The perimeter of a triangle is 50 cm. -Maths 9th

The perimeter of a triangle is 50 cm. -Maths 9th
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Let the length of the smallest side = x  According to the statement, other two sides of the triangle will be x + 4 and 2x - 6  Perimeter of triangle = x + x + 4 + 2x - 6 ⇒ 50 = 4x - 2  ⇒ 4x = 52  ⇒ x = 13  ∴ Sides of triangle are = 13, (13 + 4), (2 x 13 - 6) = 13 cm, 17 cm, 20 cm  Let, a = 13 cm, b = 17 cm and c = 20 cm ∴ s = (a + b + c)/2 = (13 + 17 + 20)/2  = 25 cm ∴  Area of  △ = root under( √(s - a)(s - b)(s -c)) = root under( √25(25 -13) (25 -17) (25 - 20)  = root under( √25 x 12 x 8 x 5)  = root under( √5 x 5 x 3 x 4 x 4 x 2 x 5)  = 20 √30 = 20 x 5.48 = 109.6 cm2
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The perimeter of a triangle is 50 cm. One side of a triangle is 4 cm longer than the smaller side and the third side is 6 cm less than twice the smaller side. -Maths 9th

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Last Answer : Let the smallest side of the triangle be x cm long So, second side =(x+4)cm and third side =(2x−6)cm Given, perimeter =50cm Therefore, x+(x+4)+(2x−6)=50 ⇒4x=52 ⇒x=13cm So, first side of the triangle is ... =25cm Therefore, area of Δ=s(s−a)(s−b)(s−c) =25(25−13)(25−17)(25−20) =25 12 8 5 = 2030 cm2

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