Calculate 4th root of 193 + underroot 2178 -Maths 9th

Calculate 4th root of 193 + underroot 2178 -Maths 9th
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Description : Find the value of the polynomial p(x) = x^3-3x^2-2x+6 at x = underroot 2 -Maths 9th

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Last Answer : Given, Area of rectangle = 25x2 - 35x + 12 We know, area of rectangle = length breadth So, by factoring 25x2 - 35x + 12, the length and breadth can be obtained. 25x2 - 35x + 12 = 25x2 - 15x - 20x + 12 => 25x2 - 35x + ... )] = 2(5x - 3 + 5x - 4) = 2(10x - 7) = 20x - 14 So, the perimeter = 20x - 14

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The bond energies of `F_(2),Cl_(2),Br_(2)` and `I_(2)` are 155.4, 243.6, 193.2 and `151.2 Kjmol^(-1)` respectively. The strongest bond is :

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Last Answer : The bond energies of `F_(2),Cl_(2),Br_(2)` and `I_(2)` are 155.4, 243.6, 193.2 and `151.2 Kjmol^(-1)` ... . F -F B. Cl - Cl C. Br - Br D. I - I

What two square numbers add up to 193?

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What is 193 divided by 12?

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Consider the given network implementation scenario. For the given classful NID 199.10.20.0/24, the requirement is to create 13 subnets. With given details, find the range of first and last valid IP in 15th subnet. a. 199.10.20.208 to 199.10.20.222 b. 199.10.20.225 to 199.10.20.238 c. 199.10.20.193 to 199.10.20.206 d. Not of these

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Harold Clayton Urey, an American, received the 193 Nobel Prize in chemistry for his discovery of: w) Francium x) Americium y) deuterium z) protium

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Simplify: root 72 + root 800 - root 18. -Maths 9th

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root( 5+2root6) -Maths 9th

Description : root( 5+2root6) -Maths 9th

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Description : Find the sum of (3 root 3 + 7 root 2) and (root 3 - 5 root 2) -Maths 9th

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Find the values of k for which the equations x^2 – kx – 21 = 0 and x^2 – 3kx + 35 = 0 will have a common root? -Maths 9th

Description : Find the values of k for which the equations x^2 – kx – 21 = 0 and x^2 – 3kx + 35 = 0 will have a common root? -Maths 9th

Last Answer : Let the common root be α ⟹α2−kα−21=0......(1) α2−3kα+35=0........(2) (1)−(2)⟹2kα=56⟹α=k28​Substituting α=k28​ in (1) (k28​)2−28−21=0 ⟹k=±4

If two equations x^2 + a^2 = 1 – 2ax and x^2 + b^2 = 1 – 2bx have only one common root, then -Maths 9th

Description : If two equations x^2 + a^2 = 1 – 2ax and x^2 + b^2 = 1 – 2bx have only one common root, then -Maths 9th

Last Answer : x2+b2=1−2bx ...... (i) x2+b2+2bx=1 (x+b)2=1 x+b= 1 ∴x=1−b,−1−b x2+a2=1−2ax ...... (ii) x2+a2+2ax=1 (x+a)2=1 ∴x=1−a,−1−a It is given that the equations have only one root in ... or −1−a=−b−1 we get a=b but then both roots will be common, which is not possible. Hence, options A,B and C are correct.

If one root of the equation (x^2/a)+ (x/a)+(1/c) = 0is reciprocal of the other, then which of the following is correct ? -Maths 9th

Description : If one root of the equation (x^2/a)+ (x/a)+(1/c) = 0is reciprocal of the other, then which of the following is correct ? -Maths 9th

Last Answer : answer:

If one root of the equation ax^2 + x – 3 = 0 is –1, then what is the other root ? -Maths 9th

Description : If one root of the equation ax^2 + x – 3 = 0 is –1, then what is the other root ? -Maths 9th

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One root of x^2 + kx – 8 = 0 is the square of the other, then the value of k is : -Maths 9th

Description : One root of x^2 + kx – 8 = 0 is the square of the other, then the value of k is : -Maths 9th

Last Answer : answer:

If x^2 + mx + n = 0 and x^2 + px + q = 0 have a common root, then the common root is -Maths 9th

Description : If x^2 + mx + n = 0 and x^2 + px + q = 0 have a common root, then the common root is -Maths 9th

Last Answer : Let α be the common root ∴α2+pα+q=0 ...........(1) and α2+qα+p=0 ........ (2) Solving (1) & (2), we get, p2−q2α2​=q−pα​=q−p1​∴α=q−pp2−q2​ and α=1 ⇒q−pp2−q2​=1 ⇒p2−q2=q−p (or) (p2−q2)+(p−q)=0 ⇒(p−q)[p+q+1]=0 ⇒p−q=0 or p+q+1=0

Obtain a relation for the distance travelled by an object moving with a uniform acceleration in the interval between 4th and 5th seconds -Physics 9th

Description : Obtain a relation for the distance travelled by an object moving with a uniform acceleration in the interval between 4th and 5th seconds -Physics 9th

Last Answer : Uniform acceleration in the interval between 4th and 5th seconds = = (5u + 1/2 * a * 5^2) - (4u + 1/2 * a * 4^2) = 5u + 1/2 *a * 25 - 4u + 1/2 * a * 16 = u + 1/2 * a * (25-16) = u + 1/2 * a * 9 = u + 9/2 * a If it starts from rest then the displacement will be 9/2a. hope this helps!

According to United Nations Conference on Trade and Development (UNCTAD) report, what is the position of India in Asia among the largest recipients of Foreign Direct Investment (FDI)? A) 12th B) 10th C) 4th D) 9th E) 6th

Description : According to United Nations Conference on Trade and Development (UNCTAD) report, what is the position of India in Asia among the largest recipients of Foreign Direct Investment (FDI)? A) 12th B) 10th C) 4th D) 9th E) 6th

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What octave bands are there in the midrange? A. 1st and 2nd B. 5th, 6th and 7th C. 3rd and 4th D. 8th and 9th

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Last Answer : B. 5th, 6th and 7th

Under which of the following conditions there will be no change in the reading frame of following mRNA? 5’ AACAGCGGUGCUAUU 3’ (a) Deletion of GGU from 7th, 8th and 9th positions (b) Insertion of G at 5th position (c) Deletion of G from 5th position (d) Insertion of A and G at 4th and 5th position respectively

Description : Under which of the following conditions there will be no change in the reading frame of following mRNA? 5' AACAGCGGUGCUAUU 3' (a) Deletion of GGU from 7th, 8th and 9th positions (b) Insertion of G ... ) Deletion of G from 5th position (d) Insertion of A and G at 4th and 5th position respectively

Last Answer : (a) Deletion of GGU from 7th, 8th and 9th positions

Under which of the following conditions there will be no change in the reading frame of following mRNA? 5’ AACAGCGGUGCUAUU 3’ (a) Deletion of GGU from 7th, 8th and 9th positions (b) Insertion of G at 5th position (c) Deletion of G from 5th position (d) Insertion of A and G at 4th and 5th position respectively

Description : Under which of the following conditions there will be no change in the reading frame of following mRNA? 5' AACAGCGGUGCUAUU 3' (a) Deletion of GGU from 7th, 8th and 9th positions (b) Insertion of G ... ) Deletion of G from 5th position (d) Insertion of A and G at 4th and 5th position respectively

Last Answer : (a) Deletion of GGU from 7th, 8th and 9th positions