for which exam was conducted. A) 150 B) 200 C) 400 D) 450 E) None

Last Answer : Answer: B The sum of the marks=6x+5x=11x But the sum of the marks is given as 275=11x. We get x=25x=25 therefore, Vinod's marks is 6x=1506x=150 and Basu's marks = 5x=125. ... Therefore, if their combined average of their percentage is 137.5 then the total marks would be 137.568.75 100=200

Number of students in 4th and 5th class is in the ratio 6 : 11. 40% in class 4 are girls and 48% in class 5 are girls. What percentage of students in both the classes are boys? A) 62.5% B) 54.8% C) 52.6% D) 55.8% E) 53.5%

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Last Answer : Answer: B Total students in both = 6x+11x = 17x Boys in class 4 = (60/100)*6x = 360x/100 Boys in class 5 = (52/100)*11x = 572x/100 So total boys = 360x/100 + 572x/100 = 932x/100 = 9.32x % of boys = [9.32x/17x] * 100=54.8%

A group of students of arithmetic mean of the marks in a test was 63. The brightest 30% of them secured a mean score of 70 and the dullest 15% a mean score of 41. The mean score of remaining 55 % is A) 63.675 B) 61.785 C) 65.181 D) 66.67

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Seats for Mathematics, Science and arts in a school are in the ratio 5:7:8. There is a proposal to increase these seats by X%, Y% and Z% respectively. And the ratio of increased seats is 2:3:4, which of the following is true? A) X = 50; Z = 40 B) Y = 40; Z = 50 C) X = 40; Z = 75 D) X = 50; Z = 40 E) Y = 50; X = 75

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Last Answer : Answer: C Number of increased seats are (140% of 5x), (150% of 7x) and (175% of 8x) i.e., (140/100 * 5x), (150/100 * 7x) and (175/100 * 8x) i.e., 7x, 21x/2 and 14x Required ratio = 7x:21x/2: ... of 8 = 6 total seats 8+6=14 Now compare ratios of all 7:21/2:14=>14:21:28 =>2:3:4

Manish, Rahul and Bharti have some stones with each of the. Five times the number of stones with Rahul equals seven times the number of stones with Manish while five times the number of stones with Manish equals seven times the number of stones with Bharti. What is the minimum number of stones that can be there with all three of them put together? A) 113 B) 109 C) 93 D) 97 E) NONE

Description : Manish, Rahul and Bharti have some stones with each of the. Five times the number of stones with Rahul equals seven times the number of stones with Manish while five times the number of stones with Manish equals seven ... there with all three of them put together? A) 113 B) 109 C) 93 D) 97 E) NONE

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The scores of an English test out of 100 of 20 students are given below : 75, 69, 88, 55, 95, 88, 73, 64, 75, 98, 88, 95, 90, 95, 88, 44, 59, 67, 88, 99. -Maths 9th

Description : The scores of an English test out of 100 of 20 students are given below : 75, 69, 88, 55, 95, 88, 73, 64, 75, 98, 88, 95, 90, 95, 88, 44, 59, 67, 88, 99. -Maths 9th

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Description : The ratio of the number of boys to the number of girls in a school is 6 : 5. If 20% of boys and 45% of girls come by bus to school, what percentage of students opt transport other than bus to come to school? A) 68 9/11% B) 68 7/11% C) 72 7/11% D) 73% E) 73 5/11%

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In a pocket of A, the ratio of Rs.1 coins, 50p coins and 25p coins can be expressed by three consecutive odd prime numbers that are in ascending order. The total value of coins in the bag is Rs 58. If the number of Rs.1, 50p, 25p coins are reversed, find the new total value of coins in the pocket of A? A) Rs 68 B) Rs 43 C) Rs 75 D) Rs 82 E) NONE

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Description :  In a test, minimum passing percentage for girls and boys is 60% and 25% respectively. A boy scored 560 marks and failed by 160 marks. How many more marks did a girl require to pass in the test if she scored 216 marks ? a) 2123 b) 1512 c) 2251 d) 1325 e) 3989

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Had Ravita scored 10 more marks in her Mathematics test out of 30 marks, 9 times these marks would have been the square of her actual marks. How many marks did she get in the test? -Maths 10th

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Two numbers are respectively 40% and 60% more than than the third number. The ratio of the two number is A) 6:7 B) 7:8 C) 8:7 D) 7:5 E) None of these

Description : Two numbers are respectively 40% and 60% more than than the third number. The ratio of the two number is A) 6:7 B) 7:8 C) 8:7 D) 7:5 E) None of these

Last Answer : Answer: B Let third number = x (140/100)x = (7/5)x (160/100)x = (8/5)x (7/5) : (8/5) = 35 : 40 = 7 : 8

The ratio of salary of two persons X and Y is 5:8. If the salary of X increases by 60% and that of Y decreases by 35% then the new ratio of their salaries become 40:27. What is X's salary? a) Rs.15000 b) Rs.12000 c) Rs.19500 d) Data inadequate. e) NONE

Description : The ratio of salary of two persons X and Y is 5:8. If the salary of X increases by 60% and that of Y decreases by 35% then the new ratio of their salaries become 40:27. What is X's salary? a) Rs.15000 b) Rs.12000 c) Rs.19500 d) Data inadequate. e) NONE

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The number of candidates writing three different entrance exams is in the ratio 4:5:6. There is a proposal to increase these numbers of candidates by 40%, 60% and 85% respectively. What will be the ratio of increased numbers? a) 14:15:16 b) 12:15:19 c)13:19:21 d) 14:16:19 E) None of these

Description : The number of candidates writing three different entrance exams is in the ratio 4:5:6. There is a proposal to increase these numbers of candidates by 40%, 60% and 85% respectively. What will be the ratio of increased numbers? a) 14:15:16 b) 12:15:19 c)13:19:21 d) 14:16:19 E) None of these

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Determine the ratio of the number of people having characteristic X to the number of people having characteristic Y in a population of 100 subjects from the following table People having X and Y are 20 People having X but not Y are 10 People having Y but not X are 30 People having neither X nor Y are 40. a) 3 : 5 b) 3 : 2 c) 1 : 2 d) 2 : 3 e) None of these

Description : Determine the ratio of the number of people having characteristic X to the number of people having characteristic Y in a population of 100 subjects from the following table People having X and Y are 20 People having X but not Y are 10 ... 3 : 5 b) 3 : 2 c) 1 : 2 d) 2 : 3 e) None of these

Last Answer : Answer: A Number of people having characteristic X = 10 + 20 = 30 Number of people having characteristic Y = 20 + 30 = 50 Therefore Required ratio = 30 : 50 = 3 : 5

In a class test, the sum of marks obtained by P in Mathematics and Science is 28. Had he got 3 more marks in Mathematics and 4 marks less in Science, the product of marks obtained in the two subjects would have been 180? Find the marks obtained in two subjects separately. -Maths 10th

Description : In a class test, the sum of marks obtained by P in Mathematics and Science is 28. Had he got 3 more marks in Mathematics and 4 marks less in Science, the product of marks obtained in the two subjects would have been 180? Find the marks obtained in two subjects separately. -Maths 10th

Last Answer : Let P has obtained x in mathematics and y in science. Then by the problem, x+y=28.......(1). If P would have got 3 marks more in mathematics, then P would have got (x+3) in mathematics ... P obtained 12 marks in mathematics and 16 in science. or, P obtained 9 marks in mathematics and 19 in science.

The salary of two friends Ramu and Raju are in the ratio 4:5. If the salary of each one increases by Rs.6000, then the new ratio becomes 48:55. What is Raju's present salary? a) Rs.10500 b) Rs.10500 c) Rs.11500 d) Rs.12500

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Last Answer : Answer : B Ratio their salary is 4:5 Let the original salary of Ramu and Raju be 4k and 5k respectively. After increasing Rs.6000, the ratio becomes 48:55 That is, (4k+6000)/(5k+6000) = 48/55 ... of Raju; that is, 5k. If 20k = 42000 then 5k = 10500. Hence the required answer is Rs.10500

In a bag there are coins of 25p, 10p and 5p in the ratio 1:2:3.If there are Rs.45 in all then find how many 25p coins are there? A) 60 B) 65 C) 70 D) 75 E) None of these

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The average marks obtained by a student in Tamil, english, maths, science, and social together is 65% above the average mark obtained in maths and science together. How many more marks exceeded by the average of maths and science together than the sum of the tamil and english together? A) 50 B) 65 C) Data insufficient D) None of these

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Last Answer : C) According to the question  There is no other information about the marks in any one of the subject. The data gives is insufficient to answer the question.

(d) Rs 1.50 Q.61. CA Co manufactures a single product and has drawn up the following flexed budget for the year. 60% 70% 80% Rs Rs Rs Direct materials 120,000 140,000 160,000 Direct labour 90,000 105,000 120,000 Production overheads 54,000 58,000 62,000 Other overheads 40,000 40,000 40,000 Total Cost 304,000 343,000 382,000 What would be the total cost in a budget that is prepared at the 77% level of activity? (a) Rs 330,300 (b) Rs 370,300 (c) Rs 373,300 (d) Rs 377,300

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Last Answer : (b) Rs 370,300

The average score in a bank examination of 13 students of a class is 50. If the scores of the top five students are not considered, the average score of the remaining students falls by 5. The pass mark was 35 and the maximum mark was 100. It is also known that none of the students failed. If each of the top five scorers had distinct integral scores, the maximum possible score of the topper is. A) 85 B) 90 C) 95 D) 100

Description : The average score in a bank examination of 13 students of a class is 50. If the scores of the top five students are not considered, the average score of the remaining students falls by 5. The pass mark ... integral scores, the maximum possible score of the topper is. A) 85 B) 90 C) 95 D) 100

Last Answer : D Average = Sum of observations/Number of observations Given, average score in a bank examination of 13 students of a class is 50. Sum of total scores = 13 50= 650 Given, if the scores of the top five students are not ... b + c + d + e = 290 ⇒46+ 47 + 48+ 49 +e = 290 ⇒e = 100

Seven men, five women and eight children were given as assignment of distributing 2000 books to students in a school over a period of three days. All of them distributed books on the first day. One of the second day two women and three children remained absent and on the third day three men and five children remained absent. If the ratio of the number of books distributed in a day by a man, a woman and a child was 5 : 4 : 2 respectively, a total of approximately how many books were distributed on the second day? a) 1000 b) 800 c) 650 d) 900 e) Cannot be determined

Description : Seven men, five women and eight children were given as assignment of distributing 2000 books to students in a school over a period of three days. All of them distributed books on the first day. One of the second ... distributed on the second day? a) 1000 b) 800 c) 650 d) 900 e) Cannot be determined

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Average age of A, B, C is 90yrs, however when D joins them, then the average comes down to 80 yrs. Now a new person E, whose age is six-fifth of the age of D, replaces A and the new average is 78. What is age of A? A) 64 B) 68 C) 62 D) 66

Description : Average age of A, B, C is 90yrs, however when D joins them, then the average comes down to 80 yrs. Now a new person E, whose age is six-fifth of the age of D, replaces A and the new average is 78. What is age of A? A) 64 B) 68 C) 62 D) 66

Last Answer : B) according to the question A+B+C/3=90 => A+B+C =270…………..(1) A+B+C +D/4=80 => A+B+C +D=320………(2) From the equation 1 and 2 D=50 E =6/5×50=60 E+B+C +D/4=78 => E+B+C +D =312 B+C +D =312-60=252……………..(3) From 2and 3 The age of A=320-252=68

The average marks of a class of 90 students is 126. Out Of them, 4 scores zero, first 60 students scored an average of 116, next 24 scored an average of 118. What is the mark obtained by the remaining student in the class? A) 750 B) 862 C) 774 D) 875

Description : The average marks of a class of 90 students is 126. Out Of them, 4 scores zero, first 60 students scored an average of 116, next 24 scored an average of 118. What is the mark obtained by the remaining student in the class? A) 750 B) 862 C) 774 D) 875

Last Answer : C) According to the question, 90*126=(4*0)+(60*116)+(24*118)+2y 11340=6960+2832+2y 2y=1548 y=774

In a diagnostic test in mathematics given to students, the following marks (out of 100) are recorded 46, 52, 48, 11, 41, 62, 54, 53, 96, 40, 98 and 44. -Maths 9th

Description : In a diagnostic test in mathematics given to students, the following marks (out of 100) are recorded 46, 52, 48, 11, 41, 62, 54, 53, 96, 40, 98 and 44. -Maths 9th

Last Answer : NEED ANSWER

In a diagnostic test in mathematics given to students, the following marks (out of 100) are recorded 46, 52, 48, 11, 41, 62, 54, 53, 96, 40, 98 and 44. -Maths 9th

Description : In a diagnostic test in mathematics given to students, the following marks (out of 100) are recorded 46, 52, 48, 11, 41, 62, 54, 53, 96, 40, 98 and 44. -Maths 9th

Last Answer : Median will be a good representative of the data, because 1.each value occurs once. 2.the data is influenced by extreme values.

180 sweets are divided among friends A, B, C and D in which B and C are brothers also such that sweets divided between A and B are in the ratio 2 : 3, between B and C in the ratio 2 : 5 and between C and D in ratio 3 : 4. What is the number of sweets received by the brothers together? A) 78 B) 84 C) 92 D) 102 E) 88

Description : 180 sweets are divided among friends A, B, C and D in which B and C are brothers also such that sweets divided between A and B are in the ratio 2 : 3, between B and C in the ratio 2 : 5 and between C ... . What is the number of sweets received by the brothers together? A) 78 B) 84 C) 92 D) 102 E) 88

Last Answer : Answer: B A : B : C : D 2*2*3 : 3*2*3 : 3*5*3 : 3*5*4 4 : 6 : 15 : 20 B and C together = [(6+15)/(4+6+15+20)] * 180 = 84

The ratio of the price of two houses was 17:24. Two years later, when the price of the first had risen by 20% while the price of second house increases by Rs.500 and their prices become 16:25. Find the original prices of the two houses together? a) Rs.2603 b) Rs.2503 c) Rs.2403 d) Rs.2303 e) None of these

Description : The ratio of the price of two houses was 17:24. Two years later, when the price of the first had risen by 20% while the price of second house increases by Rs.500 and their prices become 16:25. Find the original ... two houses together? a) Rs.2603 b) Rs.2503 c) Rs.2403 d) Rs.2303 e) None of these

Last Answer : Answer: A Let, new price of the first house=17x 120/100=102x/5 Let, new price of the second house=24x+500 According to the question, (102x/5) :(24x+500)=16 :25 ((102x/5))/((24x+500 ... price of second house=24 4000/63=1523.81 ~ Rs.1524 Required answer, =1079+1524=2603 Answer=d) Rs.2603

In a public examination , Raghav scored twice twice Sunitha’s score. If r and s represent the scores of Raghav and Sunitha respectively , Write a linear equation in r and s representing the above situation ? -Maths 9th

Description : In a public examination , Raghav scored twice twice Sunitha’s score. If r and s represent the scores of Raghav and Sunitha respectively , Write a linear equation in r and s representing the above situation ? -Maths 9th

Last Answer : Let raghav and sunita score be r and S respectively. Sunita score=2times raghav score Therefore, s=2r

What is the standard deviation and what is the probability that a student scored higher than 322 if the mean test score is 312 and 16 percent of the scores are under 307?

Description : What is the standard deviation and what is the probability that a student scored higher than 322 if the mean test score is 312 and 16 percent of the scores are under 307?

Last Answer : Assuming a normal distribution:If 16% are less than 307, then 84% are greater than 307.Using single tailed normal tables we want the z value whichgives 84%-50% = 34% = 0.34 to the left of the mean; this is z ≈ ... 1 - 0.977 = 0.023 = 2.3 % are greater than 322→ probability greater than 322 is 2.3%

In a class of 55 students, the number of students studying different subjects are 23 in Mathematics, 24 in Physics, 19 in Chemistry, 12 in Mathematics

Description : In a class of 55 students, the number of students studying different subjects are 23 in Mathematics, 24 in Physics, 19 in Chemistry, 12 in Mathematics

Last Answer : In a class of 55 students, the number of students studying different subjects are 23 in Mathematics, 24 in Physics, 19 ... ` B. `30` C. `22` D. `27`

How can I translate a few sentences in English or Hindi to Sanskrit?

Description : How can I translate a few sentences in English or Hindi to Sanskrit?

Last Answer : translate.google.com

31 candidates appeared for an examination, 15 candidates passed in English, 15 candidates passed in Hindi, 20 candidates passed in Sanskrit. 3 candida

Description : 31 candidates appeared for an examination, 15 candidates passed in English, 15 candidates passed in Hindi, 20 candidates passed in Sanskrit. 3 candida

Last Answer : 31 candidates appeared for an examination, 15 candidates passed in English, 15 candidates passed ... How many candidates passed only in two subjects

Upto what age, can the judges of Supreme Court serve? (1) (1) 62 years (2) (2) 68 years (3) 65 years (4) 70 years

Description : Upto what age, can the judges of Supreme Court serve? (1) (1) 62 years (2) (2) 68 years (3) 65 years (4) 70 years

Last Answer : (3) 65 years Explanation: The Judge of Supreme Court can serve up to 65 years of age.

What is the retirement age for a Supreme Court Judge? (1) 62 years (2) 68 years (3) 65 years (4) 70 years

Description : What is the retirement age for a Supreme Court Judge? (1) 62 years (2) 68 years (3) 65 years (4) 70 years

Last Answer : (3) 65 years Explanation: All Judges of Supreme Court are appointed by the President of India. Supreme Court Judges retire at the age of 65. A judge of Supreme Court can be removed by the ... 4) of constitution of India on ground of proved misconduct or incapacity or judge resigning from his office.

The angular separation between the vectors A = 4i + 3j + 5k and B = i – 2j + 2k is (in degrees) a) 65.8 b) 66.8 c) 67.8 d) 68.8

Description : The angular separation between the vectors A = 4i + 3j + 5k and B = i – 2j + 2k is (in degrees) a) 65.8 b) 66.8 c) 67.8 d) 68.8

Last Answer : c) 67.8

Insert the missing number: 36/62, 39/63, 43/61, 48/64, ? (A) 51/65 (B) 56/60 (C) 54/60 (D) 33/60

Description : Insert the missing number: 36/62, 39/63, 43/61, 48/64, ? (A) 51/65 (B) 56/60 (C) 54/60 (D) 33/60

Last Answer : Answer: C Observer 36/62, 39/63, 43/61, 48/64, ? series Upper part is increase by 3, 4, 5, 6 i.e 36+3= 39, 39+4 = 43, 43+5 = 48, 48 + 6 = 54.

How many removal examination (s) will be given to an examinee who obtains a passing rating in the majority of the subjects but obtains a rating in the other subject (s) below seventy percent (70%) but not lower than sixty percent (60%)? A. 1 B. 3 C. 2 D. Unlimited

Description : How many removal examination (s) will be given to an examinee who obtains a passing rating in the majority of the subjects but obtains a rating in the other subject (s) below seventy percent (70%) but not lower than sixty percent (60%)? A. 1 B. 3 C. 2 D. Unlimited

Last Answer : A. 1

Make a stem-and-leaf plot for this set of data. Find the range,median,and mode of the data. : 47 54 70 62 59 62 82 66 62 73 55 82 59?

Description : Make a stem-and-leaf plot for this set of data. Find the range,median,and mode of the data. : 47 54 70 62 59 62 82 66 62 73 55 82 59?

Last Answer : nevermind- i figured it out

A candidate successfully passes the Board exams if he/she obtains a. A general average of sixty-five percent (65%). b. A general average of seventy-five percent (75%). c. A general average of seventy-five percent (75%) in at least a majority of the subjects given in the Board exams. d. A general average of seventy-five percent (75%), with no grades lower than sixty-five percent (65%) in any given subject

Description : A candidate successfully passes the Board exams if he/she obtains a. A general average of sixty-five percent (65%). b. A general average of seventy-five percent (75%). c. A general average of ... seventy-five percent (75%), with no grades lower than sixty-five percent (65%) in any given subject

Last Answer : A general average of seventy-five percent (75%), with no grades lower than sixty-five percent (65%) in any given subject

The average of 11 results is 50. If the average of first 6 results is 49 and that of last 6is 52, find the sixth result? A.55 B.56 C.65 D.62 E.None of these

Description : The average of 11 results is 50. If the average of first 6 results is 49 and that of last 6is 52, find the sixth result? A.55 B.56 C.65 D.62 E.None of these

Last Answer : Answer – B (56) Explanation – The total of 11 results = 11 x 50 = 550 The total of first 6 results = 6 x 49 = 294 The total of last 6 results = 6 x 52 = 312 The sixth result is common to both: Sixth result = 294 + 312 – 550 = 56

Two vessels contains equal quantity of solution contains milk and water in the ratio of 7:2 and 4:5 respectively. Now the solutions are mixed with each other then find the ratio of milk and water in the final solution? A) 11:7 B) 11:6 C) 11:5 D) 11:9 E) None of these

Description : Two vessels contains equal quantity of solution contains milk and water in the ratio of 7:2 and 4:5 respectively. Now the solutions are mixed with each other then find the ratio of milk and water in the final solution? A) 11:7 B) 11:6 C) 11:5 D) 11:9 E) None of these

Last Answer : Answer: A milk = 7/9 and water = 2/9 – in 1st vessel milk = 4/9 and water = 5/9 – in 2nd vessel (7/9 + 4/9)/ (2/9 + 5/9) = 11:7

Two candles of same height are lighted at the same time. The first is consumed in 6 hours and second in 4 hours. Assuming that each candles burns at a constant rate, in how many hours after being lighted, the ratio between the first and second candles becomes 2:1? a) 1 hour b) 2 hour c) 3 hour d) 4 hour e) None of these

Description : Two candles of same height are lighted at the same time. The first is consumed in 6 hours and second in 4 hours. Assuming that each candles burns at a constant rate, in how many hours after being lighted, the ratio between ... becomes 2:1? a) 1 hour b) 2 hour c) 3 hour d) 4 hour e) None of these

Last Answer : Answer: C Let height of both candles is ‘h’ and let after t times ratio between the height be 2:1 h – t*h/6 : h – t*h/4 = 2:1 t = 3

Mr. Shrimant inherits 4325 gold coins and divides them among his three sons; Bharat, Parat and Marat; in a certain ratio. Out of the total coins received by each of them, Bharat sells 40 coins; Parat donates his 20 coins and Marat loses 30 coins. Now, the ratio of gold coins with them is 41:34:46, respectively. How many coins did Parat receive from his father? a) 1210 b) 1211 c) 1212 d) 1213 e) None of these

Description : Mr. Shrimant inherits 4325 gold coins and divides them among his three sons; Bharat, Parat and Marat; in a certain ratio. Out of the total coins received by each of them, Bharat sells 40 coins; Parat donates his ... did Parat receive from his father? a) 1210 b) 1211 c) 1212 d) 1213 e) None of these 

Last Answer : Answer: A 41x+40+34x+20+46x+30=4325 =>121x=4325-90 =>x=35 Required answer, number of coins received by parat =34x+20=34×35+20=1210

Two candles of same height are lighted at the same time. The first is consumed in 3 hours and second in 2 hours. Assuming that each candles burns at a constant rate, in how many hours after being lighted, the ratio between the first and second candles becomes 2:1? A) 2 hour B) 2.5 hour C) 4 hour D) 1.5 hour E) None of these

Description : Two candles of same height are lighted at the same time. The first is consumed in 3 hours and second in 2 hours. Assuming that each candles burns at a constant rate, in how many hours after being lighted, the ratio between the ... 2:1? A) 2 hour B) 2.5 hour C) 4 hour D) 1.5 hour E) None of these

Last Answer : Answer: D Height of both candles are same i.e. h First one takes 3 hours to burn completely, so in one hour = h/3 Similarly second one will burn in one hour = h/2 Let after t time, ratio between their height is 2:1 so, ... given 2:1, h - t*(h/3) / h - t*(h/2) = 2/1 Solving we get t = 1.5